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  • The subsets-sum problem and the solvability of NP-complete problems

    - by G.E.M.
    I was reading about the subset-sums problem when I came up with what appears to be a general-purpose algorithm for solving it: (defun subset-contains-sum (set sum) (let ((subsets) (new-subset) (new-sum)) (dolist (element set) (dolist (subset-sum subsets) (setf new-subset (cons element (car subset-sum))) (setf new-sum (+ element (cdr subset-sum))) (if (= new-sum sum) (return-from subset-contains-sum new-subset)) (setf subsets (cons (cons new-subset new-sum) subsets))) (setf subsets (cons (cons element element) subsets))))) "set" is a list not containing duplicates and "sum" is the sum to search subsets for. "subsets" is a list of cons cells where the "car" is a subset list and the "cdr" is the sum of that subset. New subsets are created from old ones in O(1) time by just cons'ing the element to the front. I am not sure what the runtime complexity of it is, but appears that with each element "sum" grows by, the size of "subsets" doubles, plus one, so it appears to me to at least be quadratic. I am posting this because my impression before was that NP-complete problems tend to be intractable and that the best one can usually hope for is a heuristic, but this appears to be a general-purpose solution that will, assuming you have the CPU cycles, always give you the correct answer. How many other NP-complete problems can be solved like this one?

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  • [SQL] Getting the sum of several columns from two tables

    - by romaintaz
    I want to get the sum of several columns from 2 different tables (these tables share the same structure). If I only consider one table, I would write this kind of query: SELECT MONTH_REF, SUM(amount1), SUM(amount2) FROM T_FOO WHERE seller = XXX GROUP BY MONTH_REF; However, I would like to also work with the data from the table T_BAR, and then have a select query that return the following columns: MONTH_REF SUM(T_FOO.amount1) + SUM(T_BAR.amount1) SUM(T_FOO.amount2) + SUM(T_BAR.amount2) everything grouped by the value of MONTH_REF. Note that a record for a given MONTH_REF can be found in one table but not in the other table. In this case, I would like to get the sum of T_FOO.amount1 + 0 (or 0 + T_BAR.amount1). How can I write my SQL query to get this information? For information, my database is Oracle 10g.

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  • Detect duplicate in a subset from a set of elements

    - by Abhinav Shrivastava
    I have a set of numbers say : 1 1 2 8 5 6 6 7 8 8 4 2... I want to detect the duplicate element in subsets(of given size say k) of the above numbers... For example : Consider the increasing subsets(for example consider k=3) Subset 1 :{1,1,2} Subset 2 :{1,2,8} Subset 3 :{2,8,5} Subset 4 :{8,5,6} Subset 5 :{5,6,6} Subset 6 :{6,6,7} .... .... So my algorithm should detect that subset 1,5,6 contains duplicates.. My approach : 1)Copy the 1st k elements to a temporary array(vector) 2) using #include file in C++ STL...using unique() I would determine if there's any change in size of vector.. Any other clue how to approach this problem..

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  • MySQL how to sum subgroup first then sum total

    - by Sunry
    My data in table_1 and table_2. table_1 id_1 num ids_2 3 33 666,777,888 4 44 111,222,333 table_2 id_2 num 111 1 222 2 333 3 666 6 777 7 888 8 I only know how to do what I want with two steps: First LEFT JOIN to get: SELECT 1.id_1, sum(2.num) FROM table_1 AS 1 LEFT JOIN table_2 AS 2 on FIND_IN_SET(2.id_2, 1.ids_2) GROUP BY 1.id_1; id_1 sum(2.num) 3 6+7+8 4 1+2+3 Then LEFT JOIN with table_1 again to sum(table_1.num+sum(2.num)): id_1 sum(table_1.num+sum(table_2.num)) 3 6+7+8+33 4 1+2+3+44 Can I do it in only one SQL?

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  • C++ Loop - Need variable to accumulate sum

    - by user1780064
    I'm writing a program to ask the user to enter a value between 5 and 21 (inclusive). If the number entered is not in this range, it prints, "Please try again". If the number is within the range, I need to take that number, and print the sum of all the numbers from 1 to the value entered. So if the user entered "7", the sum would be "28". I successfully wrote the first loop, in the case of the number not being within the range, but cannot figure out how to run the second loop- whether to use a while, do-while, or for loop. Please advise. #include <iostream> int main () { int uservalue; int count; int sum; //Prompt user for input do { cout << "Enter a value from 5 to 21: "; cin >> uservalue; if (uservalue < 5 || uservalue > 21) cout << "Value out of range. Try again..." << endl; } while (uservalue < 5 || uservalue > 21); cout << endl; //Loop to accumulate sum for (count = 1, count < uservalue, count++;) { sum = uservalue + count; if (uservalue <= 5 || uservalue <= 21) cout << the sum is " << sum << endl; } return 0; }

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  • linq get sum of two columns in one query

    - by Axarydax
    Hi, let's say that I have a table called Items (ID int, Done int, Total int) I can do it by two queries: int total = m.Items.Sum(p=>p.Total) int done = m.Items.Sum(p=>p.Done) But I'd like to do it in one query, something like this: var x = from p in m.Items select new { Sum(p.Total), Sum(p.Done)}; Surely there is a way to call aggregate functions from LINQ syntax...?

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  • Get sum of two columns in one LINQ query

    - by Axarydax
    Hi, let's say that I have a table called Items (ID int, Done int, Total int) I can do it by two queries: int total = m.Items.Sum(p=>p.Total) int done = m.Items.Sum(p=>p.Done) But I'd like to do it in one query, something like this: var x = from p in m.Items select new { Sum(p.Total), Sum(p.Done)}; Surely there is a way to call aggregate functions from LINQ syntax...?

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  • a simple program that counts and sums digits. How can I make it work?

    - by user1710386
    So I've to write a simple program(that loops) where you can enter an int and it spews out the number count and the sum of the numbers. Since I am such a tard when it comes to programming, I just scavanged the code online and tried to piece it together. I guess the sum block screws with n, but I am not really sure. Anyway, I would really appreciate it if somebody could point out mistakes and show me how can I make it work. #include <iostream> using namespace std; int main() { while(1) { int i,p,n,sum=0; //sum block cout<<"enter an int: "; cin>>n; { while(n!=0) { p=n % 10; sum+=p; n=n/10; } cout<<"int digit sum: "<<sum <<endl; } { int count = 0; while(n) { n /= 10; ++count; } cout <<"number of digits: " << count << '\n';} } }

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  • MSSQL Sum query

    - by ldb
    today my problem is this i have 2 column and i wish check if the sum of that columns isn't Higher then a value(485 for example) and if is do a query...i though to do SELECT * FROM table WHERE ColumnA+ColumnB<485 But isn't working... i've already tried with SELECT Sum(ColumnA)+Sum(ColumnB) AS Total FROM table but it gives me 1 column with the sum of all rows, i instead want a row for every sum. so how can i do..? xD i hope you understood if not just ask that i try to explain it better! and thanks in advice for who want to help me! EDIT: I Found out XD the problem was that the columns was Smallint and the result of 1 or more rows was more than 32k so it wasn't working! Thanks At all!!

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  • Get a random subset from a set in F#

    - by Cay
    I am trying to think of an elegant way of getting a random subset from a set in F# Any thoughts on this? Perhaps this would work: say we have a set of 2x elements and we need to pick a subset of y elements. Then if we could generate an x sized bit random number that contains exactly y 2n powers we effectively have a random mask with y holes in it. We could keep generating new random numbers until we get the first one satisfying this constraint but is there a better way?

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  • select SUM in Cake

    - by SpawnCxy
    When I tried using follow code to get the sum of the column named Serviceinfo.services $conditions = array('fields'=>array('SUM(Serviceinfo.services) as servicecount'),'conditions'=>array('time_id BETWEEN ? AND ?'=>array($startid,$endtid))); $services = $this->Serviceinfo->find('all',$conditions); I had to fetch the sum data with services[0][0]['servicecount'] which seems a little weird.And What I expect is services['Serviceinfo']['servicecount'],or more simple one.Then how can I fix this?Thanks in advance!

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  • Create Sum of calculated rows in Microsoft Reporting Services

    - by kd7iwp
    This seems like it should be simple but I can't find anything yet. In Reporting Services I have a table with up to 6 rows that all have calculated values and dynamic visibility. I would like to sum these rows. Basically I have a number of invoice items and want to make a total. I can't change anything on the DB side since my stored procedures are used elsewhere in the system. Each row pulls data from a different dataset as well, so I can't do a sum of the dataset. Can I sum all the rows with a table footer? Similarly to totaling a number of rows in Excel? It seems very redundant to put my visibility expression from each row into my footer row to calculate the sum.

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  • How to sum properties of the objects within an array in Ruby

    - by Ernst Fitschen
    I understand that in order to sum array elements in Ruby one can use the inject method, i.e. array = [1,2,3,4,5]; puts array.inject(0, &:+) But how do I sum the properties of objects within an object array e.g. There's an array of objects and each object has a property "cash" for example. So I want to sum their cash balances into one total. Something like... array.cash.inject(0, &:+) (but this doesn't work) I realise I could probably make a new array composed only of the property cash and sum this, but I'm looking for a cleaner method if possible!

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  • making a combined sum of two columns

    - by bsandrabr
    I have a table (apples) containing: cid date_am date_pm ---------------------- 1 1 1 2 2 1 3 1 3 1 1 2 I asked a question earlier (badly) about how I would rank the customers in order of the number of ones(1) they had. The solution was (based on one column): SELECT cid, sum( date_pm ) AS No_of_ones FROM apples WHERE date_am =1 GROUP BY cid ORDER BY no_of_ones DESC This works great for one column but how would I do the same for the sum of the two columns. ie. SELECT cid, sum( date_pm ) AS No_of_ones FROM apples WHERE date_am =1 add to SELECT cid, sum( date_am ) AS No_of_ones FROM apples WHERE date_pm =1 GROUP by cid ORDER by no_of_ones(added) hope I've managed to make that clear enough for you to help -thanks

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  • using subset but old variables still left

    - by user2520852
    I am working with a data set, which is basically daily usage data (let's just say variable X and Y) by different cities (about 150 cities). I have created a subset of data for only specific cities, choosing just 3 of the 150 cities. Then when I do tapply by cities, I get means for 3 cities but also get NA for all other 147 cities that was in the data set. I am using the below coding df<-read.csv(...) df_sub<-subset(df,df$City==1|df$City==3|df$City==19) X_Breakdown<-tapply(X,df_sub$City, mean, na.rm=TRUE) Print(X_Breakdown) City 1 City 2 15 NA City 3 City 4 12 NA City 5 City 6 NA NA Hope you get the idea. I would like to get a dataset that only contains the 3 cities that I'm interested in. It seems that the set of variables is encoded in R, is there a way to fix this? Kindly advise. Thanks

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  • Calculate the SUM of the Column which has Time DataType:

    - by thevan
    I want to calculate the Sum of the Field which has Time DataType. My Table is Below: TableA: TotalTime ------------- 12:18:00 12:18:00 Here I want to sum the two time fields. I tried the below Query SELECT CAST( DATEADD(MS, SUM(DATEDIFF(MS, '00:00:00.000', CONVERT(TIME, TotalTime))), '00:00:00.000' ) AS TOTALTIME) FROM [TableA] But it gives the Output as TOTALTIME ----------------- 00:36:00.0000000 But My Desired Output would be like below: TOTALTIME ----------------- 24:36:00 How to get this Output?

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  • Finding the sum of 2D Arrays in Ruby

    - by Bragaadeesh
    Hi, I have an array of two dimensional Arrays. I want to create a new two dimensional array which finds the sum of these values in the 2D arrays. Sum at x,y of new array = Sum at x,y of arr1 + Sum at x,y of arr2 + .... |1,2,4| |1,1,1| |1,1,1| |2,4,6| |1,1,1| |1,1,1| |2,4,6| |1,1,1| |1,1,1| |2,4,6| |1,1,1| |1,1,1| Now adding the above two dimensional arrays will result in, |3,4,6| |4,6,8| |4,6,8| |4,6,8| How to achieve this in Ruby (not in any other languages). I have written a method, but it looks very long and ugly.

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  • Sum of distinc rows after a 1-many table join

    - by Lock
    I have 2 tables that I am joining. Table 1 has 1-many relationship with table 2. That is, table 2 can return multiple rows for a single row of table 1. Because of this, the records of table 1 is duplicated for as many rows as are on table 2.. which is expected. Now, I have a sum on one of the columns from table 1, but because of the multiple rows that get returned on the join, the sum is obviously multiplying. Is there a way to get this number back to its original number? I tried dividing by the count of rows from table 2 but this didnt quite give me the expected result. Are there any analytical functions that could do this? I almost want something like "if this row has not yet been counted in the sum, add it to the sum"

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  • Django custom SQL returning single row of results when query returns 2?

    - by Alvin
    I have a custom SQL call that is returning different results to the template than I get when I run the same query against the database directly, 1 row vs 2 Query - copied from Django Debug Toolbar: SELECT ((Sum(new_recruit_interviews) / Sum(opportunities_offered)) * 100) as avg_recruit, ((Sum(inspections) / Sum(presentations)) * 100) as avg_inspect, ((Sum(contracts_signed) / Sum(roof_approvals)) * 100) as avg_contracts, ((Sum(adjusters) / Sum(contracts_signed)) * 100) as avg_adjusters, ((Sum(roof_approvals) / Sum(adjusters)) *100) as roof_approval_avg, ((Sum(roof_turned_in) / Sum(adjusters)) * 100) as roof_jobs_avg, Sum(roof_turned_in) as roof_jobs_total, ((Sum(siding_approvals) / Sum(adjusters)) *100) as siding_approval_avg, ((Sum(siding_turned_in) / Sum(adjusters)) * 100) as siding_jobs_avg, Sum(siding_turned_in) as siding_jobs_total, ((Sum(gutter_approvals) / Sum(adjusters)) *100) as gutter_approval_avg, ((Sum(gutter_turned_in) / Sum(adjusters)) * 100) as gutter_jobs_avg, Sum(gutter_turned_in) as gutter_jobs_total, ((Sum(window_approvals) / Sum(adjusters)) *100) as window_approval_avg, ((Sum(window_turned_in) / Sum(adjusters)) * 100) as window_jobs_avg, Sum(window_turned_in) as window_jobs_total, (Sum(roof_turned_in) + Sum(siding_turned_in) + Sum(gutter_turned_in) + Sum(window_turned_in)) as total_jobs, (((Sum(collections_jobs_new) + Sum(collections_jobs_previous)) / (Sum(roof_turned_in) + Sum(siding_turned_in) + Sum(gutter_turned_in) + Sum(window_turned_in))) * 100) as total_collections, sales_report_salesmen.location_id as detail_id, business_unit_location.title as title FROM sales_report_salesmen Inner Join auth_user ON sales_report_salesmen.user_id = auth_user.id Inner Join business_unit_location ON sales_report_salesmen.location_id = business_unit_location.id GROUP BY location_id Results from direct query running the above query: INSERT INTO `` (`avg_recruit`, `avg_inspect`, `avg_contracts`, `avg_adjusters`, `roof_approval_avg`, `roof_jobs_avg`, `roof_jobs_total`, `siding_approval_avg`, `siding_jobs_avg`, `siding_jobs_total`, `gutter_approval_avg`, `gutter_jobs_avg`, `gutter_jobs_total`, `window_approval_avg`, `window_jobs_avg`, `window_jobs_total`, `total_jobs`, `total_collections`, `detail_id`, `title`) VALUES (95.3968, 92.8178, 106.9622, 90.2928, 103.5420, 103.5670, 4152, 100.2494, 106.8845, 4285, 120.1297, 86.2559, 3458, 92.9658, 106.1611, 4256, 16151, 4.281469, 12, 'St Paul, MN'); VALUES (90.2982, 73.3723, 97.8474, 104.5433, 97.7585, 86.1848, 1884, 109.9268, 109.3321, 2390, 81.0156, 96.4318, 2108, 91.7200, 123.8792, 2708, 9090, 4.531573, 13, 'Denver, CO'); Results from template: {'roof_jobs_total': Decimal('4152'), 'gutter_jobs_total': Decimal('3458'), 'avg_adjusters': Decimal('90.2928'), 'title': u'St Paul, MN', 'window_approval_avg': Decimal('92.9658'), 'total_collections': Decimal('4.281469'), 'gutter_approval_avg': Decimal('120.1297'), 'avg_recruit': Decimal('95.3968'), 'siding_approval_avg': Decimal('100.2494'), 'window_jobs_total': Decimal('4256'), 'detail_id': 12L, 'siding_jobs_avg': Decimal('106.8845'), 'avg_inspect': Decimal('92.8178'), 'roof_approval_avg': Decimal('103.5420'), 'roof_jobs_avg': Decimal('103.5670'), 'total_jobs': Decimal('16151'), 'window_jobs_avg': Decimal('106.1611'), 'avg_contracts': Decimal('106.9622'), 'gutter_jobs_avg': Decimal('86.2559'), 'siding_jobs_total': Decimal('4285')} Tried tweaking it a few ways and running the results through various for loops, keep getting the same result where my results are a single row through the Django template and the expected results (through console) have 2 rows The row that is coming back is the same as the first row returned through the console query so I'm thinking that it is running correctly just a matter of passing the results through... for good measure this is the code I'm using to generate the query (yes it's a bit ugly, been playing with it) def sql_grouped(table, fields, group_by=False, where=False): from django.db import connection query = 'SELECT %s FROM %s' % (fields, table) if where: query = query + ' WHERE %s' % (where) if group_by: query = query + ' GROUP BY %s' % (group_by) cursor = connection.cursor() cursor.execute(query) desc = cursor.description data = [dict(zip([col[0] for col in desc], row)) for row in cursor.fetchall()] return data[0] any feedback is greatly appreciated - been tinkering with this since I realized I could skip a few steps by generating my averages directly within the SQL rather than post-process

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  • Ideas Related to Subset Sum with 2,3 and more integers

    - by rolandbishop
    I've been struggling with this problem just like everyone else and I'm quite sure there has been more than enough posts to explain this problem. However in terms of understanding it fully, I wanted to share my thoughts and get more efficient solutions from all the great people in here related to Subset Sum problem. I've searched it over the Internet and there is actually a lot sources but I'm really willing to re-implement an algorithm or finding my own in order to understand fully. The key thing I'm struggling with is the efficiency considering the set size will be large. (I do not have a limit, just conceptually large). The two phases I'm trying to implement ideas on is finding two numbers that are equal to given integer T, finding three numbers and eventually K numbers. Some ideas I've though; For the two integer part I'm thing basically sorting the array O(nlogn) and for each element in the array searching for its negative value. (i.e if the array element is 3 searching for -3). Maybe a hash table inclusion could be better, providing a O(1) indexing the element? For the three or more integers I've found an amazing blog post;http://www.skorks.com/2011/02/algorithms-a-dropbox-challenge-and-dynamic-programming/. However even the author itself states that it is not applicable for large numbers. So I was for 2 and 3 and more integers what ideas could be applied for the subset problem. I'm struggling with setting up a dynamic programming method that will be efficient for the large inputs as well.

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  • Subset Problem -- Any Materials?

    - by bobber205
    Yes this is a homework/lab assignment. I am interesting in coming up with/finding an algorithm (I can comprehend :P) for using "backtracking" to solve the subset sum problem. Anyone have some helpful resources? I've spent the last hour or so Googling with not much like finding something I think I could actually use. xD Thanks SO!

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  • Zend Framework how to echo value of SUM query

    - by Rick de Graaf
    Hello, I created a query for the zend framework, in which I try to retrieve the sum of a column, in this case the column named 'time'. This is the query I use: $this->timequery = $this->db_tasks->fetchAll($this->db_tasks->select()->from('tasks', 'SUM(time)')->where('projectnumber =' . $this->value_project)); $this->view->sumtime = $this->timequery; Echoing the query tells me this is right. But I can't echo the result properly. Currently I'm using: echo $this->sumtime['SUM(time)']; Returning the following error: Catchable fatal error: Object of class Zend_Db_Table_Row could not be converted to string in C:\xampp\htdocs\BManagement\application\views\scripts\tasks\index.phtml on line 46 Line 46 being the line with the echo in my view. I've been searching now for two days on how to figure this out, or achieve the same result in a different way. Tried to serialize the value, but that didn't work either. Is there somebody who knows how to achieve the total sum of a database column? Any help is greatly appriciated! note: Pretty new to zend framework...

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  • Reporting Services: Two Tables One Sum

    - by Neomoon
    My report is as follows: One table provides financial information with sums at the group footer (Grouping is called "StockTable_Shipped"). The group is controlled by a boolean value (1=shows shipped data, 0 = shows received data) The second table is a variance report for data that has been shipped (boolean value of 1) and has a sum at the bottom of the table. My ultimate goal is to take the sum from table1 where shipped=1 and subtract it from the variance sum from table2. This will be placed in a textbox at the bottom of the report. I understand if this sounds confusing but I would be more then happy to provide more information.

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  • SQL..Sum two rows

    - by Cha
    Sample data: LOCATION NAME LABEL1 LABEL2 SERVICE TIME NY Andrew A B HOUSE 2555 NY Andrew A B CAR 35 NJ Copley C A HOUSE 1025 NY Copley A B HOUSE 650 VA Dalton D C PET 25 What I want to do ias add another column where in it shows sum(Time) of rows with same data except for the Service.Also, the services that I need are only the sum of car and house.Is this possible? If not can you help me with the right query Sample output I need: LOCATION NAME LABEL1 LABEL2 SERVICE TIME SUM NY Andrew A B HOUSE 2555 **2590** NY Andrew A B CAR 35 NJ Copley C A HOUSE 1025 1025 NY Copley A B HOUSE 650 650

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