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  • Does ADFS2.0 provide custom authentication stores?

    - by chugh97
    I wanted to find out if ADFS2.0 provides a way for users to be authenticated with a Custom Store? Version 1.0 you could only authenticate users in the Windows domain, using Forms/Windows Integrated/Cardspace. I have an ASP.NEt website, which I would like the users to be authenticated against a custom store in SQL and then ADFS2.0 to take care of the claims issued to the user...

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  • how to added a GUI to my class

    - by Gerard Flynn
    hi i have a class that runs, it does the following backups a sql, zip, encrypts, ftp to an ftp server. what i want to do is add a GUI. Need to add a 2 buttons start and finish and progress bar for the procedure. my class is called backup.cs. i have tried creating a form but doesn't seam to work. any help would be great full Ta Gerard

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  • Mysql: Perform of NOT EXISTS. Is it possible to improve permofance?

    - by petRUShka
    I have two tables posts and comments. Table comments have post_id attribute. I need to get all posts with type "open", for which there are no comments with type "good" and created date MAY 1. Is it optimal to use such SQL-query: SELECT posts.* FROM posts WHERE NOT EXISTS ( SELECT comments.id FROM comments WHERE comments.post_id = posts.id AND comments.comment_type = 'good' AND comments.created_at BETWEEN '2010-05-01 00:00:00' AND '2010-05-01 23:59:59') I'm not sure that NOT EXISTS is perfect construction in this situation.

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  • mysql UNION query not working

    - by kalpaitch
    What am I doing wrong with this: $sql = "SELECT * FROM content WHERE threadName LIKE '%$filter%' ORDER BY lastUpdated desc UNION SELECT * FROM content WHERE threadName NOT LIKE '%$filter%' ORDER BY lastUpdated desc"; The first statement before the UNION works well on its own, but this one above returns: mysql_fetch_array() warning - supplied argument is not a valid MySQL result resource Am I right in believing that UNION will not return duplicate entries, in which case the second SELECT statement doesn't need to have the NOT LIKE but will just return everything that wasn't listed in the first statement.

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  • PostgreSQL compare databases tool or generating migration script util

    - by opedge
    In our development we use two servers with PostgreSQL 8.4 - development and production. So, after changes were made on development server we would like to automatically generate SQL migration scripts. I found that EMS DB Comparer for PostgreSQL can do it, but it is only for Windows (our development team use Ubuntu for developing). Do you now alternative tools to do this?

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  • PostgreSQL data comparsion tool

    - by user179056
    Hello, I am looking for a tool/command which can compare data between two PostgreSQL databases. The reason to do this is to have some external verification that the SQL script responsible for data migration from one PostgreSQL database to the other have been written correctly. Any pointers would be appreciated regards Sameer

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  • C# Outer Apply in LINQ

    - by JeremySpouken
    How can I achieve Outer Apply in LINQ? I'm having a bit of a problem. Here's the SQL Query I'm using. SELECT u.masterID ,u.user ,h.created FROM dbo.Users u OUTER APPLY (SELECT TOP 1 * FROM UserHistory h where h.masterID = u.masterID ORDER BY created DESC) h

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  • IDs necessary in update script not being stored (or even seen!?) (PHP MySQL)

    - by Derek
    Hi guys, I really need help with this one...have spent 3 hours trying to figure it out... Basically, I have 3 tables necessary for this function to work (the query and PHP)... Authors, Books and Users. An author can have many books, and a user can have many books - that's it. When the admin user selects to update a book, they are presented with a form, displaying the current data within the fields, very straight forward... However there is one tricky part, the admin user can change the author for a book (incase they make a mistake) and also change the user for which the book is associated with. When I select to update the single book information I am not getting any values what so ever for author_id or user_id. Meaning that when the user updates the book info, the associations with the user and author is being scrapped altogether (when before there was an association)... I cannot see why this is happening because I can clearly see the IDs for the users and authors for my option values (this is because they are in select dropdowns). Here is what my sql to retrieve the user ID is: SELECT user_id, name FROM users and then i have my select options which brings up all the users in the system: <label>This book belongs to:</label> <select name="name" id="name"> <option value="<?php echo $row['user_id']?>" SELECTED><?php echo $row['name']?> - Current</option> <?php while($row = mysql_fetch_array($result)) { ?> <option value="<?php echo $row['user_id']; if (isset($_POST['user_id']));?>"><?php echo $row['name']?></option> <?php } ?> In the presented HTML form, I can select the users (by name) and within the source code I can see the IDs (for the value) matching against the names of the users. Finally, in my script that performs the update, I have this: $book_id = $_POST['book_id']; $bookname = $_POST['bookname']; $booklevel = $_POST['booklevel']; $author_id = $_POST['author_id']; $user_id = $_POST['user_id']; $sql = "UPDATE books SET bookname= '".$bookname."', booklevel= '".$booklevel."', author_id='".$author_id."', user_id= '".$user_id."' WHERE book_id = ".$book_id; The result of this query returns no value for either author_id or user_id... Obviously in this question I have given the information for the user stuff (with the HTML being displayed) but im guessing that I have the same problem with authors aswell... How can I get these ID's passed to the script so that the change can be acknowledge!! :(

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  • List MySQL enum in Java

    - by Pieter
    Is there a way to get all possible values from a MySQL enum column? The MySQL documentation says the MySQL enum type is returned as a Java String, so I basically would like a way to get all possible strings I can pass when querying a table with such an enum. I couldn't immediately find anything when I was looking through the metadata returned for such a column, but since enum isn't standard SQL, I'm not sure it's even possible... any suggestions?

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  • Mysql through PHP gives a "Can't create/write to file" error

    - by Peter
    The full error is: Message: Mysqli statement execute error : Can't create/write to file '/var/www/zendApp/backup/mysql/1268733580_name.sql' (Errcode: 13) I have tried several things already with the /var/www/ZendApp/backup/mysql directory $chmod 777 mysql $chmod 1777 mysql $chown root:root mysql $chown mysql:mysql mysql But nothing helps. What am I doing wrong here? Do I have to tell mysql somewhere that I can write to that directory?

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  • Using Entity Framework (code first) migrations in production

    - by devdigital
    I'm just looking into using EF migrations for our project, and in particular for performing schema changes in production between releases. I can see that generating SQL (delta) script files is an option, but is there no way of running the migrations programmatically on app start up? Will I instead need to add each delta script to the solution and write my own framework to apply them in order (from the current version to the latest) on bootstrap?

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  • Receiving a JSON string & saving one of the array paramaters to the database as a full string

    - by ElTren
    Hi I have a JSON string that looks like this (Usingt Rails and a REST service) { person: { name:"Pepe", last:"Smith" hats:[ { team:"lakers", color:"purple"}, { team:"heats", color:"red" }] } } I want to be able to able to get that JSON, and save the Person to the database, but I want to save the "hats".. as a string to the database; without parsing it or anything like that i.e. I want to save this to SQL: hats = "[ { team:"lakers", color:"purple"}, { team:"heats", color:"red" }] }" Is there a way to do this in rails?

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  • Complicted ActiveRecord Association. Going through a 4th table

    - by Dex
    I have kind of a complicated case and am wondering how this would work in rails: I want to categories the genres of some singers. Singers can belong to more than one genres, and users can assign tags to each genre For example: singers <-- singers_genres -- genres <-- genres_tags -- tags SQL would look something like: SELECT * FROM singers S INNER JOIN singers_genres SG ON S.id=SG.singer_id INNER JOIN genres G ON G.id = SG.genre_id LEFT OUTER JOIN genre_tags GT ON G.id = GT.genre_id INNER JOIN tags T ON GT.tag_id = T.id

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  • How to make multiple queries with PHP prepared statements (Commands out of sync error)

    - by Tirithen
    I'm trying to run three MySQL queries from a PHP script, the first one works fine, but on the second one I get the "Commands out of sync; you can’t run this command now" error. I have managed to understand that I need to "empty" the resultset before preparing a new query but I can't seem to understand how. I thought that $statement-close; would do that for me. Here is the relevant part of the code: <?php $statement = $db_conn->prepare("CALL getSketches(?,?)"); // Prepare SQL routine to check if user is accepted $statement->bind_param("is", $user_id, $loaded_sketches); // Bind variables to send $statement->execute(); // Execute the query $statement->bind_result( // Set return varables $id, $name, $description, $visibility, $createdby_id, $createdby_name, $createdon, $permission ); $new_sketches_id = array(); while($statement->fetch()) { $result['newSketches'][$id] = array( "name" => $name, "description" => $description, "visibility" => $visibility, "createdById" => $createdby_id, "createdByName" => $createdby_name, "createdOn" => $createdon, "permission" => $permission ); $new_sketches_id[] = $id; } $statement->close; // Close satement $new_sketches_ids = implode(",", $new_sketches_id); // Get the new sketches elements $statement = $db_conn->prepare("CALL getElements(?,'',?,'00000000000000')"); // Prepare SQL routine to check if user is accepted // The script crashes here with $db_conn->error // "Commands out of sync; you can't run this command now" $statement->bind_param("si", $new_sketches_ids, $user_id); // Bind variables to send $statement->execute(); // Execute the query $statement->bind_result( // Set return varables $id, $user_id, $type, $attribute_d, $attribute_stroke, $attribute_strokeWidth, $sketch_id, $createdon ); while($statement->fetch()) { $result['newSketches'][$sketch_id]['newElements']["u".$user_id."e".$id] = array( "type" => $type, "d" => $attribute_d, "stroke" => $attribute_stroke, "strokeWidth" => $attribute_strokeWidth, ); } $statement->close; // Close satement ?> How can I make the second query without closing and reopening the entire database connection?

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  • LockMode With Subclasses

    - by Lester
    I'm using Fluent Nhibernate with the following query on DerivedClass which extends BaseClass: var query = Session.CreateCriteria<DerivedClass>().SetLockMode(LockMode.Upgrade) What I want is the lock hints (updlock, rowlock) to be applied to both DerivedClass and BaseClass, but the generated SQL only applies the lock hints to DerivedClass: SELECT * FROM DerivedClass this_ with (updlock, rowlock) inner join [BaseClass] this_1_ on this_.Id=this_1_.Id WHERE ... This is the same situation described in http://opensource.atlassian.com/projects/hibernate/browse/HHH-2392 If anyone could point me in the right direction it would be much appreciated.

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  • How to store date into Mysql database with play framework in scala?

    - by Rahul Kulhari
    I am working with play framework with scala and what am i doing : login page to login into web app sign up page to register into web app after login i want to store all databases values to user what i want to do: when user register for web app then i want to store user values into database with current time and date but my form is giving error. error: List(FormError(dates,error.required,List())),None) controllers/Application.scala object Application extends Controller { val ta:Form[Keyword] = Form( mapping( "id" -> ignored(NotAssigned:Pk[Long]), "word" -> nonEmptyText, "blog" -> nonEmptyText, "cat" -> nonEmptyText, "score"-> of[Long], "summaryId"-> nonEmptyText, "dates" -> date("yyyy-MM-dd HH:mm:ss") )(Keyword.apply)(Keyword.unapply) ) def index = Action { Ok(html.index(ta)); } def newTask= Action { implicit request => ta.bindFromRequest.fold( errors => {println(errors) BadRequest(html.index(errors))}, keywo => { Keyword.create(keywo) Ok(views.html.data(Keyword.all())) } ) } models/keyword.scala case class Keyword(id: Pk[Long],word: String,blog: String,cat: String,score: Long, summaryId: String,dates: Date ) object Keyword { val keyw = { get[Pk[Long]]("keyword.id") ~ get[String]("keyword.word")~ get[String]("keyword.blog")~ get[String]("keyword.cat")~ get[Long]("keyword.score") ~ get[String]("keyword.summaryId")~ get[Date]("keyword.dates") map { case id~blog~cat~word~score~summaryId~dates => Keyword(id,word,blog,cat,score, summaryId,dates) } } def all(): List[Keyword] = DB.withConnection { implicit c => SQL("select * from keyword").as(Keyword.keyw *) } def create(key: Keyword){DB.withConnection{implicit c=> SQL("insert into keyword values({word},{blog}, {cat}, {score},{summaryId},{dates})").on('word-> key.word,'blog->key.blog, 'cat -> key.cat, 'score-> key.score, 'summaryId -> key.summaryId, 'dates->new Date()).executeUpdate } } views/index.scala.html @(taskForm: Form[Keyword]) @import helper._ @main("Todo list") { @form(routes.Application.newTask) { @inputText(taskForm("word")) @inputText(taskForm("blog")) @inputText(taskForm("cat")) @inputText(taskForm("score")) @inputText(taskForm("summaryId")) <input type="submit"> <a href="">Go Back</a> } } please give me some idea to store date into mysql databse and date is not a field of form

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  • Rails migration for change column

    - by b_ayan
    We have script/generate migration add_fieldname_to_tablename fieldname:datatype syntax for adding new columns to a model. On the same line, do we have a script/generate for changing the datatype of a column? Or should I write sql directly into my vanilla migration? I want to change a column from datetime to date. Thanks

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