RSA PKCS1 implementation in Python
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        Published on 2010-04-03T15:30:36Z
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            2010/04/03
            15:33 UTC
        
        
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rsa
I'm working on the RSA PKCS1 implementation in Python,here's the message block i got:
m = [0,2,random paddings,0,message integers]
I read the RFC2313,and get a equation seems for transforming the message block object into an big-edian integer. I just get confused about how to transform it in Python.
Any help would be appreciated.
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