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  • Zend_Db_Select: regrouping conditions in where clause

    - by pvledoux
    Hi, I would like to do something like this: $select = $myTbl->select() ->from('download_log') ->joinLeft(...... etc........ ->joinLeft(...... etc........ ->joinLeft(...... etc........); //Filter all configured bots (Google, Yahoo, etc.) if(isset($this->_config->statistics->bots)){ $bots = explode(',',$this->_config->statistics->bots); foreach ($bots as $bot){ $select = $select->orWhere("user_agent NOT LIKE '%$bot%'"); } } $select = $select->where("download_log.download_log_ts BETWEEN '".$start_date." 00:00:00' AND '".$end_date." 23:59:59'"); But the outputed query is not correct because of the orWhere clauses are not grouped together in a unique AND clause. I would like to know if it is possible to regrouped those OR clauses in a pair of parentheres. My current alternative is the following: //Filter all configured bots (Google, Yahoo, etc.) if(isset($this->_config->statistics->bots)){ $bots = explode(',',$this->_config->statistics->bots); foreach ($bots as $bot){ $stmt .= "user_agent NOT LIKE '%$bot%' OR "; } $stmt = substr($stmt,0,strlen($stmt)-3); //remove the last OR $select = $select->where("($stmt)"); } Thanks!

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  • When using Query Syntax in C# "Enumeration yielded no results". How to retrieve output

    - by Shantanu Gupta
    I have created this query to fetch some result from database. Here is my table structure. What exaclty is happening. DtMapGuestDepartment as Table 1 DtDepartment as Table 2 Are being used var dept_list= from map in DtMapGuestDepartment.AsEnumerable() where map.Field<Nullable<long>>("GUEST_ID") == DRowGuestPI.Field<Nullable<long>>("PK_GUEST_ID") join dept in DtDepartment.AsEnumerable() on map.Field<Nullable<long>>("DEPARTMENT_ID") equals dept.Field<Nullable<long>>("DEPARTMENT_ID") select dept.Field<string>("DEPARTMENT_ID"); I am performing this query on DataTables and expect it to return me a datatable. Here I want to select distinct department from Table 1 as well which will be my next quest. Please answer to that also if possible.

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  • create jquery array to use as options

    - by SoulieBaby
    Hi all, I'm sure this is really simple, but I can't seem to get it working. I have a "time" select list, which has a number as "rel" attached to each option. If the user changes the time select, I want a new list of options to display depending on what is selected. If that makes sense? Here's my first select: <select name="time" id="time"> <option value="7:00am" rel="10">7:00am</option> <option value="12:30pm" rel="16">12:30pm</option> </select> If the user selects 7:00am, I want a new option list (using jquery) to give options from 1 - 10. Like this: <select name="quantity" id="quantity"> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> ............................ <option value="10">10</option> </select> Here's what I have so far... <script type="text/javascript" language="javascript"> jQuery("#time").change(function(){ var positions = jQuery("#time :selected").attr("rel"); //this grabs the rel from time //this is where it should create a list of options to append(??) to the select list.. jQuery("#showQuantity").show(); //this shows the hidden field for quantity }); </script> I hope it makes sense, but I'm stuck on it. Thank you in advance :)

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  • Ruby on Rails: Simple way to select all records of a nested model?

    - by Josh Pinter
    Just curious, I spent an embarrassing amount of time trying to get an array of all the records in a nested model. I just want to make sure there is not a better way. Here is the setup: I have three models that are nested under each other (Facilities Tags Inspections), producing code like this for routes.rb: map.resources :facilities do |facilities| facilities.resources :tags, :has_many => :inspections end I wanted to get all of the inspections for a facility and here is what my code ended up being: def facility_inspections @facility = Facility.find(params[:facility_id]) @inspections = [] @facility.tags.each do |tag| tag.inspections.each do |inspection| @inspections << inspection end end end It works but is this the best way to do this - I think it's cumbersome. Thanks in advance. Josh

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  • How can I write a MySQL query to check multiple rows?

    - by Matt
    I have a MySQL table containing data on product features: feature_id feature_product_id feature_finder_id feature_text feature_status_yn 1 1 1 Webcam y 2 1 1 Speakers y 3 1 1 Bluray n I want to write a MySQL query that allows me to search for all products that have a 'y' feature_status_yn value for a given feature_product_id and return the feature_product_id. The aim is to use this as a search tool to allow me to filter results to product IDs only matching the requested feature set. A query of SELECT feature_id FROM product_features WHERE feature_finder_id = '1' AND feature_status_yn = 'y' will return all of the features of a given product. But how can I select all products (feature_product_id) that have a 'y' value when they are on separate lines? Multiple queries might be one way to do it, but I'm wondering whether there's a more elegant solution based purely in SQL.

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  • Is there a library / tool to query MySQL data files (MyISAM / InnoDB) without the server? (the SQLit

    - by MGW
    Oftentimes I want to query my MySQL data directly without a server running or without having access to the server (but having read / write rights to the files). Is there a tool or maybe even a library around to query MySQL data files like it is possible with SQLite? I'm specifically looking for InnoDB and MyISAM support. Performance is not a factor. I don't have any knowledge about MySQL internals, but I presume it should be possible to do and not too hard to get the specific code out? Thank you for any suggestions!

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  • Bringing specific results to the front using one MySQL query.

    - by animuson
    I'm setting up my geolocation feature which lists out all the countries in order of name. However, most websites have it set up where the popular countries (such as United States, United Kingdom, Canada, Australia) are at the front of the list (are shown first rather than in their assigned places). Is it possible to achieve this using the same MySQL query that I am already running to select them? SELECT * FROM `global_flags` ORDER BY `country` Is there a better alternative somewhere? Perhaps something that can reorganize the results after the database has already been queried? I don't want to exclude those results and then manually type them at the beginning because that would waste more space in the file.

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  • MYSQL how to ignore a table in a 3 table query if it doesnt satisfy the statement

    - by user165242
    I am trying to have information displayed for this query: SELECT o.sub_number,o.unique_id,o.period_from,o.period_to,o.total_amt,i.paid_amt,i.dated,i.payment,i.paid_by,i.entered_date,i.paid_for_unique,j.cheque_num,j.drawn_on,j.dated AS cheque_dated FROM paid_details o, payment_details i,cheque j WHERE o.unique_id=i.unique_id AND o.unique_id=j.unique_id AND o.sub_number IN(SELECT sub_number FROM paid_details WHERE unique_id LIKE '%1271437707%'); it flops. Well the problem is sometimes the cheque might not have any information in it. So how do i get MYSQL to ignore that table and still continue displaying the rest of the information? thanks!

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  • Multiple connections to a MySQL database in a single PHP script.

    - by st3
    There are multiple times in one page where I need to connect and subsequently query a MySQL database, yet my code won't let me. I think it might be something to do with how my files are nested but it makes no sense. I am opening the SQL connection in the header file. The top of the offending page looks like the following: <?php $page_title = 'Dashboard'; include('templates/header.inc'); // includes a 'require_once('mysqli_connect.php') and a small query to the database; require_once('includes/functions.php'); require_once('includes/dashboard_sql.php'); // Contains functions which connect to database (which are failing.) ?> I get the PHP error Notice: Undefined variable: dbc in /Library/WebServer/Documents/pediatory_site/includes/dashboard_sql.php Where $dbc is the database connection defined in mysqli_connect.php. If anyone could help me out that would be great.

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  • How can I update a field in a MySQL database table by addition in MySQL database in a single query

    - by undefined
    I have a table that stores a value that will be added to over time. When I want to add to the value I would like to do so in a single query rather than - Get oldValue from database newValue = oldValue + X update row with newValue $query1 = "SELECT value FROM table WHERE id = thisID"; $result1 = mysql_query($query1); while($row=mysql_fetch_array($result)) { $oldValue = $row['value']; } $newValue = $oldValue + x $query1 = "UPDATE table SET value = $newValue WHERE id = thisID"; Can this be done in a single query?

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  • jQuery: Quick question. How to select string variable?

    - by user317563
    Hello world, EDIT: I would like to avoid doing something like this: var str = 'Hello'; if ( str == 'Hello') { alert(str); } I would rather do: var str = 'Hello'; $(str).filter(':contains("Hello")').each(function(){ alert(this) }); I've tried a lot of things: $(str).text().method1().method2().method3(); $(str).val().method1().method2().method3(); $(str).contents().method1().method2().method3(); Nothing worked. Is it possible to do this? Thank you for your time. Kind regards, Marius

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  • How to return null value if the query has no corresponding value?

    - by Holicreature
    Hi i've a query select c.name as companyname, u.name,u.email,u.role,a.date from useraccount u, company c, audittrial a where u.status='active' and u.companyid=c.id and (u.companyid=a.companyID and a.activity like 'User activated%' and a.email=u.email) order by u.companyid desc limit 10 So if the following part doesnt't satisfy, (u.companyid=a.companyID and a.activity like 'User activated%' and a.email=u.email) no rows will be returned.. but i want to return the result of the following query select c.name as companyname, u.name,u.email,u.role,a.date from useraccount u, company c, audittrial a where u.status='active' and u.companyid=c.id order by u.companyid desc limit 10 but to add that, i should return the date if available and return null value if date is not available.. how can i do this?

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  • jquery - how is multiple selection working in this example?

    - by hatorade
    The relevant snippet of HTML: <span class="a"> <div class="fieldname">Question 1</div> <input type="text" value="" name="q1" /> </span> The relevant jQuery: $.each($('.a'), function(){ $thisField = $('.fieldname', $(this)); }); What exactly is being set to $thisField? If my understanding of multiple selectors in jQuery is correct, it should be grabbing the outer <span> element AND the inner <div> element. But for some reason, if I use $thisField.prepend("hi"); it ends up putting hi right before the text Question 1, but not before <div>. I thought multiple selectors would grab both elements, and that prepend() adds hi to the beginning of BOTH elements, not just the <div>

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  • How to create a MySQL query for time based elements with a 'safe window'?

    - by pj4533
    I am no SQL expert, far from it. I am writing a Rails application, and I am new at that as well. I come from a desktop programming background. My application has a table of data, one of the columns is the time at which the data was logged. I want to create a query with a 'safe window' around EACH row. By that I mean, it returns the first row, then for X minutes (based on the timelogged column) it won't return any data, once X minutes is up, it will return the next row. For example: ID | TimeLogged 1 | 3/5/2010 12:01:01 2 | 3/5/2010 12:01:50 3 | 3/5/2010 12:02:03 4 | 3/5/2010 12:10:30 5 | 3/5/2010 01:30:03 6 | 3/5/2010 01:31:05 With a 'safe window' of 5 minutes I want to create a query to return: 1 | 3/5/2010 12:01:01 4 | 3/5/2010 12:10:30 5 | 3/5/2010 01:30:03 (It skipped the 12:01:50 and 12:02:03 items because they occurred within 5 minutes of the first item.) Another example, with a 'safe window' of 15 minutes I want to return: 1 | 3/5/2010 12:01:01 5 | 3/5/2010 01:30:03 Perhaps I have to just return all data and parse it myself?

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  • Write a SQL Query to replace values and include all the Dates.

    - by VJ
    Well I have this - Table DimDate- Date Table Employee- Id,Name,Points,Date Now the Employee table has points for everyday unless they did not come...so the Date does not have all the Dates entries... I mean for e.g in a week he did not come for 2 days the Employee table has only 5 rows...so I have this dimdate table which has all the dates till 2050 which I want to join with and add Zeros for the dates he does not have points. So I have written this query but does not work - Select E.EmployeeId,D.Date,isNull(E.Points,0) from DimDate D left join Employee E on D.Date between '01-01-2009'and '06-01-2009' where E.EmployeeId=1 The above query give multiple dates and I tried group by on Date but does not work.

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  • SQL grouping query question; evaluating a group of rows based on the value of one field.

    - by user324575
    I've got table vendorparts that lists all my parts and their vendor(s). Parts with multiple vendors have multiple records in this table. I'm trying to write a query that only returns the partid, and vendor of parts that do not have a default vendor assigned. Partid Vendor Defaultflag 1 A 1 2 B 0 2 C 0 3 D 0 3 E 0 3 F 1 4 G 0 I would like to return the following: Partid Vendor 2 A 2 B 4 G I'm obviously having issues with partid 3 and getting the query to see it as having a default vendor assigned.

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  • How do I add on multiple $_POST['row'] and variables?

    - by Ralph The Mouf
    I am struggling to find out the syntactically correct way in which to add on more variables and rows to these statements: /* WANT TO ADD ON FIVE MORE $_POST[''] */ if(isset($_POST['check_prof']) && $_POST['check_prof'] == 'checked') { $check_prof = "checked"; }else{ $check_prof = "unchecked"; } /* SAME HERE, WANT TO ADD THE OTHER FIVE IN HERE AS WELL */ $query = "UPDATE `Users` SET `check_prof` = '" . $check_prof . "' WHERE `id` = '" . $auth->id . "' LIMIT 1"; mysql_query($query,$connection); $auth->refresh(); }

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  • Developer’s Life – Every Developer is a Superman

    - by Pinal Dave
    I enjoyed comparing developers to Spiderman so much, that I have decided to continue the trend and encourage some of my favorite people (developers) with another favorite superhero – Superman.  Superman is probably the most famous superhero – and one of the most inspiring. Everyone has their own favorite, but Superman has been the longest enduring of all comic book characters.  Clark Kent has inspired multiple movie series, TV shows, books, cartoons, and costumes.  Superman’s enduring popularity has been attributed to his superhuman strength, integrity, dedication to good, and his humility in keeping his identity a secret. So how are developers like Superman? Well, read on my list of reasons. Secret Identities They have secret identities.  I’m not saying that all developers wear thick glasses and go by an alias like “Clark Kent.”  But developers certainly work in the background, making sure everything runs smoothly, often without recognition.  Like Superman, when they have done their job right, no one knows they were there. Working Alone You don’t have to work alone.  Superman doesn’t have a sidekick like Robin or Bat Girl, but he is a major player in the Justice League.  Developers have amazing skills, and they shouldn’t be afraid to unite those skills to solve some of the world’s major problems (like slow networks). Daily Inspiration Developers are inspiring.  Clark Kent works at The Daily Planet, Metropolis’ newspaper, which is lucky because he can keep some of the publicity Superman inspires under wraps.  Developers might go unnoticed sometimes, but when people hear about some of the tasks they accomplish on a daily basis, it inspires awe. Discover Your Superpowers You have to discover your superpowers.  Clark Kent didn’t just wake up one morning with the full understanding that he could fly, leap tall buildings in a single bound, and was stronger than a speeding locomotive.  He slowly discovered these powers (after a few comic book-worthy misunderstandings!).  Developers are always learning and growing as well.  You probably won’t wake up with super powers, either, but years of practice and continuing education can get you close. Every Day is a New Day The story continues.  The Superman comic books are still being printed, and have been in print since 1938.  There have been two TV series, (one, Smallville, was on TV for ten seasons) and multiple cartoon adaptations.  There have been multiple movies, with many different actors.  A new reboot came out last year, and another is set to premier in 2016.   So, developers, when you are having a bad day or a problem seems unsolvable – remember, the story will continue!  There is always tomorrow. I hope you are all enjoying reading about developers-as-superheroes as much as I am enjoying writing about them.  Please tell me how else developers are like Superheroes in the comments – especially if you know any developers who are faster than a speeding bullet and can leap tall buildings in a single bound. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL Tagged: Developer, Superhero

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