Point in polygon OR point on polygon using LINQ

Posted by wageoghe on Stack Overflow See other posts from Stack Overflow or by wageoghe
Published on 2010-05-06T19:32:02Z Indexed on 2010/05/06 19:38 UTC
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As noted in an earlier question, How to Zip enumerable with itself, I am working on some math algorithms based on lists of points. I am currently working on point in polygon. I have the code for how to do that and have found several good references here on SO, such as this link Hit test. So, I can figure out whether or not a point is in a polygon. As part of determining that, I want to determine if the point is actually on the polygon. This I can also do. If I can do all of that, what is my question you might ask?

Can I do it efficiently using LINQ? I can already do something like the following (assuming a Pairwise extension method as described in my earlier question as well as in links to which my question/answers links, and assuming a Position type that has X and Y members). I have not tested much, so the lambda might not be 100% correct. Also, it does not take very small differences into account.

public static PointInPolygonLocation PointInPolygon(IEnumerable<Position> pts, Position pt)
{

  int numIntersections = pts.Pairwise( (p1, p2) =>
                                       {
                                         if (p1.Y != p2.Y)
                                         {
                                           if ((p1.Y >= pt.Y && p2.Y < pt.Y) || (p1.Y < pt.Y && p2.Y >= pt.Y))
                                           {
                                             if (p1.X < p1.X && p2.X < pt.X) 
                                             {
                                               return 1;
                                             }

                                             if (p1.X < pt.X || p2.X < pt.X)
                                             {
                                               if (((pt.Y - p1.Y) * ((p1.X - p2.X) / (p1.Y - p2.Y)) * p1.X) < pt.X)
                                               {
                                                 return 1;
                                               }
                                             }
                                           }
                                         }
                                         return 0;

                                       }).Sum();
  if (numIntersections % 2 == 0)
  {
    return PointInPolygonLocation.Outside;
  }
  else
  {
    return PointInPolygonLocation.Inside;
  }
}

This function, PointInPolygon, takes the input Position, pt, iterates over the input sequence of position values, and uses the Jordan Curve method to determine how many times a ray extended from pt to the left intersects the polygon. The lambda expression will yield, into the "zipped" list, 1 for every segment that is crossed, and 0 for the rest. The sum of these values determines if pt is inside or outside of the polygon (odd == inside, even == outside). So far, so good.

Now, for any consecutive pairs of position values in the sequence (i.e. in any execution of the lambda), we can also determine if pt is ON the segment p1, p2. If that is the case, we can stop the calculation because we have our answer.

Ultimately, my question is this: Can I perform this calculation (maybe using Aggregate?) such that we will only iterate over the sequence no more than 1 time AND can we stop the iteration if we encounter a segment that pt is ON? In other words, if pt is ON the very first segment, there is no need to examine the rest of the segments because we have the answer.

It might very well be that this operation (particularly the requirement/desire to possibly stop the iteration early) does not really lend itself well to the LINQ approach.

It just occurred to me that maybe the lambda expression could yield a tuple, the intersection value (1 or 0 or maybe true or false) and the "on" value (true or false). Maybe then I could use TakeWhile(anontype.PointOnPolygon == false). If I Sum the tuples and if ON == 1, then the point is ON the polygon. Otherwise, the oddness or evenness of the sum of the other part of the tuple tells if the point is inside or outside.

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