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  • Java - Does null variable require space in memory

    - by Yatendra Goel
    class CheckStore { private String displayText; private boolean state; private String meaningfulText; private URL url; public CheckStore(String text, boolean state) { this.displayText = text; this.state = state; } : : } As I am initializing only two variables (displayText and state) in the constructor, Will the rest two variables (meaningfulText and url which will have the value null) will require space in memory to store null value. Q1. I think they will require space. If they will, then how much memory does a null value takes in the memory (like int takes 4 bytes). Q2. How much space a string takes in memory. I guess it will depend on the length of the string. So how much space a string takes of how much length?

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  • JS variable scope missunderstanding

    - by meo
    I have a little problem: slideHelpers.total = 4 for (i=1;i <= slideHelpers.total; i++) { $('<a href="#">' + i + '</a>').bind('click', function(){ alert('go to the ' + i + ' slide')}).appendTo('.slideaccess') } the alert gives out 5 what is logic, because when the function click triggers i is actually 5. But i would like to have the same i as in my <a> tag. What is the best way to handle this? I could put i in the data() of the <a> tag for example but i am sure there is a easier way.

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  • Variable won't store in session

    - by Mittens
    So I'm trying to store the "rank" of a user when they log in to a control panel which displays different options depending on the given rank. I used the same method as I did for storing and displaying the username, which is displayed on the top of each page and works just fine. I can't for the life of me figure out why it won't work for the rank value, but I do know that it is not saving it in the session. Here is the bit that's not working; $username = ($_POST['username']); $password = hash('sha512', $_POST['password']); $dbhost = 'mysql:host=¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦;dbname=¦¦¦¦¦¦¦¦¦¦¦'; $dbuser = '¦¦¦¦¦¦¦¦¦¦¦'; $dbpassword = '¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦¦'; try { $db = new PDO($dbhost, $dbuser, $dbpassword); $statement = $db->prepare("select password from users where email = :name"); $statement->execute(array(':name' => $username)); $result = $statement->fetch(); $pass = $result[password]; $rank = $result[rank];} catch(PDOException $e) {echo $e->getMessage();} if ($password == $pass) { session_start(); $_SESSION['username'] = $username; $_SESSION['rank'] = $rank; header('Location: http://¦¦¦¦¦¦¦¦¦.ca/manage.php'); } else{ include'../../includes/head.inc'; echo '<h1>Incorrect username or password.</h1>'; include'../../includes/footer.inc'; } I'm also new to the whole PDO thing, hence why my method of authenticating the password is pretty sketchy.

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  • Concatenate a table name from a variable in a FROM clause

    - by idieeasy
    I'm trying to use a dynamically generated fully-qualified table name in sql server 2008. For example, this does not work: select max([id]) from @dbName+N'.[T1]' This will give an error like: Msg 102, Level 15, State 1, Line 73 Incorrect syntax near '+'. I know that something like this works: declare @qualifiedTable varchar(200) = @dbName+N'.[T1]' select max([id]) from @qualifiedTable But I have to do this LOTS of times so I would really like to do it in line. Is it possible?

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  • How to call javascript function when url variable is sent

    - by mattlarkin
    Hello, heres basically what I need to get done. I have a jsp page which allows me to add/modify/delete an item. The items are stored in a database which I have controller classes to access(dont worry bout that part) When an item gets selected and deleted the id of the item gets sent to the controller to be processed. The item will not always be deleted if their is a foreign key constraint so I send either a delete=true or delete=false through url back to the jsp page. I would like to have it so a javascript function gets called displaying an alert saying the item was deleted or the item was not deleted. can someone please tell me the best way to do this? thank you

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  • PHP: Parsing of a given form input variable

    - by Jaime Cross
    How would I go about parsing incoming form data where the name changes based on section of site like: <input type="radio" name="Motorola section" value="Ask a question"> where 'Motorola section may be that, or Verizon section, or Blackberry section, etc. I do not have any control over changing the existing forms unfortunately, so must find a way to work with what is there. Basically, I need to be able to grab both the name="" data as well as its coresponding value="" data to be able to populate the email that gets sent properly.

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  • Use textbox value on submit as a query string variable

    - by Eric
    How would I take a text box value and use it in the query string on submit? I'd like it to start as this, /News?favorites=True and end up something like this after the user enters in a search and clicks search. /News?query=test&favorites=True The controller action looks like this public ActionResult Index(string query,bool favorites) { //search code } This question is something close to what I'd like to do, but I'd like to use the query string and maintain the existing values in the query string. Thanks.

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  • C++ - 3 possible values in Variable?

    - by noryb009
    I need to store a 30 letter combination, but each letter can only be "0", "1" or "2". When I use sizeof(myString), it returns 32. I want to use this 30 letter combination to access a row of an array, so I'm wondering if it is possible to use a 3 value bool of some sort to store 1 of 3 values in.

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  • Codeigniter passing variable to URL

    - by CyberJunkie
    I have a list of posts and an edit link for each. When clicking edit it goes to a page where I can edit the specific post I clicked on. For this I will have to pull from the db the id of the post. Would this be the correct way to do it? <a href="<?php echo site_url("post/edit/$row->id"); ?>">Edit</a> post is my controller, edit is my function, and $row->id should pull the id of the post.

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  • Performance implications of using a variable versus a magic number

    - by Nathan
    I'm often confused by this. I've always been taught to name numbers I use often using variables or constants, but if it reduces the efficiency of the program, should I still do it? Heres an example: private int CenterText(Font font, PrintPageEventArgs e, string text) { int recieptCenter = 125; int stringLength = Convert.ToInt32(e.Graphics.MeasureString(text, font)); return recieptCenter - stringLength / 2; } The above code is using named variables, but runs slower then this code: private int CenterText(Font font, PrintPageEventArgs e, string text) { return 125 - Convert.ToInt32(e.Graphics.MeasureString(text, font) / 2); } In this example, the difference in execution time is minimal, but what about in larger blocks of code?

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  • c# error: Use of unassigned local variable (context visual studio T4 ENGINE)

    - by user310291
    In C# (within the context of T4 template see http://www.olegsych.com/2008/03/how-to-generate-multiple-outputs-from-single-t4-template/) I want to do this <# String myTemplateVar; #> <# if (string.IsNullOrEmpty(myTemplateVar)) { myTemplateVar= "name"; }; #> I want to give a value to myTemplateVar if myTemplateVar has not already been setup by an external call from T4 engine in another template which would have this instruction: CallContext.SetData("myTemplate.myTemplateVar", ExternalTemplateVar); But I cannot even compile in C# why ? How to fix this ?

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  • Can i Use the value of a variable from within a ruby script inside ssh.exec()

    - by kamal
    If i have a # {} , like #{results}, in the snippet below: results = Array.new                                   f = open("/Users/kahmed/messages", "r")                                   f.each_line do |line|                                        results << "#{$.} #{line}" if line =~ /NFE/                                       put #{results}                                   end How can i use it in the following ssh.exec command Net::SSH.start( HOST, USER, :password = PASS ) do|ssh|                                   ssh.exec(#{results})

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  • How to convert a string to variable name

    - by p1xelarchitect
    I'm loading several external JSON files and want to check if they have been successfully cached before the the next screen is displayed. My strategy is to check the name of the array to see if it an object. My code works perfectly when I check only a single array and hard code the array name into my function. My question is: how can i make this dynamic? not dynamic: (this works) $("document").ready(){ checkJSON("nav_items"); } function checkJSON(){ if(typeof nav_items == "object"){ // success... } } dynamic: (this doesn't work) $("document").ready(){ checkJSON("nav_items"); checkJSON("foo_items"); checkJSON("bar_items"); } function checkJSON(item){ if(typeof item == "object"){ // success... } } here is the a larger context of my code: var loadAttempts = 0; var reloadTimer = false; $("document").ready(){ checkJSON("nav_items"); } function checkJSON(item){ loadAttempts++; //if nav_items exists if(typeof nav_items == "object"){ //if a timer is running, kill it if(reloadTimer != false){ clearInterval(reloadTimer); reloadTimer = false; } console.log("found!!"); console.log(nav_items[1]); loadAttempts = 0; //reset // load next screen.... } //if nav_items does not yet exist, try 5 times, then give up! else { //set a timer if(reloadTimer == false){ reloadTimer = setInterval(function(){checkJSON(nav_items)},300); console.log(item + " not found. Attempts: " + loadAttempts ); } else { if(loadAttempts <= 5){ console.log(item + " not found. Attempts: " + loadAttempts ); } else { clearInterval(reloadTimer); reloadTimer = false; console.log("Giving up on " + item + "!!"); } } } }

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  • session variable values are not being passed between pages

    - by ravi nankani
    hi, i am a little new to php and although i have managed to pass values of session variables before this piece of code is leaving me puzzled <form action="team_reg2.php" method="post" name="form1" class="cent" id="form1"> Team Registration "; print "member$i"; print "\n"; print "\n"; print "Please enter only id\n"; } ? now this will pass via post to team_reg2.php echo " please note your team id is 1 "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } else { $str="select * from $query where ("; for($i=1;$i<=$num;$i++) { $name='mem'.$i; $text="p_id='$_POST[$name]'"; if($i==1) $str=$str.$text; else $str=$str.' or '.$text; } $str=$str.')'; $query2=$str; echo "$str"; // echo "$query2"; $que=mysql_query($query2,$con) or die(mysql_error()); $num=mysql_num_rows($que); if($num!=0) { while($result=mysql_fetch_array($que)) { echo "$result[p_id] is already registered in team $result[t_id]"; } //include("reg_team.html"); } else if($num==0) { //echo $query; $query2="select max(t_id) from $query"; $que=mysql_query($query2,$con) or die(mysql_error()); //echo "$que"; $result=mysql_fetch_array($que); $max=$result['max(t_id)']; $max++; $num=$_SESSION['max_team']; for($i=1;$i<=$num;$i++) { $name='mem'.$i; if($_POST[$name]!="") { $query2="insert into $query values($max,'$_POST[$name]')"; $que=mysql_query($query2,$con); } } echo " please note your team id is $max "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } } ? i have done session_start(); at the beginning of the page itself. The problem is that echoing $_SESSION variables in second file is not printing anything. someone please explain me whats going on. thank you

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  • trying to show a variable in my layout

    - by user1400
    hi i have a simple question where is my code wrong ? in index controller and index action i put $this->view->username="user1"; and when i try in my layout i use echo $this->username; i got fllowing error or null value Notice: Trying to get property of non-object in D:\Zend\Apache2\htdocs\test\application\layouts\layout.phtml on line 115 thanks

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  • C# newbie problem with variable types

    - by ile
    int newWidth = 100; int newHeight = 100; double ratio = 0; if (img1.Width > img1.Height) { ratio = img1.Width / img1.Height; newHeight = (int)(newHeight / ratio); } else { ratio = img1.Height / img1.Width; newWidth = (int)(newWidth / ratio); } Image bmp1 = img1.GetThumbnailImage(newWidth, newHeight, null, IntPtr.Zero); bmp1.Save(Server.MapPath("~/Uploads/Photos/Thumbnails/") + photo.PhotoID + ".jpg"); I always get Image with both height and width having same values (100) I am obiously doing something wrong with type conversion?

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  • Trying to pass variable from 1 Function to Another to Put in Array within same Model

    - by Jason Shultz
    Ok, that sounds really confusing. What I’m trying to do is this. I’ve got a function that uploads/resizes photos to the server. It stores the paths in the DB. I need to attach the id of the business to the row of photos. Here’s what I have so far: function get_bus_id() { $userid = $this->tank_auth->get_user_id(); $this->db->select('b.id'); $this->db->from ('business AS b'); $this->db->where ('b.userid', $userid); $query = $this->db->get(); if ($query->num_rows() > 0) { return $query->result_array(); } That get’s the id of the business. Then, I have my upload function which is below: /* Uploads images to the site and adds to the database. */ function do_upload() { $config = array( 'allowed_types' => 'jpg|jpeg|gif|png', 'upload_path' => $this->gallery_path, 'max_size' => 2000 ); $this->load->library('upload', $config); $this->upload->do_upload(); $image_data = $this->upload->data(); $config = array( 'source_image' => $image_data['full_path'], 'new_image' => $this->gallery_path . '/thumbs', 'maintain_ratio' => true, 'width' => 150, 'height' => 100 ); $this->load->library('image_lib', $config); $this->image_lib->resize(); $upload = $this->upload->data(); $bus_id = $this->get_bus_id(); $data = array( 'userid' => $this->tank_auth->get_user_id(), 'thumb' => $this->gallery_path . '/thumbs/' . $upload['file_name'], 'fullsize' => $upload['full_path'], 'busid'=> $bus_id['query'], ); echo var_dump($bus_id); $this->db->insert('photos', $data); } The problem I’m getting is the following: A PHP Error was encountered Severity: Notice Message: Undefined index: id Filename: models/gallery_model.php Line Number: 48 I’ve tried all sorts of ways to get the value over, but my limited knowledge keeps getting in the way. Any help would be really appreciated.

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  • variable size datatype(int) in c++

    - by goutham
    Hello I want to use a datatype to represent sizes like 3bits or 12bits.. can anyone tell me how can I implement this in c++ and is there any code like this, which can help me define size in bits int i:3; thanks in advance ..

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  • Excel assign copied sheet name as variable

    - by rach-90
    I'm trying to copy an existing sheet in my workbook and then I want to use the copied sheet to run the rest of my code. (Sheet3 is the existing sheet, S_Temp is the copied sheet) Dim s_Temp as string Sheet3.copy Activesheet.name = S_Temp Sheets("S_Temp").Range("A1").value = "Test" How can I reference to the copied sheet?

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  • Testing variable types in Python

    - by Jasper
    Hello, I'm creating an initialising function for the class 'Room', and found that the program wouldn't accept the tests I was doing on the input variables. Why is this? def __init__(self, code, name, type, size, description, objects, exits): self.code = code self.name = name self.type = type self.size = size self.description = description self.objects = objects self.exits = exits #Check for input errors: if type(self.code) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 110' elif type(self.name) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 111' elif type(self.type) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 112' elif type(self.size) != type(int()): print 'Error found in module rooms.py!' print 'Error number: 113' elif type(self.description) != type(str()): print 'Error found in module rooms.py!' print 'Error number: 114' elif type(self.objects) != type(list()): print 'Error found in module rooms.py!' print 'Error number: 115' elif type(self.exits) != type(tuple()): print 'Error found in module rooms.py!' print 'Error number: 116' When I run this I get this error: Traceback (most recent call last): File "/Users/Jasper/Development/Programming/MyProjects/Game Making Challenge/Europa I/rooms.py", line 148, in <module> myRoom = Room(101, 'myRoom', 'Basic Room', 5, '<insert description>', myObjects, myExits) File "/Users/Jasper/Development/Programming/MyProjects/Game Making Challenge/Europa I/rooms.py", line 29, in __init__ if type(self.code) != type(str()): TypeError: 'str' object is not callable

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  • Error "initializer element is not constant" when trying to initialize variable with const

    - by tomlogic
    I get an error on line 6 (initialize my_foo to foo_init) of the following program and I'm not sure I understand why. typedef struct foo_t { int a, b, c; } foo_t; const foo_t foo_init = { 1, 2, 3 }; foo_t my_foo = foo_init; int main() { return 0; } Keep in mind this is a simplified version of a larger, multi-file project I'm working on. The goal was to have a single constant in the object file, that multiple files could use to initialize a state structure. Since it's an embedded target with limited resources and the struct isn't that small, I don't want multiple copies of the source. I'd prefer not to use: #define foo_init { 1, 2, 3 } I'm also trying to write portable code, so I need a solution that's valid C89 or C99. Does this have to do with the ORGs in an object file? That initialized variables go into one ORG and are initialized by copying the contents of a second ORG? Maybe I'll just need to change my tactic, and have an initializing function do all of the copies at startup. Unless there are other ideas out there?

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  • Setting variable to value of form [drupal 6]

    - by N Schleder
    I have this form $form['title'] = array( '#type' => 'textfield', '#title' => t('Title of Notice'), '#description' => t('Use_underscores_as_spaces'), '#size' => 30, // '#required' => TRUE ); and I want whatever the user types in to be the value of $test I've tried $test = $form['title']; which gives me $test = array also I've tried $test = current($form['title']); which gives me $test = textfield $form['values']['title'] doesn't work dont know what else to try

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