I have this piece of code that's really prone to errors so I wrapped it with try{}catch statement. I don't want to go back to the previous activity, I just want it to stay on the current activity so that the user can edit whatever is wrong with them. How do I implement this? try{ orgi.insertOrThrow(tableName, null, values); Toast.makeText(this, "You have successfully created a new profile!", 2).show(); gotoProfileList(); Log.e(getClass().getSimpleName(),"Successfully added to database"); }catch(SQLiteException se){ Log.e(getClass().getSimpleName(), "Database connection failed!" + se); //Stay in this activity... }finally{ if (orgi != null){ orgi.close(); } } Forget it, I was able to solve my own problem by showing up an alertDialog that tells the user about the error. Thanks anyways. :) try{ orgi.insertOrThrow(tableName, null, values); Toast.makeText(this, "You have successfully created a new profile!", 2).show(); gotoProfileList(); Log.e(getClass().getSimpleName(),"Successfully added to database"); }catch(SQLiteException se){ Log.e(getClass().getSimpleName(), "Database connection failed!" + se); displayError(); //stayInThisActivity(); }finally{ if (orgi != null){ orgi.close(); } public void displayError(){ AlertDialog.Builder error = new AlertDialog.Builder(this); error.setMessage("That profile name already exists, try another one.").setCancelable(false).setPositiveButton("Yes",new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.cancel(); } }); AlertDialog alert = error.create(); alert.setTitle("Error"); alert.show(); }