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  • Linear feedback shift register?

    - by Mattia Gobbi
    Lately I bumped repeatedly into the concept of LFSR, that I find quite interesting because of its links with different fields and also fascinating in itself. It took me some effort to understand, the final help was this really good page, much better than the (at first) cryptic wikipedia entry. So I wanted to write some small code for a program that worked like a LFSR. To be more precise, that somehow showed how a LFSR works. Here's the cleanest thing I could come up with after some lenghtier attempts (Python): def lfsr(seed, taps): sr, xor = seed, 0 while 1: for t in taps: xor += int(sr[t-1]) if xor%2 == 0.0: xor = 0 else: xor = 1 print xor sr, xor = str(xor) + sr[:-1], 0 print sr if sr == seed: break lfsr('11001001', (8,7,6,1)) #example I named "xor" the output of the XOR function, not very correct. However, this is just meant to show how it circles through its possible states, in fact you noticed the register is represented by a string. Not much logical coherence. This can be easily turned into a nice toy you can watch for hours (at least I could :-) def lfsr(seed, taps): import time sr, xor = seed, 0 while 1: for t in taps: xor += int(sr[t-1]) if xor%2 == 0.0: xor = 0 else: xor = 1 print xor print time.sleep(0.75) sr, xor = str(xor) + sr[:-1], 0 print sr print time.sleep(0.75) Then it struck me, what use is this in writing software? I heard it can generate random numbers; is it true? how? So, it would be nice if someone could: explain how to use such a device in software development come up with some code, to support the point above or just like mine to show different ways to do it, in any language Also, as theres not much didactic stuff around about this piece of logic and digital circuitry, it would be nice if this could be a place for noobies (like me) to get a better understanding of this thing, or better, to understand what it is and how it can be useful when writing software. Should have made it a community wiki? That said, if someone feels like golfing... you're welcome.

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  • Accessing Virtual Host from outside LAN

    - by Ray
    I'm setting up a web development platform that makes things as easy as possible to write and test all code on my local machine, and sync this with my web server. I setup several virtual hosts so that I can access my projects by typing in "project" instead of "localhost/project" as the URL. I also want to set this up so that I can access my projects from any network. I signed up for a DYNDNS URL that points to my computer's IP address. This worked great from anywhere before I setup the virtual hosts. Now when I try to access my projects by typing in my DYNDNS URL, I get the 403 Forbidden Error message, "You don't have permission to access / on this server." To setup my virtual hosts, I edited two files - hosts in the system32/drivers/etc folder, and httpd-vhosts.conf in the Apache folder of my WAMP installation. In the hosts file, I simply added the server name to associate with 127.0.0.1. I added the following to the http-vhosts.conf file: <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot "c:/wamp/www/ladybug" ServerName ladybug ErrorLog "logs/your_own-error.log" CustomLog "logs/your_own-access.log" common </VirtualHost> <VirtualHost *:80> ServerAdmin webmaster@localhost DocumentRoot "c:/wamp/www" ServerName localhost ErrorLog "logs/localhost-error.log" CustomLog "logs/localhost-access.log" common </VirtualHost> Any idea why I can't access my projects from typing in my DYNDNS URL? Also, is it possible to setup virtual hosts so that when I type in http://projects from a random computer outside of my network, I access url.dyndns.info/projects (a.k.a. my WAMP projects on my home computer)? Help is much appreciated, thanks!

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  • Wordpress.. Is it a CMS?

    - by madcolor
    I recently was contacted by a client who simply wanted to increase their organic rankings in Google. My approach was to do the following: A) Take them off of their overpriced host and move them to a nicer, cheaper, more feature-rich hosting solution which included a simple Wordpress install. B) Apply a theme to WordPress which followed the look and feel of their existing website. C) Train my client on how to login to their copy of Wordpress and create/manage pages/posts. This took me very little time.. Most of the work in converting asp forms into php and tweaking a theme to fit their design. Now my client is able to create/manage as many pages or posts as they desire. I believe, for this purpose, Worpress was the easiest solution. Would you categorize Wordpress as a CMS? Similar: http://stackoverflow.com/questions/250880/is-there-any-cms-better-than-wordpress-or-should-i-roll-my-own http://stackoverflow.com/questions/1101818/wordpress-as-a-cms-option http://stackoverflow.com/questions/490899/which-cms-to-choose http://stackoverflow.com/questions/629203/is-it-advisable-to-use-wordpress-as-cms-closed http://stackoverflow.com/questions/1451326/is-wordpress-good-for-building-a-large-cms-site-with-many-pages-about-over-100-00 External: http://codex.wordpress.org/User%3ALastnode/Wordpress%5FCMS http://wordpress.org/development/2009/11/wordpress-wins-cms-award/

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  • How to rename an existing Grails application

    - by Johan Pelgrim
    Hi there, Does anybody know how to (easily) "rename" an existing grails application? I'm running into this because my PaaS provider does not allow me to delete a subscription... So I want to deploy my application under a different name. Of course, I can do this manually, but I think it might be a useful 'top-level' script (i.e. "grails rename-app newappname") Manual hints: When I do a "grails create-app myappname" I can see the myappname exists in the following files (and filenames)... Of course this is done by the create-app script, which replaces @...@ tokens in the template. I guess once they are replaced, it's not trivial to do a rename. ./.project: <name>myappname</name> ./application.properties:app.name=myappname ./build.xml:<project xmlns:ivy="antlib:org.apache.ivy.ant" name="myappname" default="test"> ./ivy.xml: <info organisation="org.example" module="myappname"/> ./myappname-test.launch:<stringAttribute key="org.eclipse.jdt.launching.PROJECT_ATTR" value="myappname"/> ./myappname.launch:<listEntry value="/myappname"/> ./myappname.launch:<listEntry value="<?xml version="1.0" encoding="UTF-8"?> <runtimeClasspathEntry containerPath="org.eclipse.jdt.launching.JRE_CONTAINER" javaProject="myappname" path="1" type="4"/> "/> ./myappname.launch:<stringAttribute key="org.eclipse.jdt.launching.PROJECT_ATTR" value="myappname"/> ./myappname.launch:<stringAttribute key="org.eclipse.jdt.launching.VM_ARGUMENTS" value="-Dbase.dir="${project_loc:myappname}" -Dserver.port=8080 -Dgrails.env=development"/> ./myappname.tmproj: <string>myappname.launch</string> And of course... the top-level directory name is "myappname" Any hints, or information about ongoing initiatives in this area are welcome Greetz, Johan

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  • DAL Layer : EF 4.0 or Normal Data access layer with Stored Procedure

    - by Harryboy
    Hello Experts, Application : I am working on one mid-large size application which will be used as a product, we need to decide on our DAL layer. Application UI is in Silverlight and DAL layer is going to be behind service layer. We are also moving ahead with domain model, so our DB tables and domain classes are not having same structure. So patterns like Data Mapper and Repository will definitely come into picture. I need to design DAL Layer considering below mentioned factors in priority manner Speed of Development with above average performance Maintenance Future support and stability of the technology Performance Limitation : 1) As we need to strictly go ahead with microsoft, we can not use NHibernate or any other ORM except EF 4.0 2) We can use any code generation tool (Should be Open source or very cheap) but it should only generate code in .Net, so there would not be any licensing issue on per copy basis. Questions I read so many articles about EF 4.0, on outset it looks like that it is still lacking in features from NHibernate but it is considerably better then EF 1.0 So, Do you people feel that we should go ahead with EF 4.0 or we should stick to ADO .Net and use any code geneartion tool like code smith or any other you feel best Also i need to answer questions like what time it will take to port application from EF 4.0 to ADO .Net if in future we stuck up with EF 4.0 for some features or we are having serious performance issue. In reverse case if we go ahead and choose ADO .Net then what time it will take to swith to EF 4.0 Lastly..as i was going through the article i found the code only approach (with POCO classes) seems to be best suited for our requirement as switching is really easy from one technology to other. Please share your thoughts on the same and please guide on the above questions

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  • Working for free

    - by truncate
    Finances are making me take an extended period off of my college education. In my current state, I don't feel fully qualified to be employed by an iPhone software company. While I work on getting things back together, I'd like to try an work for a software company for free in my local area (I'm going to college out of state and have to move back as well). The economy has forced employers to be very picky about who they hire, if any at all. Since I'd like to continue refining my abilities, I was wondering on what the consensus is on working for free. It can't be considered an internship, as I would no longer be in school..., I guess an apprenticeship is more appropriate. Like I said, I don't think I'm qualified to be paid for my services, and I don't want to be. I just don't know how to ask, or if it's even appropriate to ask them to show me how to develop software in the real world. My thinking is that they would be willing to get some work done for free and if I prove myself, they could hire me. If not, there was no major loss. They get some free development, and lose a bit of time helping show me the ropes. I get either a job, or valuable experience that I need. The other alternative is that I try to work out things by myself on the iPhone platform, but that sounds terrifying. I appreciate any input the community has to offer.

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  • Mac CoreLocation Services does not ask for permissions

    - by Ryan Nichols
    I'm writing a Mac App that needs to use CoreLocation services. The code and location works fine, as long as I manually authenticate the service inside the security preference pane. However the framework is not automatically popping up with a permission dialog. The documentation states: Important The user has the option of denying an application’s access to the location service data. During its initial uses by an application, the Core Location framework prompts the user to confirm that using the location service is acceptable. If the user denies the request, the CLLocationManager object reports an appropriate error to its delegate during future requests. I do get an error to my delegate, and the value of +locationServicesEnabled is correct on CLLocationManager. The only part missing is the prompt to the user about permissions. This occurs on my development MPB and a friends MBP. Neither of us can figure out whats wrong. Has anyone run into this? Relevant code: _locationManager = [CLLocationManager new]; [_locationManager setDelegate:self]; [_locationManager setDesiredAccuracy:kCLLocationAccuracyKilometer]; ... [_locationManager startUpdatingLocation]; UPDATE: Answer It seems there is a problem with Sandboxing in which the CoreLocation framework is not allowed to talk to com.apple.CoreLocation.agent. I suspect this agent is responsible for prompting the user for permissions. If you add the Location Services Entitlement (com.apple.security.personal-information.location) it only gives your app the ability to use the CL framework. However you also need access to the CoreLocation agent to ask the user for permissions. You can give your app access by adding the entitlement 'com.apple.security.temporary-exception.mach-lookup.global-name' with a value of 'com.apple.CoreLocation.agent'. Users will be prompted for access automatically like you would expect. I've filed a bug to apple on this already.

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  • eclipse django using wrong settings.py in pythonpath

    - by user1290264
    I have pydev/django installed in eclipse, and it runs fine. However, after adding a second django project to eclipse and running the server ('http://127.0.0.1:8000') the pythonpath seems to be stuck on project2 even when I run project1. As a summary, I have two django projects: project1, project2. When I run the django server for project1 I get: Validating models... 0 errors found Django version 1.5, using settings 'project1.settings' Development server is running at 'http://127.0.0.1:8000/' Quit the server with CTRL-BREAK. The above seems to suggest that django is using the correct settings file; however, when I go to 'http://127.0.0.1:8000/' it displays the urls from project2. Also, if I go to 'http://127.0.0.1:8000/admin' the models are getting pulled from the sqlite.db file in project2 as well. I've even tried removing project2 from eclipse entirely and now at 'http://127.0.0.1:8000/admin' I get this error: Python Path: ['C:\Users\Brad\workspaces\In Progress\project2', 'C:\Users\Brad\workspaces\In Progress\project2', 'C:\Python27\DLLs', 'C:\Python27\lib', 'C:\Python27\lib\plat-win', 'C:\Python27\lib\lib-tk', 'C:\Python27', 'C:\Python27\lib\site-packages', 'C:\Windows\system32\python27.zip'] If I run the server on a different port with project1 the path seems to be fine: runserver 7000 --noreload Then 'http://127.0.0.1:7000/' uses project1's paths, but it doesn't seem like I should have to do this. Note: I have setup the run configurations as correctly as I know how. In the main tab, the project and main module both point to the correct project (project1), and the "PYTHONPATH that will be used in the run:" includes project1. Also, I have cleared my browser history, cookies, and everything that chrome would let me delete.

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  • ruby on rails delajed_job failing with rvm

    - by mottalrd
    I have delayed_job installed and I start the daemon to run the jobs with this ruby script require 'rubygems' require 'daemon_spawn' $: << '.' RAILS_ROOT = File.expand_path(File.join(File.dirname(__FILE__), '..')) class DelayedJobWorker < DaemonSpawn::Base def start(args) ENV['RAILS_ENV'] ||= args.first || 'development' Dir.chdir RAILS_ROOT require File.join('config', 'environment') Delayed::Worker.new.start end def stop system("kill `cat #{RAILS_ROOT}/tmp/pids/delayed_job.pid`") end end DelayedJobWorker.spawn!(:log_file => File.join(RAILS_ROOT, "log", "delayed_job.log"), :pid_file => File.join(RAILS_ROOT, 'tmp', 'pids', 'delayed_job.pid'), :sync_log => true, :working_dir => RAILS_ROOT) If I run the command with rvmsudo it works perfectly If I simply use the ruby command without rvm it fails and this is the output, but I have no idea why this happens. Could you give me some clue? Thank you user@mysystem:~/redeal.it/application$ ruby script/delayed_job start production /usr/local/rvm/gems/ruby-1.9.3-p194/gems/daemon-spawn-0.4.2/lib/daemon_spawn.rb:16:in `kill': Operation not permitted (Errno::EPERM) from /usr/local/rvm/gems/ruby-1.9.3-p194/gems/daemon-spawn-0.4.2/lib/daemon_spawn.rb:16:in `alive?' from /usr/local/rvm/gems/ruby-1.9.3-p194/gems/daemon-spawn-0.4.2/lib/daemon_spawn.rb:125:in `alive?' from /usr/local/rvm/gems/ruby-1.9.3-p194/gems/daemon-spawn-0.4.2/lib/daemon_spawn.rb:176:in `block in start' from /usr/local/rvm/gems/ruby-1.9.3-p194/gems/daemon-spawn-0.4.2/lib/daemon_spawn.rb:176:in `select' from /usr/local/rvm/gems/ruby-1.9.3-p194/gems/daemon-spawn-0.4.2/lib/daemon_spawn.rb:176:in `start' from /usr/local/rvm/gems/ruby-1.9.3-p194/gems/daemon-spawn-0.4.2/lib/daemon_spawn.rb:165:in `spawn!' from script/delayed_job:37:in `<main>'

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  • Animation not playing

    - by Tate Allen
    Hello again, I didn't say this last time but I am relatively new to iPhone programming and extremely new to iPhone game development so bear with me. In my game, when I tilt the device, the character moves and faces the correct direction, but does not animate. I am using an animated UIImageView. Here is the code: float newX = character.center.x + (accel.x * 12); if (newX 30 && newX < 290) character.center = CGPointMake(newX, character.center.y); if (accel.x < 0) { NSArray *imgArray = [[NSArray alloc] initWithObjects: [UIImage imageNamed:@"run3left.png"], [UIImage imageNamed:@"run1left.png"], [UIImage imageNamed:@"run2left.png"], [UIImage imageNamed:@"run1left.png"], nil]; character.animationImages = imgArray; character.animationDuration = 0.5; character.contentMode = UIViewContentModeBottomLeft; [self.view addSubview:character]; [character startAnimating]; } if (accel.x > 0) { NSArray *imgArray = [[NSArray alloc] initWithObjects: [UIImage imageNamed:@"run3.png"], [UIImage imageNamed:@"run1.png"], [UIImage imageNamed:@"run2.png"], [UIImage imageNamed:@"run1.png"], nil]; character.animationImages = imgArray; character.animationDuration = 0.5; character.contentMode = UIViewContentModeBottomLeft; [self.view addSubview:character]; [character startAnimating]; } }

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  • Line Break in XML?

    - by ew89
    Hello, I'm a beginner in web development, and I'm trying to insert line breaks in my XML file. This is what my XML looks like: Song Title Lyrics <song> <title>Song Title</title> <lyric>Lyrics</lyric> <song> <title>Song Title</title> <lyric>Lyrics</lyric> <song> <title>Song Title</title> <lyric>Lyrics</lyric> I want to have line breaks in between the sentences for the lyrics. I tried everything from /n, and other codes similar to it, PHP parsing, etc., and nothing works! Have been googling online for hours and can't seem to find the answer. I'm using the XML to insert data to an HTML page using Javascript. Does anyone know how to solve this problem? Thanks before :)

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  • Ways to gain a deeper understanding of programming concepts?

    - by MrPlow
    I'm a marketer and have been messing around in PHP/MySQL for years. Recently (the last several months) I've been making my own scripts/programs in Python and I've really enjoyed the whole problem solving process. I've read(skimmed) some books and understand the basics of OOP, polymorphism, etc.. I have a general interest in AI and Natural Language in particular but it seems these things require a masters in Computer Science. My knowledge of math is poor. The last class I took was calculus, and I've forgotten the majority of it. Basically I'm looking for things to learn that will help me think in a more analytic way, and maybe see solutions where I didn't before. Improving my ability to program in Python would be nice too. I don't need to learn a specific language or something for employment, just enjoyment. Although my work often involves web development so some utility would be nice. I don't like learning concepts by just reading them. I need to apply them, even if the examples are contrived. A recommendation of a couple good books or other resources would be nice. :) Apologies if this is too vague/misplaced...

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  • PHP str_replace and preg_replace work on one server but not another

    - by retailevolved
    I have a simple function on a php page that takes a url such as: http://myurl.com/mypage.html?param1=value1 and converts it to: http://myurl.com/searchpage.html?param1=value1 All it does it swap out the page.html portion. To do this, I use the following: $currentUrl = $this-getCurrentUrl(); // Grabs the current url, i.e 'http://myurl.com/mypage.html?param1=value1' // Derive a search pattern from the current url $pattern = "/" . str_replace(array("/", ".", "-"), array("\\/", "\\.", "\\-"), $currentUrl) . "/"; // get rid of the 'mypage.html' $newUrl = preg_replace($pattern, 'http://myurl.com/', $currentUrl); // replace the question mark with the correct page $newUrl = str_replace("/?", "/searchpage.html?", $newUrl); The above code is not the exact code but is a good representation. It works beautifully on one server, but when I push to production, the preg_replace does not work. I originally attempted to use str_replace. It also works on my local development machine, but not on the production server. I have confirmed that the URL variables are coming in correctly. Any ideas?

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  • Rails: Oracle constraint violation

    - by justinbach
    I'm doing maintenance work on a Rails site that I inherited; it's driven by an Oracle database, and I've got access to both development and production installations of the site (each with its own Oracle DB). I'm running into an Oracle error when trying to insert data on the production site, but not the dev site: ActiveRecord::StatementInvalid (OCIError: ORA-00001: unique constraint (DATABASE_NAME.PK_REGISTRATION_OWNERSHIP) violated: INSERT INTO registration_ownerships (updated_at, company_ownership_id, created_by, updated_by, registration_id, created_at) VALUES ('2006-05-04 16:30:47', 3, NULL, NULL, 2920, '2006-05-04 16:30:47')): /usr/local/lib/ruby/gems/1.8/gems/activerecord-oracle-adapter-1.0.0.9250/lib/active_record/connection_adapters/oracle_adapter.rb:221:in `execute' app/controllers/vendors_controller.rb:94:in `create' As far as I can tell (I'm using Navicat as an Oracle client), the DB schema for the dev site is identical to that of the live site. I'm not an Oracle expert; can anyone shed light on why I'd be getting the error in one installation and not the other? Incidentally, both dev and production registration_ownerships tables are populated with lots of data, including duplicate entries for country_ownership_id (driven by index PK_REGISTRATION_OWNERSHIP). Please let me know if you need more information to troubleshoot. I'm sorry I haven't given more already, but I just wasn't sure which details would be helpful.

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  • Sinatra application running on Dreamhost suddenly not working

    - by jbrennan
    My Sinatra application was running fine on Dreamhost until a few days ago (I'm not sure precisely when it went bad). Now when I visit my app I get this error: can't activate rack (~> 1.1, runtime) for ["sinatra-1.1.2"], already activated rack-1.2.1 for [] I have no idea how to fix this. I've tried updating all my gems, then touching the app/tmp/restart.txt file, but still no fix. I hadn't touched any files of my app, nor my Dreamhost account. It just busted on its own (my guess is DH changed something on their server which caused the bust). When I originally deployed my app, I had to go through some hoops to get it working, and I seem to think I was using gems in a custom location, but I can't remember exactly where or how. I don't know my way around Rack/Passenger very well. Here's my config.ru: (mostly grafted from around the web, I don't fully understand it) ENV['RACK_ENV'] = 'development' if ENV['RACK_ENV'].empty? #### Make sure my own gem path is included first ENV['GEM_HOME'] = "#{ENV['HOME']}/.gems" ENV['GEM_PATH'] = "#{ENV['HOME']}/.gems:" require 'rubygems' Gem.clear_paths ## NB! key part require 'sinatra' set :env, :production disable :run require 'MY_APP_NAME.rb' run Sinatra::Application

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  • UITableView madness

    - by kesrut
    Hello, I'm new to iPhone application development. I'm trying to understand how to use UITableView. I'm wrote simple code: - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 1; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { return 1 ; } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *MyIdentifier = @"MyIdentifier"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:MyIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:MyIdentifier] autorelease]; } cell.textLabel.text = @"Hello"; return cell; } UITable shows content, but if i'm drag table contents my application terminates. You can see video: http://www.youtube.com/watch?v=TucTVJVhSD0 I tried to everything with array: - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 1 ; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { return [hello count] ; } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *MyIdentifier = @"MyIdentifier"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:MyIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:MyIdentifier] autorelease]; } cell.textLabel.text = [hello objectAtIndex:indexPath.row]; return cell; } - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { [tableView deselectRowAtIndexPath:indexPath animated:NO]; NSLog(@"Selected") ; } - (void) awakeFromNib { hello = [[NSArray alloc] initWithObjects:@"hello", @"world", @"end", nil]; } // Implement viewDidLoad to do additional setup after loading the view, typically from a nib. - (void)viewDidLoad { [super viewDidLoad]; } Content is shown and if I'm selecting item i'm getting: [Session started at 2010-03-16 19:21:48 +0200.] 2010-03-16 19:21:52.295 ViewTest[1775:207] * -[ViewTestViewController respondsToSelector:]: message sent to deallocated instance 0x3911ec0 I'm total new to iPhone programming. And as i see everything i do - i'm just getting application terminated ..

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  • Why is cell phone software is still so primitive?

    - by Tomislav Nakic-Alfirevic
    I don't do mobile development, but it strikes me as odd that features like this aren't available by default on most phones: full text search: searches all address book contents, messages, anything else being a plus better call management: e.g. a rotating audio call log, meaning you always have the last N calls recorded for your listening pleasure later (your little girl just said her first "da-da" while you were on a business trip, you had a telephone job interview, you received complex instructions to do something etc.) bluetooth remote control (like e.g. anyRemote, but available by default on a bluetooth phone) no multitasking capabilities worth mentioning and in general no e.g. weekly software updates, making the phone much more usable (even if it had to be done over USB, rather than over the network). I'm sure I was dumbfounded by the lack or design of other features as well, but they don't come to mind right now. To clarify, I'm not talking about smartphones here: my plain, 2-year old phone has a CPU an order of magnitude faster than my first PC, about as much storage space and it's ridiculous how bad (slow, unwieldy) the software is and it's not one phone or one manufacturer. What keeps the (to me) obvious software functionality vacuum on a capable hardware platform from being filled up?

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  • How can I programmatically add more than just one view object to my view controller?

    - by BeachRunnerJoe
    I'm diving into iPhone OS development and I'm trying to understand how I can add multiple view objects to the "Left/Root" view of my SplitView iPad app. I've figured out how to programmatically add a TableView to that view based on the example code I found in Apple's online documentation... RootViewController.h @interface RootViewController : UITableViewController <NSFetchedResultsControllerDelegate, UITableViewDelegate, UITableViewDataSource> { DetailViewController *detailViewController; UITableView *tableView; NSFetchedResultsController *fetchedResultsController; NSManagedObjectContext *managedObjectContext; } RootViewController.m - (void)loadView { UITableView *newTableView = [[UITableView alloc] initWithFrame:[[UIScreen mainScreen] applicationFrame] style:UITableViewStylePlain]; newTableView.autoresizingMask = UIViewAutoresizingFlexibleHeight|UIViewAutoresizingFlexibleWidth; newTableView.delegate = self; newTableView.dataSource = self; [newTableView reloadData]; self.view = newTableView; [newTableView release]; } but there are a few things I don't understand about it and I was hoping you veterans could help clear up some confusion. In the statement self.view = newTableView, I assume I'm setting the entire view to a single UITableView. If that's the case, then how can I add additional view objects to that view alongside the table view? For example, if I wanted to have a DatePicker view object and the TableView object instead of just the TableView object, then how would I programmatically add that? Referencing the code above, how can I resize the table view to make room for the DatePicker view object that I'd like to add? Thanks so much in advance for your help! I'm going to continue researching these questions right now.

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  • HTML to 'pretty' text conversion for printing on text only printer (dot matrix)

    - by Gala101
    Hi, I have a web-site that generates some simple tabular data as html tables, many of my users print the web-page on a laser/inkjet printer; however some like to print on legacy Dot Matrix printers (text only) and there-in lies the problem. When giving Print from web-browser onto dot-matrix printer, the printer actually perceives data as 'graphic'/image and proceeds to print it dot-by-dot. i.e If printing a character 'C', printer slices it horizontally and prints in 3-4 passes. Same printer prints a text from an ASCII file (say from notepad) as complete characters in single pass, thereby being 5 times faster and much quieter than when printing a web-page. (Even tried 'generic text-only driver' but Mozilla Firefox has a know bug that it does not print anything over this particular driver since 2.0+) So is there some clean way of formatting an already generated HTML (say method takes the entire html table as string) and generates a corresponding text file with properly aligned columns? I have tried stripping the html tags, but the major issue there is performing good 'wrapping' of a cell's data and maintaining integrity of other cells' data (from same row). eg: ( '|' and '_' not really required) Col1 | Col2 | Colum_Name3 | Col4 | _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ 1 | this cell | this column | smaller | | is in three| spans 2 rows | | | rows | | | - - - - - - - - - - - - - - - - - - - - - - - - 2 | smaller now| this also | but this| | | | cell's | | | | data is | | | | now | | | | bigger | _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ Could you please suggest preferred approach? I've thought of using xslt and somehow outputting text (instead of more prevalent pdf), but Apache FOP's text renderer is really broken and perhaps forgotten in development path. Commercial one's are way too costly.

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  • Is it possible to unstick a remote IIS ASP server after an exception hangs the session?

    - by user89691
    I have been coding an app in classic ASP that accesses 2 Access databases. I had a page I was working on throw an exception, which is normal during development and causes no lasting problems. This time however, after the exception any attempt to open either of the databases would freeze the session with an infinite script timeout. If I delete the session cookie I an able to access ASP pages again until I try to open the database again. The database that was open when the exception was thrown is left open. There is a LDB lock file and I can't rename or delete either the LDB or MDB file, though I can download the MDB file with FTP. The 2nd access database is not open but any attempt to read this also hangs the session. Accessing HTML pages is fine. The site is hosted with Hostway and they are not interested ("Coding problem = Your problem" even though it leaves my site dead in the water, I suspect until the next reboot, whenever that might be). Here is the dump from the relevant ASP page that threw the exception: Active Server Pages error 'ASP 0115' Unexpected error /translatestats.asp A trappable error (C0000005) occurred in an external object. The script cannot continue running. Active Server Pages error 'ASP 0240' Script Engine Exception /translatestats.asp A ScriptEngine threw exception 'C0000005' in 'IActiveScript::Close()' from 'CActiveScriptEngine::FinalRelease()'. Is there any way I can unstick the site / force close the database remotely ?

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  • Translate SQL to OCL ?

    - by Roland Bengtsson
    I have a piece of SQL that I want to translate to OCL. I'm not good at SQL so I want to increase maintainability by this. We are using Interbase 2009, Delphi 2007 with Bold and modeldriven development. Now my hope is that someone here both speaks good SQL and OCL :-) The original SQL: Select Bold_Id, MessageId, ScaniaId, MessageType, MessageTime, Cancellation, ChassieNumber, UserFriendlyFormat, ReceivingOwner, Invalidated, InvalidationReason, (Select Parcel.MCurrentStates From Parcel Where ScaniaEdiSolMessage.ReceivingOwner = Parcel.Bold_Id) as ParcelState From ScaniaEdiSolMessage Where MessageType = 'IFTMBP' and not Exists (Select * From ScaniaEdiSolMessage EdiSolMsg Where EdiSolMsg.ChassieNumber = ScaniaEdiSolMessage.ChassieNumber and EdiSolMsg.ShipFromFinland = ScaniaEdiSolMessage.ShipFromFinland and EdiSolMsg.MessageType = 'IFTMBF') and invalidated = 0 Order By MessageTime desc After a small simplification: Select Bold_Id, (Select Parcel.MCurrentStates From Parcel where ScaniaEdiSolMessage.ReceivingOwner = Parcel.Bold_Id) From ScaniaEdiSolMessage Where MessageType = 'IFTMBP' and not Exists (Select * From ScaniaEdiSolMessage EdiSolMsg Where EdiSolMsg.ChassieNumber = ScaniaEdiSolMessage.ChassieNumber and EdiSolMsg.ShipFromFinland = ScaniaEdiSolMessage.ShipFromFinland and EdiSolMsg.MessageType = 'IFTMBF') and invalidated = 0 NOTE: There are 2 cases for MessageType, 'IFTMBP' and 'IFTMBF'. So the table to be listed is ScaniaEdiSolMessage. It has attributes like: MessageType: String ChassiNumber: String ShipFromFinland: Boolean Invalidated: Boolean It has also a link to table Parcel named ReceivingOwner with BoldId as key. So it seems like it list all rows of ScaniaEdiSolMessage and then have a subquery that also list all rows of ScaniaEdiSolMessage and name it EdiSolMsg. The it exclude almost all rows. In fact the query above give one hit from 28000 records. In OCL it is easy to list all instances: ScaniaEdiSolMessage.allinstances Also easy to filter rows by select for example: ScaniaEdiSolMessage.allinstances->select(shipFromFinland and not invalidated) But I do not understand how I should make a OCL to match the SQL above.

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  • Visual Studio: How to attach a debugger dynamically to a specific process

    - by Jeff Cyr
    I am building an internal dev tool to manage different processes commonly used in our development environment. The tool show the list the monitored processes, indicate their running state and allow to start or stop each process. I'd like to add the functionality of attaching a debugger to a monitored process from my tool instead of going in 'Debug-Attach to process' in visual studio and finding the process. My goal is to have something like Debugger.Launch() that would show a list of the available visual studio. I can't use Debugger.Launch() because it lauches the debugger on the process that make the call. I would need something like Debugger.Launch(processId). Does anyone know how to acheive this functionality? A solution could be to implement a command in each monitored process to call Debugger.Launch() when the command is received from the monitoring tool, but I would prefer something that does not require to modify the code of the monitored processes. Side question: When using Debugger.Launch(), instances of Visual Studio that already have a debugger attached are not listed. Visual Studio is not limited to one attached debugger, you can attach on multiple process when using 'Debug - Attach to process'. Anyone know how to bypass this limitation when using Debugger.Launch() or an alternative?

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  • Apache - "dynamic" rewrite rule

    - by Christian A. Rasmussen
    Hi there. I'm working on a Zend Framework project where I've stumbled across a bit of a problem. The problem originates from the fact that modules are 2nd class citizens in Zend Framework. In my project, I'd like for each module to have a folder containing files which are to be accessed from the outside - files such as stylesheets, javascripts and images. Now, how is this to be done. With a Zend Framework project I have a folder structure which looks like this: application/ modules/ moduleOne/ public/ stylesheet.css moduleTwo/ moduleThree/ public/ index.php The standard .htaccess file located in the public/ folder holds this: SetEnv APPLICATION_ENV development RewriteEngine On RewriteCond %{REQUEST_FILENAME} -s [OR] RewriteCond %{REQUEST_FILENAME} -l [OR] RewriteCond %{REQUEST_FILENAME} -d RewriteRule ^.*$ - [NC,L] RewriteRule ^.*$ index.php [NC,L] The way it works, is that the project's apache DocumentRoot is the public/ folder. All requests gets redirected through the index.php file where Zend Framework's router component takes over. Now, I'm by no means an expert with Apache nor mod_rewrite so pardon me if this is just silly. I imagine that I implement an extra step in the existing rewrite rule so that if I request http://project/public/moduleOne/stylesheet.css it will for instance resolve to /var/www/project/application/modules/moduleOne/public/stylesheet.css. So the steps which need to be done is to check if the first element in the URI is public/ if it is, we take the next segment as the modules name and use that in the path we're trying to resolve to and attempt to serve the file. Is this at all possible or does anyone have a better suggestion? Thank you for your time Christian Rasmussen

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  • CrystalDecisions.Web reference version changes suddenly when run the webapp

    - by Somebody
    I'm breaking my head with this issue, I have a webapp that has a report using crystal report, in the development pc it works fine, but when copy the same project to another pc, when I load the project (VS 2003) the following msg appears: One or more projects in solution need to be updated to use Crystal Reports XI Release 2. If you choose "Yes", the update will be applied permanently... I choose "Yes" and after that I can see that CrystalDecisions.Web reference has the correct version, and location according to the develpment machine, in this case: 11.5.3300.0. But when run the webapp, I can see when the version and path suddenly changes to: 11.0.3300.0. And when trying to see the report the following error appears: Parser Error Message: The base class includes the field 'CrystalReportViewer1', but its type (CrystalDecisions.Web.CrystalReportViewer) is not compatible with the type of control (CrystalDecisions.Web.CrystalReportViewer). the asp.net has the following: <%@ Register TagPrefix="cr" Namespace="CrystalDecisions.Web" Assembly="CrystalDecisions.Web, Version=11.5.3300.0, Culture=neutral, PublicKeyToken=692fbea5521e1304" %> How is this possible? what's happening here? EDIT This is what I did: the wrong version (11.0.3300.0) was located at: C:\Program Files\Common Files\Business Objects\3.0\managed and the right version (11.5.3300.0) is located at: C:\Program Files\Business Objects\Common\3.5\managed So I just deleted the files of the wrong solution, and I made it work in my new computer, no more errors when running the webapp, the report shows fine. But when try to do the same thing in production server, a different error came out, now an exception: This report could not be loaded due to the following issue: The type initializer for 'CrystalDecisions.CristalReports.Engine.ReportDocument' threw an exception. Any idea what could be causing this error now? Here is the code: Try Dim cr As New ReportDocument cr.Load(strpath) cr.SetDatabaseLogon("usring", "pwding") Select Case rt Case 1 cr.SummaryInfo.ReportTitle = "RMA Ticket" Case 2 cr.SummaryInfo.ReportTitle = "Service Ticket" End Select 'cr.SummaryInfo.ReportTitle = tt cr.SetParameterValue("TicketNo", tn) 'cr.SummaryInfo.ReportComments = comment CrystalReportViewer1.PrintMode = CrystalDecisions.Web.PrintMode.ActiveX CrystalReportViewer1.ReportSource = cr CrystalReportViewer1.ShowFirstPage() 'cr.Close() 'cr.Dispose() Catch ex As Exception MsgBox1.alert("This report could not be loaded due to the following issue: " & ex.Message) End Try

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  • Ajax Rich Internet Application framework for Linux + Firefox _AND_ iPhone consumption

    - by Maroloccio
    For a zero-budget (e.g. University) project we need to build a rich web UI for Firefox and iPhone clients. Firm requirement: all technologies to be free and open-source. Nice-to-have: all development to be done in Java/Eclipse. I generally like the Google's AppEngine + GWT combo but this project will require much more interactivity than what's in GWT 2.0. Something along the lines of: http://www.smartclient.com/smartgwt/showcase/. I know trusty plain ol' GWT won't cut it this time. Straight question: is there something that does the sort of thing that SmartGWT does and works really well on Safari/iPhone? I would say the mobile experience is even more important for this project than the desktop one. Optional question: perhaps this is not the best route to go at all? How could we otherwise render a rich UI with such capabilities and interactivity on both screen sizes? Windows, drag-and-drop, advanced tabs, dynamic grids... We don't need to support any other mobile devices. Yet. ;-)

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