Search Results

Search found 9 results on 1 pages for 'pythonista'.

Page 1/1 | 1 

  • What defines "pythonian" or "pythonic"?

    - by Thomas Owens
    I want to begin to learn Python, and I've seen that phrase come up here before, but I don't know exactly what it means. I've read some websites on Python scripting, but I don't recall ever seeing that (but I could have just glanced over it). What exactly makes something "pythonian" or "pythonic"?

    Read the article

  • Google docs spreadsheet not loading

    - by Pythonista's Apprentice
    I have a Google spreadsheet with a lot of very important data and some scripts that where working well. At some point, the brownser crash and I reload the page. After that, I can't acess that (only that!) spreadsheet any more! I try it from other Google accounts but it doesn't work. All I get is the "Loading..." message in the brownser tab and nothing more (the loading process never completes). I also can't: copy the file or download it! Ie, I can lose all the information in my spreadsheet and also lose all my scripts! (I never think something like this could hapen with a Google Product) How can I solve this problem? Thanks in advance for any help!

    Read the article

  • Alternative to "assign to a function call" in a python

    - by Pythonista's Apprentice
    I'm trying to solve this newbie puzzle: I've created this function: def bucket_loop(htable, key): bucket = hashtable_get_bucket(htable, key) for entry in bucket: if entry[0] == key: return entry[1] else: return None And I have to call it in two other functions (bellow) in the following way: to change the value of the element entry[1] or to append to this list (entry) a new element. But I can't do that calling the function bucket_loop the way I did because "you can't assign to function call" (assigning to a function call is illegal in Python). What is the alternative (most similar to the code I wrote) to do this (bucket_loop(htable, key) = value and hashtable_get_bucket(htable, key).append([key, value]))? def hashtable_update(htable, key, value): if bucket_loop(htable, key) != None: bucket_loop(htable, key) = value else: hashtable_get_bucket(htable, key).append([key, value]) def hashtable_lookup(htable, key): return bucket_loop(htable, key) Thanks, in advance, for any help! This is the rest of the code to make this script works: def make_hashtable(size): table = [] for unused in range(0, size): table.append([]) return table def hash_string(s, size): h = 0 for c in s: h = h + ord(c) return h % size def hashtable_get_bucket(htable, key): return htable[hash_string(key, len(htable))] Similar question (but didn't help me): Python: Cannot Assign Function Call

    Read the article

  • Google Apps Script: how to make suggest box library to work?

    - by Pythonista's Apprentice
    I'm trying to add an autocomplete feature in my Google Spreadsheet using this Google Apps Script suggest box library from Romain Vialard and James Ferreira's book: function doGet() { // Get a list of all my Contacts var contacts = ContactsApp.getContacts(); var list = []; for(var i = 0; i < contacts.length; i++){ var emails = contacts[i].getEmails(); if(emails[0] != undefined){ list.push(emails[0].getAddress()); } } var app = UiApp.createApplication(); var suggestBox = SuggestBoxCreator.createSuggestBox(app, 'contactPicker', 200, list); app.add(suggestBox); return app; } function onEdit() { var s = SpreadsheetApp.getActiveSheet(); if( s.getName() == "my_sheet_name" ) { //checks that we're on the correct sheet var r = s.getActiveCell(); if( r.getColumn() == 1) { doGet(); } } } But when I start editing the column 1 of "my_sheet_name" nothing hapens (if I replace doGet() for other function, this other function runs Ok). I've already installed the Suggest Box library. So, why the doGet() function doesn't work?

    Read the article

  • Why did Apple remove Python support in Mavericks, aka Mac OS X 10.9?

    - by alex gray
    Apple has removed Python support (at least on the Developer level) in 10.9. Python IS still on the machine in /System/Library/Frameworks/Python.framework... but trying to link to Python using the 10.9 SDK fails. /Applications/Xcode.app/Contents/Developer/Platforms/MacOSX.platform/Developer/SDKs/MacOSX10.9.sdk/System/Library/Frameworks does not have Python. I'm not a Pythonista, but find it interesting that Apple has made this change. I don't understand why this is done and I'm a bit annoyed that I have to remove Python from my compilation units in order to compile with 10.9 SDK. Is this a statement by Apple, along the lines of "People aren't using Python very much anymore so we're going to phase out support"? Or was something else driving the change?

    Read the article

  • How to Determine The Module a Particular Exception Class is Defined In

    - by doug
    Note: i edited my Q (in the title) so that it better reflects what i actually want to know. In the original title and in the text of my Q, i referred to the source of the thrown exception; what i meant, and what i should have referred to, as pointed out in one of the high-strung but otherwise helpful response below, is the module that the exception class is defined in. This is evidenced by the fact that, again, as pointed out in one of the answers below the answer to the original Q is that the exceptions were thrown from calls to cursor.execute and cursor.next, respectively--which of course, isn't the information you need to write the try/except block. For instance (the Q has nothing specifically to do with SQLite or the PySQLite module): from pysqlite2 import dbapi2 as SQ try: cursor.execute('CREATE TABLE pname (id INTEGER PRIMARY KEY, name VARCHARS(50)') except SQ.OperationalError: print("{0}, {1}".format("table already exists", "... 'CREATE' ignored")) # cursor.execute('SELECT * FROM pname') while 1: try: print(cursor.next()) except StopIteration: break # i let both snippets error out to see the exception thrown, then coded the try/finally blocks--but that didn't tell me anything about which module the exception class is defined. In my example, there's only a single imported module, but where there are many more, i am interested to know how an experienced pythonista identifies the exception source (search-the-docs-till-i-happen-to-find-it is my current method). [And yes i am aware there's a nearly identical question on SO--but for C# rather than python, plus if you read the author's edited version, you'll see he's got a different problem in mind.]

    Read the article

  • Python raw strings and trailing back slashes.

    - by dash-tom-bang
    I ran across something once upon a time and wondered if it was a Python "bug" or at least a misfeature. I'm curious if anyone knows of any justifications for this behavior. I thought of it just now reading "Code Like a Pythonista," which has been enjoyable so far. I'm only familiar with the 2.x line of Python. Raw strings are strings that are prefixed with an r. This is great because I can use backslashes in regular expressions and I don't need to double everything everywhere. It's also handy for writing throwaway scripts on Windows, so I can use backslashes there also. (I know I can also use forward slashes, but throwaway scripts often contain content cut&pasted from elsewhere in Windows.) So great! Unless, of course, you really want your string to end with a backslash. There's no way to do that in a 'raw' string. In [9]: r'\n' Out[9]: '\\n' In [10]: r'abc\n' Out[10]: 'abc\\n' In [11]: r'abc\' ------------------------------------------------ File "<ipython console>", line 1 r'abc\' ^ SyntaxError: EOL while scanning string literal In [12]: r'abc\\' Out[12]: 'abc\\\\' So one slash before the closing quote is an error, but two slashes gives you two slashes! Certainly I'm not the only one that is bothered by this? Thoughts on why 'raw' strings are 'raw, except for slash-quote'? I mean, if I wanted to embed a single quote in there I'd just use double quotes around the string, and vice versa. If I wanted both, I'd just triple quote. If I really wanted three quotes in a row in a raw string, well, I guess I'd have to deal, but is this considered "proper behavior"?

    Read the article

  • How to solve this problem with Python

    - by morpheous
    I am "porting" an application I wrote in C++ into Python. This is the current workflow: Application is started from the console Application parses CLI args Application reads an ini configuration file which specifies which plugins to load etc Application starts a timer Application iterates through each loaded plugin and orders them to start work. This spawns a new worker thread for the plugin The plugins carry out their work and when completed, they die When time interval (read from config file) is up, steps 5-7 is repeated iteratively Since I am new to Python (2 days and counting), the distinction between script, modules and packages are still a bit hazy to me, and I would like to seek advice from Pythonista as to how to implement the workflow described above, using Python as the programing language. In order to keep things simple, I have decided to leave out the time interval stuff out, and instead run the python script/scripts as a cron job instead. This is how I am thinking of approaching it: Encapsulate the whole application in a package which is executable (i.e. can be run from the command line with arguments. Write the plugins as modules (I think maybe its better to implement each module in a separate file?) I havent seen any examples of using threading in Python yet. Could someone provide a snippet of how I could spawn a thread to run a module. Also, I am not sure how to implement the concept of plugins in Python - any advice would be helpful - especially with a code snippet.

    Read the article

1