Search Results

Search found 37426 results on 1498 pages for 'simple talk editorial team'.

Page 99/1498 | < Previous Page | 95 96 97 98 99 100 101 102 103 104 105 106  | Next Page >

  • Simple search form passing the searched string through GET

    - by Brian Roisentul
    Hi, I'd like my Search form to return the following url after submit: /anuncios/buscar/the_text_I_searched My form is the following: <% form_for :announcement, :url => search_path(:txtSearch) do |f| %> <div class="searchBox" id="basic"> <%= text_field_tag :txtSearch, params[:str_search].blank? ? "Busc&aacute; tu curso r&aacute;pido y f&aacute;cil." : params[:str_search], :maxlength=> 100, :class => "basicSearch_inputField", :onfocus => "if (this.value=='Busc&aacute; tu curso r&aacute;pido y f&aacute;cil.') this.value=''", :onblur => "if(this.value=='') { this.value='Busc&aacute; tu curso r&aacute;pido y f&aacute;cil.'; return false; }" %> <div class="basicSearch_button"> <input type="submit" value="BUSCAR" class="basicSearch_buttonButton" /> <br /><a href="#" onclick="javascript:jQuery('#advance').modal({opacity:60});">Busqueda avanzada</a> </div> </div> <% end %> My routes' line for search_path is this: map.search '/anuncios/buscar/:str_search', :controller => 'announcements', :action => 'search' Well, this will work if I manually type the url I want in the brower, but definitely, if you look at the form's url, you'll find a ":txtSearch" parameter, which is not giving me the actual value of the text field when the form is submitted. And that's what I'd like to get! Could anybody help me on this?

    Read the article

  • Need help building SQL Query (simple JOIN)

    - by Newbie
    Hello! In my database, I have a "users", a "quests" and a "questings" table. A user can solve a quest. Solving a quest will save the "user_id" and the "quest_id" in my "questings" table. Now, I want to select all quests, a user has NOT solved (meaning there is no entry for this user and quest in "questings" table)! Let's say the user has the id 14. How to write this query? After solving this query, I want to filter the results, too. A quest and a user has a city, too. What to do for writing a query which returns all quests, a user has NOT solved yet, in the users city (user city == quest city)?

    Read the article

  • Universal control - simple question about dock and anchor

    - by Vytas999
    I use Visual Studio .NET to develop internal applications. I create a Windows control that will display custom status bar information. Different developers will use the control to display the same information in many different applications. The control must always be displayed at the bottom of the parent form in every application. It must always be as wide as the form. When the form is resized, the control should be resized and repositioned accordingly. How should I do that in the best way and why? A)Create a property to allow the developers to set the Dock property of the control. Set the default value of the property to AnchorStyle.Bottom. B) Create a property to allow the developer to set the Anchor property of the control. Set the default value of the property to AnchorStyle.Bottom.

    Read the article

  • Simple Question:Output of below Java program

    - by Abhishek Jain
    public class abc1 { private String s; public abc1(String s){this.s=s;} public static void main(String args[]) { HashSet<Object> hs=new HashSet<Object>(); abc1 a1= new abc1("abc"); abc1 a2= new abc1("abc"); String s1= new String("abc"); String s2= new String("abc"); hs.add(a1); hs.add(a2); hs.add(s1); hs.add(s2); System.out.println(hs.size()); } } Why above program output is 3?

    Read the article

  • Spring MVC simple case

    - by coure2011
    Trying to understand a sample code... I am returning a modelview successfully from my AthuenticationController like this modelAndView = new ModelAndView("redirect:/home/"); .... return modelAndView; and my browser url is changed to /home/ but its showing a 404 page I have a HomePageController and it has methods @RequestMapping(method = RequestMethod.GET) public String loadHome and @RequestMapping(method = RequestMethod.GET, value = "/main") public String reloadHome but System.out.println("Message") is not executing in any of the above methods. When authenticated I want to load a home.jsp page? It is in WEB-INF/jsp/...

    Read the article

  • A simple tutorial for a beginner with WPF

    - by Aditya
    Hi Guys, I started today working on WPF for the first time. My requirement is to create a windows application using WPF. I mean an application which has page, buttons, tree view, log details (typically of selecting a project and subproject then manipulate the data on it) using WPF controls. Can I get some basic tutorials on this please. I explored… but I couldn't get right stuff for the work. Please help. Thank You, Ramm

    Read the article

  • Need a very simple bash-based webserver for logging XML in HTTP POST

    - by Syffys
    As in title, it's for testing purpose and I need it to be extremely light (1 line to 1 single light file). Here is a XML query sample: XML_QUERY=$(cat <<EOF <?xml version='1.0' encoding='UTF-8'?> <Test></Test> EOF ) curl -H "Content-type: text/xml; charset=utf-8" -H "Soapaction: \"\"" -k -d "${XML_QUERY}" http://localhost:8088 Here are some of the tracks I have found so far even if I wasnt able to adapt them to work as I expect: Netcat minimal webserver: Problem is that my nc does not have the -q option, so the connection is closing before delivering the XML content Netcat Only webserver: Same as above Python based: But does not handle POST Thanks in advance!

    Read the article

  • Simple doubt related to strings in C (question in an interview)

    - by piemesons
    // The first example: char text[] = "henri"; char *p; p = text; *(p + 1) = 'E'; // Output = hEnri // Now If we want to remove the "e" ie hnri, we would go for????? *(p + 1)=????? Please dont say start copying the array. I am looking for the best solution. Its an interview question... EDIT I specially mentioned the question that i am not asking for the solution like start moving the element. I thought there must be some other good solution..

    Read the article

  • Need simple Twitter API v1.1 example to show timeline using jQuery or C# ASP.NET

    - by Ken Palmer
    With Twitter turning off the API 1.0 faucet on 6/11/2013, we have several sites that now fail to display timelines. I've been looking for an "If you did that, now do this" example. Here was Twitter's announcement. https://dev.twitter.com/blog/api-v1-is-retired Here is what we were originally doing to show the Twitter timeline via API 1.0. <div id="twitter"> <ul id="twitter_update_list"></ul> <script type="text/javascript" src="http://twitter.com/javascripts/blogger.js"></script> <script type="text/javascript" src="http://api.twitter.com/1/statuses/user_timeline/companytwitterhandle.json?callback=twitterCallback2&amp;count=1"></script> <div style="float:left;"><a href="https://twitter.com/companytwitterhandle" target="_blank">@companytwitterhandle</a> | </div> <div class="twitterimg">&nbsp;</div> </div> Initially I tried changing the version in the JavaScript reference URL like so, which did not work. <script type="text/javascript" src="http://api.twitter.com/1.1/statuses/user_timeline/companytwitterhandle.json?callback=twitterCallback2&amp;count=1"></script> Then I looked at the Twitter API documentation (https://dev.twitter.com/docs/api/1.1/overview) which lacks a clear transition example. I don't have 4 or 5 hours to delve into that, or into this disheveled FAQ (https://dev.twitter.com/docs/faq#17750). Then I found this API documentation regarding the user timeline. So I changed the URL again as shown below. https://dev.twitter.com/docs/api/1.1/get/statuses/user_timeline <script type="text/javascript" src="https://api.twitter.com/1.1/statuses/user_timeline.json?screen_name=companytwitterhandle&amp;count=1"></script> That did not work. Using jQuery or C# ASP.NET MVC, how can I transition that interface from Twitter API 1.0 to Twitter API 1.1? My first preference would be for a browser client side implementation if that is possible. Please include a code example. Thanks.

    Read the article

  • Creating a simple sencha listview using a loop

    - by chris_sencha
    How do we substitute a hardcoded data with a for loop in sencha and extjs? Say, I have below hardcoded one Ext.application({ launch: function() { Ext.create('Ext.List', { fullscreen: true, itemTpl: '{title}', data: [{ title: 'Item 1' }, { title: 'Item 2' }, { title: 'Item 3' }, { title: 'Item 4' }] }); } }); In the above one, how to replace data to something like below Ext.application({ launch: function() { Ext.create('Ext.List', { fullscreen: true, itemTpl: '{title}', data: [ for(int i=0;i<5;i++){ {title: 'Item '+i}, } ] }); } });

    Read the article

  • Why isn't this simple MySQL statement working?

    - by Clark
    I am trying to match a user inputted search term against two tables: posts and galleries. The problem is the union all clause isn't working. Is there something wrong with my code? $query = mysql_query(" SELECT * FROM posts WHERE title LIKE '%$searchTerm%' OR author LIKE '%$searchTerm%' OR location LIKE '%$searchTerm%' OR excerpt LIKE '%$searchTerm%' OR content LIKE '%$searchTerm%' UNION ALL SELECT * FROM galleries WHERE title LIKE '%$searchTerm%' ");

    Read the article

  • How to get REALLY fast python over a simple loop

    - by totallymike
    I'm working on a spoj problem, INTEST. The goal is to specify the number of test cases (n) and a divisor (k), then feed your program n numbers. The program will accept each number on a newline of stdin and after receiving the nth number, will tell you how many were divisible by k. The only challenge in this problem is getting your code to be FAST because it k can be anything up to 10^7 and the test cases can be as high as 10^9. I'm trying to write it in python and having trouble speeding it up. Any ideas? import sys first_in = raw_input() thing = first_in.split() n = int(thing[0]) k = int(thing[1]) total = 0 i = 0 for line in sys.stdin: t = int(line) if t % k == 0: total += 1 print total

    Read the article

  • Yet Another Simple Retain Count Question

    - by yar
    [I'm sure this is not odd at all, but I need just a bit of help] I have two retain properties @property (nonatomic, retain) NSArray *listContent; @property (nonatomic, retain) NSArray *filteredListContent; and in the viewDidLoad method I set the second equal to the first self.filteredListContent = self.listContent; and then on every search I do this self.filteredListContent = [listContent filteredArrayUsingPredicate:predicate]; I thought I should do a release right above this assignment -- since the property should cause an extra retain, right? -- but that causes the program to explode the second time I run the search method. The retain counts (without the extra release) are 2 the first time I come into the search method, and 1 each subsequent time (which is what I expected). Some guidance would help, thanks! Is it correct to not release?

    Read the article

  • SaaS tool for *simple* requirements definition?

    - by Angela
    I've seen some complex, enterprise tools for requirements like Rymatech's FeaturePlan -- is there something that enables collaboration and best practices for putting Business-Readable, Domain-Specific (or natural language) requirements and acceptance criteria in place?

    Read the article

  • Simple C++ code (what's wrong here?)

    - by JW
    Noob to C++. I'm trying to get user input (Last Name, First Name Middle Name), change part of it (Middle Name to Middle Initial) and then rearrange it (First Middle Initial Last). Where am I messing up in my code? --Thanks for ANY help you can offer! ... #include <iostream> using std::cout; using std::cin; #include <string> using std::string; int main() { string myString, last, first, middle; cout << "Enter your name: Last, First Middle"; cin >> last >> first >> middle; char comma, space1, space2; comma = myString.find_first_of(','); space1 = myString.find_first_of(' '); space2 = myString.find_last_of(' '); last = myString.substr (0, comma); // user input last name first = myString.substr (space1+1, -1); // user input first name middle = myString.substr (space2+1, -1); // user input middle name middle.insert (0, space2+1); // inserts middle initial in front of middle name middle.erase (1, -1); // deletes full middle name, leaving only middle initial myString = first + ' ' + middle + ' ' + last; // return 0; }

    Read the article

  • Can't record or play with a simple recorder?

    - by user1280535
    I have 2 classes, a record and a player. In my main scene, I create an instance of them and play and record. But, as I see, it only records and somehow does not play (the file is not there!) Here is the code for both : -(void)record { NSArray *dirPaths; NSString *docsDir; NSString *sound= @"sound0.caf" ; dirPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES) ; docsDir = [dirPaths objectAtIndex:0]; NSString *soundFilePath = [docsDir stringByAppendingPathComponent:sound]; NSURL *soundFileURL = [NSURL fileURLWithPath:soundFilePath]; NSDictionary *settings = [NSDictionary dictionaryWithObjectsAndKeys: [NSNumber numberWithFloat: 44100.0], AVSampleRateKey, [NSNumber numberWithInt: kAudioFormatAppleLossless], AVFormatIDKey, [NSNumber numberWithInt: 1], AVNumberOfChannelsKey, [NSNumber numberWithInt: AVAudioQualityMax], AVEncoderAudioQualityKey, nil]; NSError *error; myRecorder = [[AVAudioRecorder alloc] initWithURL:soundFileURL settings:settings error:&error]; if (myRecorder) { NSLog(@"rec"); [myRecorder prepareToRecord]; myRecorder.meteringEnabled = YES; [myRecorder record]; } else NSLog( @"error" ); } I can see the log of rec. -(void)play { NSArray *dirPaths; NSString *docsDir; dirPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); docsDir = [dirPaths objectAtIndex:0]; NSString *soundFilePath1 = @"sound0.caf" ; NSURL *soundFileURL = [NSURL fileURLWithPath:soundFilePath1]; BOOL isMyFileThere = [[NSFileManager defaultManager] fileExistsAtPath:soundFilePath1]; if(isMyFileThere) { NSLog(@"PLAY"); avPlayer1 = [[AVAudioPlayer alloc] initWithContentsOfURL:soundFileURL error:NULL]; avPlayer1.volume = 8.0; avPlayer1.delegate = self; [avPlayer1 play]; } } I DONT SEE THE LOG OF PLAY ! I call them both with: recInst=[recorder alloc]; //to rec [recInst record]; plyInst=[player alloc]; //play [plyInst play]; and to stop the recorder: - (void)stopRecorder { NSLog(@"stopRecordings"); [myRecorder stop]; //[myRecorder release]; } What's wrong here? Thanks.

    Read the article

  • Reconstructing simple 3d enviroment(room) from photo

    - by Riz
    I have photo of a room with three walls and floor/ceiling or both. I am trying to reconstruct this room in 3d asking user for minimal input. Right now I use 8 points defined by user, angles of left and right wall(they can be quite different from 90) and one size "InLeftBottom-InRightBottom"(I need to have real size of this room for later use). I have no info about user's camera(I can read EXIF to get FOV and use constant height but this can be only used as additional info). Is this possible to ask user for less info? Maybe it's possible to get wall angles without user interaction? Or maybe I am completly wrong and should use different approach?

    Read the article

  • simple dividing

    - by dontoo
    Lets say I am dividing 2592 / 324 = 8 Practically I must guess that 324 goes 8 times in 2592 without reminder. For example, first I try with 7 ( 7*324 = 2268, reminder 324, so 7 is wrong, so I try with 8 and 8 is correct) Is there anyway to do dividing without guessing( trying ), like multiplication ( all mechanically, digit by digit )?

    Read the article

  • Simple doubt related to strings in C

    - by piemesons
    // The first example: char text[] = "henri"; char *p; p = text; *(p + 1) = 'E'; // Output = hEnri // Now If we want to remove the "e" ie hnri, we would go for????? *(p + 1)=????? Please dont say start copying the array. I am looking for the best solution

    Read the article

< Previous Page | 95 96 97 98 99 100 101 102 103 104 105 106  | Next Page >