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Published on 2010-04-26T07:04:23Z
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2010/04/26
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Probably an easy regex question.
How do I remove all non-digts except leading + from a phone number?
i.e.
012-3456 => 0123456
+1 (234) 56789 => +123456789
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I have a list of variables:
variables = ['VariableA', 'VariableB','VariableC']
which I'm going to search for, line by line
ifile = open("temp.txt",'r')
d = {}
match = zeros(len(variables))
for line in ifile:
emptyCells=0
for i in range(len(variables)):
regex = r'('+variables[i]+r')[:|=|\(](-…
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I was looking at the regular expression for validating various data types from the (OWASP Regex Repository).
One of the regular expressions in there is called safetext and looks like:
^[a-zA-Z0-9\s.\-]+$
My first question is:
Is this regular expression correct?
complementary question
If this…
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I am writing a tool to help students learn regular expressions. I will probably be writing it in Java.
The idea is this: the student types in a regular expression and the tool shows which parts of a text will get matched by the regex. Simple enough.
But I want to support several different regex…
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I'm writing a piece of client-side javascript code that takes a function and finds the derivative of it, however, the regex that's supposed to match with the power rule fails to work in the context of the javascript program, even though it sucessfully matches when it's used with an independent regex…
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I need to be able to check for a pattern with | in them. For example an expression like d*|*t should return true for a string like "dtest|test".
I'm no regex hero so I just tried a couple of things, like:
Regex Pattern = new Regex("s*\|*d"); //unable to build because of single backslash
Regex Pattern…
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