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  • What do we call to "non-programmers" ? ( Like "muggle" in HP ) [closed]

    - by OscarRyz
    Sometimes I want to refer to people without coding powers as Muggles. But it doesn't quite feel right. Gamers have n00b ( but still a n00b has some notion of gaming ) I mean, for all those who Windows in the only OS in the world ( what's an OS ? would they ask ) For project manager who can't distinguish between excel and a database. For those who exclaim "Wooow! when you show them the ctrl-right click to see the webpage source code. What would be a good word to describe to these "persons without lack of coding ability?" Background I didn't mean to be disrespectful with ordinary people. It's just, sometimes it drives me nuts seeing coworkers struggling trying to explain to these "people" some concept. For instance, recently we were asked, what a "ear" was (in Java). My coworker was struggling on how to explain what is was, and how it differ from .war, .jar, etc. and talking about EJB's application server, deployment etc, and our "people"1 was like o_O. I realize a better way to explain was "Think about it as an installer for the application, similar to install.exe" and he understood immediately. This is none's fault, it is sometimes our "poeple" come from different background, that's it. Is our responsibility to talk at a level they can understand, some coworkers, don't get it and try very hard to explain programming concepts ( like the source code in the browser ). But I get the point, we I don't need to be disrespectful. ... But, I'm considering call them pebkac's 1As suggested

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  • Installing Refinery CMS on Windows

    - by PEBKAC
    Hi all, I cannot get Refinery cms to install on my crappy Vista machine. I have followed all instructions on http://github.com/resolve/refinerycms but the bundler doesn't work because there is not gemfile (I have copied the gemfile from github but it fails at rmagick gem) and have also tried the command line instructions but it fails at rake db:setup. I have tried installing all required gems myself but this makes no difference. Can anyone give me a quick step by step on how to get it running? I have now completely removed ruby so can start afresh. I have the installers from rubyinstaller.org and have tried with both 1.8.7 and 1.9. I have mysql 5.1 installed. Much appreciated!

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  • How do you reproduce bugs that occur sporadically?

    - by furtelwart
    We have a bug in our application that does not occur every time and therefore we don't know its "logic". I don't even get it reproduced in 100 times today. Disclaimer: This bug exists and I've seen it. It's not a pebkac or something similar. What are common hints to reproduce this kind of bug?

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  • What would cause previously sent emails to be sent again from Exchange the first time someone logs i

    - by Ken Pespisa
    A few users testing our Citrix XenApp service found that several (seemingly random) previously sent emails were sent out immediately after they logged into Outlook via Citrix for the first time. The problem hasn't occurred for them since. After one user had this happen, and we scratched our heads about it thinking it was a fluke, our IT director had this same issue. I guess I'd rule out any PEBKAC issues. I really don't know where to begin troubleshooting this problem. If you have any ideas what could have caused this, I'd appreciate you sharing them, as strange or far-fetched as they may seem :)

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  • Why can't I attach the debugger?

    - by Mike
    I'm using Visual Studio 2008 SP1 and trying to debug a website created in ASP Classic. I have read numerous tutorials, however nothing seems to be working (PEBKAC?). I have enabled server-side debugging in IIS and am attaching the debugger to dllhost.exe. When I open my page in Google Chrome, set breakpoints and set VS to debug, nothing happens. I don't get any errors so I'm not sure what else to post. Any ideas? Thank you. :)

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  • Installing and configuring Zend Framework 2 server-wide [Ubuntu] and test driving ZendSkeletonApplication

    - by kinologik
    I'm trying to have ZF2 installed for all my subdomains at once (Ubuntu 12.04). ZF2 just launched its first stable version, so I wanted to install it on my development server and finally get my hands dirty with it. I downloaded ZF2 and unzipped the files in /var/ZF2/ (which now contains Zend/[all components]). I then edited /etc/php5/apache2/php.ini and added the path to the ZF2 files: include_path = ".:/var/ZF2" I then downloaded the ZendSkeletonApplication and unzipped it in /var/www/skeleton. I know it is suggested to composer.phar to install ZF2 application, but: I don't want to make a local installation of ZF2... I want to make a server-wide installation be able to use my Zend components on all my domains/subdomains on my development server. Before using any automatic installation process, I'd really like to understand that process by doing it manually at first. Obviously, something goes wrong when I fire ZendSkeletonApplication, and I get the following when hit the following URL: http://www.myDevServer.com/skeleton/public/ Fatal error: Uncaught exception 'RuntimeException' with message 'Unable to load ZF2. Run `php composer.phar install` or define a ZF2_PATH environment variable.' in /var/www/skeleton/init_autoloader.php:48 Stack trace: #0 /var/www/skeleton/public/index.php(9): include() #1 {main} thrown in /var/www/skeleton/init_autoloader.php on line 48 I have skimmed through the docs, tutorials and the like, but there are no straight forward answer to this kind of configuration. In the official doc, in the (very short) installation chapter, I see a reference to adding an include path in PHP. But no example... http://zf2.readthedocs.org/en/latest/ref/installation.html Once you have a copy of Zend Framework available, your application needs to be able to access the framework classes found in the library folder. Though there are several ways to achieve this, your PHP include_path needs to contain the path to Zend Framework’s library. But then, when I get to the "Getting Started" chapter, it's all composer.phar and nothing else... http://zf2.readthedocs.org/en/latest/user-guide/skeleton-application.html I'm no sysAdmin, just a Zend enthusiast. I'm pretty sure this PEBKAC problem might be obvious for those who already got in ZF2 previous betas. Thanks for helping my out. EDIT: Problem was resolved, thanks to Daniel M. Just setting up ZF2_PATH in httpd.conf was all that was needed. SetEnv ZF2_PATH /var/ZF2 I also removed the include_path reference in php.ini and everything works just fine. So I have no idea why Zend suggested to include it there in their official docs.

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  • Projections.count() and Projections.countDistinct() both result in the same query

    - by Kim L
    EDIT: I've edited this post completely, so that the new description of my problem includes all the details and not only what I previously considered relevant. Maybe this new description will help to solve the problem I'm facing. I have two entity classes, Customer and CustomerGroup. The relation between customer and customer groups is ManyToMany. The customer groups are annotated in the following way in the Customer class. @Entity public class Customer { ... @ManyToMany(mappedBy = "customers", fetch = FetchType.LAZY) public Set<CustomerGroup> getCustomerGroups() { ... } ... public String getUuid() { return uuid; } ... } The customer reference in the customer groups class is annotated in the following way @Entity public class CustomerGroup { ... @ManyToMany public Set<Customer> getCustomers() { ... } ... public String getUuid() { return uuid; } ... } Note that both the CustomerGroup and Customer classes also have an UUID field. The UUID is a unique string (uniqueness is not forced in the datamodel, as you can see, it is handled as any other normal string). What I'm trying to do, is to fetch all customers which do not belong to any customer group OR the customer group is a "valid group". The validity of a customer group is defined with a list of valid UUIDs. I've created the following criteria query Criteria criteria = getSession().createCriteria(Customer.class); criteria.setProjection(Projections.countDistinct("uuid")); criteria = criteria.createCriteria("customerGroups", "groups", Criteria.LEFT_JOIN); List<String> uuids = getValidUUIDs(); Criterion criterion = Restrictions.isNull("groups.uuid"); if (uuids != null && uuids.size() > 0) { criterion = Restrictions.or(criterion, Restrictions.in( "groups.uuid", uuids)); } criteria.add(criterion); When executing the query, it will result in the following SQL query select count(*) as y0_ from Customer this_ left outer join CustomerGroup_Customer customergr3_ on this_.id=customergr3_.customers_id left outer join CustomerGroup groups1_ on customergr3_.customerGroups_id=groups1_.id where groups1_.uuid is null or groups1_.uuid in ( ?, ? ) The query is exactly what I wanted, but with one exception. Since a Customer can belong to multiple CustomerGroups, left joining the CustomerGroup will result in duplicated Customer objects. Hence the count(*) will give a false value, as it only counts how many results there are. I need to get the amount of unique customers and this I expected to achieve by using the Projections.countDistinct("uuid"); -projection. For some reason, as you can see, the projection will still result in a count(*) query instead of the expected count(distinct uuid). Replacing the projection countDistinct with just count("uuid") will result in the exactly same query. Am I doing something wrong or is this a bug? === "Problem" solved. Reason: PEBKAC (Problem Exists Between Keyboard And Chair). I had a branch in my code and didn't realize that the branch was executed. That branch used rowCount() instead of countDistinct().

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