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  • Are Interfaces "Object"?

    - by PrashantGupta
    package inheritance; class A{ public String display(){ return "This is A!"; } } interface Workable{ public String work(); } class B extends A implements Workable{ public String work(){ return "B is working!"; } } public class TestInterfaceObject{ public static void main(String... args){ B obj=new B(); Workable w=obj; //System.out.println(w.work()); //invoking work method on Workable type reference System.out.println(w.display()); //invoking display method on Workable type reference //System.out.println(w.hashCode()); // invoking Object's hashCode method on Workable type reference } } As we know that methods which can be invoked depend upon the type of the reference variable on which we are going to invoke. Here, in the code, work() method was invoked on "w" reference (which is Workable type) so method invoking will compile successfully. Then, display() method is invoked on "w" which yields a compilation error which says display method was not found, quite obvious as Workable doesn't know about it. Then we try to invoke the Object class's method i.e. hashCode() which yields a successful compilation and execution. How is it possible? Any logical explanation?

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  • priority queue implementation

    - by davit-datuashvili
    i have implemented priority queue and i am interested if it is correct public class priqueue { private int n,maxsize; int x[]; void swap(int i,int j){ int t=x[i]; x[i]=x[j]; x[j]=t; } public priqueue(int m){ maxsize=m; x=new int [maxsize+1]; n=0; } void insert(int t){ int i,p; x[++n]=t; for (i=n;i>1 && x[p=i/2] >x[i];i=p) swap(p,i); } public int extramin(){ int i,c; int t=x[1]; x[1]=x[n--]; for (i=1;(c=2*i)<=n;i=c){ if (c+1<=n && x[c+1]<x[c]) c++; if (x[i]<=x[c]) break; swap(c,i); } return t; } public void display(){ for (int j=0;j<x.length;j++){ System.out.println(x[j]); } } } public class priorityqueue { public static void main(String[] args) { priqueue pr=new priqueue(12); pr.insert(20); pr.insert(12); pr.insert(22); pr.insert(15); pr.insert(35); pr.insert(17); pr.insert(40); pr.insert(51); pr.insert(26); pr.insert(19); pr.insert(29); pr.insert(23); pr.extramin(); pr.display(); } } //result: 0 12 15 17 20 19 22 40 51 26 35 29 23

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  • Format String become xxx1, xx10 or 1****, 10*** etc

    - by trycatch4j
    Hi all, I have following numbers : 1, 2, 3, 4, 10 But I want to print those numbers like this: 0001 0002 0003 0004 0010 I have searched in Google. the keyword is number format. But I've got nothing, I just get, format decimal such ass 1,000,000.00. I hope you can suggest me a reference or give me something to solve this problem. Thanks Edit, we can use NumberFormat, or String.format("%4d", somevalue); but it just for adding 0 character before integer. How If I wanna use character such as x, # or maybe whitespace. So the character become: xxxx1 xxx10 or ####1 ###10 or 1#### 10###

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  • which delimeter to use while spliting String

    - by London
    I need to split this line string in each line, I need to get the third word(film name) but as you see the delimeter is one big blank character in some cases its small like before the numbers at the end or its big as in front of numbers at front. I tried using string split with(" ") regex, and also \t but get the out of the bounds error. 400115305 Lionel_Atwill The_Song_of_Songs_(1933_film) 7587 400115309 Brian_Aherne A_Night_to_Remember_(1943_film) 7952 Did anyone have the same problem?

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  • Arrays (toString) not output correctly

    - by DiscoDude
    Hello, Actually this tread is continuing from the other one. There wasn't enough characters to continue there. Anyway. the problem is that the output is "1(10) 2(23) 3(29)". Even though I could return string for the array values (10,23,29) and used string reference as 1, 2 and 3. My question is it possible to return index values 1,2,3 and as well as array values. Am I making an sense. Here is what I have done... // int[] groups = {10, 23, 29}; in the constructor String tempA = ""; String tempB = " "; int[] temp = new int[4]; int length = groups.length; for (int j = 0; j < length; j++) { temp[j] = groups[j]; tempB = tempB + "("+goups+")"; } groups = temp; Arrays.sort(coingroups); for(int i = 1; i < groups.length;i++) { tempA = tempA+" "+(i)+ "("+groups[i]+")"; } return tempA;

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  • Httpclient not returning entire response

    - by whakojacko
    Using HttpClient 4.0, Im having an issue where the response I get from the ResponseHandler is only about half of what the actual page content should be (~61k bytes in the string vs ~125k in the page returned to a browser). I cant seem to find any place where there might be some sort of limit that would limit this. Any ideas?

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  • MediaType of REST

    - by user357243
    Hi, I am beginner in REST web services. I wrote a program of REST to display the HTML or XML. The @Path annotation's value is @Path("{typeDocument}"). There are two methods for GET : @GET @Produces(MediaType.TEXT_XML) public String getXml(@PathParam("typeDocument") String typeDocument) to display XML file, and @GET @Produces(MediaType.TEXT_HTML) public String getHtml(@PathParam("typeDocument") String typeDocument) to display HTML. The browser Firefox always excutes getHtml() when URL is either http://localhost:8080/sources/html or localhost:8080/sources/xml But IE always excutes getXml(). How to excute the correct method, as defined by URL, in different browser ? Thanks a lot.

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  • @Path and regular expression (Jersey/REST)

    - by Castanho
    Hi there! I'm using Jersey in a REST project and I'm needing to use regular expression. Digging about it is simple like: @Path("/resources) public class MyResource { @GET @Path("{subResources:.*}/bar") public String get() {...} } But, I'm only capable of using regex if in my @Path contains a variable or text value, example: @Path("{SubResource1}/{subResources:.*}/bar") Or @Path("hardCodeString/{subResources:.*}/bar") Today I could run with this solution of a variable, but is not oK for my perspective. Question Does anyone have worked with something related? I'm doing something wrong? I think that this could be a bug, when working with more then one @Path, one in the Class and other in the Method. Any tips is appreciated! Regards

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  • Non-empty list with null elements returned from Hibernate query

    - by John
    Hi, I'm new to hibernate so not sure if this is an expected behaviour, anyway: Session session = (Session)entityManager.getDelegate(); Criteria criteria = session.createCriteria(myRequest.class); criteria.add(Restrictions.eq("username", username)); criteria.setProjection(Projections.max("accesscount")); List<myRequest> results = criteria.list(); The returned results is a non-empty list with a single null element. I can't think of any reason why it should behave this way, any idea if this is the expected behaviour or have I done something wrong? System is on hibernate/Syabse. Thanks.

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  • How to make compareTo sort a list alphabetically?

    - by Alex
    Hi How do I change my code so that it lists the elements in alphabetical order from a to z. Right now it's ordering from z to a. I can't figure it out and am stuck :-/ String sName1 = ((Address)o).getSurname().toLowerCase(); String sName2 = (this.surname).toLowerCase(); int result = (sName1).compareTo(sName2); return result; Thanks :)

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  • help with google android

    - by hero
    how powerfull is google android bluetooth programming? is it considered a low level programming langauge/emulator that enables me to have full control over bluetooth? ie protocols,encryption,layers....

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  • Implementing a plugin interface

    - by James P.
    What's a good way of adding a plugin interface such that it's possible to have optional components? I'm aware of the Class.forName() approach (used with JDBC for example) but there is also dynamic class loading.

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  • download html source android?

    - by mars
    I'm trying to download a website source code and display it in a textbox but I seem to get an error and can't figure it out :s public void getHtml() throws ClientProtocolException, IOException { HttpClient httpClient = new DefaultHttpClient(); HttpContext localContext = new BasicHttpContext(); HttpGet httpGet = new HttpGet("http://www.spartanjava.com"); HttpResponse response = httpClient.execute(httpGet, localContext); String result = ""; BufferedReader reader = new BufferedReader( new InputStreamReader( response.getEntity().getContent() ) ); String line = null; while ((line = reader.readLine()) != null){ result += line + "\n"; Toast.makeText(activity.this, line.toString(), Toast.LENGTH_LONG).show(); } } how come this doesn't work and throw an IOException?

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  • How the clients (client sockets) are identified?

    - by Roman
    To my understanding by serverSocket = new ServerSocket(portNumber) we create an object which potentially can "listen" to the indicated port. By clientSocket = serverSocket.accept() we force the server socket to "listen" to its port and to "accept" a connection from any client which tries to connect to the server through the port associated with the server. When I say "client tries to connect to the server" I mean that client program executes "nameSocket = new Socket(serverIP,serverPort)". If client is trying to connect to the server, the server "accepts" this client (i.e. creates a "client socket" associated with this client). If a new client tries to connect to the server, the server creates another client socket (associated with the new client). But how the server knows if it is a "new" client or an "old" one which has already its socket? Or, in other words, how the clients are identified? By their IP? By their IP and port? By some "signatures"? What happens if an "old" client tries to use Socket(serverIP,serverIP) again? Will server create the second socket associated with this client?

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