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  • jQuery selector for option tag value attribute returns null

    - by Ben
    Hello, I am trying to change the selected option in a select dropdown box with jQuery. I have it set so that it finds the hash tag at the end of the URL and based on that hash tag it changes the selected option in the select box. Most of my code is functional, it successfully finds the hash tag and executes the if statement that corresponds with it. However, when it goes to execute the "then" section of the statement when it goes to the selector for the option (which uses an attribute selector based on the value attribute of the option tag) it returns null. If figured this out with firebug, in the console it says that the selector is null. Here is my code: $(document).ready(function() { var $hash = window.location.hash if($hash == "#htmlcss") { $('option[value="HTML/CSS Coding"]').attr("selected","selected") } if($hash == "#php") { $('option[value="PHP Coding"]').attr("selected","selected") } if($hash == "#jscript") { $('option[value="Javascript and jQuery Coding"]').attr("selected","selected") } if($hash == "#improv") { $('option[value="General Website Improvements"]').attr("selected","selected") } if($hash == "#towp") { $('option[value="Website Conversion to Wordpress"]').attr("selected","selected") } if($hash == "#wptheme") { $('option[value="Wordpress Theme Design"]').attr("selected","selected") } if($hash == "#complete") { $('option[value="Complete Website Creation"]').attr("selected","selected") } if($hash == "#server") { $('option[value="Web Server Configuration"]').attr("selected","selected") } }); So to clarify, when I enter in a url that ends in the #php hash tag, for example, the desired action does not occur which would change the "PHP Coding" option to the selected one by using the "selected" html attribute however the selector for the particular option tag returns null. Is there a problem with my syntax or is my code not functioning in the way that I think it should? Thanks very much.

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  • form Validation white page not showing errors

    - by Jess McKenzie
    In the example below I am wanting to do all of the 'safety' checks on the $_POST variables but it seems when I click submit I get a white page why? I am wanting it to show the errors etc Form Process: /* check if the form is submitted */ if (isset($_POST['submitButton'])) { $fullName = $_POST['fullname']; if($_SERVER['REQUEST_METHOD'] == 'POST' && !empty($fullName)) { if (!ctype_alpha(str_replace(array("'", "-"), "",$fullName))) { $errorfullName .= '<span class="errorfullName">*First name should be alpha characters only.</span>'; } if (strlen($fullName) < 3 OR strlen($fullName) > 40) { $errorfullName .= '<span class="errorfullName">*First name should be within 3-40 characters long.</span>'; } } }

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  • Is it possible to split a form into multiple erb modules?

    - by Ya.
    I have a large form with multiple tabs and would like to be able to split it into multiple modules and include each as a partial. Something like: main.html.erb: <%= form_for (@myobject) do |f| %> <%= render "module1" %> .... module1.html.erb: <%= f.text_field :field1 %> ... Needless to say, when I do it like this I get an error from module1 that "f" is undefined. Is there a way to split form fields into multiple modules?

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  • How can I organize many results in a selectbox?

    - by zeckdude
    I have a select box that is part of a form. It is currently querying the addresses table and displaying the addresses into the select box. I plan on having up to 100 addresses. I'm looking for a solution where I can show all the states if the user clicks on the select box. Then if the user hovers over a state it will show all the addresses for that specific state. Then if the user clicks on an address, it will show that as the picked option in the select box. This is like a dropdown menu within a select box. Does anyone know where I can find a solution as this?

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  • Why does the following Javascript/form not work?

    - by joshim5
    <form> <input type="text" id="inputbox" value="hello"/> <input type="submit" value="Convert" onClick="convert(document.getElementById("inputbox"))"/> </form> <script type="text/javascript"> function convert (text) { alert(text); return text; </script> This also does not work when I change alert to document.write. I obviously have more HTML to go along with this. Thanks!

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  • Submit button on nested form submits the outer form in IE7

    - by Mike Christensen
    I have the following code on my Home.aspx page: <form id="frmJump" method="post" action="Views/ViewsHome.aspx"> <input name="JumpProject" /><input type="submit" value="Go" /> </form> However, when I click the "Go" button, the page posts back to Home.aspx rather than going to ViewsHome.aspx. I even tried adding some script to force the form to submit: <input name="JumpProject" onkeypress="if(event.keyCode == 13) { this.form.submit(); return false; }" /> But still even if I press ENTER, the Home.aspx page is reloaded. The only thing I can see that might be borking things is this form is actually a child form of the main POSTBACK form that ASP.NET injects into the page. I'm sure there's something stupid I'm missing and this post will get 800 downvotes instantly banishing me back into the n00b realm, but perhaps I haven't gotten enough sleep lately and I'm missing something stupid. This is on IE7 and an ASP.NET 4.0 backend. I also have jQuery libraries loaded on the page incase jQuery can improve this somehow. Thanks!

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  • How to protect a form HTML/PHP with JS callback to AS3

    - by Jk_
    Hi guys, I'm developing a Flash website (as3) where I need to be able to upload directly to YouTube by using the DATA API. However in order to do so, I had to use a proper HTML form on top of my flash object. Why? Because of the Browser Based Upload restictions. I first hide the form using JQuery and with a little CSS the form is display just where I want it. Within flash I use ExternalInterface.call() to show/hide the form when I need it! ExternalInterface.call("YTUploader.showIt"); The upload process is working great my only problem is that the form can be displayed easily... You just need a tool like firebug and you can use the form wherever you want on my flash app. So I was wandering which will be the best way to 'protect' this form or the best way to limit its access. Any advices will be appreciated. Thanks for your time. Jk.

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  • Filtering results and pagination

    - by alj
    I have a template that shows a filter form and below it a list of the result records. I bind the form to the request so that the filter form sets itself to the options the user submitted when the results are returned. I also use pagination. Using the code in the pagination documentation means that when the user clicks for the next page, the form data is lost. What is the best way of dealing with pagination and filtering in this way? Passing the querystring to the paginiation links. Change the pagination links to form buttons and therefore submit the filter form at the same time, but this assumes that the user hasn't messed about with the filter options. As above but with the original data as hidden fields. ALJ

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  • Codeigniter Form Validation - how to unset form values after success?

    - by BrynJ
    I realise this request goes against the example provided in the CI documentation (which advises a separate 'success' page view), but I would like to reutilise a given form view after a form has been successfully submitted - displaying a success message then displaying a blank form. I've tried a few ways unsuccessfully to clear the validation set values (unsetting $_POST, setting rules / fields to an empty array and rerunning validatio). I could redirect to the same page, but then I'd have to set a session variable to display a success message - which is a messy approach. Any ideas how to achieve the above?

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  • Sending Javascript variables.

    - by shinjuo
    I have a page that allows a user to choose some things in a form and it will calculate the weight using javascript. It breaks it up into 5 variables that I need to send to another page. Originally I was just having it put the variable into a text box and then I was posting that text box. However I dont want to have 5 text boxes. So now I need to somehow send or post the five variables to another page. Here is my javascript function. I need to post weightBoxOne - weightBoxFive js function function getWeight(){ var weightBoxOne; var weightBoxTwo; var totalWeight; var box = .5; var quantity = document.dhform.quantity.value; var cardSize = document.dhform.cardSize.value; if(cardSize == 0.0141){ if(quantity <= 1000){ weightBoxOne = (quantity * cardSize) + box; totalWeight = weightBoxOne; }else if(quantity > 1000 && quantity <= 2000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = ((quantity - 1000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo; }else if(quantity > 2000 && quantity <= 3000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = ((quantity - 2000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree; }else if(quantity > 3000 && quantity <= 4000){ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = (1000 * cardSize) + box; weightBoxFour = ((quantity - 3000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree + weightBoxFour; }else{ weightBoxOne = (1000 * cardSize) + box; weightBoxTwo = (1000 * cardSize) + box; weightBoxThree = (1000 * cardSize) + box; weightBoxFour = (1000 * cardSize) + box; weightBoxFive = ((quantity - 4000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo + weightBoxThree + weightBoxFour + weightBoxFive; } }else if(cardSize == 0.00949){ if(quantity <= 4000){ weightBoxOne = (quantity * cardSize) + box; totalWeight = weightBoxOne; }else{ weightBoxOne = (4000 * cardSize) + box; weightBoxTwo = ((quantity - 4000) * cardSize) + box; totalWeight = weightBoxOne + weightBoxTwo; } } document.rates.weight.value = totalWeight; } //--> this is the form that was originally posting <form action="getRates.php" name="rates" method="post" onSubmit="popupform(this, 'join')"> <table style="width: 216px"> <tr> <td style="width: 115px; height: 49px;"><span class="style16">Weight</span><br/> <input type="text" id="weight" name="weight" size="10" maxlength="4"/> </td> <td align="right" style="width: 68px; height: 49px;" valign="top"><span class="style16">Zip Code</span><br/> <input type="text" id="zip" name="zip" size="10" maxlength="5"/> </td> </tr> <tr> <td style="width: 115px"> <input name="submit" type="submit" value="Get Rate Costs" style="width: 138px" />

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  • This code is not submitting to a form? Why

    - by Ankur
    Since I am using get I expect to see the submitted values appended to the queryString but instead all I see is the URL of the servlet being called with nothing added at the end. <form id="editClassList" name="editClassList" method="get" action="EditClassList"> <% HashMap<Integer,String> classes = new HashMap<Integer,String>(); classes = (HashMap<Integer,String>) request.getAttribute("classes"); %> <% if(classes.size()==0){ %> <label><input class="small-link" type="text" id="add-this-class" size="42" value="" /></label> <% } %> <% Set<Integer> classIds = new HashSet<Integer>(); classIds = classes.keySet(); Iterator<Integer> itr = classIds.iterator(); while(itr.hasNext()){ int nextId = (Integer)itr.next(); %> <label><input class="small-link" type="text" id="<% out.print(nextId); %>" size="42" value="<% out.print(classes.get(nextId)); %>" /> </label> <img id="add-class" src="images/add.png" width="16" height="16" /><br /> <label><input class="small-link" type="text" id="class-to-add" size="42" value="" /></label> <% } %> <label><input type="submit" id="save-class-btn" value="Save Class(es)" /></label> </form>

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  • javascript check function for a html form

    - by Reteras Remus
    I'm having a problem with a HTML form (name, e-mail, subject, message), I can't validate the form if it was completed correct or not. I want to call a javascript function when the form is submitted and alert if a field wasn't completed correct. My problem is with the submit button, because my boss said that I must use he's own php function to insert a submit button. The php function looke like: function normal_button($text, $width, $param = '', $class = 'button-blue') { $content = '<div class="'.$class.'" style="width:'.$width.'px;" '.$param.'>'.$text.'</div>'; return $content; } and how I call the function: echo normal_button('Send it', '100', 'onclick="document.getElementById(\'emailForm\').submit();" '); I tried to call the js function declaring the onSubmit="return checkForm(this)" in the <form action='email.php' method='post'> HTML form, but I can't "catch" the submit. Also I tried to catch it with jquery, $(document).ready(function() { $('.normal_button').click(function() { }); ); but I can't return false if a field wasn't completed correct. I must use he's PHP function to insert the submit button, but how can I "catch" the fields, how can I validate them? Any suggestions? Thank you !

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  • How do I prevent form from redirecting after submission?

    - by Noor
    I have searched the site and I've found various solutions, most of them suggesting using return false; Problem is that I'm using this piece of code to submit the form: $(function() { $("#snd").click(function() { var dendar = "http://" + $("#inpt").val() + ":" + $("#pwd").val() + "secretsite.lol/something.xml"; $("#formen").attr("action", dendar); $("#formen").submit(); alert(dendar); return false; }); }); The alert is just there to let me know that the form has been submitted.. Thanks guys!

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  • JS Display Content based on Dropdown User input

    - by Thomas
    I am working on a search box that displays different options based on a users selection via dropdown box. Basically I need a really clean, light-weight method for switching out different divs without reloading the page. Im new to JS, but I know enough that there should be some really simple way of setting the display property using JS - Im just not totally sure how to go about it. Any help would be really appreciated, thanks.

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  • How to automatically select the selected item in list menu after submitting the form?

    - by SzamDev
    Hi I have this code : <form id="form2" name="form2" method="post" action=""> <table dir="ltr" width="554" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td width="269" class="da"><div align="center"><span id="spryselect1"> <select onchange="form2.submit()" name="mpage" id="mpage"> <option selected="selected" value="no">-----------</option> <option value="medmo">Medmo.com</option> <option value="paris">Paris.com</option> <option value="imo">IMO.com</option> </select> </span></div></td> <td width="214" class="t_b">Select Website</td> </tr> </table> </form> When the user select a value, the form will automatically submit, I want the item that the user has selected to be selected after submitting the form. Because I am facing this proplem: The user select the first item (Medmo.com) - form submit - selected item will be "-------" I want this to happen : The user select the first item (Medmo.com) - form submit - selected item will be "Medmo.com" How I can do that? Thanks in Advance.

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  • Django extending user model and displaying form

    - by MichalKlich
    Hello, I am writing website and i`d like to implement profile managment. Basic thing would be to edit some of user details by themself, like first and last name etc. Now, i had to extend User model to add my own stuff, and email address. I am having troubles with displaying form. Example will describe better what i would like achieve. This is mine extended user model. class UserExtended(models.Model): user = models.ForeignKey(User, unique=True) kod_pocztowy = models.CharField(max_length=6,blank=True) email = models.EmailField() This is how my form looks like. class UserCreationFormExtended(UserCreationForm): def __init__(self, *args, **kwargs): super(UserCreationFormExtended, self).__init__(*args, **kwargs) self.fields['email'].required = True self.fields['first_name'].required = False self.fields['last_name'].required = False class Meta: model = User fields = ('username', 'first_name', 'last_name', 'email') It works fine when registering, as i need allow users to put username and email but when it goes to editing profile it displays too many fields. I would not like them to be able to edit username and email. How could i disable fields in form? Thanks for help.

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  • Writing custom Django form fields and widgets

    - by hekevintran
    Django has very good documentation that describes how to write custom database fields and custom template tags and filters. I cannot find the document that describes how to write custom form fields and widgets. Does this document exist? The way I've been able to write custom form fields and widgets is by reading the Django source code and imitating what I see there. I know that there are still things about implementing fields and widgets that I do not completely understand because I have not read any high level document that describes their interfaces.

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  • Form is creating already loaded attributes in addition to new attributes, how do I ignore the first?

    - by looloobs
    In my application you: Have an admin user that signs on and that user has a role (separate model), then I use the declarative_authorization plugin to give access to certain areas. That admin user can also register new users in the system, when they do this (using Authlogic) they fill out a nested form that includes that new users' role. So what is happening is the role of the admin user is being loaded by the declarative_authorization and then the nested form using the has_many_nested_attributes is loading that existing role as well as the new role for the new user (users can have many roles). Is there some way I can tell the new User being created to ignore the role assigned to the current_user and only create the role in the form for the new user? I have looked through a lot of different things, but it seems to get more complicated that these are nested attributes. Thanks in advance.

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  • Livevalidation: only validate when default value is changed

    - by usr122212
    Hello there! I am validating my html form with livevalidation and everything works great except for one feature. I have a input field with a default value age, I only want the livevalidation to validate when it says something other than "age". so maybe the user will type in 20 then the validation will fire checking its things but if left as "age" it won't check it all. But as of now, it just checks everything with a validation script and this is a problem for me as I have lots of fields in my form and some of them are optional so when I hit submit, the livevalidation checks the age field as well even if the user didnt touch it to begin with. Would this be possible with livevalidation ? Thanks for the help.

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  • Submit pdf form fields to a HTTP POST request

    - by Josjojo
    I've made a pdf form in Adobe Acrobat. Now I want to make a button that submits the form to a HTTP POST request. I have searched for about 4 hours, but I have not found an example to do this. Here I read that it is possible to send the pdf form fields with a HTTP submission, but there's also no example given: http://acrobatusers.com/tutorials/form-submit-e-mail-demystified I'm looking for a JavaScript example that I can link to the submit button.

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  • How to convert submitted form array to this array on php?

    - by drfanai
    Lets suppose i have the following array submitted by a html form: array( 'firstname' => array('Sara','Jim'), 'lastname' => array('Gibson','Jobs') ); What i wanna achieve is the following array: array( array( 'firstname' => 'sara', 'lastname' => 'Gibson' ), array( 'firstname' => 'Jim', 'lastname' => 'Jim' ) ); I need a function to automatically sort the array not manually by entering data but automatically processing array data.

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  • JS: Storing dynamic variables across pages?

    - by user2467599
    I've been looking into local storage options and plugins like Persist.js, sessvars.js, and even sisyphus.js - but I am unsure if any are the best fit (though I'm fairly certain I need to use one). Page one is a form with input fields for data like names, phones, and email. I have a button that replicates a wrapper div (and it's inputs) as long as more inputs are needed. When the form is filled the user hits submit which takes them to a 'confirmation' type php page. I need to the give the user an 'edit' button on page 2 that takes them back to page 1 and leaves all the info alone. For the most part everything returns fine, but if the user had hit the 'replicate' button before submission, and then hits edit afterwards, all the inputs that were dynamically generated return empty and the div no longer exists. Someone suggested that my variables are not persistent (when the replicate button is hit, input with an id="name1" becomes "name2" and so on) so that's when I found out about the plugins mentioned before. Is there a way that I can implement one of those plugins (or any other method) so that when the user returns to page one the div and it's input values remain unchanged? And if I'm on the right track are there any examples?

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