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  • SQL query construction - separate data in a column into two columns

    - by Tommy
    I have a column that contains links. The problem is that the titles of the links are in the same column, so it looks like this: linktitle|-|linkurl I want link title and linkurl in separate columns. I've created a new column for the urls, so I'm looking for a way to extract them and update the linkurl column with them. Is there any clever way to construct a query that does this?

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  • Redundancy in doing sum()

    - by Abhi
    table1 - id, time_stamp, value This table consists of 10 id's. Each id would be having a value for each hour in a day. So for 1 day, there would be 240 records in this table. table2 - id Table2 consists of a dynamically changing subset of id's present in table1. At a particular instance, the intention is to get sum(value) from table1, considering id's only in table2, grouping by each hour in that day, giving the summarized values a rank and repeating this each day. the query is at this stage: select time_stamp, sum(value), rank() over (partition by trunc(time_stamp) order by sum(value) desc) rn from table1 where exists (select t2.id from table2 t2 where id=t2.id) and time_stamp >= to_date('05/04/2010 00','dd/mm/yyyy hh24') and time_stamp <= to_date('25/04/2010 23','dd/mm/yyyy hh24') group by time_stamp order by time_stamp asc If the query is correct, can this be made more efficient, considering that, table1 will actually consist of thousand's of id's instead of 10 ? EDIT: I am using sum(value) 2 times in the query, which I am not able to get a workaround such that the sum() is done only once. Pls help on this

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  • Get consolidated results with following tables

    - by Ted
    I have a scenario. Here's my table structure is: ID LoginDate RemovalDate ---------------------------------------- 1 2009/08/01 NULL 2 2009/09/12 2010/01/02 3 2009/08/31 2009/10/29 4 2010/02/17 NULL 5 2009/10/18 2009/11/22 I want a consolidated results of how many ID's were not removed in a particular month. So the result set should be Date NotRemoved_ID -------------------------- 2009/08 2 2009/09 3 2009/10 3 [One ID got removed in 2009/10] 2010/02 2 [Two got removed in 2009/11 and 2010/01] Please help.

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  • "Remember" last three MySql queries; Cookie, passed variable or other method?

    - by Camran
    I have a classified website, with pretty sophisticated searching, and I am about to implement a function where the last three queries is displayed for the user, so that the user can go back easier through the queries. This because for each query the user has to provide a lot of input. I have four questions for you: I wonder, how can I save the actual query (SELECT * FROM etc etc)...? Do I need to add some form of encryption to be on the safe side? How will this affect performance? (I don't like the fact that cookies slow websites down) Anything else to think about? If you need more input, let me know... Btw, the website is PHP based. Thanks

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  • MYSQL: COUNT with GROUP BY, LEFT JOIN and WHERE clause doesn't return zero values

    - by Paul Norman
    Hi guys, thanks in advance for any help on this topic! I'm sure this has a very simply answer, but I can't seem to find it (not sure what to search on!). A standard count / group by query may look like this: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` GROUP BY `t1`.`any_col` and this works as expected, returning 0 if no rows are found. So does: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 However: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 GROUP BY `t1`.`any_col` only works if there is at least one row in table_1 and fails miserably returning an empty result set if there are zero rows. I would really like this to return 0! Anyone enlighten me on this? Beer can be provided in exchange if you are in London ;-)

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  • How to repair "order by" after union of 2 selects from 1 tables

    - by 4e4el
    I have a dropDownList on my form, where i need to have union of values from 2 colums of table [ost]. Type of this columns is currency. I have russian version of access, default value of curency in "rur" and i need "uah". I need to change format and save "order by". I use this query: (SELECT distinct FORMAT([Sum1] ,'# ##0.00" uah.";-# ##0.00" uah."') FROM ost) Union (SELECT distinct FORMAT([Sum2],'# ##0.00" uah.";-# ##0.00" uah."') FROM ost) ORDER BY 1

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  • Removing part of a string in PHP

    - by Nik
    I'm trying to take a query: SHOW TABLES; which will display a bunch of tables with the chat_ prefix. I want to remove the chat_ prefix from the string, format the variable (with a link), and display it. How is this accomplished?

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  • Option Value Changed - ODBC Error 2169

    - by fredrick-ughimi
    Hello, I am connecting to ADS through ODBC DSN. Everything works well until I tried out my Save Routine. Data is saved quite alright but I get an error that says - "Option value changed". What could this be? Can't find in the help file. The full error message is: ODBC - 2169 [iAnywhere Solutions][Advantage ODBC Driver] Option Value Changed. I sent an email in respect of this to [email protected] since this error number falls between error numbers: 2168 - 2188 Internal Error that should be reported. I posted this question on the Newsgroup without a possitive response. Best regards, Fredrick Ughimi [email protected]

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  • get index name within specific table name

    - by AmRoSH
    I need to check if this index not exist in specific table name not in all tables because this select statement select all indexes under this condition. IF NOT EXISTS (SELECT name from sysindexes WHERE name = 'IDX_InsuranceID') CREATE NONCLUSTERED INDEX [IDX_InsuranceID] ON [dbo].[QuoteInsurances] ( [InsuranceID] ASC )WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = OFF, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON, FILLFACTOR = 80) ON [PRIMARY] GO Thanks,

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  • Facing trouble in retrieving relevant records

    - by Umaid
    SELECT * from MainCategory where Month = 'May' and Day in ((cast(strftime('%d',date('now','-1 day')) as Integer)),(cast(strftime('%d',date('now')) as Integer)),(cast(strftime('%d',date('now','+1 day')) as Integer))); Whenever I run this query in sqlite so it returns me 33 records instead of 3. I am insterested in fetching on 3 records of the current month but unable to do so, so plz assist. --Please note: if you can't assist so plz don't post irrelevant answer. I have also modified and try to make it simple but not achieve Select day, month from MainCategory where Month = 'May' and day in ((date('now','-1 day')),(date('now')),(date('now','+1 day')))

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  • Is there a way to force Report Builder to use "WITH (NOLOCK)" in the queries it generates?

    - by Joe Pineda
    Hi. At work, users are very happy to generate their own reports using Reporting Services' Report Builder. But, alas, the queries it generates are very inefficient, and they don't use "WITH (NOLOCK)" - slowing down things for everyone. These are reports that really do need to be run using latest data - can't be offloaded to the reporting server. And since they query very specific, detailed data, hypercubes are of no use here. So the question is: Is there a way to configure Report Builder's Data Models so the queries it generates always use "WITH (NOLOCK)" when querying a table?

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  • Combine First, Middle Initial, Last name and Suffix in T-SQL (No extra spaces)

    - by Paul
    I'm trying not to reinvent the wheel here...I have these four fields [tbl_Contacts].[FirstName], [tbl_Contacts].[MiddleInitial], [tbl_Contacts].[LastName], [tbl_Contacts].[Suffix] And I want to create a FullName field in a view, but I can't have extra spaces if fields are blank...So I can't do FirstName + ' ' + MiddleInitial + ' ' + LastName + ' ' + Suffix...Because if there is no middle initial or suffix I'd have 2 extra spaces in the field. I think I need a Case statement, but I thought someone would have a handy method for this...Also, the middleinitial and suffix may be null.

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  • Mysql - Join matches and non-matches

    - by jwzk
    This is related to my other question: http://stackoverflow.com/questions/2579249/managing-foreign-keys I am trying to join the table of matches and non-matches. So I have a list of interests, a list of users, and a list of user interests. I want the query to return all interests, whether the user has the interest or not (should be null in that case), only where the user = x. Every time I get the query working its only matching interests that the user specifically has, instead of all interests whether they have it or not.

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  • How to group by having the same id?

    - by simpatico
    Hello, I want the customerid who bought product X and Y and Z, from the following schema: Sales(customerid, productName, rid); I could do the intersection: select customerid from sales where productName='X' INTERSECT select customerid from sales where productName='X' INTERSTECT select customerid from sales where productName='Z' Is this the best I could do?

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