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  • loading table view on click of button

    - by srikanth
    hi all, i have created an iPhone application with a view based .. the problem is i want to load a table view on click of button how can i do it? i tried.. initWithNibName:@"xibfile" bundle:[NSBundle mainBundle]... but table view is not loading wat to do?

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  • Add view overlay to iPhone app

    - by Rob Lourens
    I'm trying to do something like this: - (void)sectionChanged:(id)sender { [self.view addSubview:loadingView]; // Something slow [loadingView removeFromSuperview]; } where loadingView is a semi-transparent view with a UIActivityIndicatorView. However, it seems like added subview changes don't take effect until the end of this method, so the view is removed before it becomes visible. If I remove the removeFromSuperview statement, the view shows up properly after the slow processing is done and is never removed. Is there any way to get around this?

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  • Cocoa touch - creating view template for iPad

    - by teepusink
    Hi, This is kinda a hard question to describe. I'm just starting to make an iPad app. Now with the amount of real estate I have, I'm planning to have different but similar "views" to populate the space. (might be easier to think a newspaper site, where many of the columns are similar) I would like to create a "view template" so I can reuse the view in the different spots. Is it possible to design the view template in Interface Builder? (meaning I design the UIView in Interface Builder and then somehow I can just do [window addSubview:viewController.viewTemplate1]; multiple times? If so how would I load that view template in the different places? If you know of an example code / tutorial that does something similar, that would work too. Thanks, Tee

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  • iPad pushing a split view in navigator-based application

    - by FabioWong
    I had read a lot of post from the web, but I still cannot find out how can I make this out. Please help me in detail. I need to make a split-view inside a navigation because I need to make a login system. After login, then we can see the split view. I found that someone say must need to set it to be root view, some say do not need. However I cannot do it in both way. Can anyone teach me how to do that step by step?? Here is what I did. - (void)viewDidLoad { [super viewDidLoad]; GOTSorOE_EN *gotsORoeEN = [[[GOTSorOE_EN alloc]initWithNibName:@"GOTSorOE_EN" bundle:nil]autorelease]; OEFileList_EN *oeFileListEN = [[[OEFileList_EN alloc]initWithNibName:@"OEFileList_EN" bundle:nil]autorelease]; gotsORoeEN.oeFileListEN = oeFileListEN; splitViewController = [[[UISplitViewController alloc]init]autorelease]; splitViewController.viewControllers = [NSArray arrayWithObjects:gotsORoeEN, oeFileListEN, nil]; self.view = splitViewController.view; }

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  • make VIEW of SHOW TABLE query

    - by cneeds
    Is there a way to make a VIEW of this SHOW TABLE query? SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table" When I save this as a view (using phpMyAdmin) I get #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table"' at line 4 when phpMyAdmin tries to execute this CREATE ALGORITHM = UNDEFINED VIEW `Tables` AS SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table"

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  • modal view not showing inside didfinishpickingimage

    - by sebastien
    Hi, I have a viewcontroller, and I would like to display a modal view controller with : presentModalViewController when a user finished picking an image. The modal view controller is working fine when I call it from a button in my main view. But when I call it from didfinishpickingimage callback nothing happens. Thanks.

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  • Rails - Paperclip, getting width and height of image in model

    - by Corey Tenold
    Trying to get the width and height of the uploaded image while still in the model on the initial save. Any way to do this? Here's the snippet of code I've been testing with from my model. Of course it fails on "instance.photo_width". has_attached_file :photo, :styles => { :original => "634x471>", :thumb => Proc.new { |instance| ratio = instance.photo_width/instance.photo_height min_width = 142 min_height = 119 if ratio > 1 final_height = min_height final_width = final_height * ratio else final_width = min_width final_height = final_width * ratio end "#{final_width}x#{final_height}" } }, :storage => :s3, :s3_credentials => "#{RAILS_ROOT}/config/s3.yml", :path => ":attachment/:id/:style.:extension", :bucket => 'foo_bucket' So I'm basically trying to do this to get a custom thumbnail width and height based on the initial image dimensions. Any ideas?

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  • Why self.view is not available

    - by amok
    I have this code in the main view controller and it is working just fine and as I wanted. loadingActionSheet = [[UIActionSheet alloc] initWithTitle:@"Posting To Twitter..." delegate:nil cancelButtonTitle:@"Cancel" destructiveButtonTitle:nil otherButtonTitles:nil]; [loadingActionSheet showInView:self.view]; I wanted that code to be reusable from different part of the project so I moved it in a separate file (UIView based). The poblem that I am facing is that self.view is not available there and I don't know why because I am learning and I don't know enough to understand what I am missing. What do I have to do/add/change to have the actionsheet shown in my current view even if that code lives somewhere else?

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  • Android : List View or SPinner

    - by Ram
    Team, I would like to know how to display a List View or SPinner using key and value pairs in Android platform. For example take Contacts Contact has id, First Name, LastName, i would like to display First Name and Last Name in the list view or in the spinner, id1, lastname1, firstname1 id2, lastname2, firstname2 id3, lastname3, firstname3 Once the user selected any value in the List view or spin list, I need to get the key value from the List view or spinner. How to do it? Any help or examples is greatly appreciated. Thanks, Ramesh

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  • inheritance from the django user model results in error when changing password

    - by Jerome
    I inherited form the django user model like so: from django.db import models from django.contrib.auth.models import User, UserManager from django.utils.translation import ugettext_lazy as _ class NewUserModel(User): custom_field_1 = models.CharField(_('custom field 1'), max_length=250, null=True, blank=True) custom_field_2 = models.CharField(_('custom field 2'), max_length=250, null=True, blank=True) objects = UserManager() When i go to the admin and add an entry into this model, it saves fine, but below the "Password" field where it has this text "Use '[algo]$[salt]$[hexdigest]' or use the change password form.", if i click on the "change password form' link, it produces this error Truncated incorrect DOUBLE value: '7/password' What can i do to fix this?

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  • Django - Expression based model constraints

    - by rtmie
    Is it possible to set an expression based constraint on a django model object, e.g. If I want to impose a constraint where an owner can have only one widget of a given type that is not in an expired state, but can have as many others as long as they are expired. Obviously I can do this by overriding the save method, but I am wondering if it can be done by setting constraints, e.g. some derivative of the unique_together constraint WIDGET_STATE_CHOICES = ( ('NEW', 'NEW'), ('ACTIVE', 'ACTIVE'), ('EXPIRED', 'EXPIRED') ) class MyWidget(models.Model): owner = models.CharField(max_length=64) widget_type = models.CharField(max_length = 10) widget_state = models.CharField(max_length = 10, choices = WIDGET_STATE_CHOICES) #I'd like to be able to do something like class Meta: unique_together = (("owner","widget_type","widget_state" != 'EXPIRED')

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  • asp.net mvc 2 multiple partial view

    - by 303
    Hey Guys, I have a contoller that renders 3 different views. But I also have a common part (div) for every view. I thought that I can create an UserControl with own controller and include that control on my views (New controller and view as controll). How should I use that UserControl? Should it be a partial view? Or different approach - can I have multiple partial views on one page? I've been searching the web for the last view days and haven't found working solution that suits me. Also I want to use Strongly Typed views/data. Cheers

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  • sql create view in one to many relation

    - by new to sql
    i want to create a view in a one-to-many relatiom. here is my relations: (a -* b) and (a -* c). i want to create a view to have this data : a1 - (all b's related to a1 + all c's relted to a1) i don't wnat sth like (a1 ,b1,c1 - a1,b1,c2 ,...) how can i create this view ?

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  • Django populate select field based on model query

    - by Mike
    I have the following model class DNS(models.Model): domain = models.ForeignKey(Domain) host_start = models.CharField(max_length=150, blank=True, null=True) type = models.SmallIntegerField(max_length=1, default=0, choices=DNS_CHOICE) value = models.SmallIntegerField(max_length=3, default=0, blank=True, null=True) ip = models.IPAddressField(blank=True, null=True) host_end = models.ForeignKey("DNS", blank=True, null=True) other_end = HostnameField(max_length=150, blank=True, null=True) created = models.DateTimeField(auto_now_add=True) sticky = models.BooleanField(default=0) other = models.BooleanField(default=0) When I try to init a form with just foreignkeys on host_end.. it always shows all entries in the DNS table domain = Domain.objects.get(id=request.GET['domain'], user=request.user, active=1) form = DNSFormCNAME(initial={'ip': settings.MAIN_IP, 'type': request.GET['type'], 'host_end': DNS.objects.filter(domain=domain)}) I just want the zones that match that domain.. not all domains.

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  • Rails: Pass association object to the View

    - by Fedyashev Nikita
    Model Item belongs_to User. In my controller I have code like this: @items = Item.find(:all) I need to have a corresponding User models for each item in my View templates. it works in controller(but not in View template): @items.each { |item| item.user } But manual looping just to build associations for View template kinda smells. How can I do this not in a creepy way?

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  • c# .net MVC4 Model to represent table or form

    - by Matthew Chambers
    Hello I am a little confused with regards to models in mvc 4 and thought someone may be able to point me in the right direction. This would be most appreciated. For example if i have a table that has the following fields [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 5)] public string UserName { get; set; } [Required(ErrorMessage="Email Address is Required")] [StringLength(15, ErrorMessage = "Email Address must be between {0} and {1} in size",MinimumLength = 5 )] [DataType(DataType.EmailAddress)] [Display(Name="Email")] public string Email { get; set; } [MaxLength(25)] [Display(Name="Mobile Telephone Number")] public string Mobile {get;set;} [MaxLength(500)] [Display(Name="Headline")] public string Headline {get;set;} [Required] [StringLength(200)] [Display(Name = "First Name")] public string FirstName {get;set;} [Required] [StringLength(200)] [Display(Name="Surname")] public string Surname { get; set;} public virtual int? DayOfBirthId { get; set; } public virtual DayOfBirth DayOfBirth { get; set; } public virtual int? MonthOfBirthId { get; set; } public virtual MonthOfBirth MonthOfBirth { get; set; } public virtual int? YearOfBirthId { get; set; } public virtual YearOfBirth YearOfBirth{get;set;} This is my user profile table in the database. However I would like a form that the user registers to the site with. When they first register i do not need all the details such as telephone all i really need is there username, email address and password. Do i create another model for this. Or do i have one model and on the controller set the fields to null or empty string that are not required on registration. I have validation also so would this be set for data that has not been entered on the form. My question is ultimately should all forms represent models- should the database be redesigned to meet this required. Or should the controller set the values that are not required. Or should there be another model that represents the form be created which maps to this table. I am a little confused on this and clarification of anyone would be most appreciated.

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  • Post and Comment with the same Model.

    - by xRobot
    I have created a simple project where everyone can create one or more Blog. I want to use this models for Post and for Comment: class Post_comment(models.Model): content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField(_('object ID')) content_object = generic.GenericForeignKey() # Hierarchy Field parent = models.ForeignKey('self', null=True, blank=True, default=None, related_name='children') # User Field user = models.ForeignKey(User) # Date Fields date_submitted = models.DateTimeField(_('date/time submitted'), default = datetime.now) date_modified = models.DateTimeField(_('date/time modified'), default = datetime.now) title = models.CharField(_('title'), max_length=60, blank=True, null=True) post_comment = models.TextField(_('post_comment')) markup = models.IntegerField(choices=MARKUP_CHOICES, default=DEFAULT_MARKUP, null=True, blank=True) if it is a comment the parent is not null. So in most case the text field will contain a little bit of text. Can I use this model for both Post and Comment ?

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  • measuring a view before rendering it

    - by nourdine
    hello I need to find out how big a view will be after attaching it to its parent. I have overridden this method: onMeasure(int, int); but it looks like this method is invoked only when I actually add my custom view to it's container using: addView(myView); Do you think there is a way to get this information before rendering the view itself? Basically I need to know the actuall size before attaching it and not attach the view at all if it would take more certain amount of space. anybody?

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  • Hint to MVC view generator for primary key on POCOs

    - by myotherme
    When generating a strongly-typed Index view for my model I always get the following: <%= Html.ActionLink("Edit", "Edit", new { /* id=item.PrimaryKey */ }) %> I am using a POCO class for use with our ORM. As I understand it when using LINQ to SQL the view code will know which field is the primary key. Is there a way that I can an attribute to the property (or class) that will let the View Generator know that the ID property if the primary key?

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  • how to change color of table view title

    - by madhavi
    hello, Can we change the color of the table view title the string which i am showing appears in gray color can we choose color for it .Is there any property of table view title i am not asking for table view header or footer i mean the title - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { // Keep space in the following line ........ DONT REMOVE return [NSString stringWithFormat:@"Select your service:"]; }

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  • Extending a view to the left side, animated

    - by Heinrich
    Hi, I have a view that I want to extend on the left side using an animation. All borders but the left one should remain the same, so the x position and the width of the view are changing. I use this code: [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:5.0]; self.frame = CGRectMake(self.frame.origin.x-100, self.frame.origin.y, self.frame.size.width+100, self.frame.size.height); [UIView commitAnimations]; If I run this code, the width of the view is set to the new value immediately and then the view is moved to the new x point, but why? How can I change this behaviour? Thanks for your ideas!

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