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  • Print out the amount of times 2 words appear in the syslog. But also have it tell me how many times for each hour

    - by wolfspinone
    So I'm trying to create a bash script that looks for two words in my syslog file. Then I want the script to print out how many times those two words have appeared. Also I want it to print it out for every hour of the day. So like if the word dog appeared 4 times during the first hour of today, it says Hour one, dog 4. Finally at the end of the script I want it to print out how many times those words appeared all day. The sudo code I have thus far is if 2 > hour find permit find block print both finish if 1 < hour < 2 find permit find block print both finish if 2 < hour < 3 find permit find block print both finish command is grep -o "\WORD\" Syslog.txt * | sort | uniq -c

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