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  • python RSA implemention with PKCS1

    - by user307016
    I got the following code in javascript for RSA implementionhttp://www-cs-students.stanford.edu/~tjw/jsbn/: // Return the PKCS#1 RSA encryption of "text" as an even-length hex string function RSAEncrypt(text) { var m = pkcs1pad2(text,(this.n.bitLength()+7)>>3); if(m == null) return null; var c = this.doPublic(m); if(c == null) return null; var h = c.toString(16); if((h.length & 1) == 0) return h; else return "0" + h; } // PKCS#1 (type 2, random) pad input string s to n bytes, and return a bigint function pkcs1pad2(s,n) { if(n < s.length + 11) { // TODO: fix for utf-8 alert("Message too long for RSA"); return null; } var ba = new Array(); var i = s.length - 1; while(i >= 0 && n > 0) { var c = s.charCodeAt(i--); if(c < 128) { // encode using utf-8 ba[--n] = c; } else if((c > 127) && (c < 2048)) { ba[--n] = (c & 63) | 128; ba[--n] = (c >> 6) | 192; } else { ba[--n] = (c & 63) | 128; ba[--n] = ((c >> 6) & 63) | 128; ba[--n] = (c >> 12) | 224; } } ba[--n] = 0; var rng = new SecureRandom(); var x = new Array(); while(n > 2) { // random non-zero pad x[0] = 0; while(x[0] == 0) rng.nextBytes(x); ba[--n] = x[0]; } ba[--n] = 2; ba[--n] = 0; return new BigInteger(ba); } In the snippets above, it seems that the pkcs1pad2 function is used for padding the message with some random bytes(maybe sth like 0|2|random|0 ) in front of the message. I'm using the python rsa package (http://stuvel.eu/rsa) for imitating the javascript result, i'm a newbie to python world and have no idea to traslate javascript algorithm code to the python code. Any help would be appreciated. Jiee

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  • RSA PKCS1 implementation in Python

    - by user307016
    I'm working on the RSA PKCS1 implementation in Python,here's the message block i got: m = [0,2,random paddings,0,message integers] I read the RFC2313,and get a equation seems for transforming the message block object into an big-edian integer. I just get confused about how to transform it in Python. Any help would be appreciated.

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