If I want to open binary file (in Python 2.6), that doesn't exists, program exits with an error and prints this: Traceback (most recent call last): File "C:\Python_tests\Exception_Handling\src\exception_handling.py", line 4, in <module> pkl_file = open('monitor.dat', 'rb') IOError: [Errno 2] No such file or directory: 'monitor.dat' I can handle this with 'try-except', like: try: pkl_file = open('monitor.dat', 'rb') monitoring_pickle = pickle.load(pkl_file) pkl_file.close() except Exception: print 'No such file or directory' Does anybody know, how could I, in caught Exception, print the following line? File "C:\Python_tests\Exception_Handling\src\exception_handling.py", line 11, in <module> pkl_file = open('monitor.dat', 'rb') So, program would not exits, and I would have useful information.