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  • How do I remove an old JPanel and add a new one?

    - by Roman
    I would like to remove an old JPanel from the Window (JFrame) and add a new one. How should I do it? I tried the following: public static void showGUI() { JFrame frame = new JFrame("Colored Trails"); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.add(partnerSelectionPanel); frame.setSize(600,400); frame.setVisible(true); } private static void updateGUI(final int i, final JLabel label, final JPanel partnerSelectionPanel) { SwingUtilities.invokeLater( new Runnable() { public void run() { label.setText(i + " seconds left."); } partnerSelectionPanel.setVisible(false); \\ <------------ } ); } So, my code update the "old" JPanel and them it makes the whole JPanel invisible. It was the idea. But it does not work. The compiler complains about the line indicated with "<------------". It writes: <identifier> expected, illegal start of type.

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  • Is there a way to arbitrarily load Resources at runtime in Android?

    - by Omega
    I've got some XML resources in my Android app. Each one has a different name like "bicycle.xml" and "car.xml". I'd like to know if there's a way to load resources based on conditions during run time. As an example... Say I had a text input in my app. When the user enters "bicycle", my app can look up an XML resource by that name, parse and load it. Whereas if they enter "car", they would end up with the data from the other XML file. I've noticed so far that to load resources, you have to use the autogenerated "R" class, which restricts you to hard-coding resources at compile time.

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  • J2ME polish problems when running on the phones

    - by Reza Hasht
    I built an application with j2me polish,it works well on emulator but after installing on phones, I have some basic problems: At first why the size of application is big(in my case 1.5 mb),is there any way to decrease polish apps size(my resources are just 300 kb). For installing it on the phone, I copy the jar file from dist folder; Is my way correct? Important!:arabic words in some SonyEricsson phones are seprated and reversed, I searched the web, but I just found some topics about LWUIT and I coulden't solve it on polish!

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  • NHibernate Native SQL multiple joins

    - by Chris
    Hi all, I"m having some problems with Nhibernate and native sql. I've got an entity with alot of collections and I am doing an SQL Fulltext search on it. So when returning 100 or so entities, I dont want all collections be lazy loaded. For this I changed my SQL query: SELECT Query.* FROM (SELECT {spr.*}, {adr.*}, {adrt.*}, {cty.*}, {com.*}, {comt.*}, spft.[Rank] AS [Rak], Row_number() OVER(ORDER BY spft.[Rank] DESC) AS rownum FROM customer spr INNER JOIN CONTAINSTABLE ( customerfulltext , computedfulltextindex , '" + parsedSearchTerm + @"' ) AS spft ON spr.customerid = spft.[Key] LEFT JOIN [Address] adr ON adr.customerid = spr.customerid INNER JOIN [AddressType] adrt ON adrt.addresstypeid = adr.addresstypeid INNER JOIN [City] cty ON cty.cityid = adr.cityid LEFT JOIN [Communication] com ON com.customerid = spr.customerid INNER JOIN [CommunicationType] comt ON comt.communicationtypeid = com.communicationtypeid) as Query ORDER BY Query.[Rank] DESC This is how I setup the query: var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .List<Customer>(); What happens now is, that the query returns customers twice (or more), I assume this is because of the joins since for each customer address, communicationItem (e.g. phone, email), a new sql row is returned. In this case I thought I could use the DistinctRootEntityResultTransformer. var items = GetCurrentSession() .CreateSQLQuery(query) .AddEntity("spr", typeof(Customer)) .AddJoin("adr", "spr.addresses") .AddJoin("adrt", "adr.Type") .AddJoin("cty", "adr.City") .AddJoin("com", "spr.communicationItems") .AddJoin("comt", "com.Type") .SetResultTransformer(new DistinctRootEntityResultTransformer()) .List<Customer>(); Doing so an exception is thrown. This is because I try to list customers .List<Customer>() but the transformer returns only entities of the last join added. E.g. in the case above, the entity with alias "comt" is returned when doing .List() instead of .List(). If I would switch last join with the join alias "cty", then the transformer returns a list of cities only... Anyone knows how I can return a clean list of customers in this case?

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  • Sending an SMS in Android

    - by D4N14L
    Hey, I have been making an Android app which needs to send a text message. Here is the current code I have: public class getMessage extends Service { @Override public IBinder onBind(Intent intent) { return null; } @Override public void onStart(Intent intent, int startId) { super.onStart(intent, startId); client Phone = new client(); String[] msg = Phone.getMsg(user[0],user[1]); PendingIntent pi = PendingIntent.getActivity(this, 0, new Intent(this, getMessage.class), 0); SmsManager man = SmsManager.getDefault(); Log.e("GOT MESSAGE", msg[0]+ " : " +msg[1]); man.sendTextMessage(msg[0], null, msg[1], pi, null); Log.e("Message", "Sent the message?"); } Now, for some reason, the text message will not send using this code, and I'm not sure why. I was hoping that someone here could help me out in finding why this message won't send. No error is raised, nothing appears in the log (except for the log messages that I make myself in the code). Also, the manifest does have the correct tags. Suggestions?

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  • Why is Hibernate not loading a column?

    - by B.R.
    I've got an entity with a few properties that gets used a lot in my Hibernate/GWT app. For the most part, everything works fine, but Hibernate refuses to load one of the properties. It doesn't appear in the query, despite being annotated correctly in the entity. The relevant portion of the entity: @Column(name="HasSubSlots") @Type(type="yes_no") public boolean hasSubSlotSupport() { return hasSubSlotSupport; } And the generated SQL query: Hibernate: /* load entities.DeviceModel */ select devicemode0_.DevModel as DevModel1_0_, devicemode0_.InvModelName as InvModel2_1_0_ from DeviceModels devicemode0_ where devicemode0_.DevModel=? Despite the fact that I refer to that property, it's never loaded, lazily or not, and the getter always returns false. Any ideas on how I can dig deeper into this, or what might be wrong?

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  • Wait for inline thread to complete before moving to next method...

    - by Tyler
    Hello, I have an android app where I am doing the following: private void onCreate() { final ProgressDialog dialog = ProgressDialog.show(this, "Please wait..", "Doing stuff..", true); new Thread() { public void run() { //do some serious stuff... dialog.dismiss(); } }.start(); stepTwo(); } And I would like to ensure that my thread is complete before stepTwo(); is called. How can I do this? Thanks!

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  • Can JPA do batch update | put | write | insert as pm.makePersistentAll() does in GAE/J

    - by Kenyth
    I searched through multiple discussions here. Can someone just give me a quick and direct answer? And if with JPA you can't do a batch update, what if I don't use transaction, and just use the following flow: em = emf.getEntityManager // do some query // make some data modification em.persist(..) // do some query // make some data modification em.persist(..) // do some query // make some data modification em.persist(..) ... em.close() How does this compare to batch update with regard to performance, and compare to a single transaction commit, measured by RPC calls to datastore server, CPU cycles per request, or so. Does every call to em.persist(..) before em.close() trigger a RPC call to the datastore server? Thanks very much for any response!

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  • Arithmetic + and Bitwise OR

    - by Mohanavel
    Is there any difference between Arithmetic + and bitwise OR. For the below operation i used arithmetic operation, my friend told that this is wrong. In what way this is differing. uint a = 10; uint b = 20; uint arithmeticresult = a + b; uint bitwiseOR = a | b; Both the results are 30.

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  • Possible to skip track from an Android application?

    - by parse
    I'm planning on doing a application for Android 2.1 that changes song every minute (through what I hope exists in Android, "next") for the application using the audio device atm. So if I have Spotify running in background already, playing music, can I through my program change to the next track? Let me know if I was unclear about anything. Thanks in advance!

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  • Allow Incorrect Package Name in Eclipse

    - by SamBeran
    I have some classes in my current project which have the wrong package declaration (they are in the wrong folder for their declared package.) Unfortunately, fixing the problem by moving the class is not an option. Is there a way I can get eclipse to ignore the error?

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  • How to persist in order

    - by parhs
    I have two entities: EXAM and EXAM_NORMAL. EXAM @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private Long id; private String name; private String codeName; @Enumerated(EnumType.STRING) private ExamType examType; @ManyToOne private Category category; @OneToMany(mappedBy="id",cascade=CascadeType.PERSIST) @OrderBy("id") private List<Exam_Normal> exam_Normal; EXAM_NORMAL @Id private Long item; @Id @ManyToOne private Exam id; @Enumerated(EnumType.STRING) private Gender gender; private Integer age_month_from; private Integer age_month_to; The problem is that if I put a list of EXAM_NORMAL at an EXAM class if I try to persist(EXAM) I get an error because it tries to persist EXAM_NORMAL first but it cant because the primary key of EXAM is missing because it isn't persisted... Is there any way to define the order? Or should I set null the list, persist and then set the list again? thanks:)

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  • GWT + XML documents with namespaces

    - by chris_l
    I'd like to get a quick overview of available solutions (libraries, ...) that allow me to work with XML documents with namespaces on a DOM level - in GWT's client side. Additionally, I'm looking for an XPath solution that can work on that DOM (even if it requires writing my own XPath Navigator). XML parsing and serialization isn't necessary on the client - this can be done on the server.

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  • How can we compute the LAST page with JPA?

    - by Kevin
    I would like to implement pagination in my Servlet/EJB/JPA-Hibernate project, but I can't figure out how only one page from the query and know the number of pages I must display I use setFirstResult(int first) ; setMaxResults(int max) ; and that's working alright, but how can I know how many pages I will have in total? (Hibernate is my JPA provider, but I would prefer using only JPA if possible) UPDATE: COUNT() seems to be the better/easiest solution; but what can be the cost of SELECT COUNT(*) FROM ... in comparison with executeQuery("SELECT * FROM ...).getListResult().size() ?

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  • struts annotation issue

    - by Gourav
    My issue is that i have an annotation in Struts2 action class like private String[] origfilenofrom; @FieldExpressionValidator(fieldName="origfilenofrom",key="",message="File Length should be 12 for old file format and 15 for new file format",expression="checkorigFileFormat(origfilenofrom)") now my mehtod is public boolean checkorigFileFormat(String[] files ) { for(int counter=0;counter<files.length;counter++) { int n=files[counter].length(); if(!(n==12 || n==15)) { return false; } } return true; } So for any string in that string [], which is returning false the value is bei false. No matter 3 strings in that string [] are true if one is false then the annotaion message is displayed for all. I want the message not to display where the string is true. Help please

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  • Why is false being returned in this function

    - by Kay
    Hello all, I have this function below which makes it to the second IF function which sets the variable th as true but what is returned is false? Why?! public boolean nodeExist(TreeNode Tree, T value){ boolean th = false; if(Tree.getValue()!= null){ if(value == Tree.getValue()){ th = true; }else{ if(value.compareTo((T) Tree.getValue()) < 0){ nodeExist(Tree.getLeft(), value); }else{ nodeExist(Tree.getRight(), value); } } }else{ th = false; } return th; }

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