Can someone explain me this code ?
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            by VaioIsBorn
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        Published on 2010-04-03T12:53:10Z
        Indexed on 
            2010/04/03
            13:03 UTC
        
        
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#include <stdio.h>                    
#include <unistd.h>                   
#include <string.h>                   
int good(int addr) {
        printf("Address of hmm: %p\n", addr);
}                                            
int hmm() {
        printf("Win.\n");
        execl("/bin/sh", "sh", NULL);
}                                    
extern char **environ;
int main(int argc, char **argv) {
        int i, limit;
        for(i = 0; environ[i] != NULL; i++)
        memset(environ[i], 0x00, strlen(environ[i]));
        int (*fptr)(int) = good;
        char buf[32];
        if(strlen(argv[1]) <= 40) limit = strlen(argv[1]);
        for(i = 0; i <= limit; i++) {
                buf[i] = argv[1][i];
                if(i < 36) buf[i] = 0x41;
        }
        int (*hmmptr)(int) = hmm;
        (*fptr)((int)hmmptr);
        return 0;
}
I don't really understand the code above, i have it from an online game - i should supply something in the arguments so it would give me shell, but i don't get it how it works so i don't know what to do. So i need someone that would explain it what it does, how it's working and the stuff. Thanks.
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