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  • Perl - MySQL connection problem in windows

    - by dexter
    I have two folders php and perl they contain index.php and index.pl respectivly in index.pl my perl code looks like: #!/usr/bin/perl use Mysql; print "Content-type: text/html\n\n"; print "<h2>PERL-mySQL Connect</h2>"; print "page info"; $host = "localhost"; $database = "cdcol"; $user = "root"; $password = ""; $db = Mysql->connect($host, $database, $user, $password); $db->selectdb($database); when i run above code (ie type: http://localhost:88/perl/ in browser) following error comes Error message: Can't locate Mysql.pm in @INC (@INC contains: C:/xampp/perl/site/lib/ C:/xampp/perl/lib C:/xampp/perl/site/lib C:/xampp/apache) at C:/xampp/htdocs/perl/index.pl line 2. BEGIN failed--compilation aborted at C:/xampp/htdocs/perl/index.pl line 2. while this works: in browser http://localhost:88/php/ where index.php has: <?php $con = mysql_connect("localhost","root",""); if($con) { if(mysql_select_db("cdcol", $con)) { $sql="SELECT Id From products"; if(mysql_query($sql)) { $result = mysql_query($sql); if ($result)............

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  • JQuery text display problem?

    - by SLAPme
    Kind of new to JQuery and I was wondering how can I state that the users submitted info was saved when they click the submit button by displaying the message Changes saved at the top of the form and then have it disappear when the user leaves the web page and return back to it? Right now my code only displays that changes were saved at the bottom of the form outside of the lists and will not disappear when the users leave the web page and return back to it. Here is the JQuery code. $(function() { $(".save-button").click(function() { $.post($("#contact-form").attr("action"), $("#contact-form").serialize(), function(html) { $("div.contact-info-form").html(html); $('#contact-form').append('<li>Changes saved!</li>'); }); return false; // prevent normal submit }); }); Here is the html code. <div id="contact-info-form" class="form-content"> <h2>Contact Information</h2> <form method="post" action="index.php" id="contact-form"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form> </div>

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  • Apache not loading Xdebug, but does when started from the Command Line

    - by JamesD
    I know that this sounds odd, but believe me, it's what is happening. Here are my system settings: Windows7 Apache 2.2 PHP 5.2.12 Xdebug 2.0.5 I have XDebug configured in my PHP.ini file. When I run php -m, I do in fact see that Xdebug is loaded. Now, if I start Apache AS A SERVICE (or by the Apache Monitor), and run phpinfo(), it is NOT showing Xdebug as being loaded. However, (now here's the crazy part), if I go to my Apache bin directory, and simply run httpd.exe, and then go and look at phpinfo(), Xdebug now shows as being loaded! Also, comparing some phpinfo() when started via service or by command line, it looks like the php.ini file is the same for either case. Everything looks the same except for the Xdebug being loaded part. Please, if you have any ideas it would be greatly appreciated.

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  • Using phpFlickr, how would one display the primary photo from each photoset?

    - by Michael
    Referring to this question: http://stackoverflow.com/questions/2561475/flickr-phpflickr-api how would you display a primary photo from a photoset rather than all photos and photosets? this is the code I have so far: photosets_getList($user); ? <?php $photoset_id = $ph_set['id']; $photos = $f->photosets_getPhotos($photoset_id); foreach ($photos['photoset']['photo'] as $photo): ?> <?php if($parentID == $ph_set['parent']): ?> <a rel="lightbox[album<?=$count;?>]" href="<?= $f->buildPhotoURL($photo, 'medium') ?>" title="<?= $photo['title'] ?>"> <?php endif;?> <img src="<?= $f->buildPhotoURL($photo, 'square') ?>" alt="<?= $photo['title'] ?>" width="75" height="75" title="<?= $photo['title'] ?>" /> <h3><?=$ph_set['title']?></h3> <?php if($parentID == $ph_set['parent']): ?> </a> </div> <?php endif;?>

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  • problems with chili source code highlighter (mysql)

    - by jason
    I am using Chili source code highlighter it works fine with php source using php as the class. But when i change it to mysql it doesnt highlight any SQL code i also tried sql as the classname, i double checked the recipes' and there is a mysql recipes in there. ... What could i be doing wrong? <pre><code id="code" class="php"></code></pre>

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  • jquery to check if returned data object is empty

    - by user253530
    $("#post").live("click",function() { $("input:checkbox[name='bookmarkid']:checked").each(function() { $.post("php/socialbookmark-post.php", {bookmarkID: $(this).val()},function(data) { if(data != "") alert(data); }); }); }); the php file outputs some text only if something goes wrong. The checking that I do fails if the data is empty and displays an empty message. I need to fix this. Any ideas?

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  • htaccess rewrite rule not loading site content

    - by peter
    I am struggling with .htaccess rewrite rules. Let's say I have this URL. localhost/site/index.php and I want to rewrite it as this URL localhost/site/tutorial I would use this RewriteRule Options +FollowSymLinks RewriteEngine on RewriteRule ^tutorial/(.*)$ /up/index.php The page works, but the CSS files don't load. Also, if I have a URL like this: index.php?page=home Then I would have to parse through that URL to get 'home' not using $_GET anymore correct??

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  • jeditable not updating browser display - leaves "click to edit..." after succesful edit

    - by Enoch
    I am using jeditable fairly simply and it all works fine, updates the database, etc. The only problem I have is after the user types the new value data and hits enter it doesn't update the field in the browser to show the new value - instead it puts "Click to edit..." in place of it. Am I missing something like a return value from my php file? the php fucntion just takes the args and updates the database - and it works fine. Enoch the jquery\jeditable code $('.edit').editable('update.php',{ id: 'field', name: 'val', indicator: 'Saving...', tooltip: 'Click to edit...', select : true, submitdata : { db : "pers", kn : "key", rec : "?php echo $rec; ?" } }); the div <div class="edit" id="svc_ad1"><?php echo $row-svc_ad1; ?>< /div> i also have a css class for pEdit edit{ float:left; width:200px; height:15px; margin-bottom:5px; border-bottom:1px solid #aaaaaa; }

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  • cakephp VS codeigniter VS zend framework

    - by i need help
    Very possibly very related: What PHP framework would you choose for a new application and why? Zend or CakePHP? Which one is better? Some people say CakePHP is better for php 4, what do you think? In my case, I would like the following: Lesser code to write, have really strong library and plugin base. Always have new library etc added in from contributor, eg: google map and etc... Ability to use together with the templating system like smarty. Have ACL that can control all the permission level issue. Load class when needed, unload when not needed. Load class once and use globally. Can run in windows environment (I am using xampp to run my php in windows.) After the site done, I will upload all codes into windows 2008 server (using php 5)

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  • Simple Custom rule for Jquery validator

    - by thatweblook
    Hi, I read your reply regarding the jQuery validator where you outline a method to check a username against a value in a database. Ive tried implementing this method but no matter what is returned from the PHP file I always get the message that the username is already taken. Here is ths custom method... $.validator.addMethod("uniqueUserName", function(value, element) { $.ajax({ type: "POST", url: "php/get_save_status.php", data: "checkUsername="+value, dataType:"html", success: function(msg) { // if the user exists, it returns a string "true" if(msg == "true") return false; // already exists return true; // username is free to use } })}, "Username is Already Taken"); And here is the validate code... username: { required: true, uniqueUserName: true }, Is there a specific way i am supposed to return the message from php. Thanks A

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  • CI+JQuery+Ajax problem

    - by Sadat
    Calling the ajax called URL works well without ajax eg. http://localhost/ci/controller/method/param_value. But using ajax it doesnt work. Following are the code segment, i have just started with JQuery+Ajax with CI. Here is my controller: <?php class BaseController extends Controller{ public function BaseController(){ parent::Controller(); $this->load->helper('url'); } function index(){ $this->load->view('header'); $this->load->view('body'); $this->load->view('footer'); } function ajaxTest($testData=""){ $this->load->view('ajaxtest',array('test_data'=>$testData)); } } ? Here is View <?php echo $test_data; ? Ajax Call Function function testAjaxCall(){ $.get( base_url+'basecontroller/ajaxtest/test-value', function(responseData) { $("#test-div").html(responseData); } ); } Ajax Calling Page(button) <div id="test-div"></div><input type="button" onclick="testAjaxCall()" name="ajax-test" value="Test Ajax" /> JS base_url declaration <script type="text/javascript" src="<?php echo base_url();?>js/jquery.js"></script> <script type="text/javascript" src="<?php echo base_url();?>js/application-ajax-call.js"></script> <script type="text/javascript"> /* to make ajax call easy */ base_url = '<?php echo base_url();?>'; </script>

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  • disable eclipse auto completion

    - by SpliFF
    I love Eclipse but I HATE auto-completion with a vengeance! I swear though, no matter how hard I look in prefs or Google I can't find where I turn this off! I'm having the problem with both CFEclipse and the PHP editor. How do I completely disable all "smart" quotes/tags/braces auto-inserting. Not some of it.. ALL of it. No matter how many options I untick both editors keep trying to finish my code for me.. usually with irritating results. Like this one (PHP editor): <img alt="banner" src="/images/banner.jpg"></img> This is HTML, not XHTML - I don't want, or need, my img tags closed. Anyway this is still happening after I've gone to Preferences | PHP | Editor | Typing and Preferences | PHP | Editor | Code Assist and unchecked every option. I can't be the only one having this issue but I can't find any howtos or help on this.

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  • How to not write the full url in javascript ?

    - by Axel
    Hi, I did a Mod rewrite for my website so the URLs looks like this : http://www.mydomain.com/health/54856 http://www.mydomain.com/economy/strategy/911025/ http://www.mydomain.com/tags/obama/new So, the problem is that i make AJAX calls to a file here : http://www.mydomain.com/login.php And i don't want to write the FULL url or even use ../ trick because there isn't a fixed number of folders. So, what i want now, is something worked for my code to access the login.php from the root whatever the domain name is : $.ajax({ type: "POST", url: "http://www.mydomain.com/login.php" });

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  • Permission forbidden on localhost with apache2

    - by N Alex
    Here is what I am trying to do. I tried to add another folder to apache and I get the following error when trying to acces testing/index.html. The idea is that I would like to have for every customer a folder like /home/neagoe/Work/InterWebs/Projects/[PROJECT NAME]/CustomerProjects/website/dist. Forbidden You don't have permission to access /index.html on this server. Apache/2.2.22 (Ubuntu) Server at testing Port 80 Here are the steps that I followed: Step1: sudo chmod a+x /home/neagoe/Work/InterWebs/Projects/testing/CustomerProjects/website/dist Step2: sudo chown -R www-data:www-data /home/neagoe/Work/InterWebs/Projects/testing/CustomerProjects/website/dist sudo chmod -R 775 /home/neagoe/Work/InterWebs/Projects/testing/CustomerProjects/website/dist Step3: sudo adduser $USER www-data Step4: sudo a2enmod userdir Step5: sudo cp /etc/apache/sites-available/default /etc/apache/sites-available/testing I edited the file /etc/apache/sites-available/testing so it looks like this: <VirtualHost *:80> ServerAdmin webmaster@localhost ServerName testing DocumentRoot /home/neagoe/Work/InterWebs/Projects/testing/CustomerProjects/website/dist <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /home/neagoe/Work/InterWebs/Projects/testing/CustomerProjects/website/dist/ > Options Indexes FollowSymLinks MultiViews AllowOverride All Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog ${APACHE_LOG_DIR}/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog ${APACHE_LOG_DIR}/access.log combined </VirtualHost> Step6: I edited hosts ("/etc/hosts") so it looks like this: 127.0.0.1 localhost 127.0.0.1 testing # The following lines are desirable for IPv6 capable hosts ::1 ip6-localhost ip6-loopback fe00::0 ip6-localnet ff00::0 ip6-mcastprefix ff02::1 ip6-allnodes ff02::2 ip6-allrouters Step7: sudo a2ensite testing sudo service apache2 restart I searched for about 2 hours on the internet but I can't figure out what went wrong. All the pages that I found following the same steps as described above. I know there are similar questions here on the internet, but the answer is to change permission to the directory which I did on Step2. I am sorry if this is really a duplicate but I could't find the right answer. Thank you! PS. I asked this also on AskUbuntu but didn't get any answers so I'm trying my luck here. Edit: There isn't much on the error log or the access log. On the access.log: ::1 - - [10/Aug/2013:11:23:28 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" ::1 - - [10/Aug/2013:11:23:29 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" ::1 - - [10/Aug/2013:11:23:31 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" ::1 - - [10/Aug/2013:11:23:32 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" ::1 - - [10/Aug/2013:11:23:33 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" ::1 - - [10/Aug/2013:11:23:34 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" ::1 - - [10/Aug/2013:11:23:35 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" 127.0.0.1 - - [10/Aug/2013:11:23:23 +0300] "POST /wordpress-testing/wp-cron.php?doing_wp_cron=1376123003.7026669979095458984375 HTTP/1.0" 200 705 "-" "WordPress/3.6; http://localhost/wordpress-testing" ::1 - - [10/Aug/2013:11:23:36 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" ::1 - - [10/Aug/2013:11:23:37 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" ::1 - - [10/Aug/2013:11:23:38 +0300] "OPTIONS * HTTP/1.0" 200 126 "-" "Apache/2.2.22 (Ubuntu) (internal dummy connection)" 127.0.0.1 - - [10/Aug/2013:11:31:32 +0300] "GET /index.html HTTP/1.1" 200 485 "-" "Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:23.0) Gecko/20100101 Firefox/23.0" And the last line repeats for about 200 rows. On the error.log: 1. This lines repeat from time to time. PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php5/20100525 /msql.so' - /usr/lib/php5/20100525/msql.so: cannot open shared object file: No such file or directory in Unknown on line 0 [Sat Aug 10 13:06:42 2013] [notice] Apache/2.2.22 (Ubuntu) PHP/5.4.9-4ubuntu2.2 configured -- resuming normal operations [Sat Aug 10 13:07:36 2013] [notice] caught SIGTERM, shutting down PHP Warning: PHP Startup: Unable to load dynamic library '/usr/lib/php5/20100525/msql.so' - /usr/lib/php5/20100525/msql.so: cannot open shared object file: No such file or directory in Unknown on line 0 [Sat Aug 10 13:07:37 2013] [notice] Apache/2.2.22 (Ubuntu) PHP/5.4.9-4ubuntu2.2 configured -- resuming normal operations 2. And this is the predominant error. (hundreds of lines) [Sat Aug 10 13:07:40 2013] [error] [client 127.0.0.1] (13)Permission denied: access to /index.html denied

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  • General RewriteRule for many undefined parameters in URL

    - by FedericoBiccheddu
    I'm trying to write a rule to make that one can generalize, since multiple pages to pass the values are different. Right now I could do: RewriteRule ^forum/([^/]{1,255})/([\+]{1})/((([a-z]+)([_]{1})([a-zA-Z0-9]+)([/]?))+)$ forum.php?name=$1&$5=$7 [L] To address such as: Nome+del+Forum/+/page_1/action_do Should return: forum.php?name=Nome+del+Forum&page=1&action=do Instead, take only the last parameter (in this case action=do): forum.php?name=Nome+del+Forum&action=do How can I fix? Thanks in advance!

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  • Twitter Bootstrap modal spans, side-by-side divs and "control-group"?

    - by Federico Stango
    I'm trying my best to have a good looking modal login form but for some reasons it seems that no matter how I nest divs, I cannot obtain the proper shape. What I need is a big "lock" image side-by-side with a username/password form. The best I could do adds a horizontal scroller by the modal bottom and shows the input gadgets fairly distant from the image partly hidden on the right side of the modal canvas. Inspecting with FireBug it seems that the spans in row-fluid are ok but the "control-label" and "controls" class adds way too much space on the left by width (for the labels) and margin-left (for the controls). How would you solve it? Am I doing something wrong with divs and classes nesting? This is the current modal without the main wrapper as it gets added by some js code that loads modal contents through ajax: <form class="form-horizontal" id="login" name="login" method="post" action="<?php echo site_url('user/login'); ?>"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-hidden="true">&times;</button> <h3>Login</h3> </div> <div class="modal-body"> <?php if ( isset($error) ) { ?> <div class="row"> <div class="alert alert-error"> <strong>Warning!</strong> <?php echo $error; ?> </div> </div> <?php } ?> <div class="row-fluid"> <div class="span4"> <img src="skins/frontend/base/images/lock.png" width="96px" height="96px" /> </div> <div class="span8"> <div class="control-group"> <label class="control-label" for="email">Email</label> <div class="controls"><input type="text" placeholder="Type your email" id="email" name="email" /></div> <?php echo form_error('email', '<div id="error_email" class="alert alert-error">* ', '</div>'); ?> </div> <div class="control-group"> <label class="control-label" for="password">Password</label> <div class="controls"><input type="password" placeholder="Password" id="password" name="password" /></div> <?php echo form_error('password', '<div id="error_password" class="alert alert-error">* ', '</div>'); ?> </div> <div class="control-group"> <div class="controls"><label class="checkbox inline"><input type="checkbox" id="remember" name="remember" checked="checked" />&nbsp;Remember Me</label></div> </div> </div> </div> </div> <div class="modal-footer"> <button type="submit" class="btn btn-primary">Login</button> </div> </form> Just don't take into account the php code you see... :) Thanks in advance for all the support you can give! Federico

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  • Mod Rewrite Trouble

    - by Adrian
    I want to have a main section which is found on services.php and then some sub-sections like services_logodesign.php. I want to make url's look like: When I click a button to open services_logodesign.php the browser should show "services/logo design" I have several other sub-sections, it will be nice to have one code for any other pages.

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  • Wordpress Taxonomy title output

    - by Blackbird
    I'm trying to output the title of a taxonomy page when viewing it... So like, if i was on a 'tag' page i would go: <?php if (is_tag()) {?> <h1><?php single_cat_title(); ?></h1> <?php } ?> But how would i achieve the same thing for if the user is viewing a specific taxonomy page? is_taxonomy() doesn't exist so i'm suck! :/

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  • apc.cache_by_default with CodeIgniter

    - by Dennis
    I'm trying to use APC (Alternative PHP Cache) on my localhost with wamp 2, PHP 5.3 and CodeIgniter 1.7.2, however If I turn on cache_by_default and enable apc.stat the server will crash and I get the following error: [apc-error] Cannot redeclare class ci_benchmark in C:\wamp\www\k\mvc\codeigniter\Common.php on line 127. What can I do to fix this issue?

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  • Installing sfJqueryTreeDoctrineManagerPlugin to Symfony 1.4

    - by Christine Q.
    I have faced serious difficulties while installing sfJqueryTreeDoctrineManagerPlugin to Symfony 1.4 w/ Doctrine ORM. The installation directly from the server did not work out like with previous plugins that I have installed: C:\pathsymfony plugin:install sfJqueryTreeDoctrineManagerPlugin plugin installing plugin "sfJqueryTreeDoctrineManagerPlugin" No release available for plugin "sfJqueryTreeDoctrineManagerPlugin" This is why I needed to install the plugin by downloading the tgz-archive and install it manually like this: C:\pathsymfony plugin:install "C:\path\to\downloads\sfJqueryTreeDoctrineManagerPlugin-1.2.4.tgz" plugin installing plugin "C:\path\to\downloads\sfJqueryTreeDoctrineManagerPlugin-1.2.4.tgz" sfSymfonyPluginManager Installing web data for plugin I guess everything should be fine this far? After that I edited \apps\admin\config\settings.yml like instructed in the plugins readme file. all: .settings: enabled_modules: [default, sfJqueryTreeDoctrineManager] I also checked that the plugin was enabled in \config\ProjectConfiguration.class.php like this: $this->enablePlugins(array( // other plugins, 'sfJqueryTreeDoctrineManagerPlugin' )); I published assets and cleared cache: C:\pathsymfony plugin:publish-assets >> plugin Configuring plugin - sfJqueryTreeDoctrineManagerPlugin C:\pathsymfony cc Finally I added the required helper to the newly created apps\admin\modules\category\templates\indexSuccess.php <?php use_helper("sfJqueryTreeDoctrine"); echo get_nested_set_manager("Category", "name"); When loading the page I unfortunately get the following error: 500 | Internal Server Error | InvalidArgumentException Unable to load "sfJqueryTreeDoctrineHelper.php" helper in: SF_ROOT_DIR\apps\admin\modules/businessunitgroup/lib/helper, SF_ROOT_DIR\apps\admin\lib/helper, SF_ROOT_DIR\lib/helper, SF_SYMFONY_LIB_DIR/helper. The file sfJqueryTreeDoctrineHelper.php exists indeed but not in any previously mentioned folder. The file can only be found in the folder \plugins\sfJqueryTreeDoctrineManagerPlugin\lib\helper. I guess that Symfony doesn't look to that folder while finding helpers? I have tried to move the helper file to one of the previously mentioned folders. As expected, that changes the error. Now I get: 500 | Internal Server Error | sfConfigurationException The component does not exist: "sfJqueryTreeDoctrineManager", "manager". Unfortunately I can't figure out how should I be able to retrieve the "missing" component from the correct folder. I would be very grateful for any advice to help me forward. By the way, I am aware that there are other nested-set / tree plugins available for Symfony (like sfDoctrineTreePlugin and caPropelTreePlugin) but unluckily those are either uncompatible or too limited for my needs.

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  • Setting up phpstorm 4 with XAMPP on Windows 7

    - by stirredo
    I need help setting up phpstorm (4.0) with XAMPP which is at the default location c:\htdocs. I create all my projects at c:\htdocs\projectname. Here are the things I have already done: Setup the PHP interpretator by going to settings and then PHP (main menu) Go to PHP Servers and then To setup run configuration I have the done the following: Now when I run using the above configuration it just takes me to localhost in my browser, instead of the file I am editing (http://localhost instead of localhost/myproject/myfile.php). What am I missing? I read the help topics of phpstorm and googled a lot but still couldn't figure it out.

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  • Mysql : Count Posts and Group by date

    - by Oguz
    Hello , I am not very good at sql , generally I use php to do my complicated tasks , But in this task , there are lots of data , so using php for counting posts is very slow. So I want a sql which counts post by date , but my date column in table is php's time stamp.I will crate post number x date chart

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