HELP Translate A[i] = B[i-1] + B[i] + B[i+1] to MIPS the address of array A is $s1 the address of array B is $s2 the value of i is $s3 lb $s1,0($s3) # $s1=A[i] lb $s2,0($s3) # $s2=B[i] sb $s2,0($s3) # store s2 add $t0, $zero, $s2 #t0=B[i] addi $s3,$s3,-1 #i=i-1 lb $s2 0($s3) #$s2=B[i-1] add $t1,$zero,$s2 #t1=B[i-1] add $s1,$t0,$t1 #A[i]=B[i-1]+B[i] addi $s3,$s3,2 #i+1 lb $s2,0($s3) #s2=B[i+1] add $t2,$zero,$s2 #t2=B[i+1] add $s1,$s1,$t2 #A[i] = t1 + B[i+1] sb $s1 I know this is kind of mess, but it's the best i can write