The implicit function __strcpy_chk() call

Posted by Summer_More_More_Tea on Stack Overflow See other posts from Stack Overflow or by Summer_More_More_Tea
Published on 2010-04-04T05:47:56Z Indexed on 2010/04/04 5:53 UTC
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Hi everyone:

I'm now performing a stack buffer overflow attack test on my own PC( Ubuntu 9.10, gcc-4.4.1 ) based on the article http://www.tenouk.com/Bufferoverflowc/Bufferoverflow4.html. Yet I haven't achieved the goal. Each time a segfault is thrown accompanied with some error informaiton.

I compile the source code, and wanna get further information using objdump. Function __strcpy_chk is invoked in the assembly code dumped out, and it's said that "The __strcpy_chk() function is not in the source standard; it is only in the binary standard." Does this the mechanism a compiler employed to protect runtime stack? To finish my test, how can I bypass the protection?

Regards.

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