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  • NHibernate and MySql Keywords

    - by jalchr
    Why Nibernate HQL can not handle the following query: from Deal D where (D.ApprovalDate + INTERVAL 1 Year) < current_timestamp() < (D.RenewalDate + INTERVAL -1 Year) knowing that INTERVAL and YEAR are keywords in MySQL, so this is kind of mixing Sql within Hql (unless Hql can handle date functions like so and I don't know) . The dialect is MySQLDialect Its perfectly valid to execute this query SELECT '2005-01-01' + INTERVAL 1 Year;

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  • Pass windows authentication username to asp variable

    - by Darren Cook
    Hi, I have a site that processes orders taken by phone into a SQL database. Access to the portal uses Windows Authentication and I would like to pass the username of the order processor along with the order so that I can record who has taken the order. How can I pass the user name to a form element? The pages are written in classic asp. Thanks.

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  • You do not have sufficient permissions to access this page.

    - by WmasterJ
    I recently set up a local copy of Wordpress, added some content and created a child theme. Then I moved it to my webserver, changed the config file, changed the "localhost" occurences in my SQL file to my online URL. I also changed my database prefix from what I had locally on all tables and in the config file. Everything works well on the outside. But then as I log-in is get the: You do not have sufficient permissions to access this page.

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  • Criticise/Recommendations for my code

    - by aLk
    Before i go any further it would be nice to know if there is any major design flaws in my program so far. Is there anything worth changing before i continue? Model package model; import java.sql.*; import java.util.*; public class MovieDatabase { @SuppressWarnings({ "rawtypes", "unchecked" }) public List queryMovies() throws SQLException { Connection connection = null; java.sql.Statement statement = null; ResultSet rs = null; List results = new ArrayList(); try { DriverManager.registerDriver(new com.mysql.jdbc.Driver()); connection = DriverManager.getConnection("jdbc:mysql://localhost:3306/test", "root", "password"); statement = connection.createStatement(); String query = "SELECT * FROM movie"; rs = statement.executeQuery(query); while(rs.next()) { MovieBean bean = new MovieBean(); bean.setMovieId(rs.getInt(1)); bean.setTitle(rs.getString(2)); bean.setYear(rs.getInt(3)); bean.setRating(rs.getInt(4)); results.add(bean); } } catch(SQLException e) { } return results; } } Servlet public class Service extends HttpServlet { @SuppressWarnings("rawtypes") protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType("text/html"); PrintWriter out = response.getWriter(); out.println("Movies!"); MovieDatabase movies = new MovieDatabase(); try { List results = movies.queryMovies(); Iterator it = results.iterator(); while(it.hasNext()) { MovieBean movie = new MovieBean(); movie = (MovieBean)it.next(); out.println(movie.getYear()); } } catch(SQLException e) { } } } Bean package model; @SuppressWarnings("serial") public class MovieBean implements java.io.Serializable { protected int movieid; protected int rating; protected int year; protected String title; public MovieBean() { } public void setMovieId(int movieidVal) { movieid = movieidVal; } public void setRating(int ratingVal) { rating = ratingVal; } public void setYear(int yearVal) { year = yearVal; } public void setTitle(String titleVal) { title = titleVal; } public int getMovieId() { return movieid; } public int getRating() { return rating; } public int getYear() { return year; } public String getTitle() { return title; } }

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  • php parse error always on the last line

    - by is0lated
    I'm trying to read a comment that is stored in a mysql table. For some reason I always get a parse error on the last line of the file even if the last line is blank. I'm not sure if it's relevant but the connect.php works for putting the comment into the database. I'm using wampserver to host it and coding it by hand. I think that's it's something to do with the while loop, when I comment out the while(){ and the } near the end I just get a few missing variable errors as you would expect. I'm quite new to php coding so I'm pretty sure the problem will be something simple that I've either missed or not understood properly. Anyway, here's my code: <?php include "connect.php"; ?> <?php $sql = "SELECT * FROM main"; $result = mysql_query($sql) or die("Could not get posts from table"); while($rows=mysql_fetch_array($result)){ ?> <table bgcolor="green" align="center"> <tr> <td></td> </tr> <tr> <td><strong> <? echo $rows['name']; ?> </strong></td> </tr> <tr> <td> <? echo $rows['email']; ?> </td> </tr> <tr> <td> <? echo $rows['comment']; ?> </td> </tr> </table> <? } ?> Thanks for the help. :)

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  • how to solve syntax error in procedure in mysql?

    - by Shooter
    Hi all, i am executing a procedure in mysql, procedure is- delimiter $$ create procedure getFacility (in id int, out MyFacility VARCHAR(200)) begin select Facility into MyFacility from facilities where FacilityID = id ; end $$ delimiter ; and it is giving error below- Error Code : 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'end $$ delimiter' at line 1 (0 ms taken) how to solve this error? Thanks, Yugal

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  • @Resource annotation is null at run-time.

    - by Andrew
    I'm using GlassFish v3. The following field is declared in a class: @Resource private javax.sql.DataSource _data_source; The following is declare in web.xml: <data-source <namejava:app/env/data</name <class-namecom.mysql.jdbc.Driver</class-name <server-namelocalhost</server-name <port-number3306</port-number <usermyUser</user <passwordmyPass</password </data-source At run-time _data_source is empty. What am I doing wrong?

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  • Different databases using WCF dataservice

    - by espenk
    I have multiple SQL Server databases with the same schema. I would like to use one WCF data service (Rest service) to access the different databases. How can I accomplish this so the client can pass in the correct database name or connection string?

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  • Entity Framework 4 omits some associations during model generation

    - by kzen
    After creating an EF4 model from a SQL Server database I noticed that all the relationships of my Users table were not imported into the model as associations. All the other relationships were imported fine. My Users table has a PK userId which is a char(7) field and it is integrated into several other tables in the database as an FK but for some reason EF4 does not import these relationships as associations during the model generation process... Does anyone have any ideas why this would be happening?

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  • how to provide list of sheets of file in combo box ?

    - by angel ansari
    Hi, I have to load excel file into sql server i use window application so i select filepath in textbox when click button using fileopendialogbox my problem is that i want ot provide list of sheets of file in combo box. so user can select appropriate sheet to upload. Because it may possible that there are many sheets in file and tool doesn’t know which one to upload.

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  • PHP mysql - ...AND column='anything'... ?

    - by Nike
    Is there any way to check if a column is "anything"? The reason is that i have a searchfunction that get's an ID from the URL, and then it passes it through the sql algorithm and shows the result. But if that URL "function" (?) isn't filled in, it just searches for: ...AND column=''... and that doesn't return any results at all. I've tried using a "%", but that doesn't do anything. Any ideas?

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  • Facing problem in configuring Reporting Server

    - by idrees99
    Dear All, I am unable to configure reporting server with sql server 2005 express edition. I have posted the link of a screen shot which shows the status.when ever i go to configure the reporting services it gives me the following errors(see screen shot)...also unable to start the reporting services.It starts and then stopped automatically.... I am using windowsxp professional..... Need help... thanks. ![alt text][1] http://www.freeimagehosting.net/image.php?8977c7f37a.jpg

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  • mysql insert with auto-increment column

    - by czuroski
    Hello, I am trying to insert data into a mysql table from a csv file. I am using the infile sql command, but I am having trouble because the first column of the table is an id that is set as an auto increment field. what do I have to set my first column value to in order to get this to work, or can I do it at all? Thanks

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  • Blind Injection [closed]

    - by Ajay
    Blind SQL Injection Severity: High Test Type: Application Vulnerable URL: Remediation Tasks: Filter out hazardous characters from user input Variant 1 of 2 [ID=12654] The following changes were applied to the original request: • Set parameter 'nm's value to 'Demography'%20and%20'foobar'='foobar'

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  • Page not redirecting properly(php)

    - by user225269
    I want to do the login page this way so that I won't be having trouble posting the username in the userpage. But everytime I try to access login.php. I get an error in firefox, that the page is not redirecting properly. What do I do? This works when I separate them into two. Into something like, login.php and verifylogin.php as the form action. But if I do it like this, I get redirection errors: <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $uname = mysql_real_escape_string($_POST['username']); $pword = mysql_real_escape_string($_POST['password']); $SQL = "SELECT * FROM users WHERE username = '$uname' AND password = '$pword'"; $result = mysql_query($SQL); $num_rows = mysql_num_rows($result); if ($result) { if ($num_rows > 0) { session_start(); $_SESSION['login'] = "1"; header ("Location: userpage.php"); } else { session_start(); $_SESSION['login'] = ""; header ("Location: login.php"); } } else { $errorMessage = "Error logging on"; } ?> <tr> <form name="form1" method="post" action="login.php"> <td> <table> <tr> <td><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="username" type="text" id="username" maxlength="17"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="password" type="password" id="password" maxlength="17"></td> </tr> <td><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> please help, thanks.

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  • MySQL Queries using Doctrine & CodeIgniter

    - by 01010011
    Hi, How do I write plane SQL queries using Doctrine connection object and display the results? For example, how do I perform: SELECT * FROM table_name WHERE column_name LIKE '%anything_similar_to_this%'; using Doctrine something like this (this example does not work) $search_key = 'search_for_this'; $conn = Doctrine_Manager::connection(); $conn->execute('SELECT * FROM table_name WHERE column_name LIKE ?)', $search_key); echo $conn;

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  • How to output items in Order in MySQL?

    - by RailsRor
    I have a column called "menu_order" which has no default value. When I select the contents of this column using the following select statement: SELECT * FROM categories ORDER BY menu_order ASC It lists the category items that have nothing as their menu order first and then the one's that have 1's and 2's and 3's. Is there any way to prevent SQL from take nothing to come before numbers when I am trying to list things in order? So for example, if I have: cat_name | menu_order ---------------------- Lunch | 1 Dinner | And I perform my query, the output should be: Lunch Dinner Not: Dinner Lunch

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