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  • Multiple possible jsp views for a request

    - by Karl Walsh
    I'm looking to offer the user some way of changing how a single page looks based on some pre-defined jsps. i.e. Two or more jsp's contain similar information, and would be backed by a single controller method. The controller would decide which view to return. Is there a common way of achieving this? At the moment I have some administration screens where I control a list of possible views. The user can then choose which one to see from a drop-down. My current issue is that I don't know how to confirm (at the admin screen) that the view is valid. Is there a way of asking spring for all possible views so I can filter them and resent a drop-down on the admin screen rather than a free text field? If not is there a way of asking spring if a single view is valid? All these views will reside under a common directory, so it would probably be possible to scan recursively from that point and build a list of possible views. This goes beyond simply changing the css, since the page content might be different despite being backed by the same model.

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  • Help with complex MVVM (multiple views)

    - by jsjslim
    I need help creating view models for the following scenario: Deep, hierarchical data Multiple views for the same set of data Each view is a single, dynamically-changing view, based on the active selection Depending on the value of a property, display different types of tabs in a tab control My questions: Should I create a view-model representation for each view (VM1, VM2, etc)? 1. Yes: a. Should I model the entire hierarchical relationship? (ie, SubVM1, HouseVM1, RoomVM1) b. How do I keep all hierarchies in sync? (e.g, adding/removing nodes) 2. No: a. Do I use a huge, single view model that caters for all views? Here's an example of a single view Figure 1: Multiple views updated based on active room. Notice Tab control Figure 2: Different active room. Multiple views updated. Tab control items changed based on object's property. Figure 3: Different selection type. Entire view changes

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  • How to redirect page

    - by sharun
    Hi i created one java application in which i tried to open my company's standard login page and i planned to redirect the link to open my own design page. Standard login page is displayed, instead of going to my own design page as usual its going to mail page. After sign out the mail page i'm gettting my own design page. But my need is, when i sign in the standard login page it should diplay my own design page. Is it possible? Please Help me. And this is code that i followed import java.io.IOException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import com.google.appengine.api.users.User; public class New extends HttpServlet { /** * */ private static final long serialVersionUID = 1L; public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setHeader("Cache-Control", "no-store, no-cache, must-revalidate"); resp.setContentType("text/html"); UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { if(user.getEmail().equals("[email protected]")) { resp.getWriter().println("done"); resp.sendRedirect("/login.jsp"); } else { resp.getWriter().println("Hello, " + user.getNickname()+"<br>"); resp.getWriter().println("Thanks for your interest. But this application is still not available to everybody."); resp.getWriter().println("<a href="+UserServiceFactory.getUserService().createLogoutURL(userService.createLoginURL(req.getRequestURI()))+">Log out</a>"); } } else { resp.sendRedirect(userService.createLoginURL("http://mail.yyy.edu.in")); } } } Thanks in advance Regards Sharun.

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  • Web page from the terminal

    - by juanpablo
    Hi, I use snow leopard. how I can send a html page to web browser from the terminal? example: if I am in $HOME dir, where exist myPage.html, I can send this page for see in web browser with a command ? Many thanks.

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  • query to select topic with highest number of comment +support+oppose+views

    - by chetan
    table schema title description desid replyto support oppose views browser used a1 none 1 1 12 - bad topic b2 1 2 3 14 sql database a3 none 4 5 34 - crome b4 1 3 4 12 Topic desid starts with a and comment desid starts with b .For comment replyto is the desid of topic . Its easy to select * with highest number of support+oppose+views by query "select * from [DB_user1212].[dbo].[discussions] where desid like 'a%' order by (sup+opp+visited) desc" For highest (comment +support+oppose+views ) i tried "select * from [DB_user1212].[dbo].[discussions] where desid like 'a%' order by ((select count(*) from [DB_user1212].[dbo].[discussions] where replyto = desid )+sup+opp+visited) desc" but it didn't work . Because its not possible to send desid from outer query to innner subquery .

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  • Separating Db from business with Inherited classes using multiple views

    - by catalinux
    I have a software that has a car model that will be used in different views (listing, ads, detail page, carousel, up sell widget,etc). class CarModel extends DbModel{ } I look for a "nice way" (a combination of flexible, easy to maintain,etc) to have this used in views. I'm thinking at two different ways Having object views for each context CarViewBase{ var car;// of type CarModel function constructor(args){ //will instantienta internal variable car based on args } function getThumb(){ } function getTitle(){ } } CarListingView extends CarViewBase{ function getListing(){ } } CarAdsView extends CarViewBase{ //the busines rule changes for ads widget function getThumb(){ } } Extending directly the CarModel The challenges comes when My Car Model might need an abstract factory. Let's say I have a field on my car object that states the type of the car : a truck, or a bike, or van. How would affect that my object view? Let's say that getTitle() rule would be different for each type of it. How would you do it?

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  • MVC2: Validate PartialView before Form Submit of Page containing Partial View

    - by Pascal
    I am using asp.net mvc2 and having a basic Page that includes a Partial View within a form <% using (Html.BeginForm()) { %> <% Html.RenderAction("partialViewActionName", "Controllername"); %> <input type="submit" value="Weiter" /> <% } %> When I submit the form, the httpPost Action of my Page is called, and AFTER that the httpPost Action of my Partial View is called [HttpPost] public virtual ActionResult PagePostMethod(myModel model) { // here I should know about the validation of my partial View // If partialView.ModelState is valid then // return View("success"); // else return View(model) } [HttpPost] public virtual ActionResult partialViewActionName(myModel model) { ModelState.AddModelError("Error"); return View(model); } But as I am doing the Validation in the httpPost Method of my Partial View (because I want to use my Partial View in several Places) I cant decide if my hole page is valid or not. Has anyone an Idea how I could do this? Isn´t it a common task to have several partial Views in a page but have the information about validation in the page action methods? Thanks very much for your help!!

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  • Problem Using Partial View In for each loop

    - by leen3o
    I'm a little confused here, I am trying use a partial view in a for each loop like so <% foreach (var item in (IEnumerable<MVCLD.Models.Article>)ViewData["LatestWebsites"]){%> <% Html.RenderPartial("articlelisttemaple", item); %> <% } %> And my partial view looks like this <div class="listingholders"> <h4><%=Html.ActionLink(item.ArticleTitle, "details", "article", new { UrlID = item.UrlID, ArticleName = item.ArticleTitle.ToString().niceurl() }, null)%> </h4> <p><%= Html.Encode(item.ArticleSnippet) %></p> <div class="clearer">&nbsp;</div> </div> But when I run the project I get told the partial view doesn't understand what item is?? CS0103: The name 'item' does not exist in the current context I can't see why it would be doing this as I'm passing item into the partial view?

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  • access dropdown control from the master page to the content page using asp.net

    - by Isha Jain
    i have a master page and the content pages in the master page i have the textbox and dropdown the value in the dropdown may vary according to the content pages e.g for one content page the dropdown may contain branchname, city, address and let for other content page under same master page the dropdown may have values like Contactnumber, EmailID, ........... ......... etc..... so please help me to how can i bind that dropdown from my content page thanks.

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  • android webview returns blank page when load dynamic html page

    - by user2962555
    I am trying to click one button to load a page into a div block dynamically. To test it, I try to append a list item with text "abc" into the loaded page. However, I always get a blank page. load function works fine because if I try to load a static page, it works. Following is my main html page code. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>LoadPageTest</title> <link rel="stylesheet" href="http://fonts.googleapis.com/css?family=Open+Sans:300,400,700"> <link rel="stylesheet" href="./css/customizedstyle.css"> <link rel="stylesheet" href="./css/themes/default/jquery.mobile-1.4.3.min.css"> <link rel="stylesheet" href="./css/jqm-demos.css"> <script src="./js/jquery.js"></script> <script scr="./js/customizedjs.js"></script> <script src="./js/jquery.mobile-1.4.3.min.js"></script> <script> $( document ).on( "pagecreate", "#demo-page", function() { $( document ).on( "swipeleft swiperight", "#demo-page", function( e ) { if ( $( ".ui-page-active" ).jqmData( "panel" ) !== "open" ) { if ( e.type === "swipeleft" ) { $( "#right-panel" ).panel( "open" ); } } }); }); </script> <style type="text/css"> body { overflow:hidden; } </style> </head> <body style= "overflow:hidden" scrolling="no"> <style type="text/css"> body { overflow:hidden; } </style> <div data-role="page" id="main-page" style= "overflow:hidden" scrolling="no"> <div role="main" class="ui-content" id ="maindiv" style= "overflow: auto"> Will load diff pages here. </div><!-- /content --> <div data-role="panel" id="left-panel" data-theme="b"> <ul data-role="listview" data-icon="false" id="menu"> <li> <a href="#" id = "btnA" data-rel="close">Go Page A <img src="./images/icona.png" class="ui-li-thumb"/> </li> <li> <a href="#" id = "btnB" data-rel="close">Go Page B <img src="./images/iconb.png" class="ui-li-thumb"/> </li> </ul> </div><!-- /panel --> <script type="text/javascript"> $("#btnA").on("click", function(){ $("#maindiv").empty(); $("#maindiv").load("pageA.html"); }); $("#btnB").on("click", function(){ $("#maindiv").empty(); $("#maindiv").load("pageB.html"); }); </script> </div><!-- /page --> </body> </html> Next is code for the page I try to load dynamically. <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <title>Page should be loaded</title> <link rel="stylesheet" href="http://fonts.googleapis.com/css?family=Open+Sans:300,400,700"> <link rel="stylesheet" href="./css/customizedstyle.css"> <link rel="stylesheet" href="./css/themes/default/jquery.mobile-1.4.3.min.css"> <link rel="stylesheet" href="./css/jqm-demos.css"> <script src="./js/jquery.js"></script> <script scr="./js/customizedjs.js"></script> <script src="./js/jquery.mobile-1.4.3.min.js"></script> <script> $(document).on('pagebeforeshow', function () { $('#postlist').append('<li> abc </li>'); $('#postlist').listview('refresh'); }); </script> </head> <body > <div data-role="page" id="posthome"> <div data-role = "content"> <ul data-role='listview' id = "postlist"> </ul> </div> </div> </body> </html> I doubt if it is because my javascript in the page doesn't work, cause the swipe js code in the main page seems not work either. Is that possible? I have enabled javascript in the onCreate() function of the activity file as below. protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_message); new LongRunningGetIO().execute(); mWebView = (WebView) findViewById(R.id.webview); mWebView.setWebViewClient(new AppClient()); mWebView.setVerticalScrollBarEnabled(false); mWebView.getSettings().setJavaScriptEnabled(true); mWebView.getSettings().setDomStorageEnabled(true); mWebView.loadUrl("file:///android_asset/index.html"); } I noticed there is a warning for statement to enable javascript "Using setJavaScriptEnabled can introduce XSS vulnerabilities into you application, review carefully". Will that maybe the reason? Then, I added @SuppressLint("SetJavaScriptEnabled") on top of the activity. The warning is gone, but the js code in pages seem still not work.

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  • Change the Views location

    - by Vinni
    I am developing a website in MVC 2.0. I want to change the View folder location in my website. I wanted to keep the views folder inside other folders, When I try to do so i am getting following errors The view 'Index' or its master was not found. The following locations were searched: ~/Views/Search/Index.aspx ~/Views/Search/Index.ascx ~/Views/Shared/Index.aspx ~/Views/Shared/Index.ascx Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. My Views folder will be in ~/XYZ/ABC/Views instead of ~/Views. Please solve my problem. Will I get any problems If I change the default Views folder location. Do I need to change anything in HTML Helper classes because I don't know anything in MVC as this is my starting project i dont want to risk..Please help me out...

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  • Why make the login page to a single page application a separate page?

    - by ryanzec
    I am wondering why it seems to be popular to have the login page of a SPA be a separate page that is not page of the SPA (as in loaded and send data through ajax requests)? I only thing I can think of is security but I can't think a specific security reason. I mean the only thing that come to mind is that if your login page in part of the SPA, it sends the username/password through ajax which can be seen by such tools like firebug or web inspector however even if you send it as a normal POST request, there are other tools that can easily capture this data (like fiddler, httpscoop, etc...). Is there something I am missing?

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  • how to open HTML page stored on client machine from aspx page.

    - by shania
    Hi, I m developing asp.net application in which I m opening HTML page that is stored on client machine on that page I have a link which will open aspx page on server, On that aspx page I have a button that will open another html page stored on client machine. Since I m new to web development Plz help me and suggest me some solutions for this ASAP. Thanks....

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  • Should you disable page file with SSD?

    - by Pyrolistical
    I've been reading http://serverfault.com/questions/23621/any-benefit-or-detriment-from-removing-a-pagefile-on-an-8gb-ram-machine, and it has a lot of great information. But assuming you have more than enough ram, I think page file should be disabled on SSD to extend the life time. I know you would lose the core dump on crash, but not many people need that information. From my understand without a page file as you reach the limit of your ram that might trigger thrashing on disk. But for SSDs there is no concept of thrashing, reads are fast. What do you guys think?

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  • Dynamically created controls and the ASP.NET page lifecycle

    - by Dirk
    I'm working on an ASP.NET project in which the vast majority of the forms are generated dynamically at run time (form definitions are stored in a DB for customizability). Therefore, I have to dynamically create and add my controls to the Page every time OnLoad fires, regardless of IsPostBack. This has been working just fine and .NET takes care of managing ViewState for these controls. protected override void OnLoad(EventArgs e) { base.OnLoad(e); RenderDynamicControls() } private void RenderDynamicControls(){ //1. call service layer to retrieve form definition //2. create and add controls to page container } I have a new requirement in which if a user clicks on a given button (this button is created at design time) the page should be re-rendered in a slightly different way. So in addition to the code that executes in OnLoad (i.e. RenderDynamicControls()), I have this code: protected void MyButton_Click(object sender, EventArgs e) { RenderDynamicControlsALittleDifferently() } private void RenderDynamicControlsALittleDifferently() (){ //1. clear all controls from the page container added in RenderDynamicControls() //2. call service layer to retrieve form definition //3. create and add controls to page container } My question is, is this really the only way to accomplish what I'm after? It seems beyond hacky to effectively render the form twice simply to respond to a button click. I gather from my research that this is simply how the page-lifecycle works in ASP.NET: Namely, that OnLoad must fire on every Postback before child events are invoked. Still, it's worthwhile to check with the SO community before having to drink the kool-aid. On a related note, once I get this feature completed, I'm planning on throwing an UpdatePanel on the page to perform the page updates via Ajax. Any code/advice that make that transition easier would be much appreciated. Thanks

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  • one page filter results in new page in javascript

    - by Jake
    I have links set up on one page and the relationship between the links is a parent child relationship. (For example: Parent: All, Children: Software; Hardware) These links of course lead the user to a new page that shows the results from a table that is populated. Currently these links are all Similar destinations, but just a filter in the url. But the problem is that there is a javascript filter on the page that gives the user to choose between All, Software, or Hardware. Understand basically that if the url is still reading that there on the software page but they just filtered on the page to be Hardware that doesn't look good IMO. So what I was trying to do was make the links on the inital page all go the the exact same destination and somehow still know on the new page which link was clicked and run the javascript filter from knowing which link was clicked on that page. Is there a way to found that out from javascript? I guess a way to pass that value to the new page and retrieving it in javascript without showing it in the url so I can filter the table for the user based on that value?

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  • Rails paginate array items one-by-one instead of page-by-page

    - by hnovick
    Hi Guys, I have a group of assets, let's call them "practitioners". I'm displaying these practitioners in the header of a calendar interface. There are 7 columns to the calendar. 7 columns = 7 practitioners per view/page. Right now: if the first page shows you practitioners 1-7, when you go the next page you will see practitioners 8-15, next page 16-23, etc. etc. i am wondering how to page the practitioners so that if the first page shows you practitioners 1-7, the next page will show you practitioners 2-8, then 3-9, etc. etc. i would greatly appreciate any help you can offer. here is the rails code i am working with. best regards, harris novick # get the default sort order sort_order = RESOURCE_SORT_ORDER # if we've been given asset ids, start our list with them unless params[:asset_ids].blank? params[:asset_ids] = params[:asset_ids].values unless params[:asset_ids].is_a?(Array) sort_order = "#{params[:asset_ids].collect{|id| "service_provider_resources.id = #{id} DESC"}.join(",")}, #{sort_order}" end @asset_set = @provider.active_resources(:include => {:active_services => :latest_approved_version}).paginate( :per_page => RESOURCES_IN_DAY_VIEW, :page => params[:page], :order => sort_order )

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  • [php] Firefox refreshes page 1, even after redirection to page 2

    - by Znarkus
    Hi! This is a quite weird and annoying problem, which is reproduced with the script below. Say we have two pages: script.php and script.php?second. Page 1 creates some database entries and redirects to page 2. On page 2, the user is presented with an editor for said entries. If page 1 for some reason crashes on the first try, and prints some error message, a strange thing will happend. If we refresh page 1 (and this time it redirects fine), every consecutive refresh (of page 2) will actually refresh page 1 and again redirect to page 2. In the above example this would create new database entries for every refresh, which is the problem I want to circumvent by redirecting to page 2. <?php header('Content-type: text/plain'); session_start(); if (!isset($_GET['second'])) { $_SESSION['counter'] = isset($_SESSION['counter']) ? $_SESSION['counter'] + 1 : 1; /*$_SESSION['counter'] = 0; exit('asd');*/ header("Location: {$_SERVER['PHP_SELF']}?second", true, 303); exit; } echo "Counter: {$_SESSION['counter']}"; To try the above complete script, first run it with the commented code intact, then by enabling the commented code. I've tried 301, 302 and 303 redirections. Does someone know why this is happening?

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  • How can I replicate Google Page Speed's lossless image compression as part of my workflow?

    - by Keefer
    I love that Google's Page Speed is able to losslessly compress a lot of my images, but I'd love to make it part of my workflow, prior to uploading a site and making it live. Is there anything I can run locally to give me the same lossless compression? I currently export images from Export For Web from Photoshop, and use a little application called PNGCrusher to reduce file size of PNGs. I'd love to find a faster way though than saving out and replacing the individual images from Page Speed's results.

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  • Google Analytics Views - Why Use Them?

    - by pee2pee
    I've been reading about Google Analytics views but still not sure why I would use them. I'm the only person in the company who understands and uses Google Analytics. We have no subdomains. Is there any reason why I would want to use views? Google Analytics has been going for some years now and I just created a copy of the original view but this has zero data, so I can't see how it would benefit me.

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  • SQL Server Indexed Views

    Views can be an effective tool for speeding up your selects and simplifying complex queries. Learn what indexed views are, where you might want to use them, how to create them, and what constraints exist with their use.

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