PHP syntax question: global $argv, $argc;

Posted by Andrew on Stack Overflow See other posts from Stack Overflow or by Andrew
Published on 2010-05-07T17:49:58Z Indexed on 2010/05/07 17:58 UTC
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So I have a PHPUnit test, and found this code within a function.

global $argv, $argc;
echo $argc;
print_r($argv);

I understand what these variables represent (arguments passed from the command line), but I've never seen this syntax before:global $argv, $argc;

What specifically is going on here?

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