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  • Get spiral index from location

    - by ricick
    I'm using Alberto Santini's solution to this question to get a spiral grid reference based on an items index Algorithm for iterating over an outward spiral on a discrete 2D grid from the origin It's not the accepted solution, but it's the best for my needs as it avoids using a loop. It's working well, but what I want now is to do the inverse. Based on a known x and y coordinate return the index of a location. This is as a precursor to returning the items surrounding a given location.

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