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  • Is it possible to bind arrays of literals in sqlite3-ruby?

    - by willb
    I'd like to execute the following sort of query through sqlite3-ruby: SELECT * FROM foo WHERE bar IN (:items) and bind :items to one or many literals. Is this possible? The obvious technique of passing the list of literals as an array as follows doesn't seem to work: db.execute("SELECT * FROM foo WHERE bar IN (:items)", :items=>[3,1]) (In the above example, only the first value in the array is bound to :items.)

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  • XSL match some but not all

    - by Willb
    I have a solution from an earlier post that was kindly provided by Dimitre Novatchev. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="my:my"> <xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/> <xsl:key name="kPhysByName" match="KB_XMod_Modules" use="Physician"/> <xsl:template match="/"> <result> <xsl:apply-templates/> </result> </xsl:template> <xsl:template match="/*/*/*[starts-with(name(), 'InfBy')]"> <xsl:variable name="vCur" select="."/> <xsl:for-each select="document('doc2.xml')"> <xsl:variable name="vMod" select="key('kPhysByName', $vCur)"/> <xsl:copy> <items> <item> <label> <xsl:value-of select="$vMod/Physician"/> </label> <value> <xsl:value-of select="$vMod/XModID"/> </value> </item> </items> </xsl:copy> </xsl:for-each> </xsl:template> </xsl:stylesheet> I now need to use additional fields in my source XML and need the existing labels intact but I'm having problems getting this going. <instance> <NewTag>Hello</newTag1> <AnotherNewTag>Everyone</AnotherNewTag> <InfBy1>Dr Phibes</InfBy1> <InfBy2>Dr X</InfBy2> <InfBy3>Dr Chivago</InfBy3> </instance> It drops the additional labels and outputs <result xmlns:my="my:my"> HelloEveryone <items> <item> <label>Dr Phibes</label> <value>60</value> </item> </items> ... I've been experimenting a lot with <xsl:otherwise> <xsl:copy-of select="."> </xsl:copy-of> </xsl:otherwise> but being an xsl newbie I can't seem to get this to work. I've a feeling I'm barking up the wrong tree! Does anyone have any ideas? Thanks, Will

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