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  • One template specialization for multiple classes

    - by peper0
    Let's assume we have a template function "foo": template<class T> void foo(T arg) { ... } I can make specialization for some particular type, e.g. template<> void foo(int arg) { ... } If I wanted to use the same specialization for all builtin numeric types (int, float, double etc.) I would write those lines many times. I know that body can be thrown out to another function and just call of this is to be made in every specialization's body, however it would be nicer if i could avoid writting this "void foo(..." for every type. Is there any possibility to tell the compiler that I want to use this specialization for all this types?

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