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  • the difference of String.valueOf(char) and +

    - by Will Yu
    to show the default value of char ,I wrote code like this: public class TestChar { static char a; public static void main(String[] args) { System.out.println("."+String.valueOf(a)+"."); System.out.println("the default char is "+a); } } but the console output is confused.the first is ". ." ,however the second is "the default char is [](like this ,I don't know how to describe it.)" why?thanks for help

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  • Just a small help about switch's use

    - by Laurent Fournier
    If an answer on this already exist, my apologies i've not found on this question... is this statement correct if i want presice actions on integers from -2 to 0, and for those between 1 and 6 apply the same methods with only my integer who'll change ? Like this: public void setCaseGUI(Point pt, int i, boolean b){ plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setSelected(b); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setIcon(null); switch(i) { case -2: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("F"); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red); break; case -1: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("B"); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red); break; case 0: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(""); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null); break; case 1: case 2: case 3: case 4: case 5: case 6: case 7: case 8: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(String.valueOf(i)); plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null); break; default: System.out.println("Erreur de changement d'état/case !"); } } Please don't be too harsh on me i've started to learn dev only a few month ago

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  • OnLowMemory getting called

    - by Sam97305421562
    Hi, I am doing an App which access the gprs .I am facing problem when the user starts another application who uses gprs also like google maps .It takes it own heap memory ,after doing some operation on Maps app it calls OnLowMemory of my service .and my ui is also killed in background. I am not getting any proper tutorial haw can i start my app when it is getting killed during onLowMemory ,or is there any other way to handle it . Thanks in advance.

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  • Adding interfaces that won't be actually used

    - by devoured elysium
    I currently have two interfaces(that I'll name here IA and IB): interface IA { int Width; int Height; ... } interface IB { int Width; int Height; ... } that share the same two properties: they both have a Width and a Height property. I was thinking if there is any point in defining an IMatrix interface containing a Width and Height properties: interface IMatrix { int Width; int Height; } The thing is that although they share both the same properties, I won't make use of polymorphism with IMatrix in any of my coding: i.e., there won't by any situation where I'll want to use an IMatrix, I'll just want to use IA and IB. Adding an IMatrix seems more like over-engineering than other thing, but I'd like to ask you guys what your opinion is on the matter. Thanks

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  • Args error in main method for client-server program

    - by socket
    Hi I have a client and server program, all the coding is done and compiles, the client has a GUI and the server is command line. The program uses sockets. But when I run the client to connect to the server it keeps coming with the error message: "Usage: TodoClient []", rather than connecting to the server and starting up. This is where the problem lies: public static void main(String[] args) { TodoClient client; if (args.length > 2 || args.length == 0) { System.err.println("Usage: TodoClient <host> [<port>]"); } else if (args.length == 1) { client = new TodoClient(args[0], DEFAULT_PORT); } else { client = new TodoClient(args[0], Integer.parseInt(args[1])); } } Thank You

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  • mysql for dummies

    - by kalixxx
    I just started using mysql and I just can see myself woking with strings! I mean the compiler cant catch errors like this... and its just a mess! is there a wrapper or some kind of class i can add that does something as simple as making a function that adds a table and asks for args? I'm sure there is a tool like that but i cant find it or know its name. plz help.

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  • how to create a logo and graphical images [closed]

    - by priya
    hi Can you tell me how to create code for this? Insert a new logo of the company Use layout manager to place the components on the applet Insert graphical images The details of the music CDs should be stored category-wise in seperate text files. For example, classic.txt file stores the music titles of classic tracks, western.txt file stores the music title of western tracks. Display the list of the title available with the music store depending upon the category selected. The images should also change according to the selection.

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  • trying to switch beginning of an array with another

    - by user1874574
    I have a problem where i am trying to swap two arrays so that they switch beginnings. example: array 1 = (1,2,3,4,5,6,7,8) and array 2 = (11,12,13,14,15,16,17,18) i want to end up with the first array being (11,12,13,14,5,6,7,8) and i want the second array to be (1,2,3,4,15,16,17,18) but for some reason i end up with 1=(11,12,13,14,5,6,7,8) and 2=(11,12,13,14,15,16,17,18) my code is provided below, what am i doing wrong? public static void Mutate(Genetic lowest, Genetic secondLowest) { int halfway = (lowest.getPopulation().length)/2; int[] one = lowest.getPopulation(); int[] two = secondLowest.getPopulation(); int[] temp = secondLowest.getPopulation(); int[] temp2 = lowest.getPopulation(); for(int i = 0; i < halfway; i++){ temp[i] = one[i]; } lowest.setPopulation(temp); for(int i = 0; i < lowest.getPopulation().length; i++){ System.out.print(temp[i]); } System.out.println(); for(int i = 0; i < halfway; i++){ temp2[i] = two[i]; } for(int i = 0; i < lowest.getPopulation().length; i++){ System.out.print(temp2[i]); } }

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  • Sending two servlet responses per request

    - by sangi
    Hi, I write, because I can not solve the following problem. I have a servlet that processes some information. In response I put both text and binary content. How do I get two response, then two html page, starting from the same request? is a thing possible? The first response should continue to do what he does now, while the second would appear to make a popup window to save an image. There are easier ways to achieve the same result? Many thanks in advance

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  • Union of two or more (hash)maps

    - by javierfp
    I have two Maps that contain the same type of Objects: Map<String, TaskJSO> a = new HashMap<String, TaskJSO>(); Map<String, TaskJSO> b = new HashMap<String, TaskJSO>(); public class TaskJSO { String id; } The map keys are the "id" properties. a.put(taskJSO.getId(), taskJSO); I want to obtain a list with: all values in "Map b" + all values in "Map a" that are not in "Map b". What is the fastest way of doing this operation? Thanks EDIT: The comparaison is done by id. So, two TaskJSOs are considered as equal if they have the same id (equals method is overrided). My intention is to know which is the fastest way of doing this operation from a performance point of view. For instance, is there any difference if I do the "comparaison" in a map (as suggested by Peter): Map<String, TaskJSO> ab = new HashMap<String, TaskJSO>(a); ab.putAll(b); ab.values() or if instead I use a set (as suggested by Nishant): Set s = new Hashset(); s.addAll(a.values()); s.addAll(b.values());

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  • hashmap and list compare

    - by sarah
    Hi, I have a hashmap having four values a,b,c,d and list having only a i want to see if the hashmap has the value a and print it. hashmap.get('data') results a,b,c,d list l is having a how will i print only the value a

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  • Eclipse debug - line: not available

    - by Mike
    I can't seem to find anything on google telling me why this might be and what the resolution is. I'm Stepping through third party code (that I have the source for) and would really like to see the current line being executed... Looking at javac compile flags, I see the -g:none flag. If this flag is set, would this be enough to explain why I'm not able to see line numbers? If so, why would someone do this, are there performance implications? Do I need to recompile the jar myself to attach the missing debug info (if possible)? Thanks!

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  • Why I see only part of the image in the button?

    - by Roman
    I add an image to the button in the following way: ImageIcon icon = new ImageIcon("images/col.jpg"); tmp = new JButton(icon); My image is a red sphere but in my button I see only read color. I assume that I see just a small part of the sphere. How can I see the whole image in the button?

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