Use XSLT to arrange a list of items in a table

Posted by Mark Sp on Stack Overflow See other posts from Stack Overflow or by Mark Sp
Published on 2010-03-29T09:29:35Z Indexed on 2010/03/29 9:33 UTC
Read the original article Hit count: 299

Filed under:
|
|
|
|

I have a linear list of items which I wish to arrange in a table using XSLT. I wish to specify the number of columns as a parameter. For example, if I have a list of 12 items, I can select a 2x6, 3x4, 4x3 or 6x2 table. I cannot see a general way to do this.

I have seen this article: http://www.nedcomp.nl/support/origdocs/xml4/extracted/xpath_hdi_1_4llx.aspx

It tells you how to generate a table with a specific number of columns, but does not allow a general case. (Ideally there would be a loop for the xsl:value-of lines).

Thanks

Mark

© Stack Overflow or respective owner

Related posts about Xml

Related posts about xsl