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  • EC2 Amazon Linux AMI MySQL CPU @ 62% When Idle?

    - by Jeff
    I am running MySQL on an Amazon Linux AMI. There is nothing connected to it. There are no connections and no other applications running that use MySQL. It is completely idle, but yet, top is reporting that mysql is using 62% of the CPU? Why is this happening and how do I fix it? Cpu(s): 0.2%us, 0.2%sy, 0.0%ni, 97.8%id, 0.0%wa, 0.0%hi, 0.0%si, 1.7%st Mem: 1738504k total, 390708k used, 1347796k free, 56888k buffers Swap: 917500k total, 0k used, 917500k free, 229804k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 2959 mysql 20 0 466m 39m 5244 S 62.2 2.3 4:00.67 mysqld 1 root 20 0 19252 1504 1212 S 0.0 0.1 0:00.20 init 2 root 20 0 0 0 0 S 0.0 0.0 0:00.00 kthreadd There are no connections... mysql> show processlist; +----+------+-----------+------+---------+------+-------+------------------+ | Id | User | Host | db | Command | Time | State | Info | +----+------+-----------+------+---------+------+-------+------------------+ | 5 | root | localhost | NULL | Query | 0 | NULL | show processlist | +----+------+-----------+------+---------+------+-------+------------------+

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  • SQL SERVER – UNION ALL and ORDER BY – How to Order Table Separately While Using UNION ALL

    - by pinaldave
    I often see developers trying following syntax while using ORDER BY. SELECT Columns FROM TABLE1 ORDER BY Columns UNION ALL SELECT Columns FROM TABLE2 ORDER BY Columns However the above query will return following error. Msg 156, Level 15, State 1, Line 5 Incorrect syntax near the keyword ‘ORDER’. It is not possible to use two different ORDER BY in the UNION statement. UNION returns single resultsetand as per the Logical Query Processing Phases. However, if your requirement is such that you want your top and bottom query of the UNION resultset independently sorted but in the same resultset you can add an additional static column and order by that column. Let us re-create the same scenario. First create two tables and populated with sample data. USE tempdb GO -- Create table CREATE TABLE t1 (ID INT, Col1 VARCHAR(100)); CREATE TABLE t2 (ID INT, Col1 VARCHAR(100)); GO -- Sample Data Build INSERT INTO t1 (ID, Col1) SELECT 1, 'Col1-t1' UNION ALL SELECT 2, 'Col2-t1' UNION ALL SELECT 3, 'Col3-t1'; INSERT INTO t2 (ID, Col1) SELECT 3, 'Col1-t2' UNION ALL SELECT 2, 'Col2-t2' UNION ALL SELECT 1, 'Col3-t2'; GO If we SELECT the data from both the table using UNION ALL . -- SELECT without ORDER BY SELECT ID, Col1 FROM t1 UNION ALL SELECT ID, Col1 FROM t2 GO We will get the data in following order. However, our requirement is to get data in following order. If we need data ordered by Column1 we can ORDER the resultset ordered by Column1. -- SELECT with ORDER BY SELECT ID, Col1 FROM t1 UNION ALL SELECT ID, Col1 FROM t2 ORDER BY ID GO Now to get the data in independently sorted in UNION ALL let us add additional column OrderKey and use ORDER BY  on that column. I think the description does not do proper justice let us see the example here. -- SELECT with ORDER BY - with ORDER KEY SELECT ID, Col1, 'id1' OrderKey FROM t1 UNION ALL SELECT ID, Col1, 'id2' OrderKey FROM t2 ORDER BY OrderKey, ID GO The above query will give the desired result. Now do not forget to clean up the database by running the following script. -- Clean up DROP TABLE t1; DROP TABLE t2; GO Here is the complete script used in this example. USE tempdb GO -- Create table CREATE TABLE t1 (ID INT, Col1 VARCHAR(100)); CREATE TABLE t2 (ID INT, Col1 VARCHAR(100)); GO -- Sample Data Build INSERT INTO t1 (ID, Col1) SELECT 1, 'Col1-t1' UNION ALL SELECT 2, 'Col2-t1' UNION ALL SELECT 3, 'Col3-t1'; INSERT INTO t2 (ID, Col1) SELECT 3, 'Col1-t2' UNION ALL SELECT 2, 'Col2-t2' UNION ALL SELECT 1, 'Col3-t2'; GO -- SELECT without ORDER BY SELECT ID, Col1 FROM t1 UNION ALL SELECT ID, Col1 FROM t2 GO -- SELECT with ORDER BY SELECT ID, Col1 FROM t1 UNION ALL SELECT ID, Col1 FROM t2 ORDER BY ID GO -- SELECT with ORDER BY - with ORDER KEY SELECT ID, Col1, 'id1' OrderKey FROM t1 UNION ALL SELECT ID, Col1, 'id2' OrderKey FROM t2 ORDER BY OrderKey, ID GO -- Clean up DROP TABLE t1; DROP TABLE t2; GO I am sure there are many more ways to achieve this, what method would you use if you have to face the similar situation? Reference: Pinal Dave (http://blog.sqlauthority.com)   Filed under: Best Practices, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • MySQL Connect in 4 Days - Sessions From Users and Customers

    - by Bertrand Matthelié
    72 1024x768 Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Cambria","serif";} Let’s review today the conference sessions where users and customers will describe their use of MySQL as well as best practices. Remember you can plan your schedule with Schedule Builder. Saturday, 11.30 am, Room Golden Gate 7: MySQL and Hadoop—Chris Schneider, Ning.com Saturday, 1.00 pm, Room Golden Gate 7: Thriving in a MySQL Replicated World—Ed Presz and Andrew Yee, Ticketmaster Saturday, 1.00 pm, Room Golden Gate 8: Rick’s RoTs (Rules of Thumb)—Rick James, Yahoo! Saturday, 2.30 pm, Room Golden Gate 3: Scaling Pinterest—Yashwanth Nelapati and Evrhet Milam, Pinterest Saturday, 4.00 pm, Room Golden Gate 3: MySQL Pool Scanner: An Automated Service for Host Management—Levi Junkert, Facebook Sunday, 10.15 am, Room Golden Gate 3: Big Data Is a Big Scam (Most of the Time)—Daniel Austin, PayPal Sunday, 11.45 am, Room Golden Gate 3: MySQL at Twitter: Development and Deployment—Jeremy Cole and Davi Arnaut, Twitter Sunday, 1.15 pm, Room Golden Gate 3: CERN’s MySQL-as-a-Service Deployment with Oracle VM: Empowering Users—Dawid Wojcik and Eric Grancher, DBA, CERN Sunday, 2.45 pm, Room Golden Gate 3: Database Scaling at Mozilla—Sheeri Cabral, Mozilla Sunday, 5.45 pm, Room Golden Gate 4: MySQL Cluster Carrier Grade Edition @ El Chavo, Latin America’s #1 Facebook Game—Carlos Morales, Playful Play You can check out the full program here as well as in the September edition of the MySQL newsletter. Not registered yet? You can still save US$ 300 over the on-site fee – Register Now!

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  • MySQL documentation writer for MEM and Replication wanted!

    - by stefanhinz
    As MySQL is thriving and growing, we're looking for an experienced technical writer located in the UK or Ireland to join the MySQL documentation team. For this job, we need the best and most dedicated people around. You will be part of a geographically distributed documentation team responsible for the technical documentation of all MySQL products. Team members are expected to work independently, requiring discipline and excellent time-management skills as well as the technical facilities and experience to communicate across the Internet. Candidates should be prepared to work intensively with our engineers and support personnel. The overall team is highly distributed across different geographies and time zones. Our source format is DocBook XML. We're not just writing documentation, but also handling publication. This means you should be familiar with DocBook, and willing to learn our publication infrastructure. Your areas of responsibility would initially be MySQL Enterprise Monitor, and MySQL Replication. This means you should be familiar with MySQL in general, and preferably also with the MySQL Enterprise offerings. A MySQL certification will be considered an advantage. Other qualifications you should have: Native English speaker 5 or more years previous experience in writing software documentation Familiarity with distributed working environments and versioning systems such as SVN Comfortable with working on multiple operating systems, particularly Windows, Mac OS X, and Linux Ability to administer own workstations and test environment Excellent written and oral communication skills Ability to provide (online) samples of your work, e.g. books or articles If you're interested, contact me under [email protected]. For reference, the job offer can be viewed here.

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  • Building MySQL with boost on windows

    - by user13177919
    As you've probably heard already MySQL needs boost to build. However, in the good ol' MySQL tradition, the above link does give you only the instructions on how to build it on linux. And completely ignores the fact that there're other OSes too that people develop on. To fill in that gap, I've compiled a small step by step guide on how to do it on windows. Note that I always, as a principle, build out-of-source. The typical setup I have is : bzr clone lp:~mysql/mysql-server/5.7 mysql-trunkcd mysql-trunkmkdir bldcd bldcmake -DWITH_DEBUG=1 -DMYSQL_PROJECT_NAME=mysql-trunk ..devenv /build debug mysql-trunk.sln This has been tested to work on a 32 bit compile using VS2013 on a Windows7 64 bit build. Note that you'll need other things too (bison, eventually openssl etc) that I will assume you already have set up. Steps: Download Boost 1.55.0. It's the *only* version that is known to work currently. Extract boost_1_55_0/ from the zip to c:\boost\boost_1_55_0 Go to Control Panel/System/Environment variables and set WITH_BOOST=C:\boost\boost_1_55_0 in User variables. Make sure you restart your open command line terminal windows after this !  If you're upgrading from non-boost build, remove your bld/ directory and create a new one. run cmake as you'd typically do. You should get: -- Local boost dir C:/boost/boost_1_55_0 -- Local boost zip LOCAL_BOOST_ZIP-NOTFOUND -- BOOST_VERSION_NUMBER is #define BOOST_VERSION 105500 -- BOOST_INCLUDE_DIR C:/boost/boost_1_55_0 Build as normal (devenv /build debug ...). It should work.

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  • javascript select box hanging on second select in ie7

    - by bsandrabr
    I have a drop down select box inside a div. When the user clicks on change, a dropdown box appears next to the change/submit button and the user makes a selection which then updates the db and the selection appears instead of the dropdown. All works fine in IE8 and firefox but in IE7 it allows one selection (there are several identical dropdowns) but the second time a selection is made it hangs on please wait. This is the relevant code <td width=200> <input type="button" onclick="startChanging(this)" value="Change" /></td> <script type="text/javascript"> var selectBox, isEditing = false; var recordvalue; if( window.XMLHttpRequest ) { recordvalue = new XMLHttpRequest(); } else if( window.ActiveXObject ) { try { recordvalue = new ActiveXObject('Microsoft.XMLHTTP'); } catch(e) {} } window.onload = function () { selectBox = document.getElementById('changer'); selectBox.id = ''; selectBox.parentNode.removeChild(selectBox); }; function startChanging(whatButton) { if( isEditing && isEditing != whatButton ) { return; } //no editing of other entries if( isEditing == whatButton ) { changeSelect(whatButton); return; } //this time, act as "submit" isEditing = whatButton; whatButton.value = 'Submit'; var theRow = whatButton.parentNode.parentNode; var stateCell = theRow.cells[3]; //the cell that says "present" stateCell.className = 'editing'; //so you can use CSS to remove the background colour stateCell.replaceChild(selectBox,stateCell.firstChild); //PRESENT is replaced with the select input selectBox.selectedIndex = 0; } function changeSelect(whatButton) { isEditing = true; //don't allow it to be clicked until submission is complete whatButton.value = 'Change'; var stateCell = selectBox.parentNode; var theRow = stateCell.parentNode; var editid = theRow.cells[0].firstChild.firstChild.nodeValue; //text inside the first cell var value = selectBox.firstChild.options[selectBox.firstChild.selectedIndex].value; //the option they chose selectBox.parentNode.replaceChild(document.createTextNode('Please wait...'),selectBox); if( !recordvalue ) { //allow fallback to basic HTTP location.href = 'getupdate.php?id='+editid+'&newvalue='+value; } else { recordvalue.onreadystatechange = function () { if( recordvalue.readyState != 4 ) { return; } if( recordvalue.status >= 300 ) { alert('An error occurred when trying to update'); } isEditing = false; newState = recordvalue.responseText.split("|"); stateCell.className = newState[0]; stateCell.firstChild.nodeValue = newState[1] || 'Server response was not correct'; }; recordvalue.open('GET', "getupdate.php?id="+editid+"&newvalue="+value, true); recordvalue.send(null); } } </script> If anyone has any idea why this is happening I'd be very grateful

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  • Automatically select option from select menu with link

    - by Ben
    Hello there, I am trying to use php (and if not php, javascript) to link to a page and include a "?type=foo" or "#foo" at the end of the link so that when the linked page loads it will automatically select a specific option, depending on the end of the link, from a dropdown menu in a form. I have tried to search for this but do not know what this action is actually called, but I've seen it done before. Does anyone know how to achieve this? Thanks very much.

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  • Which of the following relational database management systems would a company adopt (for migration), if any, MS Access, MS SQL Server or MySQL?

    - by Hassan Hagi
    Dear programmers, as part of my final year university project, I am conducting research into relational database management systems such as Microsoft Office Access 2007, Microsoft SQL Server 2008 and MySQL 5.1. The description does not need to be detailed however; I am trying to find empirical evidence and professional opinion/fact to determine which of the three databases are best suited for the required size of company (stated or unstated). OS: Microsoft windows (XP or newer) Please consider the following, but full details are not necessary: Memory management Migration Design constraints Integrity (data and others) Triggers User constraints Ease of use Performance Crash Recovery (not the operating system) Total Cost of Ownership (TCO) Also any info on Open source (to do with the three RDBMS) Thank you for your time and help. Hassan Hagi

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  • 127.0.0.1:9051 doesnt work after apache, mysql, php installation?

    - by Rana Muhammad Waqas
    I have installed apache2, mysql, and php and now it doesnt let Vidalia run on localhost. i tried to change the TCP connection (controlport) to any other ip 192.168.0.40 and tried to change the default port 9051 to any other but that doesnt work. I thought apache is running so i used this command sudo service apache2 stop but that still doesnt work. So now when i type 127.0.0.1:9051 in browser it says and if i type only type 127.0.0.1 after stopping the apapche2 service with the command mentioned above it says unable to connect I am not sure what to do now Help!

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  • What is the best way to INSERT a large dataset into a MySQL database (or any database in general)

    - by Joe
    As part of a PHP project, I have to insert a row into a MySQL database. I'm obviously used to doing this, but this required inserting into 90 columns in one query. The resulting query looks horrible and monolithic (especially inserting my PHP variables as the values): INSERT INTO mytable (column1, colum2, ..., column90) VALUES ('value1', 'value2', ..., 'value90') and I'm concerned that I'm not going about this in the right way. It also took me a long (boring) time just to type everything in and testing writing the test code will be equally tedious I fear. How do professionals go about quickly writing and testing these queries? Is there a way I can speed up the process?

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  • How can I make my Java desktop application to run on different computers in a network locally and updating same mysql database?

    - by JaMpa
    I have developed Java desktop application for registration of students in the computer laboratories in our college, but what I need is to make this application whenever it runs on any computer (Windows XP machines) on the laboratory each and every data filled by the college students goes to the same MySql database (through WAMP server) running on the server machine (Win Server 2003). Also, I need this application to run during booting of windows computers in the laboratory for the purpose when any student tries to switch on any PC in the comp lab before interfacing the desktop icons should sign in through user name and password when he has already registered or signing up in order for getting the access.

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  • showing null rows using join

    - by Pradyut Bhattacharya
    Hi, In mysql i m selecting from a table shouts having a foreign key to another table named "roleuser" with the matching column as user_id Now the user_id column in the shouts table for some rows is null (not actually null but with no inserts in mysql) How to show all the rows of the shouts table either with user_id null or not I m executing the sql statement SELECT s.*, r.firstname, r.lastname FROM shouts s left join roleuser r where r.user_id = s.user_id limit 50; which does not executes and shows You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'where r.user_id = s.user_id limit 50' at line 2 but using inner join the sql executes which shows rows which only have user_id values in the shouts table. the nulls are not shown. SELECT s.*, r.firstname, r.lastname FROM shouts s inner join roleuser r where r.user_id = s.user_id limit 50; How can i show all the rows from the shouts table and null values in the firstname and lastname columns where the user_id is null in the shouts table. If not at all possible with sql may be using stored procedures... Thanks Pradyut

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  • Getting percentage of "Count(*)" to the number of all items in "GROUP BY"

    - by celalo
    Let's say I need to have the ratio of "number of items available from certain category" to "the the number of all items". Please consider a MySQL table like this: /* mysql> select * from Item; +----+------------+----------+ | ID | Department | Category | +----+------------+----------+ | 1 | Popular | Rock | | 2 | Classical | Opera | | 3 | Popular | Jazz | | 4 | Classical | Dance | | 5 | Classical | General | | 6 | Classical | Vocal | | 7 | Popular | Blues | | 8 | Popular | Jazz | | 9 | Popular | Country | | 10 | Popular | New Age | | 11 | Popular | New Age | | 12 | Classical | General | | 13 | Classical | Dance | | 14 | Classical | Opera | | 15 | Popular | Blues | | 16 | Popular | Blues | +----+------------+----------+ 16 rows in set (0.03 sec) mysql> SELECT Category, COUNT(*) AS Total -> FROM Item -> WHERE Department='Popular' -> GROUP BY Category; +----------+-------+ | Category | Total | +----------+-------+ | Blues | 3 | | Country | 1 | | Jazz | 2 | | New Age | 2 | | Rock | 1 | +----------+-------+ 5 rows in set (0.02 sec) */ What I need is basically a result set resembles this one: /* +----------+-------+-----------------------------+ | Category | Total | percentage to the all items | (Note that number of all available items is "9") +----------+-------+-----------------------------+ | Blues | 3 | 33 | (3/9)*100 | Country | 1 | 11 | (1/9)*100 | Jazz | 2 | 22 | (2/9)*100 | New Age | 2 | 22 | (2/9)*100 | Rock | 1 | 11 | (1/9)*100 +----------+-------+-----------------------------+ 5 rows in set (0.02 sec) */ How can I achieve such a result set in a single query? Thanks in advance.

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  • Creating PHP strings using other variables...works manually, can't figure out how automatically

    - by Matt
    Hello, I'm trying to get a variable to be formed automatically using data pulled from a mysql database. I know the data is being pulled from the database in some form resembling its original form, but that data does not act the same as data that is manually typed and assigned to a string. For example, if a cell in a mysql table says... I said "goodbye" before I left. She also said "goodbye." ...and I manually copy/paste it and add the necessary escapes... $string1 = " I said \"goodbye\" before I left. She also said \"goodbye.\" "; ...that does not equal... $string1 = $mysqlResultArray['specificCellWithQuoteShownAbove'] Interestingly, if I echo both versions of $string1 and view the output, they appear to be exactly the same. But they do not function the same when put through various functions I've created. The functions only work if I do the manual copy/paste method--which is not what I want, obviously. I'm not sure if it has to do with the line breaks or the escapes--or some combination of the two. But while both strings are superficially the same, they are apparently functionally different and I don't know why. So how can I create $string1 without manually copy/pasting the contents from the mysql entry and instead querying for the data and assigning it to $string1 in such a way that it's exactly functionally equivalent as the manual copy/pasted string?

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  • Ordering by number of rows?

    - by Rob
    Alright, so I have a table outputting data from a MySQL table in a while loop. Well one of the columns it outputs isn't stored statically in the table, instead it's the sum of how many times it appears in a different MySQL table. Sorry I'm not sure this is easy to understand. Here's my code: $query="SELECT * FROM list WHERE added='$addedby' ORDER BY time DESC"; $result=mysql_query($query); while($row=mysql_fetch_array($result, MYSQL_ASSOC)){ $loghwid = $row['hwid']; $sql="SELECT * FROM logs WHERE hwid='$loghwid' AND time < now() + interval 1 hour"; $query = mysql_query($sql) OR DIE(mysql_error()); $boots = mysql_num_rows($query); //Display the table } The above is the code displaying the table. As you can see it's grabbing data from two different MySQL tables. However I want to be able to ORDER BY $boots DESC. But as its a counting of a completely different table, I have no idea of how to go about doing that. I would appreciate any help, thank you.

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  • multiple mysql_real_query() in while loop

    - by Steve
    It seems that when I have one mysql_real_query() function in a continuous while loop, the query will get executed OK. However, if multiple mysql_real_query() are inside the while loop, one right after the other. Depending on the query, sometimes neither the first query nor second query will execute properly. This seems like a threading issue to me. I'm wondering if the mysql c api has a way of dealing with this? Does anyone know how to deal with this? mysql_free_result() doesn't work since I am not even storing the results. //keep polling as long as stop character '-' is not read while(szRxChar != '-') { // Check if a read is outstanding if (HasOverlappedIoCompleted(&ovRead)) { // Issue a serial port read if (!ReadFile(hSerial,&szRxChar,1, &dwBytesRead,&ovRead)) { DWORD dwErr = GetLastError(); if (dwErr!=ERROR_IO_PENDING) return dwErr; } } // Wait 5 seconds for serial input if (!(HasOverlappedIoCompleted(&ovRead))) { WaitForSingleObject(hReadEvent,RESET_TIME); } // Check if serial input has arrived if (GetOverlappedResult(hSerial,&ovRead, &dwBytesRead,FALSE)) { // Wait for the write GetOverlappedResult(hSerial,&ovWrite, &dwBytesWritten,TRUE); //load tagBuffer with byte stream tagBuffer[i] = szRxChar; i++; tagBuffer[i] = 0; //char arrays are \0 terminated //run query with tagBuffer if( strlen(tagBuffer)==PACKET_LENGTH ) { sprintf(query,"insert into scan (rfidnum) values ('"); strcat(query, tagBuffer); strcat(query, "')"); mysql_real_query(&mysql,query,(unsigned int)strlen(query)); i=0; } mysql_real_query(&mysql,"insert into scan (rfidnum) values ('2nd query')",(unsigned int)strlen("insert into scan (rfid) values ('2nd query')")); mysql_free_result(res); } }

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  • jqGrid dynamic select option - beforeEditCell not firing

    - by mango
    I'm creating a jqgrid with one drop down column. I need the options of the drop down columns to change dynamically so I thought I can catch the beforeCellEdit event. however it does not seem to be firing. any idea on what i am doing wrong? there is no error, and i did check that i have included the jqgrid edit js files. var lastsel2; jQuery(document).ready(function(){ jQuery("#projectList").jqGrid({ datatype: 'json', url:'projectDrv.jsp', mtype: 'GET', height: 250, colNames:['Node','Proposal #', 'Status', 'Vendor', 'Actions'], colModel :[ {name:'node', index:'node', width:100, editable:false, sortable:false}, {name:'proposal', index:'proposal', width:100, editable:false, resizable:true }, {name:'status', index:'status', width:100, resizable:true, sortable:false, editable:false }, {name:'vendor', index:'vendor', width:100, resizable:true, editable:false, sortable: false }, {name:'actions', index:'actions', width:100, resizable:true, sortable:false, editable: true, edittype:"select" } ], pager: '#pager', rowNum: 10, sortname: 'proposal', sortorder: 'desc', viewrecords: true, onSelectRow: function(id){ if (id && id!==lastsel2){ jQuery('#projectList').jqGrid('restoreRow',lastsel2); jQuery('#projectList').jqGrid('editRow',id,true); lastsel2 = id; } }, beforeEditCell: function(rowid, cellname, value, irow, icol) { alert("before edit here " + rowid); // set editoptions here } });

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  • MySQL Interview Questions

    - by Campbell
    Hi, I've been asked to screen some candidates for a MySQL DBA / Developer position for a role that requires an enterprise level skill set. I myself am a SQL Server person so I know what I would be looking for from that point of view with regards to scalability / design etc but is there anything specific I should be asking with regards to MySQL? I would ideally like to ask them about enterprise level features of MySQL that they would typically only use when working on a big database. Need to separate out the enterprise developers from the home / small website kind of guys. Thanks.

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  • django select max field from mysql when column is varchar

    - by doza
    Hi, Using Django 1.1, I am trying to select the maximum value from a varchar column (in MySQL.) The data stored in the column looks like: 9001 9002 9017 9624 10104 11823 (In reality, the numbers are much bigger than this.) This worked until the numbers incremented above 10000: Feedback.objects.filter(est__pk=est_id).aggregate(sid=Max('sid')) Now, that same line would return 9624 instead of 11823. I'm able to run a query directly in the DB that gives me what I need, but I can't figure out the best way to do this in Django. The query would be: select max(sid+0) from Feedback; Any help would be much appreciated. Thanks!

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  • fluent nhibernate select n+1 problem

    - by Andrew Bullock
    I have a fairly deep object graph (5-6 nodes), and as I traverse portions of it NHProf is telling me I've got a "Select N+1" problem (which I do). The two solutions I'm aware of are Eager load children Break apart my object graph (and eager load) I don't really want to do either of these (although I may break the graph apart later as I forsee it growing) For now.... Is it possible to tell NHibernate (with fluentnhib) that whenever i try to access children, to load them all in one go, instead of selectn+1ing as i iterate over them? I'm also getting "unbounded results set"s, which is presumably the same problem (or rather, will be solved by the above solution if possible). Each child collection (throughout the graph) will only ever have about 20 members, but 20^5 is a lot, so i dont want to eager load everything when i get the root, but simply get all of a child collection whenever i go near it Edit: an afterthought.... what if i want to introduce paging when i want to render children? do i HAVE to break my object graph here, or is there some sneakyness i can employ to solve all these issues?

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  • Can I force MySql table name case sensitivity on file systems that aren't case sensitive

    - by Brian Deacon
    So our target environment is linux, making mysql case-sensitive by default. I am aware that we can make our linux environment not case sensitive with the lower_case_table_names variable, but we would rather not. We have a few times been bitten with a case mismatch because our dev rigs are OSX, and mysql is not case sensitive there. Is there a way we can force table names to be case sensitive on my OSX install of MySql (5.0.83 if that matters) so that we catch a table name case mismatch prior to deploying to the integration servers running on linux?

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  • MySQL differences between to select queries

    - by bpmccain
    I have two mysql queries that return a column of phone numbers. I want am trying to end up with a list of phone numbers that are in one list, but not in the other. So the two queries I have are: SELECT phone FROM civicrm_phone phone LEFT JOIN civicrm_participant participant ON phone.contact_id = participant.contact_id WHERE phone.is_primary = 1 AND participant.id IS NULL and SELECT phone FROM civicrm_phone phone LEFT JOIN civicrm_participant participant ON phone.contact_id = participant.contact_id WHERE phone.is_primary = 1 AND participant.id IS NOT NULL And before anyone asks, the above two queries do not provide mutually exclusive results (based on using IS NULL and IS NOT NULL for the last WHERE statement), since we have related individuals in the database who use the same phone number, but do not necessarily all have a participant.id. Thanks for any help.

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  • Select query 2-3 times faster than view

    - by Richard Knop
    This query run alone: SELECT -- lots of columns FROM (((((((((((`table1` `t1` LEFT JOIN `table2` `t2` ON(( `t2`.`userid` = `t1`.`userid` ))) LEFT JOIN `table3` `t3` ON(( `t1`.`orderid` = `t3`.`orderid` ))) LEFT JOIN `table4` `t4` ON(( `t4`.`orderitemlicenseid` = `t3`.`orderitemlicenseid` ))) LEFT JOIN `table5` `t5` ON(( `t1`.`orderid` = `t5`.`orderid` ))) LEFT JOIN `table6` `t6` ON(( `t5`.`transactionid` = `t6`.`transactionid` ))) LEFT JOIN `table7` `t7` ON(( `t7`.`transactionid` = `t5`.`transactionid` ))) LEFT JOIN `table8` `t8` ON(( `t8`.`voucherid` = `t7`.`voucherid` ))) LEFT JOIN `table9` `t9` ON(( `t8`.`voucherid` = `t9`.`voucherid` ))) LEFT JOIN `table10` `t10` ON(( ( `t10`.`vouchergroupid` = `t9`.`vouchergroupid` ) AND ( `t2`.`territoryid` = `t10`.`territoryid` ) ))) LEFT JOIN `table11` `t11` ON(( `t11`.`voucherid` = `t8`.`voucherid` ))) LEFT JOIN `table12` `t12` ON(( `t12`.`orderid` = `t1`.`orderid` ))) GROUP BY `t5`.`transactionid` Takes about 2.5 seconds to finish. When I save it to a view and run it as: SELECT * FROM viewName; It takes 7 seconds to finish. What is the reason and how can I make the view faster?

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  • Cassandra or mysql 5

    - by saturngod
    Should I use cassandra in 100,000 users project ? In mysql 5 have full text search and partition table. I'm starting to make Question and answer system like stackoverflow with CodeIgniter. It's move from vbulletin to new system. In old vbulletin have around 100,000 users and total post is around 80,000. In next 3 or 4 year, users and posts will be more and more. So, Should I use cassandra instead of mysql 5 ? If I use cassandra, I need to change gridserver in mediatemple to DV server in mediatemple. Cassandra is not built in hosting system. So, I must use VPS or DV server. If I use mysql 5, hosting is not problem but how about speed and search. Btw, What database using in Stack Over ?

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