A simple question about type coercion in C++
- by David
Given a function prototype, and a type definition:
int my_function(unsigned short x);
typedef unsigned short blatherskite;
Is the following situation defined by standard:
int main(int argc, char** argv) {
int result;
blatherskite b;
b=3;
result = my_function(b);
}
Do I get type coercion predictably via the function prototype?
