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  • Run bat file in Java and wait 2

    - by Savvas Dalkitsis
    This is a followup question to my other question : http://stackoverflow.com/questions/2434125/run-bat-file-in-java-and-wait The reason i am posting this as a separate question is that the one i already asked was answered correctly. From some research i did my problem is unique to my case so i decided to create a new question. Please go read that question before continuing with this one as they are closely related. Running the proposed code blocks the program at the waitFor invocation. After some research i found that the waitFor method blocks if your process has output that needs to be proccessed so you should first empty the output stream and the error stream. I did those things but my method still blocks. I then found a suggestion to simply loop while waiting the exitValue method to return the exit value of the process and handle the exception thrown if it is not, pausing for a brief moment as well so as not to consume all the CPU. I did this: import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; public class Test { public static void main(String[] args) { try { Process p = Runtime.getRuntime().exec( "cmd /k start SQLScriptsToRun.bat" + " -UuserName -Ppassword" + " projectName"); final BufferedReader input = new BufferedReader(new InputStreamReader(p.getInputStream())); final BufferedReader error = new BufferedReader(new InputStreamReader(p.getErrorStream())); new Thread(new Runnable() { @Override public void run() { try { while (input.readLine()!=null) {} } catch (IOException e) { e.printStackTrace(); } } }).start(); new Thread(new Runnable() { @Override public void run() { try { while (error.readLine()!=null) {} } catch (IOException e) { e.printStackTrace(); } } }).start(); int i = 0; boolean finished = false; while (!finished) { try { i = p.exitValue(); finished = true; } catch (IllegalThreadStateException e) { e.printStackTrace(); try { Thread.sleep(500); } catch (InterruptedException e1) { e1.printStackTrace(); } } } System.out.println(i); } catch (IOException e) { e.printStackTrace(); } } } but my process will not end! I keep getting this error: java.lang.IllegalThreadStateException: process has not exited Any ideas as to why my process will not exit? Or do you have any libraries to suggest that handle executing batch files properly and wait until the execution is finished?

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  • php upload file function

    - by Jacksta
    I am trying to write a script which uploads a file via a html form. When I click submit nothing happens. file: upload_form.html <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <form action="do_upload.php" method="post" enctype="multipart/form-data"></form> <p><strong>File to upload</strong></p> <p><input name="img1" type="file" size="30" /></p> <p><input name="submit" type="submit" value="Upolad File" /></p> </body> </html> file: do_upload.php <?php if ($_FILES[img1] != "" { @copy($_FILES[img1] [tm_name], "/tmp" .$_FILES[img1][name]) or die("couldnt copy the file"); } else { die("no file specified"); } ?> <HTML> <head> <title>Successfull File Upload</title> </head> <body> <h1>Success</h1> <p>You sent: <? echo $_FILES[img1][name]; ?>, a <? echo $_FILES[img1][size]; ?>byte filw with a mime type of <? echo $_FILES[img1][type]; ?></p> </body> </HTML>

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  • Add entries to Nautilus' right-click menu (copy, move to arbitrary directories)

    - by qbi
    Assume I want to copy a file from /home/foo/bar/baz to /opt/quuz/dir1/option3. When I try it with Nautilus, first I have to open the correct directory, copy the file, go to the other directory and paste it there. I was thinking of a better way and old KDE3 versions of Konqueror came to mind. It was possible to right-click on a file. The context menu had an option for copying, moving the file to some default directories. Furthermore you could select any directory under /. So for the above action one would right click on a file, select /opt first, a list of subdirectories will open, select /opt/quuz and so on. Using GNOME there are only two possible values (home and desktop). Is there any way to insert more directories to this context menu in GNOME? Can I copy somehow the behaviour of Konqueror?

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  • Drag-and-drop file upload in Chromium?

    - by Zarel
    Drag-and-drop file uploading can be done in Firefox 3.6 by using FileReader: http://stackoverflow.com/questions/2121018/native-drag-drop-file-upload-in-firefox-3-6 However, Google recently released an update for Gmail that allowed drag-and-drop file uploading in Chromium as well as Firefox, and Chromium does not have FileReader. I'm using the latest Chromium nightly, and it can drag-drop upload files, while not supporting FileReader. I've seen someone mention that drag-drop uploading can be possible by dragging onto an <input type="file" />, but that can only support one file at a time, while Gmail's uploader can handle multiple files being dragged onto it, so that's clearly not what they're doing. So the question is, how do they do it? How do you support Chromium for HTML5 file uploading?

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  • Upload and parse csv file with "universal newline" in python on Google App Engine

    - by greg
    Hi, I'm uploading a csv/tsv file from a form in GAE, and I try to parse the file with python csv module. Like describe here, uploaded files in GAE are strings. So I treat my uploaded string a file-like object : file = self.request.get('catalog') catalog = csv.reader(StringIO.StringIO(file),dialect=csv.excel_tab) But new lines in my files are not necessarily '\n' (thanks to excel..), and it generated an error : Error: new-line character seen in unquoted field - do you need to open the file in universal-newline mode? Does anyone know how to use StringIO.StringIO to treat strings like files open in universal-newline?

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  • Is it possible to preview arbitrary formats in Nautilus?

    - by alfC
    I recently found out that Nautilus (Ubuntu 12.04 at least) can show thumbnails of files of non-image formats, for example (data grapher) grace files (.agr) shows a small version of the graph contained in its data. Obviously, there some library or script that is processing the file, making the image, and allowing nautilus to show a small version of it. This made me think that in principle any file that potentially can be processed into an image can serve as a Nautilus thumbnail. For example, a .tex file (which can be converted to .pdf) or a gnuplot script can be displayed as a thumbnail when possible. In the case of .tex file, the correspoding .pdf can be created by the command pdflatex file.tex. The question is, how can I tell Nautilus to create a thumbnail for an arbitrary format and how do I specify the commands to do so within Nautilus?

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  • [grails] attaching multiple files to a domain class

    - by Emyr
    I've seen various Grails plugins which allow easier handling of file uploads, however these tend only to support a single file per form-submit. I'd like a multi-attach form where as soon as you pick one file, an extra field and button is added using JS (various sites do it like this). Do you know of any good plugins which provide elegant uploading of multiple files without excessive coding? A progress bar either per-file of for the whole process would also be very nice. I don't know to what extent I can allow GORM to handle a java.io.File field (or in this case a Collection<File>).

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  • Java: file write on finalize method

    - by sowrov
    In my understanding a singleton object will destroy only when the application is about to terminate. So in C++ I write a Singleton class to log my application and in that Singleton logger's destructor I log the time when my application was terminated. Things worked perfectly in C++. Now I want to have that same logger in Java, as in java there is no destructor so I implemented the finalize method for that singleton logger. But it seem that finalize method actually never get called. So, I add that System.runFinalizersOnExit(true); line, somewhere in my code (though I know it is deprecated) and that finalize method get called every time before termination of the app. But still there is a problem! If I try to write anything on file in that finalize method, It does not work, though System.out work without any problem! :( Can you guys help me on this problem? Here is a sample code of what I am try to do: Singleton Logger Class: public class MyLogger { FileWriter writer; private MyLogger() { try { this.writer = new FileWriter("log.txt"); } catch (IOException ex) { } } public static MyLogger getInstance() { return MyLoggerHolder.INSTANCE; } private static class MyLoggerHolder { private static final MyLogger INSTANCE = new MyLogger(); } @Override protected void finalize () { try { super.finalize(); System.out.println("Here"); //worked correctly. this.writer.write(new Date().toString()+System.getProperty("line.separator")); this.writer.write("End"); this.writer.flush(); //does not work! this.writer.close(); } catch (Throwable ex) { } } public synchronized void log(String str) { try { this.writer.write(new Date().toString()+System.getProperty("line.separator")); this.writer.write(str+"\n"); this.writer.flush(); } catch (IOException ex) { } } } Main: public class Main { public static void main(String[] args) { System.runFinalizersOnExit(true); MyLogger logger = MyLogger.getInstance(); logger.log("test"); } }

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  • Monitoring file upload progress in Actionscript 3

    - by helloworlder
    I'm trying to track the progress of a file upload in AS3, and I'm getting strange behavior. When I select a file and upload it, the progress is instantaneously 100% even if the file is 10 or more megabytes, but it's not finished. The onComplete event is fired about 30 second to a few minutes later (depending on file size) when the file has really finished uploading. I've tested this locally and on the server, the behaviour is the same. Has anyone else experienced this? Very frustrating ... Otherwise, the file is uploading fine. The code is simple: myFileReference.addEventListener(ProgressEvent.PROGRESS, onUploadProgress); function onUploadProgress(e:ProgressEvent) { var pctDone:Number = (e.bytesLoaded / e.bytesTotal) * 100; trace(pctDone); }

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  • Do any database "styles" use discrete files for their tables?

    - by Brad
    I've been talking to some people at work who believe some versions of a database store their data in discrete tables. That is to say you might open up a folder and see one file for each table in the database then several other supporting files. They do not have a lot of experience with databases but I have only been working with them for a little over a half year so I am not a canonical source of info either. I've been touting the benefits of SQL Server over Access (and before this, Access over Excel. Great strides have been made :) ). But, other people were of the impression that the/one of the the benefit(s) of using SQL Server over Access was that all the data was not consolidated down into one file. Yet, SQL Server packs everything into a single .mdf file (plus the log file). My question is, is there an RDBMS which holds it's data in multiple discrete files instead of one master file? And if the answer is yes, why do it one way over the other?

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  • How do I make a multiple file upload?

    - by Bluemagica
    I am trying to make a multiple image uploader. The file upload fields are being added in the form dynamically using jquery. I tried making an array of the fields since I don't want to have a hidden field. so my generated upload fields look like <input type="file" id="img0" name="img[]"/> <input type="file" id="img1" name="img[]"/> <input type="file" id="img2" name="img[]"/> ..... .. And on the php side I did something like if(isset($_FILES['img'])) { foreach($_FILES['img'] as $k=>$v) { if($v!="") { uploadImage($k,0,0,0,"content/gallery/"); } } } Now I know I am way too wrong, since in that code I am looping through the 'img' file's properties instead of all images....but I have no idea how to fix this. PS: uploadImage is a function I wrote which expects the file input field's name as the first parameter.

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  • attaching multiple files to a domain class

    - by Emyr
    I've seen various Grails plugins which allow easier handling of file uploads, however these tend only to support a single file per form-submit. I'd like a multi-attach form where as soon as you pick one file, an extra field and button is added using JS (various sites do it like this). Do you know of any good plugins which provide elegant uploading of multiple files without excessive coding? A progress bar either per-file of for the whole process would also be very nice. I don't know to what extent I can allow GORM to handle a java.io.File field (or in this case a Collection<File>).

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  • I can't upload a file with CGIHTTPServer

    - by sdemingo
    Hi all, I'm using the CGIHTTPServer to implement a simple cgi server. I'm trying to upload a file by a form with the post method and the multipart/form-data enctype but I have problems when I recover the value of the fields in the cgi script. When the script catch the form fields, the value of the file is a MiniFieldStorage with two fields only (key and file name), and I can't recover the content of the file. As the API doc shows, this content is in value field of a StorageField but in the MiniFieldStorage this field isn't exits. ¿How can I recover a StorageField with the content of the file instead a MiniStorageField? ¿There are other method to upload a file using CGIHTTPServer? Thanks a lot

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  • Using the HTML5 &lt;input type=&quot;file&quot; multiple=&quot;multiple&quot;&gt; Tag in ASP.NET

    - by Rick Strahl
    Per HTML5 spec the <input type="file" /> tag allows for multiple files to be picked from a single File upload button. This is actually a very subtle change that's very useful as it makes it much easier to send multiple files to the server without using complex uploader controls. Please understand though, that even though you can send multiple files using the <input type="file" /> tag, the process of how those files are sent hasn't really changed - there's still no progress information or other hooks that allow you to automatically make for a nicer upload experience without additional libraries or code. For that you will still need some sort of library (I'll post an example in my next blog post using plUpload). All the new features allow for is to make it easier to select multiple images from disk in one operation. Where you might have required many file upload controls before to upload several files, one File control can potentially do the job. How it works To create a file input box that allows with multiple file support you can simply do:<form method="post" enctype="multipart/form-data"> <label>Upload Images:</label> <input type="file" multiple="multiple" name="File1" id="File1" accept="image/*" /> <hr /> <input type="submit" id="btnUpload" value="Upload Images" /> </form> Now when the file open dialog pops up - depending on the browser and whether the browser supports it - you can pick multiple files. Here I'm using Firefox using the thumbnail preview I can easily pick images to upload on a form: Note that I can select multiple images in the dialog all of which get stored in the file textbox. The UI for this can be different in some browsers. For example Chrome displays 3 files selected as text next to the Browse… button when I choose three rather than showing any files in the textbox. Most other browsers display the standard file input box and display the multiple filenames as a comma delimited list in the textbox. Note that you can also specify the accept attribute in the <input> tag, which specifies a mime-type to specify what type of content to allow.Here I'm only allowing images (image/*) and the browser complies by just showing me image files to display. Likewise I could use text/* for all text formats registered on the machine or text/xml to only show XML files (which would include xml,xst,xsd etc.). Capturing Files on the Server with ASP.NET When you upload files to an ASP.NET server there are a couple of things to be aware of. When multiple files are uploaded from a single file control, they are assigned the same name. In other words if I select 3 files to upload on the File1 control shown above I get three file form variables named File1. This means I can't easily retrieve files by their name:HttpPostedFileBase file = Request.Files["File1"]; because there will be multiple files for a given name. The above only selects the first file. Instead you can only reliably retrieve files by their index. Below is an example I use in app to capture a number of images uploaded and store them into a database using a business object and EF 4.2.for (int i = 0; i < Request.Files.Count; i++) { HttpPostedFileBase file = Request.Files[i]; if (file.ContentLength == 0) continue; if (file.ContentLength > App.Configuration.MaxImageUploadSize) { ErrorDisplay.ShowError("File " + file.FileName + " is too large. Max upload size is: " + App.Configuration.MaxImageUploadSize); return View("UploadClassic",model); } var image = new ClassifiedsBusiness.Image(); var ms = new MemoryStream(16498); file.InputStream.CopyTo(ms); image.Entered = DateTime.Now; image.EntryId = model.Entry.Id; image.ContentType = "image/jpeg"; image.ImageData = ms.ToArray(); ms.Seek(0, SeekOrigin.Begin); // resize image if necessary and turn into jpeg Bitmap bmp = Imaging.ResizeImage(ms.ToArray(), App.Configuration.MaxImageWidth, App.Configuration.MaxImageHeight); ms.Close(); ms = new MemoryStream(); bmp.Save(ms,ImageFormat.Jpeg); image.ImageData = ms.ToArray(); bmp.Dispose(); ms.Close(); model.Entry.Images.Add(image); } This works great and also allows you to capture input from multiple input controls if you are dealing with browsers that don't support multiple file selections in the file upload control. The important thing here is that I iterate over the files by index, rather than using a foreach loop over the Request.Files collection. The files collection returns key name strings, rather than the actual files (who thought that was good idea at Microsoft?), and so that isn't going to work since you end up getting multiple keys with the same name. Instead a plain for loop has to be used to loop over all files. Another Option in ASP.NET MVC If you're using ASP.NET MVC you can use the code above as well, but you have yet another option to capture multiple uploaded files by using a parameter for your post action method.public ActionResult Save(HttpPostedFileBase[] file1) { foreach (var file in file1) { if (file.ContentLength < 0) continue; // do something with the file }} Note that in order for this to work you have to specify each posted file variable individually in the parameter list. This works great if you have a single file upload to deal with. You can also pass this in addition to your main model to separate out a ViewModel and a set of uploaded files:public ActionResult Edit(EntryViewModel model,HttpPostedFileBase[] uploadedFile) You can also make the uploaded files part of the ViewModel itself - just make sure you use the appropriate naming for the variable name in the HTML document (since there's Html.FileFor() extension). Browser Support You knew this was coming, right? The feature is really nice, but unfortunately not supported universally yet. Once again Internet Explorer is the problem: No shipping version of Internet Explorer supports multiple file uploads. IE10 supposedly will, but even IE9 does not. All other major browsers - Chrome, Firefox, Safari and Opera - support multi-file uploads in their latest versions. So how can you handle this? If you need to provide multiple file uploads you can simply add multiple file selection boxes and let people either select multiple files with a single upload file box or use multiples. Alternately you can do some browser detection and if IE is used simply show the extra file upload boxes. It's not ideal, but either one of these approaches makes life easier for folks that use a decent browser and leaves you with a functional interface for those that don't. Here's a UI I recently built as an alternate uploader with multiple file upload buttons: I say this is my 'alternate' uploader - for my primary uploader I continue to use an add-in solution. Specifically I use plUpload and I'll discuss how that's implemented in my next post. Although I think that plUpload (and many of the other packaged JavaScript upload solutions) are a better choice especially for large uploads, for simple one file uploads input boxes work well enough. The advantage of this solution is that it's very easy to handle on the server side. Any of the JavaScript controls require special handling for uploads which I'll also discuss in my next post.© Rick Strahl, West Wind Technologies, 2005-2012Posted in HTML5  ASP.NET  MVC   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

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  • send multiple file over TCP with C# using TcpClient

    - by xnoor
    I'm trying to send multiple files over TCP using C# TcpClient, for a single file it works great, but when I have multiple files, it sends only the first one. Here is my code: SENDING FILES try { TcpClient tcpClient = new TcpClient(); NetworkStream networkStream; FileStream fileStream = null; tcpClient.Connect(appUpdateMessage.receiverIpAddress, 12000); networkStream = tcpClient.GetStream(); byte[] byteSend = new byte[tcpClient.ReceiveBufferSize]; string startupPath = System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase).Substring(6); DirectoryInfo directoriesInfo = new DirectoryInfo(startupPath); DirectoryInfo[] directories = directoriesInfo.GetDirectories(); FileInfo[] files = directoriesInfo.GetFiles(); for (int iLoop = 0; iLoop < directories.Length; iLoop++) { FileInfo[] subdirectoryFiles = directories[iLoop].GetFiles(); foreach (FileInfo fi in subdirectoryFiles) { fileStream = new FileStream(fi.FullName, FileMode.Open, FileAccess.Read); BinaryReader binFile = new BinaryReader(fileStream); FileUpdateMessage fileUpdateMessage = new FileUpdateMessage(); fileUpdateMessage.fileName = fi.Name; fileUpdateMessage.fileSize = fi.Length; fileUpdateMessage.targetDirectory = fi.Directory.Name; MessageContainer messageContainer = new MessageContainer(); messageContainer.messageType = MessageType.FileProperties; messageContainer.messageContnet = SerializationManager.XmlFormatterObjectToByteArray(fileUpdateMessage); byte[] messageByte = SerializationManager.XmlFormatterObjectToByteArray(messageContainer); networkStream.Write(messageByte, 0, messageByte.Length); int bytesSize = 0; byte[] downBuffer = new byte[2048]; while ((bytesSize = fileStream.Read(downBuffer, 0, downBuffer.Length)) > 0) { networkStream.Write(downBuffer, 0, bytesSize); } fileStream.Close(); } } tcpClient.Close(); networkStream.Close(); return true; } catch (Exception ex) { //logger.Info(ex.Message); return false; } finally { } RECEIVING FILES try { TcpClient tcpClient = c as TcpClient; NetworkStream networkstream = tcpClient.GetStream(); FileStream fileStream = null; byte[] _data = new byte[1024]; int _bytesRead = 0; _bytesRead = networkstream.Read(_data, 0, _data.Length); MessageContainer messageContainer = new MessageContainer(); messageContainer = SerializationManager.XmlFormatterByteArrayToObject(_data, messageContainer) as MessageContainer; switch (messageContainer.messageType) { case MessageType.FileProperties: FileUpdateMessage fileUpdateMessage = new FileUpdateMessage(); fileUpdateMessage = SerializationManager.XmlFormatterByteArrayToObject(messageContainer.messageContnet, fileUpdateMessage) as FileUpdateMessage; string startupPath = @"d:updatefolder";//System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().GetName().CodeBase).Substring(6); DirectoryInfo mainDirectory = new DirectoryInfo(startupPath); DirectoryInfo targetDirecotry = new DirectoryInfo(startupPath + "\\" + fileUpdateMessage.targetDirectory); if (!targetDirecotry.Exists) { mainDirectory.CreateSubdirectory(fileUpdateMessage.targetDirectory); } fileStream = new FileStream(startupPath + "\\" + fileUpdateMessage.targetDirectory + "\\" + fileUpdateMessage.fileName, FileMode.Create, FileAccess.Write, FileShare.ReadWrite); long filezie = fileUpdateMessage.fileSize; int byteSize = 0; byte[] downBuffer = new byte[2048]; while ((byteSize = networkstream.Read(downBuffer, 0, downBuffer.Length)) > 0) { fileStream.Write(downBuffer, 0, byteSize); if (this.InvokeRequired) { this.Invoke((MethodInvoker)delegate { //progressBar1.Value = Convert.ToInt32((byteSize * 100) / fileUpdateMessage.fileSize); progressBar1.Value = Convert.ToInt32((fileStream.Length * 100) / fileUpdateMessage.fileSize); lblFileName.Text = fileUpdateMessage.fileName; }); } else { //progressBar1.Value = Convert.ToInt32((byteSize * 100) / fileUpdateMessage.fileSize); lblFileName.Text = fileUpdateMessage.fileName; } } fileStream.Close(); networkstream.Close(); break; } } catch (Exception ex) { //logger.Error(ex.Message); } Any idea what I am doing wrong?

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  • Uploadify Not Working

    - by azz0r
    Hello, I'll re-edit this to tackle the uploadify issue. Its very strange, essentially the script isn't uploading and isn't triggering onAllComplete. Also if I try to upload an image that's to large, and click Upload files, it skips from 0 to 100%. But does not trigger onAllComplete. It does not upload either. Whats strange, is I have an earlier revision of this and the codes no different and it works, ive tried switched back to the same jquery/uploadify/layout and it still doesnt work. However due to the nature of uploadify not being very forthcoming about errors or whats going on, I can't figure out where its going wrong! Controller: public function manageImagesAction() { $id = $this->_getParam('id'); $object = Eurocreme_Gallery::load_by_fields(array('id' => $id), 1); $images = Eurocreme_Image::load_by_type(array('type' => 'gallery_id', 'values' => $id, 'from' => 0, 'to' => COUNT_HIGH, 'order' => 'gi.position ASC')); $this->view->object = $object; $this->view->images = $images; $this->view->headScript()->appendFile('/library/jquery/uploadify/swfobject.js'); $this->view->headScript()->appendFile('/library/jquery/uploadify/jquery.uploadify.v2.1.0.js'); $this->view->headScript()->appendFile('/library/jquery/ui.js'); } View: <div class="content-area"> <h1>Adding Images To "<?php echo $this->object->name; ?>" Gallery</h1> <p><input id="fileInput2" name="fileInput2" type="file" /></p> <p><a href="javascript:$('#fileInput2').uploadifyUpload();">Upload Files</a> | <a href="javascript:$('#fileInput2').uploadifyClearQueue();">Clear Queue</a></p> </div> <?php if (!empty($this->images)) { ?> <div class="content-area"> <h1>Order Images For <?php echo $this->object->name; ?></h1> <p id="status_update">Drop And Drag Images to re-order them, I will automatically save it for you!</p> <ul id="sort_list"> <?php foreach ($this->images as $image) { ?> <li class="removable" id="recordsArray_<?php echo $image->id; ?>"><img src="/images/Image/thumb/<?php echo $image->image_url; ?>" alt="<?php echo $image->name_url; ?>" title="<?php echo $image->name; ?>" /><p><a class="removable" id="<?php echo $image->id; ?>">Delete</a></p></li> <?php } ?> </ul> <p class="clear"></p> </div> <?php } ?> <?php $this->headScript()->captureStart(); ?> $('document').ready(function() { $("#fileInput2").uploadify({ 'uploader' : '/library/jquery/uploadify/uploadify.swf', 'script' : '/<?php echo $this->object->name_url; ?>/upload.php', 'cancelImg' : '/library/jquery/uploadify/cancel.png', 'folder' : '/images/Image/', 'multi' : true, 'onAllComplete' : function(e, queueId, file, response, data) { window.location.reload(); }, }) //sortable $(function() { $("#sort_list").sortable({ opacity: 0.6, cursor: 'move', update: function() { $("#status_update").html('Processing'); var order = $(this).sortable("serialize"); $.post("/administration/gallery/save-image-order/id/<?php echo $this->object->id; ?>", order, function(theResponse){ $("#status_update").html(theResponse); }); } }); //delete $('a.removable').click(function(){ var id = this.id; $.post("/administration/gallery/delete-image/gallery_id/<?php echo $this->object->id; ?>/image_id/"+id+"", '', function(theResponse) { $("#recordsArray_"+id+"").remove(); }); }); }); }); <?php $this->headScript()->captureEnd(); ?>

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  • What file format can represent an uncompressed raster image at 48 or 64 bits per pixel?

    - by finnw
    I am creating screenshots under Windows and using the LockBits function from GDI+ to extract the pixel data, which will then be written to a file. To maximise performance I am also: Using the same PixelFormat as the source bitmap, to avoid format conversion Using the ImageLockModeUserInputBuf flag to extract the pixel data into a pre-allocated buffer This pre-allocated buffer (pointed to by BitmapData::Scan0) is part of a memory-mapped file (to avoid copying the pixel data again.) I will also be writing the code that reads the file, so I can use (or invent) any format I wish. However I would prefer to use a well-known format that existing programs (ideally web browsers) are able to read, because that means I can visually confirm that the images are correct before writing the code for the other program (that reads the image.) I have implemented this successfully for the PixelFormat32bppRGB format, which matches the format of a 32bpp BMP file, so if I extract the pixel data directly into the memory-mapped BMP file and prefix it with a BMP header I get a valid BMP image file that can be opened in Paint and most browsers. Unfortunately one of the machines I am testing on returns pixels in PixelFormat64bppPARGB format (presumably this is influenced by the video adapter driver) and there is no corresponding BMP pixel format for this. Converting to a 16, 24 or 32bpp BMP format slows the program down considerably (as well as being lossy) so I am looking for a file format that can use this pixel format without conversion, so I can extract directly into the memory-mapped file as I have done with the 32bpp format. What raster image file formats support 48bpp and/or 64bpp?

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  • Can you Download the cmid.ctt File

    - by ArtistDigital
    Can you Download the cmid.ctt File Zong.com.pk http://203.82.55.30/websms/default.aspx?txt_Msg=your-name&txt_MNumber=033489667417&txt_Nick=your-name Still Waiting for Reply.... kindly more Developer to broke the Server expection function alphanumeric(alphane) { var numaric = alphane; for(var j=0; j 47 && hh<59) || (hh 64 && hh<91) || (hh 96 && hh<123)) { } else { return false; } } return true; } function charscount(msg, frm) { frm.num_chars.value = 147 - msg.length; // m = msg; } function moveDivDown() { var el = document.getElementById("chatwindow") st = el.scrollTop; el.scrollTop = el.scrollTop + 300 } function trim(str) { return str.replace(/^\s*|\s*$/g,""); } var XMLHttp; var XMLHttp2; /SEND TO SERVER/ function GetXmlHttpObject() { var objXMLHttp=null /* if (window.XMLHttpRequest) { objXMLHttp=new XMLHttpRequest() } else if (window.ActiveXObject) { objXMLHttp=new ActiveXObject("Microsoft.XMLHTTP") }*/ var ua = navigator.userAgent.toLowerCase(); if (!window.ActiveXObject) objXMLHttp = new XMLHttpRequest(); else if (ua.indexOf('msie 5') == -1) objXMLHttp = new ActiveXObject("Msxml2.XMLHTTP"); else objXMLHttp = new ActiveXObject("Microsoft.XMLHTTP"); return objXMLHttp } function updateChatWindow() { var txt_Msg, txt_mNumber, txt_Nick, myMessage txt_MNumber = document.getElementById("txt_MNumber").value txt_Msg = document.getElementById("txt_Msg").value txt_Nick = document.getElementById("txt_Nick").value txt_Nick = trim (txt_Nick) if (txt_Nick.length==0) { alert ("Please enter the Nick Name") document.getElementById("txt_Nick").focus() document.getElementById("txt_Nick").value="" return false; } if (!alphanumeric(txt_Nick)) { alert ("Please enter a valid alphanumeric Nick Name") document.getElementById("txt_Nick").value="" document.getElementById("txt_Nick").focus() return false; } if (txt_Msg.length==0) return false; if (txt_MNumber.length != 10) { alert ("Please Enter a 10 digit recipient mobile number") return false } if (!IsNumeric (txt_MNumber)) { alert ("Please Enter a valid 10 digit recipient mobile number") return false } document.getElementById("txt_Msg").value = "" document.getElementById("num_chars").value = "147" document.getElementById("txt_Msg").focus() myMessage = '' +txt_Nick + ' Says: ' + txt_Msg + '' document.getElementById("chatwindow").innerHTML= document.getElementById("chatwindow").innerHTML + myMessage moveDivDown() XMLHttp = GetXmlHttpObject() if (XMLHttp==null) { alert ("Browser does not support HTTP Request") return false; } var url="default.aspx?" url=url+"txt_Msg="+txt_Msg url=url+"&txt_MNumber="+txt_MNumber url=url+"&txt_Nick="+txt_Nick url=url+"&sid="+Math.random() XMLHttp.onreadystatechange=stateChanged XMLHttp.open("GET",url,true) XMLHttp.send(null) return false; } function stateChanged() { if (XMLHttp.readyState==4 || XMLHttp.readyState=="complete") { try { document.getElementById("chatwindow").innerHTML= document.getElementById("chatwindow").innerHTML+ XMLHttp.responseText moveDivDown() } catch (e){} } } /RECEIVE FROM SERVER/ function checkResponse() { XMLHttp2 = GetXmlHttpObject() if (XMLHttp2==null) { alert ("Browser does not support HTTP Request") return } var url="" url=url+"?r=C" url=url+"&sid="+Math.random() XMLHttp2.onreadystatechange=stateChanged2 XMLHttp2.open("GET",url,true) XMLHttp2.send(null) } function stateChanged2() { if (XMLHttp2.readyState==4 || XMLHttp2.readyState=="complete") { try { document.getElementById("chatwindow").innerHTML= document.getElementById("chatwindow").innerHTML + XMLHttp2.responseText moveDivDown() } catch (e){} //Again Check Updates after 3 Seconds setTimeout("checkResponse()", 2000); } } function IsNumeric(sText) { var ValidChars = "0123456789"; var IsNumber=true; var Char; for (i = 0; i < sText.length && IsNumber == true; i++) { Char = sText.charAt(i); if (ValidChars.indexOf(Char) == -1) { IsNumber = false; } } return IsNumber; }

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  • Create Folders from text file and place dummy file in them using a CustomAction

    - by Birkoff
    I want my msi installer to generate a set of folders in a particular location and put a dummy file in each directory. Currently I have the following CustomActions: <CustomAction Id="SMC_SetPathToCmd" Property="Cmd" Value="[SystemFolder]cmd.exe"/> <CustomAction Id="SMC_GenerateMovieFolders" Property="Cmd" ExeCommand="for /f &quot;tokens=* delims= &quot; %a in ([MBSAMPLECOLLECTIONS]movies.txt) do (echo %a)" /> <CustomAction Id="SMC_CopyDummyMedia" Property="Cmd" ExeCommand="for /f &quot;tokens=* delims= &quot; %a in ([MBSAMPLECOLLECTIONS]movies.txt) do (copy [MBSAMPLECOLLECTIONS]dummy.avi &quot;%a&quot;\&quot;%a&quot;.avi)" /> These are called in the InstallExecuteSequence: <Custom Action="SMC_SetPathToCmd" After="InstallFinalize"/> <Custom Action="SMC_GenerateMovieFolders" After="SMC_SetPathToCmd"/> <Custom Action="SMC_CopyDummyMedia" After="SMC_GenerateMovieFolders"/> The custom actions seem to start, but only a blank command prompt window is shown and the directories are not generated. The files needed for the customaction are copied to the correct directory: <Directory Id="WIX_DIR_COMMON_VIDEO"> <Directory Id="MBSAMPLECOLLECTIONS" Name="MB Sample Collections" /> </Directory> <DirectoryRef Id="MBSAMPLECOLLECTIONS"> <Component Id="SampleCollections" Guid="C481566D-4CA8-4b10-B08D-EF29ACDC10B5" DiskId="1"> <File Id="movies.txt" Name="movies.txt" Source="SampleCollections\movies.txt" Checksum="no" /> <File Id="series.txt" Name="series.txt" Source="SampleCollections\series.txt" Checksum="no" /> <File Id="dummy.avi" Name="dummy.avi" Source="SampleCollections\dummy.avi" Checksum="no" /> </Component> </DirectoryRef> What's wrong with these Custom Actions or is there a simpler way to do this?

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  • Control pdb file output from build defintion file

    - by Urvi
    Hello, I am trying to generate a release build with no pdb files generated. I have seen numerous posts that suggest right-clicking on the project, selecting Properties, going to the Build tab and then to the Advanced... butoon and changing Debug Info to none. This works and all, but I need to do this for a build of ~50 solutions which contain ~25 projects each! Other posts mention editing the appropriate .csproj file, but again, with so many projects, this would take a long time. Is there any way to achieve this via the TFSBuild.proj file? I have tried adding the following to the TFSBuild.proj file, with no luck. <PropertyGroup> <Configuration>Release</Configuration> <Platform>AnyCPU</Platform> </PropertyGroup> <PropertyGroup> <DebugSymbols>false</DebugSymbols> <DebugType>none</DebugType> <Optimize>true</Optimize> </PropertyGroup> The following line prints out Release|AnyCPU, none, and false, but I still see .pdb file in the $(OutputDir) folder. <Message Text="$Configuration|Platform): $(Configuration)|$(Platform)" /> <Message Text="DebugType is: $(DebugType)"/> <Message Text="DebugSymbols is: $(DebugSymbols)"/> Thanks in advance, Urvi

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  • Define a swig interface file for generation of wrapper to every type from some header file

    - by Dmitriy Matveev
    Hi! We're using some C library in our Java project. Several years ago some other developer which has retired few years ago (as always) has created all the wrappers for us. The wrappers were generated by the swig, but the interface file is lost now. The basic idea of library and the wrappers for it is following: There only one function which returns pointer to some complex object. And there are wrapper for that function. The complex object is a tree-like structure with dozens of node kinds and types (C structures) used to represent them. There are hundreds of wrappers for every field of every type and we're trying to use them all. The library was updated some time ago and now there are some new data we unaware of which yet, but would like to use. This data is contained in some of the objects indirectly contained or referenced from the object created by the function we call (Some new fields and types were added). I know that I shouldn't make any changes to the wrappers by hand and should rather modify the interface, but as I already wrote it's missing. For now I only want to generate wrappers some few types which are added/changed and them to our old wrappers, but later I want to start creation of interface file which will define "what and how should be wrapped". All the definitions necessary for us are defined in single header file. Is it possible to tell swig to generate wrappers for every type in this header? If so, how can I write such interface file?

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  • libcurl - unable to download a file

    - by marmistrz
    I'm working on a program which will download lyrics from sites like AZLyrics. I'm using libcurl. It's my code lyricsDownloader.cpp #include "lyricsDownloader.h" #include <curl/curl.h> #include <cstring> #include <iostream> #define DEBUG 1 ///////////////////////////////////////////////////////////////////////////// size_t lyricsDownloader::write_data_to_var(char *ptr, size_t size, size_t nmemb, void *userdata) // this function is a static member function { ostringstream * stream = (ostringstream*) userdata; size_t count = size * nmemb; stream->write(ptr, count); return count; } string AZLyricsDownloader::toProviderCode() const { /*this creates an url*/ } CURLcode AZLyricsDownloader::download() { CURL * handle; CURLcode err; ostringstream buff; handle = curl_easy_init(); if (! handle) return static_cast<CURLcode>(-1); // set verbose if debug on curl_easy_setopt( handle, CURLOPT_VERBOSE, DEBUG ); curl_easy_setopt( handle, CURLOPT_URL, toProviderCode().c_str() ); // set the download url to the generated one curl_easy_setopt(handle, CURLOPT_WRITEDATA, &buff); curl_easy_setopt(handle, CURLOPT_WRITEFUNCTION, &AZLyricsDownloader::write_data_to_var); err = curl_easy_perform(handle); // The segfault should be somewhere here - after calling the function but before it ends cerr << "cleanup\n"; curl_easy_cleanup(handle); // copy the contents to text variable lyrics = buff.str(); return err; } main.cpp #include <QString> #include <QTextEdit> #include <iostream> #include "lyricsDownloader.h" int main(int argc, char *argv[]) { AZLyricsDownloader dl(argv[1], argv[2]); dl.perform(); QTextEdit qtexted(QString::fromStdString(dl.lyrics)); cout << qPrintable(qtexted.toPlainText()); return 0; } When running ./maelyrica Anthrax Madhouse I'm getting this logged from curl * About to connect() to azlyrics.com port 80 (#0) * Trying 174.142.163.250... * connected * Connected to azlyrics.com (174.142.163.250) port 80 (#0) > GET /lyrics/anthrax/madhouse.html HTTP/1.1 Host: azlyrics.com Accept: */* < HTTP/1.1 301 Moved Permanently < Server: nginx/1.0.12 < Date: Thu, 05 Jul 2012 16:59:21 GMT < Content-Type: text/html < Content-Length: 185 < Connection: keep-alive < Location: http://www.azlyrics.com/lyrics/anthrax/madhouse.html < Segmentation fault Strangely, the file is there. The same error is displayed when there's no such page (redirect to azlyrics.com mainpage) What am I doing wrong? Thanks in advance EDIT: I made the function for writing data static, but this changes nothing. Even wget seems to have problems $ wget http://www.azlyrics.com/lyrics/anthrax/madhouse.html --2012-07-06 10:36:05-- http://www.azlyrics.com/lyrics/anthrax/madhouse.html Resolving www.azlyrics.com... 174.142.163.250 Connecting to www.azlyrics.com|174.142.163.250|:80... connected. HTTP request sent, awaiting response... No data received. Retrying. Why does opening the page in a browser work and wget/curl not? EDIT2: After adding this: curl_easy_setopt(handle, CURLOPT_FOLLOWLOCATION, 1); The log is: * About to connect() to azlyrics.com port 80 (#0) * Trying 174.142.163.250... * connected * Connected to azlyrics.com (174.142.163.250) port 80 (#0) > GET /lyrics/anthrax/madhouse.html HTTP/1.1 Host: azlyrics.com Accept: */* < HTTP/1.1 301 Moved Permanently < Server: nginx/1.0.12 < Date: Fri, 06 Jul 2012 09:09:47 GMT < Content-Type: text/html < Content-Length: 185 < Connection: keep-alive < Location: http://www.azlyrics.com/lyrics/anthrax/madhouse.html < * Ignoring the response-body * Connection #0 to host azlyrics.com left intact * Issue another request to this URL: 'http://www.azlyrics.com/lyrics/anthrax/madhouse.html' * About to connect() to www.azlyrics.com port 80 (#1) * Trying 174.142.163.250... * connected * Connected to www.azlyrics.com (174.142.163.250) port 80 (#1) > GET /lyrics/anthrax/madhouse.html HTTP/1.1 Host: www.azlyrics.com Accept: */* < HTTP/1.1 200 OK < Server: nginx/1.0.12 < Date: Fri, 06 Jul 2012 09:09:47 GMT < Content-Type: text/html < Transfer-Encoding: chunked < Connection: keep-alive < Segmentation fault

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  • using ini file in vb6, problem with path to file

    - by DrPut
    I have read many articles about how to use an INI file within my VB6 project. I don't have a problem with the methods, my problem is how to make the EXE file find the INI file. I don't want to hard code the path in the program. I simply want the EXE to expect the INI file to be present in the same folder the EXE is executed from. When I run the program from inside VB6 IDE, the INI is found and processed. When I compile the program and run the EXE, nothing is found. My code looks like: gServer = sGetINI(sINIFile, "TOOLBOM", "ServerName", "?") where TOOLBOM is the [Section] and "ServerName" is the key for the value. I obtained the following code for the API: Rem API DECLARATIONS Declare Function GetPrivateProfileString Lib "kernel32" Alias _ "GetPrivateProfileStringA" (ByVal lpApplicationName _ As String, ByVal lpKeyName As Any, ByVal lpDefault _ As String, ByVal lpReturnedString As String, ByVal _ nSize As Long, ByVal lpFileName As String) As Long Declare Function WritePrivateProfileString Lib "kernel32" Alias _ "WritePrivateProfileStringA" (ByVal lpApplicationName _ As String, ByVal lpKeyName As Any, ByVal lpString As Any, _ ByVal lpFileName As String) As Long Public Function sGetINI(sINIFile As String, sSection As String, sKey _ As String, sDefault As String) As String Dim sTemp As String * 256 Dim nLength As Integer sTemp = Space$(256) nLength = GetPrivateProfileString(sSection, sKey, sDefault, sTemp, _ 255, sINIFile) sGetINI = Left$(sTemp, nLength) End Function Public Sub writeINI(sINIFile As String, sSection As String, sKey _ As String, sValue As String) Dim n As Integer Dim sTemp As String sTemp = sValue Rem Replace any CR/LF characters with spaces For n = 1 To Len(sValue) If Mid$(sValue, n, 1) = vbCr Or Mid$(sValue, n, 1) = vbLf _ Then Mid$(sValue, n) = " " Next n n = WritePrivateProfileString(sSection, sKey, sTemp, sINIFile) End Sub

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  • Handling file upload in a non-blocking manner

    - by Kaliyug Antagonist
    The background thread is here Just to make objective clear - the user will upload a large file and must be redirected immediately to another page for proceeding different operations. But the file being large, will take time to be read from the controller's InputStream. So I unwillingly decided to fork a new Thread to handle this I/O. The code is as follows : The controller servlet /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub System.out.println("In Controller.doPost(...)"); TempModel tempModel = new TempModel(); tempModel.uploadSegYFile(request, response); System.out.println("Forwarding to Accepted.jsp"); /*try { Thread.sleep(1000 * 60); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ request.getRequestDispatcher("/jsp/Accepted.jsp").forward(request, response); } The model class package com.model; import java.io.IOException; import java.util.concurrent.ExecutionException; import java.util.concurrent.Future; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.utils.ProcessUtils; public class TempModel { public void uploadSegYFile(HttpServletRequest request, HttpServletResponse response) { // TODO Auto-generated method stub System.out.println("In TempModel.uploadSegYFile(...)"); /* * Trigger the upload/processing code in a thread, return immediately * and notify when the thread completes */ try { FileUploaderRunnable fileUploadRunnable = new FileUploaderRunnable( request.getInputStream()); /* * Future<FileUploaderRunnable> future = ProcessUtils.submitTask( * fileUploadRunnable, fileUploadRunnable); * * FileUploaderRunnable processed = future.get(); * * System.out.println("Is file uploaded : " + * processed.isFileUploaded()); */ Thread uploadThread = new Thread(fileUploadRunnable); uploadThread.start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* * catch (InterruptedException e) { // TODO Auto-generated catch block * e.printStackTrace(); } catch (ExecutionException e) { // TODO * Auto-generated catch block e.printStackTrace(); } */ System.out.println("Returning from TempModel.uploadSegYFile(...)"); } } The Runnable package com.model; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.nio.ByteBuffer; import java.nio.channels.Channels; import java.nio.channels.ReadableByteChannel; public class FileUploaderRunnable implements Runnable { private boolean isFileUploaded = false; private InputStream inputStream = null; public FileUploaderRunnable(InputStream inputStream) { // TODO Auto-generated constructor stub this.inputStream = inputStream; } public void run() { // TODO Auto-generated method stub /* Read from InputStream. If success, set isFileUploaded = true */ System.out.println("Starting upload in a thread"); File outputFile = new File("D:/06c01_output.seg");/* * This will be changed * later */ FileOutputStream fos; ReadableByteChannel readable = Channels.newChannel(inputStream); ByteBuffer buffer = ByteBuffer.allocate(1000000); try { fos = new FileOutputStream(outputFile); while (readable.read(buffer) != -1) { fos.write(buffer.array()); buffer.clear(); } fos.flush(); fos.close(); readable.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("File upload thread completed"); } public boolean isFileUploaded() { return isFileUploaded; } } My queries/doubts : Spawning threads manually from the Servlet makes sense to me logically but scares me coding wise - the container isn't aware of these threads after all(I think so!) The current code is giving an Exception which is quite obvious - the stream is inaccessible as the doPost(...) method returns before the run() method completes : In Controller.doPost(...) In TempModel.uploadSegYFile(...) Returning from TempModel.uploadSegYFile(...) Forwarding to Accepted.jsp Starting upload in a thread Exception in thread "Thread-4" java.lang.NullPointerException at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:512) at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:497) at org.apache.coyote.http11.InternalInputBuffer$InputStreamInputBuffer.doRead(InternalInputBuffer.java:559) at org.apache.coyote.http11.AbstractInputBuffer.doRead(AbstractInputBuffer.java:324) at org.apache.coyote.Request.doRead(Request.java:422) at org.apache.catalina.connector.InputBuffer.realReadBytes(InputBuffer.java:287) at org.apache.tomcat.util.buf.ByteChunk.substract(ByteChunk.java:407) at org.apache.catalina.connector.InputBuffer.read(InputBuffer.java:310) at org.apache.catalina.connector.CoyoteInputStream.read(CoyoteInputStream.java:202) at java.nio.channels.Channels$ReadableByteChannelImpl.read(Unknown Source) at com.model.FileUploaderRunnable.run(FileUploaderRunnable.java:39) at java.lang.Thread.run(Unknown Source) Keeping in mind the point 1., does the use of Executor framework help me in anyway ? package com.utils; import java.util.concurrent.Future; import java.util.concurrent.ScheduledThreadPoolExecutor; public final class ProcessUtils { /* Ensure that no more than 2 uploads,processing req. are allowed */ private static final ScheduledThreadPoolExecutor threadPoolExec = new ScheduledThreadPoolExecutor( 2); public static <T> Future<T> submitTask(Runnable task, T result) { return threadPoolExec.submit(task, result); } } So how should I ensure that the user doesn't block and the stream remains accessible so that the (uploaded)file can be read from it?

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  • Windows 2003 R2 zip program blocking EXE file

    - by Harvey Kwok
    I have a Windows 2003 R2 Enterprise Edition SP2 32-bit machine with all latest patch (as of 1-6-2011). It's a VM. I have a zip file, including a pdf file, a txt file and a exe file. If I copy the zip file onto the machine via a shared network drive, I can unzip all the files properly without problems. If I put the zip file on my web server and then I download it from there, I can only unzip the pdf file and txt file. The exe file is silently ignored. I searched the web and found somebody reporting similar issue on XP. If I right click on the zip file downloaded from the web server, at the bottom of the general page, it has a warning message saying that "This file came from antoher computer and might be blocked to help protect this computer" I understand that I can solve the problem by simply clicking the "Unblock" button and extract the file again. The things that bothering me is that why the warning message says "might be blocked"? I tried downloading the same zip file from the same web server on to my Windows 7 box with latest patch. It also shows the same warning message. However, even with the warning message, I can extract all the files properly without clicking the "Unblock" button. Is it a bug in Windows 2003 R2 SP1? Is there any security settings controlling this? How likely will the end user seeing this problem? I want to dig into this because I am worrying people downloading my zip file from my web server might see similar problems. The first thought coming to the user's mind will be the zip file is somehow corrupted. Honestly, I didn't know this "Unblock" feature in Windows before I run into this problem. EDIT I just tried it on another Windows 2003 R2 SP1 machine. The zip program doesn't block the EXE file on that machine either. Both Windows 2003 R2 SP1 machines are joining to the same forest.

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