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  • How to append a tag after a link with BeaufitulSoup

    - by systempuntoout
    Starting from an Html input like this: <p> <a href="http://www.foo.com">this if foo</a> <a href="http://www.bar.com">this if bar</a> </p> using BeautifulSoup, i would like to change this Html in: <p> <a href="http://www.foo.com">this if foo</a><b>OK</b> <a href="http://www.bar.com">this if bar</a><b>OK</b> </p> Is it possible to do this using BeautifulSoup?

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  • How to validate if all check boxes are ticked in jQuery?

    - by Jude
    I am a beginner in jQuery and I was wondering how to validate the form before submission specifically for check boxes. I am creating a simple check list form where my user would tick a check box if he finished that step. What I am planning to do is that, the script would prevent the form submission if there is an "unticked" checkbox and highlight it with a color. Here's my code : <!doctype html> <html> <head> <meta charset="utf-8"> <title>checkbox</title> <style> .error { background-color:#F00; } .valid { background-color:#0F0; } </style> <script type="application/javascript" src="http://code.jquery.com/jquery-1.8.2.min.js"> </script> <script type="application/javascript"> function validateAll() { $(".tick").change(function(){ if ($('.tick:checked').length == $('.tick').length) { $('#container').removeClass(); $('#container').addClass('error'); } else { $('#container').removeClass(); $('#container').addClass('valid'); } }); } </script> </head> <body> <div id="container"><input class="tick" id="option1" type="checkbox"></div> <div id="container"><input class="tick" id="option1" type="checkbox"></div> <input id="button" type="button" onClick="validateAll();" value="check"> </body> </html> So what I am trying to do here is when the user clicks the button, the script will highlight all the unchecked check box with red and highlight all checked with green. However, my script is not functioning. What is wrong with my script? Any suggestions on a more efficient way to do this?

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  • Is there a limitation to the length of the query in mysql?

    - by Bakhtiyor
    I am asking this question because I need to know this limitation as I am generating SELECT query in my PHP script and the part of WHERE in this query is generated inside the loop. Precisely it looks like this $query="SELECT field_names FROM table_name WHERE "; $condition="metadata like \"%$uol_metadata_arr[0]%\" "; for($i=1; $i<count($uol_metadata_arr); $i++){ $condition.=" OR metadata like \"%$uol_metadata_arr[$i]%\" "; } $query.=$condition; $result=mysql_query($query); So, that's why I need to know how long my $query string can be, because the array *$uol_metadata_arr* could contain many items.

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  • if( $_GET) if else problem

    - by webdev
    need help... the getting input form: <select name="age"> <option value="25-30">25-30</option> <option value="31-40">31-40</option> <option value="41-50">41-50</option> <option value="51-60">51-60</option> </select> example url search/?age=25-30 the function php: if ( $_GET['age'] !="25-30") $age = '("A")'; elseif ( $_GET['age'] !="31-40") $age = '("B")'; elseif ( $_GET['age'] !="41-50") $age = '("C")'; elseif ( $_GET['age'] !="51-60") $age = '("D")'; else ( $_GET['age'] !="25-30") $age = '("A")'; $search ="http://domain.com/?q='.$age; the problem: the $age inside $search always returns A (or 25-30) even though i have selected other values (31-40, 41-50, 51-60) please help..thanks

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  • I can NOT submit the form

    - by buri kuri
    Hey guys Im trying to develop an advance consumer website using php and I stuck somewhere while trying to get the data with submitting to another page. All I want to do is to get the checkbox values which are stored in an array and checked by user. I urgently need your help please here is the code: $sql2="SELECT * FROM alinanfis WHERE alinanfis.fis_id='".$fis."'" ; $resultFis=mysql_query($sql2); if(mysql_num_rows($resultFis)>0) { print "<form method='POST' action='deletionResult.php'>"; print "<table>"; print "<tr>"; print "<th style='background: transparent;'></th>"; print "<th>Fis No</th>"; print "<th>isim</th>"; print "<th>soyisim</th>"; print "<th >Tarih</th>"; print "<th>Fis Tipi</th>"; print "<th>Nerede</th>"; print "<th>Litre</th>"; print "<th>Tutar</th>"; print "</tr>"; while($rowAlinan=mysql_fetch_array($resultFis)) { $sqlFisTipi="SELECT * FROM atype WHERE a_id='".$rowAlinan['a_id']."'" ; $resultFisTipi=mysql_query($sqlFisTipi); $rowFisTipi=mysql_fetch_array($resultFisTipi); $sqlNerede="SELECT * FROM isyeri WHERE i_id='".$rowAlinan['nerde']."'" ; $resultNerede=mysql_query($sqlNerede); $rowNerede=mysql_fetch_array($resultNerede); $sqlMID="SELECT * FROM musteri WHERE m_id='".$rowAlinan['m_id']."'" ; $resultMID1=mysql_query($sqlMID); $rowMID1=mysql_fetch_array($resultMID1); print "<tr>"; print "<td><input name='checkBox[]' type='checkbox' value='".$rowAlinan['fis_id']."' /> php</td>"; print "<td>".$rowAlinan['fis_id']."</td>"; print "<td>".$rowMID1['m_name']."</td>"; print "<td>".$rowMID1['m_lastName']."</td>"; print "<td>".$rowAlinan['alinan_tarih']."</td>"; print "<td>".$rowFisTipi['a_name']."</td>"; print "<td>".$rowNerede['i_name']."</td>"; print "<td>".$rowAlinan['litre']."</td>"; print "<td>".$rowAlinan['tutar']."</td>"; print "</tr>"; } print '<div class="form_settings">'; print "<input class='submit' type='submit' name= 'send' value='Send'>"; / print '</div>'; print "</table>"; print "</form>"; }//end of if(num_rows>0) else echo '*no such receipt found!!'; mysql_close($con);

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  • ERROR: there is no parameter $1 when creating view

    - by idlemoments
    When we try to create a view within a funcion we get ERROR: there is no parameter $1. This is the sample code. Begin CREATE VIEW artikelnr AS SELECT datum, 'uitgifte' as "type", CASE WHEN 'test'='test' THEN 0 END as "aantal ontvangen", aantal as "aantal uitgegeven" FROM uitgifteregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN uitgifte ON uitgifte.uitgiftenr = uitgifteregel.uitgiftenr UNION SELECT datum, 'ontvangst' as "type", aantal as "aantal ontvangen" , CASE WHEN 'test'='test' THEN 0 END as "aantal uitgegeven" FROM ontvangstregel JOIN artikel ON artikel.artikelnr = new.artikelnr JOIN ontvangst ON ontvangst.ontvangstnr = ontvangstregel.ontvangstnr; Return new; end; When we replace new.artikelnr on line 7 with value 1 it works like it should, but the function needs to work with different artikelnr's. example line 7: JOIN artikel ON artikel.artikelnr = new.artikelnr Please point us in the right direction.

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  • how to format (css) data loaded with $.load or $.get or $.ajax?

    - by user356981
    I need to load a piece of content html when an link in a menu is clicked; once loaded, the css format is not working properly, how do I re-format (re-styling via css) the loaded code? My code is: $('a', mainMenu).click(function() { ref = this.href; $('#content').load(ref + ' #content' function() { url = '../css/jquery-ui-1.8.2.custom.css'; //styling here if (document.createStyleSheet) document.createStyleSheet(url); else $('<link rel="stylesheet" type="text/css" href="'+url+'"/>').appendTo('head'); }); }) is it another way to load and re-style html (plugins perhaps)? thanks in adv'n.

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  • How modify Details view

    - by ognjenb
    How modify strongly typed Details view created in asp.net mvc? View need to present data Similarly to the table. Is this possible in CSS? Part of my view is: <fieldset > <legend>Fields</legend> <p> ArticleNumber: <%= Html.Encode(Model.ArticleNumber) %> </p> <p> CalCertificateFile: <%= Html.Encode(Model.CalCertificateFile) %> </p> </fieldset>

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  • magento set subcategory as rootcategory

    - by user1113130
    I have 1 magento installation with 2 websites. i want to set a subcategory from website 1 as rootcategory of website 2. and i don't know the id of the category, because this is local and has to work on production with other categories. So i can't set the id of the wanted category in code. it must be adjustable in the backend. in system-manage stores- select a store here you can set the rootcategory but there are no subcategories available. is the only solution to build a module to select the id of the category?

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  • SQL query to get lowest 2 values of a counted query selection (using db2)?

    - by jNoob
    Hi, Imagine I already have a query that returns the following: Col1 | Col2 ------------ A | 2 B | 3 C | 3 D | 4 E | 8 ... Say I used something like this: select Col1, count ( * ) as Col2 \ from ... where ... order by Col2 \ group by Col1 \ So now, all I want to select are (Col1, Col2) such that it returns the selections (a, b) and (c, d) where (b >= all (Col2)) and (d >= ((all (Col2)) - a)). So for the above example, it would return {(A, 2), (B, 3), (C, 3)}. How do I go about doing this? Any help would be highly appreciated. Thanks.

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  • Compare two date whit jquery

    - by Mercer
    Hello, i have two String fields who represent Date in my page and i would to compare this two fields to know if my first date < second date <tr> <td align="right">First Date: </td> <td align="left"> <html:text name="addPublicationForm" styleId="firstDate" property="firstDate" maxlength="10"/></td> </tr> <tr> <td align="right">Second Date: </td> <td align="left"> <html:text name="addPublicationForm" styleId="secondDate" property="secondDate" maxlength="10"/></td>

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  • undefined GET id?

    - by Azzyh
    <?php $s = $_GET["s"]; if($s) { $hent_b = mysql_query("SELECT * FROM member_battles WHERE state = '1' ORDER BY id DESC LIMIT 0,200") or die(mysql_error()); }else{ $hent_b = mysql_query("SELECT * FROM member_battles WHERE state = '0' ORDER BY id DESC LIMIT 0,200") or die(mysql_error()); } while($vis = mysql_Fetch_array($hent_b)) { ?> I have this now i want when i enter my site (index.php) it should not come up undefined $_GET["s"]; how do i do this? but i want when you do index.php?s then it should change the query

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  • Which should I use? (performance)

    - by Yim
    I want to know a simple thing: when setting up a style that is inherited by all its children, is it recommended most specific? (even if you don't care others having this style) Structure: html body parent_content wrapper p I don't care having parent_content or wrapper having the style I do care changing the html or body style (or all p) So what should I use? #parent_content{ color:#555; } #parent_content p{ color:#555; } #wrapper{ color:#555; } ... Also, some links to tutorials about this would be great

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  • Create div tag template and reuse

    - by user1683645
    Is it possible to create a template e.g with lots of other elements inside it with proper attribute "tagging" and reuse it with jquery? For instance when you want to display user submitted comments without refreshing the page. The reason I ask this is because the code between the div tags are rather long. So using for instance prepend() would be to long to rewrite. Whats the best approach for larger manipulations? Create a separate html? Im pretty new to manipulation, but since I have a programming background i would expect that there is an efficient way to reuse already existing HTML instead of redefining it in jquery.

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  • Does a form gets closed after form.submit()?

    - by user281180
    I have the following code: $.ajax({ type: "POST", url: '<%=Url.Action("test","pepole") %>', data: $("#PeopleForm").submit(), contentType: "application/json; charset=utf-8", dataType: "html", sucess: function() { }, error: function(request, status, error) { $("#NotSelectedList").html("Error: " & request.responseText); } }); The PeopleForm is displayed in a dialog. After the submit, the dialog gets closed. Is that normal? I don`t want the dialog to get closed after the submit. How can I do that?

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  • Apache not handling files correctly (Handler Help)

    - by ethanschaefer
    I'm trying to set up my .htaccess file correctly and I'm having an issue. The only thing my .htaccess file at the moment is: AddType application/x-httpd-php .php .html .htm This is included because my server is not parsing php in my html files. However when this is included in my .htaccess file, when I open a page in my browser, the user is prompted to save or open the file locally. I believe the answer to my issues is setting up an action to be done (run with php) however I cannot find out the path to my php files. Any help is appreciated.

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  • Fill data gaps without UNION

    - by Dave Jarvis
    Problem There are data gaps that need to be filled, possibly using PARTITION BY. Query Statement The select statement reads as follows: SELECT count( r.incident_id ) AS incident_tally, r.severity_cd, r.incident_typ_cd FROM report_vw r GROUP BY r.severity_cd, r.incident_typ_cd ORDER BY r.severity_cd, r.incident_typ_cd Code Tables The severity codes and incident type codes are from: severity_vw incident_type_vw Actual Result Data 36 0 ENVIRONMENT 1 1 DISASTER 27 1 ENVIRONMENT 4 2 SAFETY 1 3 SAFETY Required Result Data 36 0 ENVIRONMENT 0 0 DISASTER 0 0 SAFETY 27 1 ENVIRONMENT 0 1 DISASTER 0 1 SAFETY 0 2 ENVIRONMENT 0 2 DISASTER 4 2 SAFETY 0 3 ENVIRONMENT 0 3 DISASTER 1 3 SAFETY Any ideas how to use PARTITION BY (or JOINs) to fill in the zero counts?

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  • Delete rows out of table that is innerjoined and unioned with 2 others

    - by jonathan
    We have 3 tables (table1, table2, table3), and I need to delete all the rows from table1 that have the same ID in table2 OR table3. To see a list of all of these rows I have this code: ( select table2.ID, table2.name_first, table2.name_last, table2.Collected from table2 inner join table1 on table1.ID = table2.ID where table2.Collected = 'Y' ) union ( select table3.ID, table3.name_first, table3.name_last, table3.Collected from table3 inner join table1 on table1.ID = table3.ID where table3.Collected = 'Y' ) I get back about 200 rows. How do I delete them from table1? I don't have a way to test if my query will work, so I'm nervous about modifying something I found online and potentially deleting data (we do have backups, but I'd rather not test out their integrity). TIA!

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  • Slow performance of query

    - by user642378
    Hi, I have asked the performance of query and i tried to simplyfy it.but still it not works.I am adding my query below.Please can you simplify it more effectively select r.parent_itemid f_id, parent_item.name f_name, parent_item.typeid f_typeid, parent_item.ownerid f_ownerid, parent_item.created f_created, parent_item.modifiedby f_modifiedby, parent_item.modified f_modified, pt.name f_tname, child_item.id i_id, t.name i_tname, child_item.typeid i_typeid, child_item.name i_name, child_item.ownerid i_ownerid, child_item.created i_created, child_item.modifiedby i_modifiedby, child_item.modified i_modified, r.ordinal i_ordinal from item child_item, type t, relation r, item parent_item, type pt where r.child_itemid = child_item.id and t.id=child_item.typeid and parent_item.id = r.parent_itemid and pt.id = parent_item.typeid and parent_item.id in ( select itemid from permission where itemid=parent_item.id and (holder_itemid in (10,100) and level > 0) ) order by r.parent_itemid, r.relation_typeid, r.ordinal Thanks you regards jennie

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  • mysql query for change in values in a logging table

    - by kiasectomondo
    I have a table like this: Index , PersonID , ItemCount , UnixTimeStamp 1 , 1 , 1 , 1296000000 2 , 1 , 2 , 1296000100 3 , 2 , 4 , 1296003230 4 , 2 , 6 , 1296093949 5 , 1 , 0 , 1296093295 Time and index always go up. Its basically a logging table to log the itemcount each time it changes. I get the most recent ItemCount for each Person like this: SELECT * FROM table a INNER JOIN ( SELECT MAX(index) as i FROM table GROUP BY PersonID) b ON a.index = b.i; What I want to do is get get the most recent record for each PersonID that is at least 24 hours older than the most recent record for each Person ID. Then I want to take the difference in ItemCount between these two to get a change in itemcount for each person over the last 24 hours: personID ChangeInItemCountOverAtLeast24Hours 1 3 2 -11 3 6 Im sort of stuck with what to do next. How can I join another itemcount based on latest adjusted timestamp of individual rows?

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