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  • What does P mean in Sort(Expression<Func<T, P>> expr, ListSortDirection direction)?

    - by Grasshopper
    I am attempting to use the answer in post: How do you sort an EntitySet<T> to expose an interface so that I can sort an EntitySet with a Binding list. I have created the class below and I get the following compiler error: "The type or namespace 'P' could not be found (are you missing a using directive or assembly reference?). Can someone tell me what the P means and which namespace I need to include to get the method below to compile? I am very new to delegates and lamba expressions. Also, can someone confirm that if I create a BindingList from my EntitySet that any modifications I make to the BindingList will be made to the EntitySet? Basically, I have an EntitySet that I need to sort and make changes to. Then, I will need to persist these changes using the original Entity that the BindingList came from. public class EntitySetBindingWrapper<T> : BindingList<T> { public EntitySetBindingWrapper(BindingList<T> root) : base(root) { } public void Sort(Expression<Func<T, P>> expr, ListSortDirection direction) { if (expr == null) base.RemoveSortCore(); MemberExpression propExpr = expr as MemberExpression; if (propExpr == null) throw new ArgumentException("You must provide a property", "expr"); PropertyDescriptorCollection descriptorCol = TypeDescriptor.GetProperties(typeof(T)); IEnumerable<PropertyDescriptor> descriptors = descriptorCol.Cast<PropertyDescriptor>(); PropertyDescriptor descriptor = descriptors.First(pd => pd.Name == propExpr.Member.Name); base.ApplySortCore(descriptor, direction); } }

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  • Python sort 2-D list by time string

    - by Mark Kennedy
    How do I sort a multi dimensional list like this based on a time string? The sublists can be of different sizes (i.e. 4 and 5, here) I want to sort by comparing the first time string in each sublist (sublist[-4]) x = (['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['0690', '07:25AM', '09:19AM', 1, 4], ['0201', '08:50AM', '10:50AM', 1, 4], ['1166', '04:35PM', '06:36PM', 1, 4], ['0845', '05:40PM', '07:44PM', 1, 4], ['1267', '07:05PM', '09:07PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['8772', '0159', '12:33PM', '02:43PM', 1, 5], ['0888', '0570', '09:42PM', '12:20AM', 1, 5], ['2086', '2231', '04:10PM', '06:20PM', 1, 5]) The sorted result would be sortedX = (['0690', '07:25AM', '09:19AM', 1, 4], ['0201', '08:50AM', '10:50AM', 1, 4], ['1166', '04:35PM', '06:36PM', 1, 4], ['0845', '05:40PM', '07:44PM', 1, 4], ['1267', '07:05PM', '09:07PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['8772', '0159', '12:33PM', '02:43PM', 1, 5], ['2086', '2231', '04:10PM', '06:20PM', 1, 5], ['0888', '0570', '09:42PM', '12:20AM', 1, 5]) I tried the following: sortedX = sorted(x, key=lambda k : k[-4]) #k[-4] is the first time string and it works but it doesn't respect the sublist size ordering

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  • Sort Java List/Map by order in which items are in an XML File

    - by Brandon Smith
    Hello everyone, What I'm looking to do is to sorta a Java List or Map in the order the items are in a XML File. For Example I have a list of function names as so: functionOne functionThree functionTwo The XML File looks like this: <xml> <function>functionOne</function> <function>functionTwo</function> <function>functionThree</function> </xml> So I would like to sort the list so the function names are as so: functionOne functionTwo functionThree Now Im trying to do this for Variables as well, so there are around 500+ unique 'items'. Does anyone have any idea how I can go about doing this? Now for the file that determines that sort order doesn't have to be XML it just what I use the most, it can be anything that can get the job done. Thanks in advance for your time.

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  • I need to sort the facets that come back from SOLR by relevancy

    - by Pinguthepenguin
    I have within my SOLR index song objects which belong to a higher level album object. An example is shown below: <song> <album title>Blood Sugar Sex Magic</album title> <song title>Under the Bridge</song title> <description>A sad song about junkies</description> </song> What I can do at the moment is create a facet on the album title so that a search on songs will also show me what albums contain hits for that keyword. The default behaviour for SOLR is that the facets are shown in the order of most hits to least. However what I want to achieve is the facet list to be sorted according to the relevancy of the top hit for that album. For example a search on the word "sad" may show a facet with one hit for "Blood Sugar Sex Magic" and there may also be an album called "Sad Clown songs" where there are 10 hits. "Sad clown songs" will show as the first facet even though it may be that "Under the bridge" comes up as the most relevant song. My question is how can I get all the facets back but then have them ordered by the relevancy of the songs within them? If I would need to change or extend some underlying SOLR code what would that be? Thanks in advance.

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  • Best tree/heap data structure for fixed set of nodes with changing values + need top 20 values?

    - by user350139
    I'm writing something like a game in C++ where I have a database table containing the current score for each user. I want to read that table into memory at the start of the game, quickly change each user's score while the game is being played in response to what each user does, and then when the game ends write the current scores back to the database. I also want to be able to find the 20 or so users with the highest scores. No users will be added or deleted during the short period when the game is being played. I haven't tried it yet, but updating the database might take too much time during the period when the game is being played. Fixed set of users (might be 10,000 to 50,000 users) Will map user IDs to their score and other user-specific information. User IDs will be auto_increment values. If the structure has a high memory overhead that's probably not an issue. If the program crashes during gameplay it can just be re-started. Quickly get a user's current score. Quickly add to a user's current score (and return their current score) Quickly get 20 users with highest score. No deletes. No inserts except when the structure is first created, and how long that takes isn't critical. Getting the top 20 users will only happen every five or ten seconds, but getting/adding will happen much more frequently. If not for the last, I could just create a memory block equal to sizeof(user) * max(user id) and put each user at user id * sizeof(user) for fast access. Should I do that plus some other structure for the Top 20 feature, or is there one structure that will handle all of this together?

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  • On counting pairs of words that differ by one letter

    - by Quintofron
    Let us consider n words, each of length k. Those words consist of letters over an alphabet (whose cardinality is n) with defined order. The task is to derive an O(nk) algorithm to count the number of pairs of words that differ by one position (no matter which one exactly, as long as it's only a single position). For instance, in the following set of words (n = 5, k = 4): abcd, abdd, adcb, adcd, aecd there are 5 such pairs: (abcd, abdd), (abcd, adcd), (abcd, aecd), (adcb, adcd), (adcd, aecd). So far I've managed to find an algorithm that solves a slightly easier problem: counting the number of pairs of words that differ by one GIVEN position (i-th). In order to do this I swap the letter at the ith position with the last letter within each word, perform a Radix sort (ignoring the last position in each word - formerly the ith position), linearly detect words whose letters at the first 1 to k-1 positions are the same, eventually count the number of occurrences of each letter at the last (originally ith) position within each set of duplicates and calculate the desired pairs (the last part is simple). However, the algorithm above doesn't seem to be applicable to the main problem (under the O(nk) constraint) - at least not without some modifications. Any idea how to solve this?

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  • Initial state of autoCreateRowSorter in Swing JTable

    - by Nazgulled
    I have this JTable on my Swing app with the autoCreateRowSorter enabled. My table only has 3 columns, two strings and one int, it works well for all of them when I click the column headers. However, I'm looking for way to do it programatically. I wanted to set the "initial state" for this table. With the Windows look and feel, the column header (when sorted) has a little arrow showing the sort order. But at startup that doesn't show, I have to do one initial click. How can I do that by code?

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  • MySQL - Selecting the top occuring entries

    - by RC
    Hi, Should be a simple one. Database is mydb. One of the columns is mydata. What SELECT query do I need in order to select the top 3 occuring results from mydata, but sorted alphabetically? For example, if my data is this: mydata ====== kilo (x 1 occurrence) lima (x 9 occurrences) golf (x 5 occurrences) echo (x 9 occurrences) zulu (x 8 occurrences) How do I get it to return "echo, lima, zulu", which are the top three frequently occurring entries sorted alphabetically? Thanks! EDIT: Just to add, they need to be distinct entries. Thanks!

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  • Alternatives to sign() in sqlite for custom order by

    - by Pentium10
    I have a string column which contains some numeric fields, but a lot are 0, empty string or null. The rest are numbers having different range, all positive. I tried to create a custom order by. The order would be done by two fields. First I would like to order the fields that have this number 0 and then sort by name. So something this would work: select * from table order by sign(referenceid) desc, name asc; But Sqlite lacks the sign() -1/0/1 function, and I am on Android and I can't create user defined functions. What other options I have to get this sort done.

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  • Stable/repeatable random sort (MySQL, Rails)

    - by Matt Rogish
    I'd like to paginate through a randomly sorted list of ActiveRecord models (rows from MySQL database). However, this randomization needs to persist on a per-session basis, so that other people that visit the website also receive a random, paginate-able list of records. Let's say there are enough entities (tens of thousands) that storing the randomly sorted ID values in either the session or a cookie is too large, so I must temporarily persist it in some other way (MySQL, file, etc.). Initially I thought I could create a function based on the session ID and the page ID (returning the object IDs for that page) however since the object ID values in MySQL are not sequential (there are gaps), that seemed to fall apart as I was poking at it. The nice thing is that it would require no/minimal storage but the downsides are that it is likely pretty complex to implement and probably CPU intensive. My feeling is I should create an intersection table, something like: random_sorts( sort_id, created_at, user_id NULL if guest) random_sort_items( sort_id, item_id, position ) And then simply store the 'sort_id' in the session. Then, I can paginate the random_sorts WHERE sort_id = n ORDER BY position LIMIT... as usual. Of course, I'd have to put some sort of a reaper in there to remove them after some period of inactivity (based on random_sorts.created_at). Unfortunately, I'd have to invalidate the sort as new objects were created (and/or old objects being removed, although deletion is very rare). And, as load increases the size/performance of this table (even properly indexed) drops. It seems like this ought to be a solved problem but I can't find any rails plugins that do this... Any ideas? Thanks!!

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  • How to sort & Group in Android?

    - by crickpatel0024
    I have ArrayList and I want to sort and group all data by header in Android. How it is possible in Android? please help me.below me from owner And set header Me And Joe Manager From owner And set Header in listview. How to do that in Android? My code in below:: public class Request extends Activity { private String assosiatetoken; private ArrayList<All_Request_data_dto> list = new ArrayList<All_Request_data_dto>(); ListView lv; Button back; private Spinner spndata; String[] reqspinner = { "Request Date", "Last Update", "Type", "Owner", "State" }; ArrayAdapter<String> adapter; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.request); assosiatetoken = MyApplication.getToken(); new doinbackground(this).execute(); back = (Button) findViewById(R.id.button1); spndata = (Spinner) findViewById(R.id.list_all_quize_req); adapter = new ArrayAdapter<String>(this, android.R.layout.simple_spinner_item, reqspinner); spndata.setAdapter(adapter); lv = (ListView) findViewById(R.id.listrequestdata); lv.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> a, View v, int position, long id) { Intent edit = new Intent(Request.this, Request_webview.class); // edit.putExtra("Cat_url", url_link); startActivity(edit); } }); spndata.setOnItemSelectedListener(new OnItemSelectedListener() { public void onItemSelected(AdapterView<?> arg0, View arg1, int position, long arg3) { switch (position) { case 0: list = DBAdpter.requestUserData(assosiatetoken); Collections.sort(list, byDate1); // Collections.reverse(list); for (int i = 0; i < list.size(); i++) { if (list.get(i).submitDate != null) { lv.setAdapter(new MyListAdapter( getApplicationContext(), list)); } } break; case 1: list = DBAdpter.requestUserData(assosiatetoken); Collections.sort(list, byDate); for (int i = 0; i < list.size(); i++) { if (list.get(i).lastModifiedDate != null) { lv.setAdapter(new MyListAdapter( getApplicationContext(), list)); } } break; case 2: list = DBAdpter.requestUserData(assosiatetoken); Collections.sort(list, byDate3); // Collections.reverse(list); for (int i = 0; i < list.size(); i++) { if (list.get(i).state != null) { lv.setAdapter(new MyListAdapter( getApplicationContext(), list)); } } break; case 3: list = DBAdpter.requestUserData(assosiatetoken); for (int i = 0; i < list.size(); i++) { lv.setAdapter(new MyListAdapter( getApplicationContext(), list)); } break; default: break; } } public void onNothingSelected(AdapterView<?> arg0) { } }); back.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { finish(); } }); } static final Comparator<All_Request_data_dto> byDate = new Comparator<All_Request_data_dto>() { SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a"); public int compare(All_Request_data_dto ord1, All_Request_data_dto ord2) { java.util.Date d1 = null; java.util.Date d2 = null; try { d1 = sdf.parse(ord1.lastModifiedDate); d2 = sdf.parse(ord2.lastModifiedDate); } catch (java.text.ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } return (d1.getTime() > d2.getTime() ? -1 : 1); // descending // return (d1.getTime() > d2.getTime() ? 1 : -1); //ascending } }; static final Comparator<All_Request_data_dto> byDate1 = new Comparator<All_Request_data_dto>() { SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a"); public int compare(All_Request_data_dto ord1, All_Request_data_dto ord2) { java.util.Date d1 = null; java.util.Date d2 = null; try { d1 = sdf.parse(ord1.submitDate); d2 = sdf.parse(ord2.submitDate); } catch (java.text.ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } return (d1.getTime() > d2.getTime() ? -1 : 1); // descending // return (d1.getTime() > d2.getTime() ? 1 : -1); //ascending } }; static final Comparator<All_Request_data_dto> byDate3 = new Comparator<All_Request_data_dto>() { public int compare(All_Request_data_dto ord1, All_Request_data_dto ord2) { String d1 = null; String d2 = null; d1 = ord1.state; d2 = ord2.state; return d1.compareToIgnoreCase(d2); } }; class doinbackground extends AsyncTask<Void, Void, Void> { ProgressDialog pd; private Context ctx; public doinbackground(Context c) { ctx = c; } @Override protected void onPreExecute() { super.onPreExecute(); pd = new ProgressDialog(ctx); pd.setMessage("Loading..."); pd.show(); } @Override protected Void doInBackground(Void... Params) { return null; } @Override protected void onPostExecute(Void result) { super.onPostExecute(result); pd.cancel(); } } public class MyListAdapter extends BaseAdapter { private ArrayList<All_Request_data_dto> list; public MyListAdapter(Context mContext, ArrayList<All_Request_data_dto> list) { this.list = list; } public int getCount() { return list.size(); } public All_Request_data_dto getItem(int position) { return list.get(position); } public long getItemId(int position) { return position; } public View getView(int position, View convertView, ViewGroup parent) { // if (convertView == null) { LayoutInflater inflator = (LayoutInflater) getSystemService(LAYOUT_INFLATER_SERVICE); convertView = inflator.inflate(R.layout.custom_request_data, null); TextView req_id = (TextView) convertView.findViewById(R.id.req_txt); TextView date = (TextView) convertView.findViewById(R.id.date_txt); TextView owner = (TextView) convertView .findViewById(R.id.owner_txt); TextView state = (TextView) convertView .findViewById(R.id.state_txt); req_id.setText(list.get(position).requestId + " - " + list.get(position).title); date.setText(list.get(position).lastModifiedDate + " - " + list.get(position).submitDate); owner.setText(list.get(position).owner); state.setText(list.get(position).state); // } return convertView; } } }

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  • Two-pass multi way merge sort?

    - by Nimesh
    If I have a relation (SQL) that does not fit in memory and I want to sort the relation using TPMMS (Two-pass multi-way merge sort method). How would I divide the table in sub tables (and how many) that can fit in memory and than merge them? Let's say I am using C#.

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  • How to fill a dataset after getting a gridview?

    - by user175084
    I have a gridview which has many columns.. the columns are got separately and displayed in a gridview. now i need to sort this gridview but i cannot do that.... i have found a way but i will need to get the gridview in a datatable or a dataset.... is there a a way to do this? DataSet ds= new DataSet(); ds = Gridview1.???? please help..

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  • SSRS - Sort table based on column value

    - by Ehsan
    I am trying to sort the following table: hYear hSale ------------------------------------ [year] =Count(Fields!sale.Value) The table only has one row group (year) and no column group. I'd like to: -initially sort the table based on the calculated value; is it possible? -add interactive sort to calculated column based on the value. I assume I should sort 'Detail rows', but what will be the sort expression?

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  • Combining entries, filtering of Python dictionaries

    - by matt
    I have two large lists that are filled with dictionaries. I need to combine the entries if a value from dict2==dict1 and place the newly combined matches somewhere else. I'm having trouble explaining it. List one contains: {'keyword':value, 'keyword2':value2} List two: {'keyword2':value2, 'keyword3':value3} I want a new list with dictionaries including keyword1, keyword2, and keyword3 if both lists share the same 'keyword2' value. What's the best way to do this? When I try, I only come up with tons of nested for loops. Thanks

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  • getting rid of repeated customer id's in mysql query

    - by bsandrabr
    I originally started by selecting customers from a group of customers and then for each customer querying the records for the past few days and presenting them in a table row. All working fine but I think I might have got too ambitious as I tried to pull in all the records at once having heard that mutiple queries are a big no no. here is the mysqlquery i came up with to pull in all the records at once SELECT morning, afternoon, date, date2, fname, lname, customers.customerid FROM customers LEFT OUTER JOIN attend ON ( customers.customerid = attend.customerid ) RIGHT OUTER JOIN noattend ON ( noattend.date2 = attend.date ) WHERE noattend.date2 BETWEEN '$date2' AND '$date3' AND DayOfWeek( date2 ) %7 >1 AND group ={$_GET['group']} ORDER BY lname ASC , fname ASC , date2 DESC tables are customer-customerid,fname,lname attend-customerid,morning,afternoon,date noattend-date2 (a table of all the days to fill in the blanks) Now the problem I have is how to start a new row in the table when the customer id changes My query above pulls in customer 1 morning 2 customer 1 morning 1 customer 2 morning 2 customer 2 morning 1 whereas I'm trying to get customer1 morning2 morning1 customer2 morning2 morning1 I dont know whether this is possible in the sql or more likely in the php

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  • matlab: simple matrix filtering - group size

    - by Art
    I have a huuuge matrix storing information about X and Y coordinates of multiple particle trajectories , which in simplified version looks like that: col 1- track number; col 2- frame number; col 2- coordinate X; col 3- coordinate Y for example: A = 1 1 5.14832 3.36128 1 2 5.02768 3.60944 1 3 4.85856 3.81616 1 4 5.17424 4.08384 2 1 2.02928 18.47536 2 2 2.064 18.5464 3 1 8.19648 5.31056 3 2 8.04848 5.33568 3 3 7.82016 5.29088 3 4 7.80464 5.31632 3 5 7.68256 5.4624 3 6 7.62592 5.572 Now I want to filter out trajectories shorter than lets say 2 and keep remaining stuff like (note renumbering of trajectories): B = 1 1 5.14832 3.36128 1 2 5.02768 3.60944 1 3 4.85856 3.81616 1 4 5.17424 4.08384 2 1 8.19648 5.31056 2 2 8.04848 5.33568 2 3 7.82016 5.29088 2 4 7.80464 5.31632 2 5 7.68256 5.4624 2 6 7.62592 5.572 How to do it efficiently? I can think about some ideas using for loop and vertcat, but its the slowest solution ever :/ Thanks!

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  • How can I do a multi level parent-child sort using Linq?

    - by Tenacious T
    How can I do a multi-level parent-child sort using Linq if I have a table structure like the one below: [Table: Sections] Id Seq Name ParentSectionId 1 1 TOP NULL 2 1 AAAA 1 3 2 SSSS 1 4 3 DDDD 1 5 1 SectionA1 2 6 2 SectionA2 2 7 1 SectionS1 3 8 3 ASummary 2 Expected sort result: TOP AAAA SectionA1 SectionA2 ASummary SSSS SectionS1 DDDD

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  • 2 compareTo method overriden in the same class definition, how could I force to use the second?

    - by jayjaypg22
    I want to sort a list List<Blabla> donnees by a criterion on one of its field. My problem is that compareTo is already overriden for this Class. So I've got something like : Blabla { public int compareTo(Object other) { ... } public int compareTo(Blabla other) { ... } } In a business layer class I call : Business { method (){ Collections.sort(List<Blabla > donnees); } } But this call N°1 compareTo method with object parameter. How could I sort my list with the N°2 method?

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  • Django: ordering numerical value with order_by

    - by h3
    I'm in a situation where I must output a quite large list of objects by a CharField used to store street addresses. My problem is, that obviously the data is ordered by ASCII codes since it's a Charfield, with the predictable results .. it sort the numbers like this; 1, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 2, 20, 21.... Now the obvious step would be to change the Charfield the proper field type (IntegerField let's say), however it cannot work since some address might have apartments .. like "128A". I really don't know how I can order this properly ..

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  • Mysql select most frequent and sort alphabetically

    - by user2605793
    I am trying to select the most common 100 names from a table then display the list showing the names and count. I want the user to be able to re-sort the list alphabetically rather than based on count. I thought the following code would do it. It works for the default sort by count but fails on the sort alphabetically. The line "$count = mysql_num_rows($table);" gives an error: mysql_num_rows() expects parameter 1 to be resource, boolean given. Any help would be greatly appreciated. // Get most popular surnames echo '<h2>Most Common Surnames</h2>'; if ($sort == "") { // default sort by count echo '<a href="http://mysite/names.php?id='.$id.'&sort=name">Sort by name</a><br>'; $query = "SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100"; } else { // sort alphabetically echo '<a href="http://mysite/names.php?id='.$id.'">Sort by count</a><br>'; $query = "SELECT * FROM ( SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100) AS alpha ORDER BY family_name"; } $table = mysql_query($query); $count = mysql_num_rows($table); $tot = 0; $i = 0; echo '<table><tr>'; while ($tot < $count2) { $rec2 = mysql_fetch_array($table2); echo '<td>'.$rec2[0].'</td><td>'.$rec2[1].'</td><td width="40">&nbsp;</td><td>'; if ($i++ == 6) { echo '</tr><tr>'; $i = 0; } $tot++; } echo '</tr></table><br>'; UPDATE: I needed to add "AS alpha" to give the outer select a unique name. (alpha is just a random name I made up.) It now works perfectly. Code updated for the benefit of any others who need something similar.

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