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Search found 41 results on 2 pages for 'sajid nizami'.

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  • Third argument in strstr is only valid in PHP 5.3.0

    - by Muhammad Sajid
    Hello I want to get user from an email address, eg: [email protected] then output must be sajid for this is use below mentioned code but an warning occur $user = strstr($email, '@', true); Warning: Wrong parameter count for strstr() in /var/www/DataTable/dialog.php on line 3 & in php manul it is clearly define that the 3rd argument true is only valid for PHP 5.3.0 So is there any string function which could solve my problem?

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  • Removal of libsound2 file causes graphics loss

    - by Sajid Ahmad
    I was trying to install skype on ubuntu 12.10 desktop. but it was giving some error related to libsound2:i386 file. to overcome this problem i removed file libsound2 thinking that will install it later. but it removes all the graphics from my system. after removal of the file system started to give error that system is running in low graphics mode. I tried to install libsound2 file again but couldn't. After it i have upgraded the release of my ubuntu version using command do-release-upgrade think that it will install the missing file. But still there are no graphics on the system. I am using Dell Inspiron 15 . Please help me to tell that how can i get the graphics of system back.

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  • Uploading on Youtube via HTTP Post

    - by sajid.nizami
    I am following the steps provided on this link [http://code.google.com/apis/youtube/2.0/developers_guide_dotnet.html#Browser_based_Upload][1] Whenever I try to upload anything using this method, I get a HTTP 400 error saying that the next_url is not provided. Code is pretty simple and is a copy of Google's own code. <%@ Page Language="C#" AutoEventWireup="true" CodeFile="BrowserUpload.aspx.cs" Inherits="BrowserUpload" %> <%@ Import Namespace="Google.YouTube" %> <%@ Import Namespace="Google.GData.Extensions.MediaRss" %> <%@ Import Namespace="Google.GData" %> <%@ Import Namespace="Google.GData.YouTube" %> <%@ Import Namespace="Google.GData.Client" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> <script type="text/javascript"> function checkForFile() { if (document.getElementById('file').value) { return true; } document.getElementById('errMsg').style.display = ''; return false; } </script> </head> <body> <% YouTubeRequestSettings settings = new YouTubeRequestSettings("Danat", "API-KEY", "loginid", "password" ); YouTubeRequest request = new YouTubeRequest(settings); Video newVideo = new Video(); newVideo.Title = "My Test Movie"; newVideo.Tags.Add(new MediaCategory("Autos", YouTubeNameTable.CategorySchema)); newVideo.Keywords = "cars, funny"; newVideo.Description = "My description"; newVideo.YouTubeEntry.Private = false; newVideo.Tags.Add(new MediaCategory("mydevtag, anotherdevtag", YouTubeNameTable.DeveloperTagSchema)); FormUploadToken token = request.CreateFormUploadToken(newVideo); %> <form action="<%= token.Url %>?next_url=<%= Server.UrlEncode("http://www.danatev.com") %>" name="PostToYoutube" method="post" enctype="multipart/form-data" onsubmit="return checkForFile();" > <input id="file" type="file" name="file" /> <div id="errMsg" style="display: none; color: red"> You need to specify a file. </div> <input type="hidden" name="token" value="<%= token.Token %>" /> <input type="submit" value="go" /> </form>

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  • Localhost doesnot work.

    - by Muhammad Sajid
    Hi, I installed wamp server on xp. During the installation it did not show any error/warning message. Then i start it & type http://localhost/ in url bar but it just show a blank page. I also checked notepad C:\WINDOWS\system32\drivers\etc\hosts their is no restriction for localhost. Help. Thanks...

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  • Localhost doesnot work.

    - by Muhammad Sajid
    Hi, I installed wamp server on xp. During the installation it did not show any error/warning message. Then i start it & type http://localhost/ in url bar but it just show a blank page. I also checked notepad C:\WINDOWS\system32\drivers\etc\hosts their is no restriction for localhost. Help. Thanks...

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  • Debugger for IE7

    - by Muhammad Sajid
    I m using PHP5 & during testing on IE7 if some thing does no work then i can not find the bug quickly as i can do in FF (by the help of Firebug). Is there any tool for code debugging in IE7 like in FireFox we have firebug ?

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  • Change array format in PHP.

    - by Muhammad Sajid
    I have an array like: Array ( [6] => Array ( [quantity] => 23 [orgId] => 6 [validity] => 20 ) [2] => Array ( [quantity] => 5 [orgId] => 2 [validity] => 2 ) [5] => Array ( [quantity] => 5 [orgId] => 5 [validity] => 4 ) [4] => Array ( [quantity] => 7 [orgId] => 4 [validity] => 10 ) ) and i want to show that like this: Array ( [0] => Array ( [quantity] => 23 [orgId] => 6 [validity] => 20 ) [1] => Array ( [quantity] => 5 [orgId] => 2 [validity] => 2 ) [2] => Array ( [quantity] => 5 [orgId] => 5 [validity] => 4 ) [3] => Array ( [quantity] => 7 [orgId] => 4 [validity] => 10 ) ) To do that i used array_push & some other technique but fail. can someone help me thanks.

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  • Display label character by character using javascript

    - by Muhammad Sajid
    Hi, I am creating Hang a Man using PHP, MySQL & Javascript. Every thing is going perfect, I get a word randomly from DB show it as a label apply it a class where display = none. Now when I click on a Character that character become disable fine which i actually want but the label-character does not show. My code is: <link href="style.css" rel="stylesheet" type="text/css" media="screen" /> <?php include( 'config.php' ); $question = questions(); // Get question. $alpha = alphabats(); // Get alphabets. ?> <script language="javascript"> function clickMe( name ){ var question = '<?php echo $question; ?>'; var questionLen = <?php echo strlen($question); ?>; for ( var i = 0; i < questionLen; i++ ){ if ( question[i] == name ){ var link = document.getElementById( name ); link.style.display = 'none'; var label = document.getElementById( 'questionLabel' + i ); label.style.display = 'block'; } } } </script> <div> <table align="center" style="border:solid 1px"> <tr> <?php for ( $i = 0; $i < 26; $i++ ) { echo "<td><a href='#' id=$alpha[$i] name=$alpha[$i] onclick=clickMe('$alpha[$i]');>". $alpha[$i] ."</a>&nbsp;</td>"; } ?> </tr> </table> <br/> <table align="center" style="border:solid 1px"> <tr> <?php for ( $i = 0; $i < strlen($question); $i++ ) { echo "<td class='question'><label id=questionLabel$i >". $question[$i] ."</label></td>"; } ?> </tr> </table> </div>

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  • Display lable character by character using javascript

    - by Muhammad Sajid
    Hi, I am creating Hang a Man using PHP, MySQL & Javascript. Every thing is going perfect, I get a word randomly from DB show it as a label apply it a class where display = none. Now when I click on a Character that character become disable fine which i actually want but the label-character does not show. My code is: <link href="style.css" rel="stylesheet" type="text/css" media="screen" /> <?php include( 'config.php' ); $question = questions(); // Get question. $alpha = alphabats(); // Get alphabets. ?> <script language="javascript"> function clickMe( name ){ var question = '<?php echo $question; ?>'; var questionLen = <?php echo strlen($question); ?>; for ( var i = 0; i < questionLen; i++ ){ if ( question[i] == name ){ var link = document.getElementById( name ); link.style.display = 'none'; var label = document.getElementById( 'questionLabel' + i ); label.style.display = 'none'; } } } </script> <div> <table align="center" style="border:solid 1px"> <tr> <?php for ( $i = 0; $i < 26; $i++ ) { echo "<td><a href='#' id=$alpha[$i] name=$alpha[$i] onclick=clickMe('$alpha[$i]');>". $alpha[$i] ."</a>&nbsp;</td>"; } ?> </tr> </table> <br/> <table align="center" style="border:solid 1px"> <tr> <?php for ( $i = 0; $i < strlen($question); $i++ ) { echo "<td class='question'><label id=questionLabel$i >". $question[$i] ."</label></td>"; } ?> </tr> </table> </div>

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  • Show hide DIVs : jQuery

    - by Muhammad Sajid
    Hi, I have two links & I want to show / hide them one at a time, my code is : <!DOCTYPE html> <html> <head> <script class="jsbin" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script> <script type="text/javascript" src="js/jquery.js"></script> <script type="text/javascript"> // we will add our javascript code here $(document).ready(function() { $(function(){ $('#link').click(function(){ $('#colorDiv').slideToggle('slow'); return false; }); }); }); </script> <meta charset=utf-8 /> <title>JS Bin</title> <!--[if IE]> <script src="http://html5shiv.googlecode.com/svn/trunk/html5.js"></script> <![endif]--> <style> #dv { width:100px; height:100px; border:1px solid; } </style> </head> <body> <table cellspacing="2"> <tr><td><a href="#" id="link">Color</a></td><td><a href="#" id="link">Car</a></td></tr> <tr><td><div id="colorDiv">Red</div></td><td><div id="carDiv">PRADO</div></td></tr> </table> </body> </html> by default first div should me shown. hanks.

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  • Fetch all emails in PHP.

    - by Muhammad Sajid
    Hello. I want to fetch all my emails available in different online accounts eg:(gmail, yahoo, hotmail, aol, etc..) using PHP such that if necessary to reply any email then I could reply. How it is possible?

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  • MySql Retrive data from same table.

    - by Muhammad Sajid
    Hi, I have a table which contains id, name, parentId of Top level Menus & their children like: -------------------------------------- id | name | parentId -------------------------------------- 1 | Color | 0 -------------------------------------- 2 | Flower | 0 -------------------------------------- 3 | Red | 1 -------------------------------------- 4 | pink | 1 -------------------------------------- 5 | Rose | 2 -------------------------------------- 6 | Lily | 2 -------------------------------------- And I want to fetch these record some thing that the resultant array must be like --------------------------------------------------------------- id | Pname | parentId | child | childId --------------------------------------------------------------- 1 | Color | 1 | Red | 3 --------------------------------------------------------------- 2 | Color | 1 | Pink | 4 --------------------------------------------------------------- 3 | Flower | 2 | Rose | 5 --------------------------------------------------------------- 4 | Flower | 2 | Lily | 6 --------------------------------------------------------------- my query was like: SELECT name AS Pname FROM myTbl WHERE id = (SELECT parentId FROM myTbl WHERE parentId = 1 ) but mysql say #1242 - Subquery returns more than 1 row Could anyone solve it. Thanks..

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  • What transaction manager should I use for JBDC template When using JPA ?

    - by Sajid
    I am using standard JPA transaction manager for my JPA transactions. However, now I want to add some JDBC entities which will share the same 'datasource'. How can I make the JDBC operations transactional with spring transaction? Do I need to swith to JTA transaction managers? Is it possible to use both JPA & JDBC transactional service with same datasource? Even better, is it possible to mix these two transactions?

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  • Array filteration PHP

    - by Muhammad Sajid
    I have an array with values like: Array ( [0] => Array ( [parent] => Basic [parentId] => 1 [child] => Birthday [childId] => 2 ) [1] => Array ( [parent] => Basic [parentId] => 1 [child] => Gender [childId] => 3 ) [2] => Array ( [parent] => Geo [parentId] => 10 [child] => Current City [childId] => 11 ) [3] => Array ( [parent] => Known me [parentId] => 5 [child] => My personality [childId] => 7 ) [4] => Array ( [parent] => Known me [parentId] => 5 [child] => Best life moment [childId] => 8 ) ) And I want to filter this array such that their filtration based on parent index, and the final result would be like: Array ( [0] => Array ( [parent] => Basic [parentId] => 1 [child] => Array ( [0] => Birthday [1] => Gender ) ) [1] => Array ( [parent] => Geo [parentId] => 10 [child] => Array ( [0] => Current City ) ) [2] => Array ( [parent] => Known me [parentId] => 5 [child] => Array ( [0] => My personality [1] => Best life moment ) ) ) For that I coded : $filter = array(); $f = 0; for ($i=0; $i<count($menuArray); $i++) { $c = 0; for( $b = 0; $b < count($filter); $b++ ){ if( $filter[$b]['parent'] == $menuArray[$i]['parent'] ){ $c++; } } if ($c == 0) { $filter[$f]['parent'] = $menuArray[$i]['parent']; $filter[$f]['parentId'] = $menuArray[$i]['parentId']; $filter[$f]['child'][] = $menuArray[$i]['child']; $f++; } } But it results : Array ( [0] => Array ( [parent] => Basic [parentId] => 1 [child] => Array ( [0] => Birthday ) ) [1] => Array ( [parent] => Geo [parentId] => 10 [child] => Array ( [0] => Current City ) ) [2] => Array ( [parent] => Known me [parentId] => 5 [child] => Array ( [0] => My personality ) ) ) Could anyone point out my missing LOC?

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  • How to get <select> options either (value or text) using jQuery

    - by Muhammad Sajid
    Hello, i have a code for <select id='list'> <option value='1'>Option A</option> <option value='2'>Option B</option> <option value='3'>Option C</option> </select> and i want that how ever i select any option, it will show in an alert message. i have try <script type='text/javascript'> //var value = $("#list option[value=2]").text(); //var value = $("#list option:selected").text(); //var value = $('#list').val(); var value = $(this).val(); alert(value); </script> but fail.

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  • Show values in TDropDownList in PRADO.

    - by Muhammad Sajid
    I m new to PRADO, I have a file Home.page with code: <%@ Title="Contact List" %> <h1>Contact List</h1> <a href="<%= $this->Service->constructUrl('insert')%>">Create New Contact</a> <br/> <com:TForm> <com:TDropDownList ID="personInfo"> <com:TListItem Value="value 1" Text="item 1" /> <com:TListItem Value="value 2" Text="item 2" Selected="true" /> <com:TListItem Value="value 3" Text="item 3" /> <com:TListItem Value="value 4" Text="item 4" /> </com:TDropDownList> </com:TForm> & Home.php with code <?php class Home extends TPage { /** * Populates the datagrid with user lists. * This method is invoked by the framework when initializing the page * @param mixed event parameter */ public function onInit($param) { parent::onInit($param); // fetches all data account information $rec = ContactRecord::finder()->findAll(); } } ?> the $rec contain array of all values. Now I want to show all name in Dropdown list. I tried my best but fail. Can anyone help me? Thanks

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  • Replace images in a DIV using javascript.

    - by Muhammad Sajid
    Hi, I want to show different images in a DIV, the turn of an image depend on a random number. The image name is like 1.gif, 2.gif, .. 6.gif to do that I coded var img = document.createElement("IMG"); img.src = "images/1.gif"; document.getElementById('imgDiv').appendChild(img); but it does not replace the old image how ever it add an another image right in the bottom of first image. syntax for DIV is: <div id="imgDiv" style="width:85px; height:100px; margin:0px 10px 10px 375px;"></div> may u halp me ?

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  • Define variables outside the PHP class.

    - by Muhammad Sajid
    Hello, I m using zend. I want to define the below code outside the controller class & access in different Actions. $user = new Zend_Session_Namespace('user'); $logInArray = array(); $logInArray['userId'] = $user->userid; $logInArray['orgId'] = $user->authOrgId; class VerifierController extends SystemadminController { public function indexAction() { // action body print_r($logInArray); } } How it is possible.

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