Search Results

Search found 7972 results on 319 pages for 'shell extensions'.

Page 93/319 | < Previous Page | 89 90 91 92 93 94 95 96 97 98 99 100  | Next Page >

  • grep options (unix)

    - by lego69
    hello everyone, can You explain please, can grep pick rows if at least one element from the list appeared, for exmaple grep "hello world" file1 grep must give me all rows which have or word hello or world or both of them, thanks in advance

    Read the article

  • Problem with cyrillic symbols in console

    - by woto
    Hi everyone, sorry for bad English. It's Ruby code. s = "???????" `touch #{s}` `cat #{s}` `cat < #{s}` Can anybody tell why it's code fails? With sh: cannot open ???????: No such file But thic code works fine s = "????????" `touch #{s}` `cat #{s}` `cat < #{s}` Problem is only when Russian symbol '?' in the word and with symobol '<' woto@woto-work:/tmp$ locale LANG=ru_RU.UTF-8 LC_CTYPE="ru_RU.UTF-8" LC_NUMERIC="ru_RU.UTF-8" LC_TIME="ru_RU.UTF-8" LC_COLLATE="ru_RU.UTF-8" LC_MONETARY="ru_RU.UTF-8" LC_MESSAGES="ru_RU.UTF-8" LC_PAPER="ru_RU.UTF-8" LC_NAME="ru_RU.UTF-8" LC_ADDRESS="ru_RU.UTF-8" LC_TELEPHONE="ru_RU.UTF-8" LC_MEASUREMENT="ru_RU.UTF-8" LC_IDENTIFICATION="ru_RU.UTF-8" LC_ALL= woto@woto-work:/tmp$ ruby -v ruby 1.8.7 (2010-01-10 patchlevel 249) [x86_64-linux] woto@woto-work:/tmp$ uname -a Linux woto-work 2.6.32-26-generic #48-Ubuntu SMP Wed Nov 24 10:14:11 UTC 2010 x86_64 GNU/Linux woto@woto-work:/tmp$ lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 10.04.1 LTS Release: 10.04 Codename: lucid

    Read the article

  • Tips / Resources for building a Google Chrome plugin

    - by David
    After test driving Google Chrome for 30 minutes or so, I like it, even if it seems bare-bones at the moment. The obvious way to add a few things I can't live without would be through plugins. Does anyone have any links to resources on how to get started building a plugin/addon for Chrome? Thanks.

    Read the article

  • Batch & log files

    - by Mat
    Hi All, Please help!!! ;) I have a problem with this code in a batch file (Linux): Mil=`date +"%Y%m%d%H%M%S"` batch=`echo "${DatMusic}"` TabimportEnteteMusic="importentetemusic.dat" { grep '^ENTETE' ${IMPORT}/${DatMusic} > ${IMPORT}/$TabimportEnteteMusic mysql -u basemine --password="basemine" -D basemine -e "delete from importmusic;" mysql -u basemine --password="basemine" -D basemine -e "delete from importentetemusic;" } >> $TRACES/batch/$Mil.$batch.log 2>&1 When I run this batch, its answer is: /home/mmoine/sgbd_mysql/batch/importMusic.sh: line 51: /batch/20100319160018.afce01aa.cr.log: Aucun fichier ou répertoire de ce type (in english, I suppose: "No files or Directory found") So, please, how can I put all generated messages in this log file? Thanks for your answers. Sorry for my english ;)

    Read the article

  • grep from a log file to get count

    - by subodh1989
    I have to get certain count from files. The grep statement i am using is like this : counter_pstn=0 completed_count_pstn=0 rec=0 for rec in `(grep "merged" update_completed*.log | awk '{print $1}' | sed 's/ //g' | cut -d':' -f2)` do if [ $counter_pstn -eq 0 ] then completed_count_pstn=$rec else completed_count_pstn=$(($completed_count_pstn+$rec)) fi counter_pstn=$(($counter_pstn+1)) done echo "Completed Orders PSTN Primary " $completed_count_pstn But the log file contains data in this format : 2500 rows merged. 2500 rows merged. 2500 rows merged. 2500 rows merged.2500 rows merged. 2500 rows merged. 2500 rows merged. As a result , it is missing out the count of one merge(eg on line 4 of output).How do i modify the grep or use another function to get the count. NOTE that the 2500 number maybe for different logs. So we have to use "rows merged" pattern to get the count. i have tried -o ,-w grep options,but it is not working. Expected output from above data: 17500 Actual output showing : 15000

    Read the article

  • Get part of a string of part of regular expression?

    - by Buttink
    Im trying to make a script that will go into a directory and run my own application with each file matching a regular expression, specifically "Test[0-9]*.txt". My input filenames look like this "TestXX.txt". Now, I could just use cut and chop off the Test and .txt, but how would I do this if XX wasn't predefined to be 2 numbers? What would I do if i had "Test1.txt" ... "Test10.txt"? In other words, How would I get the [0-9]* part? Just so you know, I want to be able to make a OutputXX.txt :)

    Read the article

  • sed 's/this/that/' -- ignoring g but still replace entire file

    - by lakshmipathi
    as title said, Im trying to change only the first occurrence of word.By using sed 's/this/that/' file.txt though i'm not using g option it replace entire file. How to fix this.? UPDATE: $ cat file.txt first line this this this this $ sed -e '1s/this/that/;t' file.txt first line this // ------> I want to change only this "this" to "that" :) this this this

    Read the article

  • How to delete "-" file from svn?

    - by ~brzeti
    Accidentally I have created file "-" (just a minus) in a directory and commited it. I have to delete it because its causing error on other machines: svn: Can't convert string from 'UTF-8' to native encoding: svn: ?\226?\128?\147 I can remove it from local directory using "rm -i *" or with python "os.remove('\xe2\x80\x93')" but those methods do not work with "svn rm". How to delete such file from svn repository?

    Read the article

  • strip version from package name using Bash

    - by cd1
    hi, I'm trying to strip the version out of a package name using only Bash. I have one solution but I don't think that's the best one available, so I'd like to know if there's a better way to do it. by better I mean cleaner, easier to understand. suppose I have the string "my-program-1.0" and I want only "my-program". my current solution is: #!/bin/bash PROGRAM_FULL="my-program-1.0" INDEX_OF_LAST_CHARACTER=`awk '{print match($0, "[A-Za-z0-9]-[0-9]")} <<< $PROGRAM_FULL` PROGRAM_NAME=`cut -c -$INDEX_OF_LAST_CHARACTER <<< $PROGRAM_FULL` actually, the "package name" syntax is an RPM file name, if it matters. thanks!

    Read the article

  • Bash Scripting: I want to open a set of .html files, and add line before html tag

    - by Bashn00b
    Hi guys, I have a set of .php files in a folder, I want to add text just before these lines: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en" > What i want is to insert just before these lines in the html file. So just want to prepend that file before each docType declaration. However the DOCTYPE declaration is never on line 1, as there is loads of php lines before. I have this current script (where FE is the folder containing all the scripts i want to edit): for file in ${fe}*; do echo "$file" done Thanks,

    Read the article

  • grep value inside a variable pointing to other variable

    - by Joice
    using : ksh *abc = 1 efg = 2 hgd = 3 not known to me * say if i have Value="abc efg hgd" abc efg hgd all contains some value which i dnt know. Now I want to grep the value contained inside abc. like for i in $Value do grep "echo $(($((echo $i | cut -d'|' -f2))))" done this grep should look for the value inside abc efg hgd grep 1 grep 2 grep 3

    Read the article

  • Linux How to print all the files with the same prefix after searching for them?

    - by Alyx
    I need to search through a directory which contains many sub directories, each which contain files. The files read as follows question1234_01, where 1234 are random digits and the suffix _01 is the number of messages that contain the prefix, meaning they are apart of the same continuing thread. find . -name 'quest*' | cut -d_ -f1 | awk '{print $1}' | uniq -c | sort -n example output: 1 quest1234 10 quest1523 This searches for all the files then sorts them in order. What I want to do is print all the files which end up having the most occurrences, in my example the one with 10 matches. So it should only output quest1523_01 - 11

    Read the article

  • Creating a Custom Ubuntu Daemon

    - by Chris S
    What's the "correct" way to create a custom daemon in Ubuntu, that will start at boot time and be controllable by Ubuntu's standard daemon start/stop commands? Can I just copy and paste one of the scripts in /etc/init.d or do I need to "register" the daemon somewhere else?

    Read the article

  • Ignoring specific differences in diff

    - by naumcho
    When doing recursive diffs I want to ignore expected differences/translations - is there a way to do that with standard unix tools? E.g. file1: 1 ... 2 /path/to/something/ver1/blah/blah 3 /path/to/something/ver1/blah/blah 4 ... file2: 1 ... 2 /path/to/something/ver2/blah/blah 3 /path/to/something/ver3/blah/blah 4 ... I want to be able to do something like: diff file1 file2 --ignore-transltion "ver1>ver2" This should show only show me that line 3 is different Does anyone know of a good way to do that? I can easily write a perl script to do it but i will end up re-implementing most of the rest of the functionality of 'diff'. Update: My goal is to run this on directories with different versions of the same files with "diff -r" so I can spot unexpected differences in versions.

    Read the article

  • How to get line count from variable (from MYSQL query)?

    - by Mint
    My problematic code: testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';"` $testMYSQL now contains: test test test Then I do: TEST=$(echo $testMYSQL | wc -l) echo "$TEST" I would of thought that would work, but it doesn't, it returns 1 But if I put this into $testMYSQL: "test\ntest\ntest" it will say 3… Whats going on here? does MYSQL not use new lines? PS, I know I can use a for loop to loop though the lines then count up the lines that way, but I was hoping for a simpler solution like wc

    Read the article

  • how to search for a term only in non test files

    - by dorelal
    I use ack and I like it. However from time to time I need to search for something in my code base and I want to ignore all the files residing in test directory. Basically all the files which have test in their absolute path should be not included in the search. How do I achieve that? I am willing to have a custom bash script. Something like ack_no_test "application" - search for "application" in all files but ignore files residing in test directory

    Read the article

  • Prompt message box Linux or any system from removable device

    - by Zloy Smiertniy
    Hi all, I have some files that in windows enable me to prompt messages when a device is plugged. In case it is lost it pops up a message that says the user to please return it to he owner. Does anybody know how can I do this in Linux? I doesnt need to be a complex thing, it can be an option in a right clic menu, or a splashcreen, or anything, just to make sure that the owner of the device may be looking for it.

    Read the article

  • How to check an exectuable's path is correct in PHP?

    - by nickf
    I'm writing a setup/installer script for my application, basically just a nice front end to the configuration file. One of the configuration variables is the executable path for mysql. After the user has typed it in (for example: /path/to/mysql-5.0/bin/mysql or just mysql if it is in their system PATH), I want to verify that it is correct. My initial reaction would be to try running it with "--version" to see what comes back. However, I quickly realised this would lead to me writing this line of code: shell_exec($somethingAUserHasEntered . " --version"); ...which is obviously a Very Bad Thing. Now, this is a setup script which is designed for trusted users only, and ones which probably already have relatively high level access to the system, but still I don't think the above solution is something I want to write. Is there a better way to verify the executable path? Perhaps one which doesn't expose a massive security hole?

    Read the article

  • Python 3.1: Syntax Error for Everything! (Mac OS X)

    - by Nathan G.
    I updated to Python 3.1.3 (I've got OS X 10.6). If I type python in Terminal, I get a working 2.6.1 environment. If I type python3 in Terminal, I get a 3.1.3 environment. Everything looks fine until I do something. If I try to run print "hello", I get a syntax error. This problem is the same in IDLE. I tried deleting everything for 3.1 and then reinstalling, but it hasn't worked. Ideas? Thanks in advance!

    Read the article

< Previous Page | 89 90 91 92 93 94 95 96 97 98 99 100  | Next Page >