Find multiple regex in each line and skip result if one of the regex doesn't match

Posted by williamx on Stack Overflow See other posts from Stack Overflow or by williamx
Published on 2010-03-22T11:27:30Z Indexed on 2010/03/22 11:31 UTC
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I have a list of variables:

variables = ['VariableA', 'VariableB','VariableC']

which I'm going to search for, line by line

ifile = open("temp.txt",'r')

d = {}

match = zeros(len(variables))
for line in ifile:
    emptyCells=0
    for i in range(len(variables)):
        regex = r'('+variables[i]+r')[:|=|\(](-?\d+(?:\.\d+)?)(?:\))?'
        pattern_variable = re.compile(regex)
        match[i] = re.findall(pattern_variable, line)

        if match[j] == []:
            emptyCells = emptyCells+1

    if emptyCells == 0:
        for k, v in match[j]:
            d.setdefault(k, []).append(v)

The requirement is that I will only keep the lines where all the regex'es matches!

I want to collect all results for each variable in a dictionary where the variable name is the key, and the value becomes a list of all matches.

The code provided is only what I've found out so far, and is not working perfectly yet...

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