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  • jQuery.data() works in Mac OS WebKit, but not on iPhone OS?

    - by rpj
    I'm playing around with jQTouch for an iPhone OS app that I've been toying with off and on for a while. I wanted to try my hand building it as a web app so I started playing with jQTouch. For reference, here is the page+source (all my code is currently in index.html so you can just "View Source" to see it all): http://rpj.me/doughapp.com/wd/ Essentially, I'm trying to save pertinent JSON objects retrieved from Google Local into DOM objects using the data() method (in this example, obj is the Google Local object): $('#locPane').data('selected', obj); then later (in a different "pane"), retrieving that object to be used: $('#locPane').bind('pageAnimationEnd', function(e, inf) { var selobj = $(this).data('selected'); // use 'selobj' here ... } In Chromium and Safari on the desktop OS (Snow Leopard in my case), this works perfectly (try it out). However, the same code returns undefined for the call to $(this).data('selected') in the second snippet above. I've also tried $('#' + e.target.id).data('selected') and even the naive $('#locPane').data('selected'). All variants return undefined in the iPhone OS version of WebKit, but not on the desktop. Interestingly, the running this on Mobile Safari in the iPhone Simulator fails as well. If you look at the full source, you'll see that I even try to save this object into my global jQTouch object (named jqt in my code). This, too, fails on the mobile platform. Has anyone else ever ran into this? I'll admit to not being a web/javascript programmer by trade, so if I'm making an idiot's error please call me out on it. Thank you in advance for the help! -RPJ Update: I didn't make it clear in the original post, but I'm open to any workaround if it works consistently. Since I'm having trouble storing these objects in general, anything that allows me to keep them around is good enough for now. Thanks!

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  • Using a UITableViewController with a small-sized table?

    - by rpj
    When using a UITableViewController, the initWithStyle: method automatically creates the underlying UITableView with - according to the documentation - "the correct dimensions". My problem is that these "correct dimensions" seem 320x460 (the iPhone's screen size), but I'm pushing this TableView/Controller pair into a UINavigationController which is itself contained in a UIView, which itself is about half the height of the screen. No frame or bounds wrangling I can come up with seems to correctly reset the table's size, and as such it's "too long", meaning there are a collection of rows that are pushed off the bottom of the screen and are not visible nor reachable by scrolling. So my question comes down to: what is the proper way to tell a UITableViewController to resize its component UITableView to a specified rectangle? Thanks! Update I've tried all the techniques suggested here to no avail, but I did find one interesting thing: if I eschew the UINavigationController altogether (which I'm not yet willing to do for production, but as an experiment), and add the table view as a direct subview of the enclosing view I mentioned, the frame size given is respected. The very moment I re-introduce the UINavigationController into the mix, no matter if it is added as a subview before or after the table view, and no matter if alloc/init it before or after the table view is added as a subview, the result is the same as it was before. I'm beginning to suspect UINavigationController isn't much of a team player... Update 2 The suggestion to check frame size after the table view on screen was a good one: turns out that the navigation controller is in fact resizing it some time in between load and display. My solution, hacky at best, has been to cache the frame given on load and to reset it if changed at the beginning of tableView:cellForRowAtIndexPath:. Why there you ask? Because it's the one place I found that worked, that's why! I don't consider this a solution as it's obviously improper, but for the benefit of anyone else reading, it does seem to work.

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