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Search found 313 results on 13 pages for 'showdialog'.

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  • mybase.showdialog event fired without apparent reason

    - by António Mendes
    Hi, i'm new to vb .net and oop although i have learned the basics. I'm working in VB and .NET CF 3.5 and i'm trying to pass and received a value with showdialog. The issue here is when i'm done with a procedure in Load, for some reason MyBase.Showdialog (line 3) gives an error of "NullReferenceException was unhandled", but the same procedure doesn't have anything to do with Showdialog. Also, this same error happens with me in other forms when i use AlphaImageButton from AlphaMobileControls. I even created an custom AlphaImageButton with a DialogResult Property and set it to None with no avail. Public Overloads Function ShowDialog(ByRef sArg As String) As String sParam = Split(sArg, vbTab) sArtigo = sParam(0) If MyBase.ShowDialog() = Windows.Forms.DialogResult.OK Then Return lblQuant.Text End If Return Nothing End Function

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  • When would ShowDialog() return null?

    - by Joe White
    WPF's Window.ShowDialog method returns a nullable boolean. So does CommonDialog.ShowDialog. Now, I understand cases where these would return false (user clicked Cancel or pressed Esc), and when they would return true (code sets Window.DialogResult to true, probably in response to OK being clicked). But null? My first thought is that clicking the title bar's Close button might return null. But the docs state (and I confirmed by testing) that the title-bar Close button is treated as a Cancel. So when would Window.ShowDialog or CommonDialog.ShowDialog ever return null?

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  • WPF Dispatcher.UnhandledException within a ShowDialog call.

    - by Eric
    It appears that ShowDialog() invokes the Dispatcher message handling loop within. Thus, you have a stack that looks something like: Outer-most Dispatcher message loop ... x.ShowDialog() Inner Dispatcher message loop ... I am using the Dispatcher.UnhandledException to catch exceptions not handled by my code. However, it appears that the Inner Dispatcher message loop, above, is undesirably catching exceptions that my code would catch. Example: Outer-most Dispatcher message loop try/catch FooException ... x.ShowDialog() Inner Dispatcher message loop ... throw FooException What I would like is for the thrown FooException to get caught by the try/catch. However. It gets caught first by the (inner) Dispatcher.UnhandledException. I see there are ways to filter the exception. However, those filters will apply to both the inner and outer most handlers. What I am looking for is to have my Dispatcher.UnhandledException code run only on the outer-most dispatcher message loop. Does that make sense? I could, of course, reflect the call stack from within my handler to see if this is the outer-most dispatcher, but that seems a bit fragile. Other ideas? Thanks! Eric

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  • showDialog in Activity not displaying dialog

    - by Mohit Deshpande
    Here is my code: public class TasksList extends ListActivity { ... private static final int COLUMNS_DIALOG = 7; private static final int ORDER_DIALOG = 8; ... /** * @see android.app.Activity#onCreateDialog(int) */ @Override protected Dialog onCreateDialog(int id) { Dialog dialog; final String[] columns; Cursor c = managedQuery(Tasks.CONTENT_URI, null, null, null, null); columns = c.getColumnNames(); final String[] order = { "Ascending", "Descending" }; switch (id) { case COLUMNS_DIALOG: AlertDialog.Builder columnDialog = new AlertDialog.Builder(this); columnDialog.setSingleChoiceItems(columns, -1, new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { bundle.putString("column", columns[which]); } }); dialog = columnDialog.create(); case ORDER_DIALOG: AlertDialog.Builder orderDialog = new AlertDialog.Builder(this); orderDialog.setSingleChoiceItems(order, -1, new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { String orderS; if (order[which].equalsIgnoreCase("Ascending")) orderS = "ASC"; else orderS = "DESC"; bundle.putString("order", orderS); } }); dialog = orderDialog.create(); default: dialog = null; } return dialog; } /** * @see android.app.Activity#onOptionsItemSelected(android.view.MenuItem) */ @Override public boolean onOptionsItemSelected(MenuItem item) { switch (item.getItemId()) { case SORT_MENU: showDialog(COLUMNS_DIALOG); showDialog(ORDER_DIALOG); String orderBy = bundle.getString("column") + bundle.getString("order"); Cursor tasks = managedQuery(Tasks.CONTENT_URI, projection, null, null, orderBy); adapter = new TasksAdapter(this, tasks); getListView().setAdapter(adapter); break; case FILTER_MENU: break; } return false; } The showDialog doesn't display the dialog. I used the Debugger and it does executes these statements, but the dialog doesn't show. }

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  • WinForms and ShowDialog problem.

    - by SchlaWiener
    I have a borderless WinForms app. The main window creates other forms (simple dialogs where I can click yes or no) with ShowDialog(). Every created dialog is not visible in the taskbar, my app has only one taskbar entry that focuses my app (and if a dialog is open that one is focused). If I use ALT+TAB to cycle to all open windows I only see one entry, too. However, If the dialog is created while my app doesn't have the focus (for example the user starts a long running task, starts to work on something else and while being in the background, my app shows a dialog "Task done...") and I want to go back to my app, things are getting strange. If I click on the taskbar to focus my app, the main window is focused (not the dialog). I can't use the main window (because there is still an open modal dialog). Windows 7 ALT-TAB preview shows the Dialog while taskbar mouseover preview shows the main window (In normal behavior both show the dialog in front of the main window). The only way to make my app usable again is to ALT-TAB to the entry and close the modal dialog. If I use ALT-TAB only the dialog is brought to the front and the main window is still in the background Is there a way to prevent that from happening? I know what to do, but most customers think the app crashed since the main window doesn't respond.

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  • Synclock a section of code while waiting for ShowDialog to return

    - by clawson
    I'm having trouble working out how to lock my application out of a section of code while it waits for a response from an external program. I've used Synclock on a section of code with the Me object in the expression. In this Synclock I call an overridden ShowDialog method of a dialog box, which has a timeout parameter, but does return the value from the underlying ShowDialog function call ,once the timer is setup. Works like this. SyncLock Me Dim frmDlgWithTimeout As New frmDlgWithTimeout ' dialog box with overridden ShowDialog ' Dim res As DialogResult = frmDlgWithTimeout.ShowDialog(10 * 1000) ' 10 sec timeout ' End SyncLock Now, external programs may raise events that bring my application to this Synclock but it doesn't prevent it from entering it, even though the ShowDialog function hasn't returned a value (and hence what I thought would keep the section of code locked). There is only one instance of the object that is used for lock in the program. Your help is greatly appreciated.

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  • ShowDialog returns immediately after a handled exception in .net compact framework

    - by leiz
    The problem I am having is that for some reason ShowDialog returns immediately after handle an exception. However, it works for MessageBox.Show() or at the second time I call ShowDialog. What is the best workaround for this problem? I was only able to find this. And I cannot believe that no one else has this issue. I am using .net compact framework 3.5. Sample code: try { using(SomeForm f = new SomeForm()) { f.ShowDialog(); } } catch(SomeException) { using(SomeOtherForm f = new SomeOtherForm()) { f.ShowDialog(); // this returns immediately // if this is MessageBox.Show(), it works correctly. f.ShowDialog(); // then this works fine } }

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  • How to check whether the form has any ShowDialog() forms open?

    - by kornelijepetak
    I have a form MainForm with several properties/methods that are accessed from another thread. At some point I might open a form AuxForm with ShowDialog() and then while that modal form is open, the other thread still modifies the MainForm's properties. This is all desired. In one of the methods accessed from another thread I need to execute some code, but only if the modal AuxForm is not open. Is there any way to check this (by using .NET WF Form properties) or I need to use a flag variable? NOTE: None of these properties/methods modify the controls (so no Invoke is required).

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  • WPF ShowDialog returns immediately

    - by dthrasher
    Sometimes when I call ShowDialog on an OpenFileDialog Window in WPF, the dialog closes immediately with a return value of false. I'm calling ShowDialog in response to a button click event. I can reproduce this problem using the sample code for OpenFileDialog on MSDN: // Configure open file dialog box Microsoft.Win32.OpenFileDialog dlg = new Microsoft.Win32.OpenFileDialog(); dlg.FileName = "Document"; // Default file name dlg.DefaultExt = ".txt"; // Default file extension dlg.Filter = "Text documents (.txt)|*.txt"; // Filter files by extension // Show open file dialog box Nullable<bool> result = dlg.ShowDialog(); // Process open file dialog box results if (result == true) { // Open document string filename = dlg.FileName; } The problem occurs intermittently when I run my solution in Debug mode from Visual Studio 2008 SP1. It's quite annoying. Is this a known issue? Are there workarounds?

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  • can not override showDialog in Activity tab

    - by hornetbzz
    Trying to downgrade my appl from android 2.2 (API 8) down to android 2.1 (API7), I'm facing some issues with dialog boxes. Based on this thread, I'm trying to catch these exceptions but can't override the showDialog method. I turned the Java compiler from 1.5 to 1.6 according to this answer to a similar issue, but no changes, Eclipse still returns : Cannot override the final method from Activity public class MyActivity extends Activity implements SeekBar.OnSeekBarChangeListener { // ... some stuffs @Override // here is the issue public void showDialog(int dialogId) { try { super.showDialog(dialogId); } catch (IllegalArgumentException e) { Log.e(ACTIVITY_TAG, "Error dialog"); } } @Override protected Dialog onCreateDialog(int id) { switch (id) { case DIALOG_ALERT: // Create out AlertDialog Builder builder = new AlertDialog.Builder(this); builder.setMessage(msg); builder.setCancelable(false); builder.setPositiveButton(GOTO_BOOK, new OkOnClickListener()); builder.setNegativeButton(STAY_HERE, new CancelOnClickListener()); AlertDialog dialog = builder.create(); dialog.show(); break; case DIALOG_ONCREATE: // Create out AlertDialog during the "onCreate" method (only "Ok" // button) Builder builder2 = new AlertDialog.Builder(getParent()); builder2.setMessage(msg); builder2.setCancelable(false); builder2.setPositiveButton(GO_BACK, new OkOnClickListener()); AlertDialog dialog2 = builder2.create(); dialog2.show(); break; } return super.onCreateDialog(id); } // ... some stuffs }

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  • ShowDialog and Hide form, when from is called from other object in VS2010

    - by Piotr Dabrowski
    Hallo, I have a modal Form, used for searching information in DB. This Form is used by a COM object, that waits for search result. Initialization of the form take a lot of time (because of building connection to DB). So, I initialize the Form (without showing it), and keep Form-object alive, as long as COM-object work. In this way I keep the state of the Form: public void Search() this.ShowDialog(); string result = this.ResultOfSearch; this.Hide() return result; And it doesn't work anymore on VS2010 (compiled for Framework 2.0). I search for alternative way to make a modal form (or a method to protect a form against Destroy() at the end of ShowDialog). Any ideas?

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  • How do i use Form.ShowDialog?

    - by Daniel Lip
    private void button2_Click(object sender, EventArgs e) { ChangeLink cl = new ChangeLink(); // Show testDialog as a modal dialog and determine if DialogResult = OK. if (cl.ShowDialog() == DialogResult.OK) { // Read the contents of testDialog's TextBox. // cl.AcceptButton.DialogResult = DialogResult.OK; this.label4.Text = cl.textBox1Text; } else { this.label4.Text = "Cancelled"; } cl.Dispose(); } When i click the button i see the new Form and the textBox1 in the new Form and i can type in the textBox1 something but i dont see anywhere an OK or CANCEL buttons. Should i add them manualy in the new Form designer ? And how to use them then ? This is the code in my new Form what i wanted to do is to type something in the new Form textBox1 and pass the text in the textBox1 to Form1 label4. using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace GatherLinks { public partial class ChangeLink : Form { public ChangeLink() { InitializeComponent(); } public string textBox1Text { get { return textBox1Text = textBox1.Text; } set { } } } } So where are the OK and CANCEL buttons of the Form.ShowDialog ?

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  • Show form that showDialog from mainForm won't block it, but closing mainForm will close it

    - by meme
    how yo show a form which needs to run synchronously. I tried running application.run from a queueworker of a threadpool- but I had some invalid handles sometime. tried using a regular thread but then when main form closes it doesn't close this- and I don't really like the idea of killing the thread on_formclosing. if I use form.show it's fine besides that fact that any showdialog from the main form will block also this. What's the best way to handle this?

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  • ShowDialog won't run

    - by clawson
    I've come across a situation where I try to run a simple line of code in a method Dim res As DialogResult = frmOptions.ShowDialog() but nothing happens. The dialog box will not appear. If I run this method from another location in the code it executes fine (i.e. displays the form in dialog mode and code executes fine thereafter). Hence, it may be the way in which I arrive at this code that is causing my problem, but I cannot see to find what is wrong. When I pause the debugger the line of code is highlighted in green but I can't see to step over it or into it. Any idea what may cause this to happen, or what I should be looking for that might be causing the problem?? Thanks for the help!

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  • Form.ShowDialog() does not show form.

    - by clawson
    I've come across a situation where I try to run a simple line of code in a method Dim res As DialogResult = frmOptions.ShowDialog() but nothing happens. The dialog box will not appear. If I run this method from another location in the code it executes fine (i.e. displays the form in dialog mode and code executes fine thereafter). Hence, it may be the way in which I arrive at this code that is causing my problem, but I cannot see to find what is wrong. When I pause the debugger the line of code is highlighted in green but I can't see to step over it or into it. Any idea what may cause this to happen, or what I should be looking for that might be causing the problem?? Thanks for the help!

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  • What's wrong with my cross-thread call in Windows Forms?

    - by MainMa
    Hi, I encounter a problem with a Windows Forms application. A form must be displayed from another thread. So in the form class, I have the following code: private delegate void DisplayDialogCallback(); public void DisplayDialog() { if (this.InvokeRequired) { this.Invoke(new DisplayDialogCallback(DisplayDialog)); } else { this.ShowDialog(); } } Now, every time I run this, an InvalidOperationException is thrown on the line this.ShowDialog();: "Cross-thread operation not valid: Control 'SampleForm' accessed from a thread other than the thread it was created on." What's wrong with this piece of code? Isn't it a valid way to make cross-thread calls? Is there something special with ShowDialog()?

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  • Android : showDialog not displayer inside onActivityResult after take photo

    - by Nicolas
    Hello, When i'm in onActivityResult and i try to show a custom progress dialog, The dialog is not show, but the function is called, but nothing is displayed If i put this dialog in Oncreate it's working i see the dialogbox, Is it possible to show a custom dialog on return of Intent.ACTION_GET_CONTENT / MediaStore.ACTION_IMAGE_CAPTURE Thanks protected void onActivityResult(int requestCode, int resultCode, Intent data) { Parseur UploadPhoto = new Parseur(); showDialog(PROGRESS_DIALOG); if (requestCode == z_const.REQUEST_INTENT_CODE_PHOTO_CHOISIR) { String selectedImagePath; Uri selectedImageUri; if (data != null){ selectedImageUri = data.getData(); selectedImagePath = getPath(selectedImageUri); Log.e(TAG, "PHOTO CHOISIR " + selectedImagePath+"Res"+resultCode); UploadPhoto.uploadPhoto(InfoPasse,selectedImagePath); } } finish(); } protected Dialog onCreateDialog(int id) { Log.e(TAG," DIAL appeller "+id); switch(id) { case PROGRESS_DIALOG: progressDialog = new ProgressDialog(Photo.this); progressDialog.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL); progressDialog.setMessage("Loading..."); progressThread = new ProgressThread(handler); progressThread.start(); return progressDialog; default: return null; } }

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  • Save Dialog on top of another custom dialog is behaving strangely!

    - by Raghu
    I have a save as image feature for charts in my application. The chart control is a custom user control with custom logic in them. It also has some scaling based on size, zoom etc. However, while saving them as an image I would like to give the user the option to set the size of the image (eg: 800x600 px @ 300 DPI). To do this I have created a Form with textboxes/checkboxes etc for various settings for image. One of these TextBoxes is for the file name. The file name textbox is readonly and is accompanied with a browse button which shows a SaveFileDialog when clicked. The user clicks "Save As Image" in the main form's menu. I show the ImageExportDialog using the code below: using(ImageExportDialog dlg = new ImageExportDialog()) { if(dlg.ShowDialog() == DialogResult.OK) { //get the settings selected by the user and generate the image } } In the ImageExportDialog, the user clicks on the browse button and the SaveFileDialog is shown as follows: using(SaveFileDialog dlg = new SaveFileDialog()) { if(dlg.ShowDialog() == DialogResult.OK) { txtFileName.Text = dlg.FileName; } } Now the problem is, when the user clicks on "Save" button in the SaveFileDialog, as expected the txtFileName.Text is set, but the parent custom dialog also seems to return from the ShowDialog method and the DialogResult is the same as the one for SaveFileDialog! The control then goes on to the "get the settings selected by the user and generate the image" part of the code above. Not really sure what I am doing wrong here!

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  • public DialogResult ShowDialog() help!

    - by Luke
    I have two forms. The first form is the mainForm, this never goes anywhere. On opening the second form (saveForm), it will display over the top. When i close this form, I want a certain piece of code in the mainForm to run. I assume this is the correct way to get this to happen? The code on saveForm when I close and return to the mainForm: private void btnSaveDetails_Click(object sender, EventArgs e) { Delivery d = new Delivery(txtNameBox.Text, txtAddressBox.Text, txtDayBox.Text, txtTimeBox.Text, txtMealBox.Text, txtInstructionsBox.Text, txtStatusBox.Text); mainForm.myDeliveries.Add(d); this.Close(); } Any ideas?

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  • Modal dialog blocks wcf callback

    - by Bjarne
    I am working on an application that relies strongly on a wcf request/callback pattern. That is, it uses a service which exposes a number of methods, and for each method there is a callback on which the result is returned. In the client, I wish to open a modal dialog, make a request on the server and then wait for the result on the callback. But I never get a callback since the UI thread is blocked by the modal dialog. Has anyone worked with a similar pattern? I would hate to have more threads in the client, and I also don't like the idea of 'simulating' a modal dialog.

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  • Clicking Elements in Android Doesn't Display the Correct Values

    - by Devin
    I apologize if this code looks a bit like a mess (considering the length); I figured I'd just include everything that goes on in my program at the moment. I'm attempting to create a fairly simple Tic Tac Toe app for Android. I've set up my UI nicely so far so that there are a "grid" of TextViews. As a sort of "debug" right now, I have it so that when one clicks on a TextView, it should display the value of buttonId in a message box. Right now, it displays the correct assigned value for the first element I click, but no matter what I click afterwards, it always just displays the first value buttonID had. I attempted to debug it but couldn't exactly find a point where it would pull the old value (to the best of my knowledge, it reassigned the value). There's a good possibility I'm missing something small, because this is my first Android project (of any note). Can someone help get different values of buttonId to appear or point out the error in my logic? The code: package com.TicTacToe.app; import com.TicTacToe.app.R; //Other import statements public class TicTacToe extends Activity { public String player = "X"; public int ALERT_ID; public int buttonId; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); //Sets up instances of UI elements final TextView playerText = (TextView)findViewById(R.id.CurrentPlayerDisp); final Button button = (Button) findViewById(R.id.SetPlayer); final TextView location1 = (TextView)findViewById(R.id.location1); final TextView location2 = (TextView)findViewById(R.id.location2); final TextView location3 = (TextView)findViewById(R.id.location3); final TextView location4 = (TextView)findViewById(R.id.location4); final TextView location5 = (TextView)findViewById(R.id.location5); final TextView location6 = (TextView)findViewById(R.id.location6); final TextView location7 = (TextView)findViewById(R.id.location7); final TextView location8 = (TextView)findViewById(R.id.location8); final TextView location9 = (TextView)findViewById(R.id.location9); playerText.setText(player); //Handlers for events button.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { // Perform action on click if (player.equals("X")){ player = "O"; playerText.setText(player); } else if(player.equals("O")){ player = "X"; playerText.setText(player); } //Sets up the dialog buttonId = 0; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location1.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 1; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location2.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 2; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location3.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 3; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location4.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 4; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location5.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 5; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location6.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 6; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location7.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 7; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location8.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 8; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); location9.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Sets up the dialog buttonId = 9; ALERT_ID = 0; onCreateDialog(ALERT_ID); showDialog(ALERT_ID); } }); } protected Dialog onCreateDialog(int id){ String msgString = "You are on spot " + buttonId; AlertDialog.Builder builder = new AlertDialog.Builder(this); builder.setMessage(msgString) .setCancelable(false) .setNeutralButton("Ok", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { dialog.cancel(); } }); AlertDialog alert = builder.create(); return alert; } }

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  • Naming methods that do the same thing but return different types

    - by Konstantin Ð.
    Let's assume that I'm extending a graphical file chooser class (JFileChooser). This class has methods which display the file chooser dialog and return a status signature in the form of an int: APPROVE_OPTION if the user selects a file and hits Open /Save, CANCEL_OPTION if the user hits Cancel, and ERROR_OPTION if something goes wrong. These methods are called showDialog(). I find this cumbersome, so I decide to make another method that returns a File object: in the case of APPROVE_OPTION, it returns the file selected by the user; otherwise, it returns null. This is where I run into a problem: would it be okay for me to keep the showDialog() name, even though methods with that name — and a different return type — already exist? To top it off, my method takes an additional parameter: a File which denotes in which directory the file chooser should start. My question to you: Is it okay to call a method the same name as a superclass method if they return different types? Or would that be confusing to API users? (If so, what other name could I use?) Alternatively, should I keep the name and change the return type so it matches that of the other methods? public int showDialog(Component parent, String approveButtonText) // Superclass method public File showDialog(Component parent, File location) // My method

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  • Save as DialogBox to save textbox content to a newfile using asp.net

    - by user195114
    I want the users to type their text in the given textbox and on clicking on createNewFile Button, a SaveAs Dialogbox should popup and the users should browse through the location and save the file as desired. I have tried some thing but (1) the dialog box goes behind the application (2) when run, dialogbox opens 3 times, means it executes 3 times REPLY TO THE POST protected void btnNewFile_Click(object sender, EventArgs e) { StreamWriter sw = null; try { SaveFileDialog sdlg = new SaveFileDialog(); DialogResult result = sdlg.ShowDialog(); sdlg.InitialDirectory = @"C:\"; sdlg.AddExtension = true; sdlg.CheckPathExists = true; sdlg.CreatePrompt = false; sdlg.OverwritePrompt = true; sdlg.ValidateNames = true; sdlg.ShowHelp = true; sdlg.DefaultExt = "txt"; // sdlg.ShowDialog = Form.ActiveForm; string file = sdlg.FileName.ToString(); string data = txtNewFile.Text; if (sdlg.ShowDialog() == DialogResult.OK) { sw.WriteLine(txtNewFile.Text); sw.Close(); } if (sdlg.ShowDialog() == DialogResult.Cancel) { sw.Dispose(); } //Save(file, data); } catch { } finally { if (sw != null) { sw.Close(); } } } private void Save(string file, string data) { StreamWriter writer = new StreamWriter(file); SaveFileDialog sdlg1 = new SaveFileDialog(); try { if (sdlg1.ShowDialog() == DialogResult.OK) { writer.Write(data); writer.Close(); } else writer.Dispose(); } catch (Exception xp) { MessageBox.Show(xp.Message); } finally { if (writer != null) { writer.Close(); } } } I have tried this.

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