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  • How to set multiple timezones in Gnome Classic?

    - by Serrano Pereira
    For some strange reason, additional timezones cannot be added to the clock using the date-time indicator in Gnome Classic (Ubuntu 12.04). I used Unity before I switched to Gnome Classic, and it was possible to add more timezones. Even in Gnome Classic I can see the other timezones in the menu of the date-time indicator which I added when I was still using Unity. When I go to System Settings Date and Time, there is no option for adding other timezones. How can I set additional timezones in Gnome Classic?

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  • Failure to toubleshoot a juju charm deployment

    - by Bruno Pereira
    My environments.yaml looks like this: environments: test: type: local control-bucket: juju-a14dfae3830142d9ac23c499395c2785999 admin-secret: 6608267bbd6b447b8c90934167b2a294999 default-series: oneiric juju-origin: distro data-dir: /home/bruno/projects/juju juju bootstrap runs perfect: 2011-11-22 19:19:31,999 INFO Bootstrapping environment 'test' (type: local)... 2011-11-22 19:19:32,004 INFO Checking for required packages... 2011-11-22 19:19:33,584 INFO Starting networking... 2011-11-22 19:19:34,058 INFO Starting zookeeper... 2011-11-22 19:19:34,283 INFO Starting storage server... 2011-11-22 19:19:40,051 INFO Initializing zookeeper hierarchy 2011-11-22 19:19:40,247 INFO Starting machine agent (origin: distro)... [sudo] password for bruno: 2011-11-22 19:23:16,054 INFO Environment bootstrapped 2011-11-22 19:23:16,079 INFO 'bootstrap' command finished successfully Deploy from a known good charm is accepted (tried it with one that I am trying to create): juju deploy --repository=/home/bruno/projects/charms_repo/ local:teamspeak 2011-11-22 19:28:49,929 INFO Charm deployed as service: 'teamspeak' 2011-11-22 19:28:49,962 INFO 'deploy' command finished successfully After this I can see that juju debug-log shows activity and I can see the network indicator going on and off and activity on my hard-disk. Wait... Looking at juju status I get: services: teamspeak: charm: local:oneiric/teamspeak-1 relations: {} units: teamspeak/0: machine: 0 public-address: 192.168.122.226 relations: {} state: start_error juju debug-log does not help and I have no files under /var/log/juju or /var/lib/juju. Last juju debug-log only shows this: 2011-11-22 19:45:20,790 Machine:0: juju.agents.machine DEBUG: Units changed old:set(['wordpress/0']) new:set(['wordpress/0', 'teamspeak/0']) 2011-11-22 19:45:20,823 Machine:0: juju.agents.machine DEBUG: Starting service unit: teamspeak/0 ... 2011-11-22 19:45:21,137 Machine:0: juju.agents.machine DEBUG: Downloading charm local:oneiric/teamspeak-1 to /home/bruno/projects/juju/bruno-test/charms 2011-11-22 19:45:22,115 Machine:0: juju.agents.machine DEBUG: Starting service unit teamspeak/0 2011-11-22 19:45:22,133 Machine:0: unit.deploy INFO: Creating container teamspeak-0... 2011-11-22 19:47:04,586 Machine:0: unit.deploy INFO: Container created for teamspeak/0 2011-11-22 19:47:04,781 Machine:0: unit.deploy DEBUG: Charm extracted into container 2011-11-22 19:47:04,801 Machine:0: unit.deploy DEBUG: Starting container... 2011-11-22 19:47:07,086 Machine:0: unit.deploy INFO: Started container for teamspeak/0 2011-11-22 19:47:07,107 Machine:0: juju.agents.machine INFO: Started service unit teamspeak/0 How can I troubleshot what is happening here?

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  • Is Ubuntu MAAS free? Will it remain like that?

    - by Bruno Pereira
    Ubuntu MAAS, very cool, awesome in fact, looks like a unique tool for several jobs. It looks free, but part of its documentation starts already with clauses that would scare anyone with interest in it: Documentation is copy righted by Canonical; Documentation must be used only for non-commercial purposes; If documentation is distributed within the non-commercial clause you must retain copyright; It just sounds a lot for a guide on how to install MAAS + Juju + Openstack and that scares me a bit. Under what license is Ubuntu MAAS distributed and what would be the reasoning for being so worried about copyrighting a guide like that so heavily? Is Ubuntu MAAS free? Will it continue like that?

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  • SQl function in android

    - by rui.pereira
    Cursor cursor = db.rawQuery("SELECT COUNT(rat) FROM "+ TABLE_NAME_EXTRA +" apkid=\""+apkid, null); cursor.moveToFirst(); int somatotal = cursor.getInt(0); I'm trying to do a SQL function like count and sum, but this code returns a exception saying "emptyvalues". anyone know why?

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  • SQLServer using too much memory

    - by Israel Pereira Valverde
    I have installed on my desktop machine (with windows 7) SQLServer 2008 R2 Express. I have only one local server running (./SQLEXPRESS) but the sqlserver process is taking ALL the RAM possible. With an machine with 3GB of RAM the things starts to get slow, so I limited the maximun amount of RAM in the server, and now, constantly the SQLServer give some error messages that the memory is not enought. It's using 1GB of RAM with only one LOCAL server with 2 databases completely empty, how 1GB of RAM isn't enought ? When the process start it's using an really acceptable amount of memory (around 80MB) but it's keep increasing until it reaches the maximun defined and start to complain about having not enought memory available. In that point I have to restart the server to use it again. I have read about an hotfix to solve one of the errors I got from sqlserver: There is insufficient system memory in resource pool 'internal' to run this query But it's already installed on my sqlserver. Why it's using so much memory?

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  • SQL SERVER Subquery or Join Various Options SQL Server Engine Knows the Best Part 2

    This blog post is part 2 of the earlier written article SQL SERVER Subquery or Join Various Options SQL Server Engine knows the Best by Paulo R. Pereira. Paulo has left excellent comment to earlier article once again proving the point that SQL Server Engine is smart enough to figure out the [...]...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Create a unique ID by fuzzy matching of names (via agrep using R)

    - by tbrambor
    Using R, I am trying match on people's names in a dataset structured by year and city. Due to some spelling mistakes, exact matching is not possible, so I am trying to use agrep() to fuzzy match names. A sample chunk of the dataset is structured as follows: df <- data.frame(matrix( c("1200013","1200013","1200013","1200013","1200013","1200013","1200013","1200013", "1996","1996","1996","1996","2000","2000","2004","2004","AGUSTINHO FORTUNATO FILHO","ANTONIO PEREIRA NETO","FERNANDO JOSE DA COSTA","PAULO CEZAR FERREIRA DE ARAUJO","PAULO CESAR FERREIRA DE ARAUJO","SEBASTIAO BOCALOM RODRIGUES","JOAO DE ALMEIDA","PAULO CESAR FERREIRA DE ARAUJO"), ncol=3,dimnames=list(seq(1:8),c("citycode","year","candidate")) )) The neat version: citycode year candidate 1 1200013 1996 AGUSTINHO FORTUNATO FILHO 2 1200013 1996 ANTONIO PEREIRA NETO 3 1200013 1996 FERNANDO JOSE DA COSTA 4 1200013 1996 PAULO CEZAR FERREIRA DE ARAUJO 5 1200013 2000 PAULO CESAR FERREIRA DE ARAUJO 6 1200013 2000 SEBASTIAO BOCALOM RODRIGUES 7 1200013 2004 JOAO DE ALMEIDA 8 1200013 2004 PAULO CESAR FERREIRA DE ARAUJO I'd like to check in each city separately, whether there are candidates appearing in several years. E.g. in the example, PAULO CEZAR FERREIRA DE ARAUJO PAULO CESAR FERREIRA DE ARAUJO appears twice (with a spelling mistake). Each candidate across the entire data set should be assigned a unique numeric candidate ID. The dataset is fairly large (5500 cities, approx. 100K entries) so a somewhat efficient coding would be helpful. Any suggestions as to how to implement this?

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  • Google I/O 2010 - Building your own Google Wave provider

    Google I/O 2010 - Building your own Google Wave provider Google I/O 2010 - Open source Google Wave: Building your own wave provider Wave 101 Dan Peterson, Jochen Bekmann, JD Zamfirescu Pereira, David LaPalomento (Novell) Learn how to build your own wave service. Google is open sourcing the lion's share of the code that went into creating Google Wave to help bootstrap a network of federated providers. This talk will discuss the state of the reference implementation: the software architecture, how you can plug it into your own use cases -- and how you can contribute to the code and definition of the underlying specification. For all I/O 2010 sessions, please go to code.google.com From: GoogleDevelopers Views: 8 0 ratings Time: 59:03 More in Science & Technology

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  • SQL SERVER – Subquery or Join – Various Options – SQL Server Engine Knows the Best – Part 2

    - by pinaldave
    This blog post is part 2 of the earlier written article SQL SERVER – Subquery or Join – Various Options – SQL Server Engine knows the Best by Paulo R. Pereira. Paulo has left excellent comment to earlier article once again proving the point that SQL Server Engine is smart enough to figure out the best plan itself and uses the same for the query. Let us go over his comment as he has posted. “I think IN or EXISTS is the best choice, because there is a little difference between ‘Merge Join’ of query with JOIN (Inner Join) and the others options (Left Semi Join), and JOIN can give more results than IN or EXISTS if the relationship is 1:0..N and not 1:0..1. And if I try use NOT IN and NOT EXISTS the query plan is different from LEFT JOIN too (Left Anti Semi Join vs. Left Outer Join + Filter). So, I found a case where EXISTS has a different query plan than IN or ANY/SOME:” USE AdventureWorks GO -- use of SOME SELECT * FROM HumanResources.Employee E WHERE E.EmployeeID = SOME ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA UNION ALL SELECT EA.EmployeeID FROM HumanResources.EmployeeDepartmentHistory EA ) -- use of IN SELECT * FROM HumanResources.Employee E WHERE E.EmployeeID IN ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA UNION ALL SELECT EA.EmployeeID FROM HumanResources.EmployeeDepartmentHistory EA ) -- use of EXISTS SELECT * FROM HumanResources.Employee E WHERE EXISTS ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA UNION ALL SELECT EA.EmployeeID FROM HumanResources.EmployeeDepartmentHistory EA ) When looked into execution plan of the queries listed above indeed we do get different plans for queries and SQL Server Engines creates the best (least cost) plan for each query. Click on image to see larger images. Thanks Paulo for your wonderful contribution. Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, Readers Contribution, SQL, SQL Authority, SQL Joins, SQL Optimization, SQL Performance, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – Solution – Puzzle – Challenge – Error While Converting Money to Decimal

    - by pinaldave
    Earlier I had posted quick puzzle and I had received wonderful response to the same. Today we will go over the solution. The puzzle was posted here: SQL SERVER – Puzzle – Challenge – Error While Converting Money to Decimal Run following code in SSMS: DECLARE @mymoney MONEY; SET @mymoney = 12345.67; SELECT CAST(@mymoney AS DECIMAL(5,2)) MoneyInt; GO Above code will give following error: Msg 8115, Level 16, State 8, Line 3 Arithmetic overflow error converting money to data type numeric. Why and what is the solution? Solution is as following: DECLARE @mymoney MONEY; SET @mymoney = 12345.67; SELECT CAST(@mymoney AS DECIMAL(7,2)) MoneyInt; GO There were more than 20 valid answers. Here is the reason. Decimal data type is defined as Decimal (Precision, Scale), in other words Decimal (Total digits, Digits after decimal point).. Precision includes Scale. So Decimal (5,2) actually means, we can have 3 digits before decimal and 2 digits after decimal. To accommodate 12345.67 one need higher precision. The correct answer would be DECIMAL (7,2) as it can hold all the seven digits. Here are the list of the experts who have got correct answer and I encourage all of you to read the same over hear. Fbncs Piyush Srivastava Dheeraj Abhishek Anil Gurjar Keval Patel Rajan Patel Himanshu Patel Anurodh Srivastava aasim abdullah Paulo R. Pereira Chintak Chhapia Scott Humphrey Alok Chandra Shahi Imran Mohammed SHIVSHANKER The very first answer was provided by Fbncs and Dheeraj had very interesting comment. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Pinal Dave, Readers Contribution, Readers Question, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Lançamento do Oracle Enterprise Manager 11g - (27/Mai/10)

    - by Claudia Costa
    Não perca este evento exclusivo para executivos, responsáveis de TI e Parceiros Oracle, e explore em que medida a versão mais recente do Oracle Enterprise Manager permite que a gestão das TI seja orientada para o negócio. Registe-se hoje! Descubra as novas capacidades do Oracle Enterprise Manager 11g, que incluem: ·         Gestão integrada, desda a aplicação até ao Cloud Computing, visando a maximização do retorno do investimento em TI ·         Gestão de aplicações orientadas para o negócio, que permte ao departamento de TI identificar e corrigir os problemas antes de estes terem impacto no negócio ·         Gestão e suporte intregrados dos sistemas, fornecendo notificações e correcções proactivas, associadas à partilha de conhecimento entre pares, para aumentar a satisfação dos clientes Junte-se a nós e fique a saber como somente o Oracle Enterprise Manager 11g pode ajudar as TI a melhorarem proactivamente o valor empresarial em diversas tecnologias, incluindo sistemas Sun; sistema operativo Oracle Solaris; Oracle Database; Oracle Fusion Middleware; Oracle E Business Suite; soluções Siebel, PeopleSoft e JD Edwards da Oracle; tecnologias de virtualização e ambientes de nuvem privada. Irá decorrer uma sessão exclusiva para parceiros da Oracle onde falará de temas como a especialização e exploração de oportunidades de negócio conjunto nas áreas de Gestão de aplicações e sitemas. Agenda - Sana Lisboa Park Hotel Avenida Fontes Pereira de Melo, 8 Lisboa Quinta-Feira, 27 de Maio de 2010 Horario: 9:00- 15:30h 9:00    Registo e Café 9:30    Introdução 9:40    Keynote: Business-driven IT Mnagement with Oracle Enterprise Manager 11g 10:25  Experiências de Cliente 11:00  Pausa 11:15  Integrated Application-to-disk Mangement 11:45  Business-driven Application Management 12:15  Integrated Cloud Management 12:45  Integrated Systems Management and Support Experience 13:15  Almoço 14:30  Sessão para Parceiros - Especialização e Oportunidades de negócio com Oracle      Enterprise Manager   Registe-se hoje mesmo para reservar o seu lugar neste evento exclusivo.      

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  • PRUEBAS DE ESPECIALIZACION GRATUITAS 2013

    - by agallego
    Consigue  tu Certificado de Especialista Oracle  de forma GRATUITA , 27 y 28 de Noviembre de 2013  Ahora puedes realizar los exámenes de implementación de las especializaciones de Oracle y convertirte en especialista. Podrás realizar cualquiera de los exámenes de implementación de la siguiente lista: Oracle Fusion Customer Relationship Management 11g Sales Certified Implementation Specialist (1Z0-456) Oracle Fusion Financials 11g General Ledger Implementation Specialist(1Z0-508) Oracle Fusion Financials 11g Accounts Payable Implementation Specialist(1Z0-507) Oracle Fusion Financials 11g Accounts Receivable Implementation Specialist(1Z0-506) Oracle Fusion Human Capital Management 11g Human Resources Certified Implementation Specialist (1Z0-584) Oracle Fusion Human Capital Management 11g Talent Management Certified Implementation Specialist (1Z0-585) Oracle ATG Web Commerce 10 Implementation Developer Certified Implementation Specialist (1Z0-510) Oracle Hyperion Planning 11 Essentials (1Z0-533) Oracle Business Intelligence Applications 7.9.6 for ERP Essentials (1Z0-525) Oracle Hyperion Financial Management 11 Essentials (1Z0-532) Oracle Business Intelligence Applications 7.9.6 for CRM Essentials (1Z0-524) Oracle Hyperion Data Relationship Management 11.1.2 Essentials (1Z1-588) Oracle Business Intelligence Foundation Suite 11g Essentials (1Z0-591) Oracle Essbase 11 Essentials (1Z0-531) SPARC T4-Based Server Installation Essentials (1Z0-597) Oracle Solaris 11 Installation and Configuration Essentials (1Z0-580) Sun ZFS Storage Appliance Certified Implementation Specialist Exalogic Elastic Cloud X2-2 Certified Implementation Specialist Oracle Exadata 11g Essentials (1Z0-536) Oracle VM 3 for x86 Essenstials (1Z0-590) Oracle Linux Fundamentals (1Z0-402) Oracle Linux System Administration (1Z0-403) Oracle Service-Oriented Architecture Certified Implementation Specialist (1Z0-451) Oracle Unified Business Process Management Suite 11g Certified Implementation Specialist (1Z0-560) Oracle WebLogic Server 12c Certified Implementation Specialist (1Z0-599) Oracle WebCenter Portal 11g Essentials (1Z0-541) Oracle WebCenter Content 11g Essentials (1Z0-542) Oracle Application Development Framework 11g Certified Implementation Specialist Oracle Identity Analytics 11g Certified Implementation Specialist (1Z0-545) Oracle Enterprise Manager 12c Essentials (1Z0-457) Puedes consultar la información acerca de los examenes en cada uno de los enlaces. Para prepararte los examenes sigue la Guia de estudio que encontrarás en la página de cada examen. Requisitos: ser  Partner Gold, Platinum o Diamond de Oracle y tener un usuario de Oracle Pearson Vue.  ¿Cuándo?: 27 y 28 de noviembre  a las (9:00, 12:00, 16:00)  ¿Dónde?: Core Networks, C.E.Parque Norte, Edificio Olmo, Planta 1 Serrano Galvache 56 | 28033, Madrid Para inscribirte: Create una cuenta en Pearson Vue (www.pearsonvue.com/oracle). Para Registrarte aquí. Para más información sobre el programa de especializaciones, haz clic aquí. No pierdas esta oportunidad e inscríbete hoy.  Para cualquier duda contactar con [email protected]. Ana María Gallego Partner Enablement Manager Spain and Portugal      

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  • C programming XML

    - by Pedro
    Hello, Do you imagine that I have the following txt: /* Licenciaturas na ESTG-IPVC 2009 – v1.1*/ - Info, 3 dados, ;; - disciplinas, ;;[;] LEI;7671;Maria Albertina da silva;[email protected]; 9;8;12;9;12;11;6;15;7;11; LTCGM;6567;Artur Pereira Ribeiro;[email protected]; 6;13;14;12;11;16;14; LEI;7701;Ana Maria Carvalho;[email protected]; 8;13;11;7;14;12;11;16;14; How can I make a C program that convert txt to XML. thanks

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  • How do I convert text to XML in C?

    - by pedro
    How can I make a program that opens a text file, and converts it into a XML file? The XML might look like: <curso> <sigla>LTCGM</sigla> <NAlunos>1</NAlunos> <lista_alunos> <aluno> <numero>6567</numero> <nome>Artur Pereira Ribeiro</nome> <email>[email protected]</email> <estado>Aprovado</estado> <media_notas>13</media_notas> <maior_nota>16</maior_nota> <menor_nota>11</menor_nota> </aluno> </lista_alunos> </curso>

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  • PRUEBAS DE ESPECIALIZACION 2013/2014

    - by agallego
    Consigue  tu Certificado de Especialista Oracle  de forma GRATUITA , 27 y 28 de Noviembre de 2013  Ahora puedes realizar los exámenes de implementación de las especializaciones de Oracle y convertirte en especialista. Podrás realizar cualquiera de los exámenes de implementación de la siguiente lista: Oracle Fusion Customer Relationship Management 11g Sales Certified Implementation Specialist (1Z0-456) Oracle Fusion Customer Relationship Management 11g Incentive Compensation Certified Implementation Specialist (1Z0-472) Oracle ATG Web Commerce 10 Implementation Developer Certified Implementation Specialist (1Z0-510) Oracle RightNow CX Cloud Service 2012 Certified Implementation Specialist (1Z0-465) Oracle RightNow CX Cloud Service 2012 Developer Certified Implementation Specialist (1Z0-480) Oracle Fusion Human Capital Management 11g Human Resources Certified Implementation Specialist (1Z0-584) Oracle Fusion Human Capital Management 11g Talent Management Certified Implementation Specialist (1Z0-585) Oracle Taleo Recruiting Cloud Service 2013 Certified Implementation Specialist  (1Z0-474) Oracle Fusion Financials 11g Accounts Payable Certified Implementation Specialist(1Z0-507) Oracle Fusion Financials 11g Accounts Receivable Certified Implementation Specialist(1Z0-506) Oracle Fusion Financials 11g General Ledger Certified Implementation Specialist (1Z0-508) Oracle Fusion Distributed Order Orchestration 11g Essentials (1Z0-469) Oracle Documaker Standard Edition 12 Implementation Essentials (1Z0-570) Oracle Hyperion Planning 11 Essentials (1Z0-533) Oracle Hyperion Financial Management 11 Essentials (1Z0-532) Oracle Business Intelligence Foundation Suite 11g Essentials (1Z0-591) Oracle Essbase 11 Essentials (1Z0-531) Oracle GoldenGate 10 Essentials (1Z0-539) Oracle GoldenGate 11g Certified Implementation Exam Essentials Oracle Business Intelligence Applications 7.9.6 for CRM Essentials (1Z0-524) Oracle Business Intelligence Applications 7.9.6 for ERP Essentials (1Z0-525) Oracle Oracle Endeca Information Discovery 2.3 Certified Implementation Specialist (1Z0-461) Oracle SOA Suite 11g Essentials (1Z0-478) Oracle Service-Oriented Architecture Certified Implementation Specialist (1Z0-451) Oracle Unified Business Process Management Suite 11g Certified Implementation Specialist (1Z0-560) Oracle WebLogic Server 12c Certified Implementation Specialist (1Z0-599) Oracle Application Grid Certified Implementation Specialist(1Z0-523) Oracle WebCenter Content 11g Essentials (1Z0-542) Oracle WebCenter Portal 11g Essentials (1Z0-541) Oracle Application Development Framework Essentials (1Z1-554) Oracle Identity Governance Suite 11g Essentials(1z0-459) Oracle Access Management Suite Plus 11g Essentials Exam(1z0-479) M2M Platform Certified Architecture Essentials (1Z0-467) Oracle WebCenter Sites 11g Certified Implementation Specialist (1Z0-462)  Oracle Cloud Application Foundation Essentials(1Z0-468) Oracle Exadata 11g Essentials (1Z0-536) Exadata Database Machine Models X3-2 and X3-8 Certified Implementation Specialist (1Z0-485) Oracle Certified Expert, Oracle Exadata X3 Administration(1Z0-027) Exalogic Elastic Cloud X2-2 Certified Implementation Specialist (1Z0-569) Oracle Linux System Administration (1Z0-403) Oracle Linux Fundamentals (1Z0-402) Oracle Linux 6 Certified Implementation Specialist (1Z0-460) Oracle VM 3 for x86 Certified Implementation Specialist (1Z0-590) Oracle Enterprise Manager 11g Essentials  (1Z0-530 ) Oracle Enterprise Manager 12c Essentials (1Z0-457) SPARC T4-Based Server Installation Essentials (1Z0-597) 1Z0-821 Oracle Solaris 11 System Administration 1Z0-822 Oracle Solaris 11 Advanced System Administration Oracle Solaris 11 Installation and Configuration Essentials (1Z0-580) StorageTek Tape Libraries Certified Implementation Specialist(1Z0-546) Sun ZFS Storage Appliance Certified Implementation Specialist The Primavera P6 Enterprise Project Portfolio Management 8 Essentials (1Z0-567) The Primavera Portfolio Management Essentials (1Z0-544) Primavera Contract Management 14 Certified Implementation Specialist (1Z0-582) Oracle Utilities Customer Care and Billing 2 Certified Implementation Specialist (1Z0-562) Oracle Policy Automation 10 Certified Implementation Specialist (1Z0-534) Oracle User Productivity Kit 11 Certified Implementation Specialist (1Z0-566) Oracle User Productivity Kit 11 Technical Certified Implementation Specialist (1Z0-583) Oracle Retail Demand Forecasting 13.3 Functional Implementer Certified Implementation Specialist (1Z0-463) Oracle Retail Predictive Application Server 13 Configuration Implementation Specialist (1Z0-576) Oracle Retail Merchandising System 13.2 Foundation Functional Implementer Certified Implementation Specialist (1Z0-453) Oracle Retail Predictive Application Server 13 Configuration Implementation Specialist (1Z0-576) Oracle Retail Point-of-Service Technical Certified Implementation Specialist (1Z0-572) Oracle Retail Price Management 13.2 Functional Implementer Certified Implementation Specialist (1Z0-454) Oracle Retail Predictive Application Server 13 Configuration Implementation Specialist (1Z0-576) Oracle Retail Store Inventory Management 13.2 Functional Implementer Certified Implementation Specialist (1Z0-455) Oracle Flexcube Universal Banking 11 Technical Implementation Essentials (1Z0-579) Oracle FlexCube Universal Banking 11 Basic Implementation Essentials (1Z0-561) Oracle Flexcube Universal Banking 11 Technical Implementation Essentials (1Z0-579) Oracle FLEXCUBE Direct Banking 6 Implementation Essentials (1Z0-594)   Puedes consultar la información acerca de los examenes en cada uno de los enlaces. Para prepararte los examenes sigue la Guia de estudio que encontrarás en la página de cada examen. Requisitos: ser  Partner Gold, Platinum o Diamond de Oracle y tener un usuario de Oracle Pearson Vue.  ¿Cuándo?: 27 y 28 de noviembre  a las (9:00, 12:00, 16:00)  ¿Dónde?: Core Networks, C.E.Parque Norte, Edificio Olmo, Planta 1 Serrano Galvache 56 | 28033, Madrid Para inscribirte: Create una cuenta en Pearson Vue (www.pearsonvue.com/oracle). Para Registrarte aquí. Para más información sobre el programa de especializaciones, haz clic aquí. No pierdas esta oportunidad e inscríbete hoy.  Para cualquier duda contactar con [email protected]. Ana María Gallego Partner Enablement Manager Spain and Portugal        

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  • C - array count, strtok, etc

    - by Pedro
    Hi... i have a little problem on my code... HI open a txt that have this: LEI;7671;Maria Albertina da silva;[email protected]; 9;8;12;9;12;11;6;15;7;11; LTCGM;6567;Artur Pereira Ribeiro;[email protected]; 6;13;14;12;11;16;14; LEI;7701;Ana Maria Carvalho;[email protected]; 8;13;11;7;14;12;11;16;14; LEI, LTCGM are the college; 7671, 6567, 7701 is student number; Maria, Artur e Ana are the students name; [email protected], ...@gmail are emails from students; the first number of every line is the total of classes that students have; after that is students school notes; example: College: LEI Number: 7671 Name: Maria Albertina da Silva email: [email protected] total of classes: 9 Classe Notes: 8 12 9 12 11 6 15 7 11. My code: typedef struct aluno{ char sigla[5];//college char numero[80];//number char nome[80];//student name char email[20];//email int total_notas;// total of classes char tot_not[40]; // total classes char notas[20];// classe notes int nota; //class notes char situacao[80]; //situation (aproved or disaproved) }ALUNO; void ordena(ALUNO*alunos, int tam)//bubble sort { int i=0; int j=0; char temp[100]; for( i=0;i<tam;i++) for(j=0;j<tam-1;j++) if(strcmp( alunos[i].sigla[j], alunos[i].sigla[j+1])>0){ strcpy(temp, alunos[i].sigla[j]); strcpy(alunos[i].sigla[j],alunos[i].sigla[j+1]); strcpy(alunos[i].sigla[j+1], temp); } } void xml(ALUNO*alunos, int tam){ FILE *fp; char linha[60];//line int soma, max, min, count;//biggest note and lowest note and students per course count float media; //media of notes fp=fopen("example.txt","r"); if(fp==NULL){ exit(1); } else{ while(!(feof(fp))){ soma=0; media=0; max=0; min=0; count=0; fgets(linha,60,fp); if(linha[0]=='L'){ if(ap_dados=strtok(linha,";")){ strcpy(alunos[i].sigla,ap_dados);//copy to struct // i need to call bubble sort here, but i don't know how printf("College: %s\n",alunos[i].sigla); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].numero,ap_dados);//copy to struct printf("number: %s\n",alunos[i].numero); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].nome, ap_dados);//copy to struct printf("name: %s\n",alunos[i].nome); if(ap_dados=strtok(NULL,";")){ strcpy(alunos[i].email, ap_dados);//copy to struct printf("email: %s\n",alunos[i].email); } } } }i++; } if(isdigit(linha[0])){ if(info_notas=strtok(linha,";")){ strcpy(alunos[i].tot_not,info_notas); alunos[i].total_notas=atoi(alunos[i].tot_not);//total classes for(z=0;z<=alunos[i].total_notas;z++){ if(info_notas=strtok(NULL,";")){ strcpy(alunos[i].notas,info_notas); alunos[i].nota=atoi(alunos[i].notas); // student class notes } soma=soma + alunos[i].nota; media=soma/alunos[i].total_notas;//doesn't work if(alunos[i].nota>max){ max=alunos[i].nota;;//doesn't work } else{ if(min<alunos[i].nota){ min=alunos[i].nota;;//doesn't work } } //now i need to count the numbers of students in the same college, but doesn't work /*If(strcmp(alunos[i].sigla, alunos[i+1].sigla)=0){ count ++; printf("%d\n", count); here for LEI should appear 2 students and for LTCGM appear 1, don't work }*/ //Now i need to see if student is aproved or disaproved // Student is disaproved if he gets 3 notes under 10, how can i do that? } printf("media %d\n",media); //media printf("Nota maxima %d\n",max);// biggest note printf("Nota minima %d\n",min); //lowest note }i++; } } } fclose(fp); } int main(int argc, char *argv[]){ ALUNO alunos; FILE *fp; int tam; fp=fopen(nomeFicheiro,"r"); alunos = (ALUNO*) calloc (tam, sizeof(ALUNO)); xml(alunos,nomeFicheiro, tam); system("PAUSE"); return 0; }

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