In Powerpoint 2007, how can I position a Callout's Tail programatically?

Posted by Rorschach on Stack Overflow See other posts from Stack Overflow or by Rorschach
Published on 2009-12-01T21:21:04Z Indexed on 2010/03/16 22:41 UTC
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I'm looking at the XML and this is what it has for the Callout object's coordinates and geometry:

<p:spPr>
    <a:xfrm>
    	<a:off x="2819400" y="5181600"/> // X,Y Position of Callout Box
    	<a:ext cx="609600" cy="457200"/> // Width,Height of Callout Box
    </a:xfrm>
    <a:prstGeom prst="wedgeRectCallout">
    	<a:avLst>
    		<a:gd name="adj1" fmla="val 257853"/> // X Position Of Tail
    		<a:gd name="adj2" fmla="val -532360"/> // Y Position of Tail
    	</a:avLst>
    </a:prstGeom>
    <a:solidFill>
    	<a:schemeClr val="accent1">
    		<a:alpha val="50000"/>
    	</a:schemeClr>
    </a:solidFill>
</p:spPr>

What I'm having trouble with is the formula for telling it to place the tail at a particular coordinate on the slide. I've tried this to calculate it, but it does not work correctly.

//This gives me the distance between the Coordinate and the Center of the Callout.
DistanceX = Coordinate.X - (Callout.X + Callout.X_Ext)/2
DistanceY = Coordinate.Y - (Callout.Y + Callout.Y_Ext)/2

But, the geometric value is not the distance between the two points.

Anybody know what the formula is for calculating this?

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