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• In Python, urllib2 giving error

  - by pythBegin

  I tried running this, >>> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') But it is giving error like this, can anyone tell me a solution ? Traceback (most recent call last): File "<pyshell#11>", line 1, in <module> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') File "C:\Python26\lib\urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "C:\Python26\lib\urllib2.py", line 391, in open response = self._open(req, data) File "C:\Python26\lib\urllib2.py", line 409, in _open '_open', req) File "C:\Python26\lib\urllib2.py", line 369, in _call_chain result = func(*args) File "C:\Python26\lib\urllib2.py", line 1161, in http_open return self.do_open(httplib.HTTPConnection, req) File "C:\Python26\lib\urllib2.py", line 1136, in do_open raise URLError(err) URLError: <urlopen error [Errno 11001] getaddrinfo failed>

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• Using Python, How to copy files in 'temporary internet files' folder in Windows

  - by pythBegin

  I am using this code to find files recursively in a folder , with size greater than 50000 bytes. def listall(parent): lis=[] for root, dirs, files in os.walk(parent): for name in files: if os.path.getsize(os.path.join(root,name))>500000: lis.append(os.path.join(root,name)) return lis This is working fine. But when I used this on 'temporary internet files' folder in windows, am getting this error. Traceback (most recent call last): File "<pyshell#4>", line 1, in <module> listall(a) File "<pyshell#2>", line 5, in listall if os.path.getsize(os.path.join(root,name))>500000: File "C:\Python26\lib\genericpath.py", line 49, in getsize return os.stat(filename).st_size WindowsError: [Error 123] The filename, directory name, or volume label syntax is incorrect: 'C:\\Documents and Settings\\khedarnatha\\Local Settings\\Temporary Internet Files\\Content.IE5\\EDS8C2V7\\??????+1[1].jpg' I think this is because windows gives names with special characters in this specific folder... Please help to sort out this issue.

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• In Python, how to find all the files under a directory, including the files in subdirectories ?

  - by pythBegin

  Is there any built in functions to find all the files under a particular directory including files under subdirectories ? I have tried this code, but not working...may be the logic itself is wrong... def fun(mydir): lis=glob.glob(mydir) length=len(lis) l,i=0,0 if len(lis): while(l+i

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