VB.NET - Removing a number from a random number generator

Posted by Alex on Stack Overflow See other posts from Stack Overflow or by Alex
Published on 2010-05-13T01:23:43Z Indexed on 2010/05/13 1:34 UTC
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I am trying to create a lottery simulator. The lottery has 6 numbers, the number generated must be between 1 - 49 and cannot be in the next number generated. I have tried using the OR function but I'm not entirely sure if I am using it properly. Any help would be great. Thanks.

Public Class Form1

Private Sub cmdRun_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdRun.Click
    'Creates a new Random class in VB.NET
    Dim RandomClass As New Random()



    '####################################
    Dim RandomNumber1 As Integer
    RandomNumber1 = RandomClass.Next(1, 49)
    'Displays first number generated
    txtFirst.Text = (RandomNumber1)



    '####################################
    Dim RandomNumber2 As Integer
    RandomNumber2 = RandomClass.Next(1, 49)
    If RandomNumber2 = RandomNumber1 Then
        RandomNumber2 = RandomClass.Next(1, 49)
    End If

    'Displays second number generated
    txtSecond.Text = (RandomNumber2)



    '####################################
    Dim RandomNumber3 As Integer
    RandomNumber3 = RandomClass.Next(1, 49)
    If RandomNumber3 = RandomNumber2 Or RandomNumber2 Then
        RandomNumber3 = RandomClass.Next(1, 49)
    End If

    'Displays third number generated
    txtThird.Text = (RandomNumber3)



    '####################################
    Dim RandomNumber4 As Integer
    RandomNumber4 = RandomClass.Next(1, 49)
    If RandomNumber4 = RandomNumber3 Or RandomNumber2 Or RandomNumber1 Then
        RandomNumber4 = RandomClass.Next(1, 49)
    End If

    'Displays fourth number generated
    txtFourth.Text = (RandomNumber4)



    '####################################
    Dim RandomNumber5 As Integer
    RandomNumber5 = RandomClass.Next(1, 49)
    If RandomNumber5 = RandomNumber4 Or RandomNumber3 Or RandomNumber2 Or RandomNumber1 Then
        RandomNumber5 = RandomClass.Next(1, 49)
    End If

    'Displays fifth number generated
    txtFifth.Text = (RandomNumber5)



    '####################################
    Dim RandomNumber6 As Integer
    RandomNumber6 = RandomClass.Next(1, 49)
    If RandomNumber6 = RandomNumber5, RandomNumber4, RandomNumber3, RandomNumber2, RandomNumber1 Then
        RandomNumber6 = RandomClass.Next(1, 49)
    End If

    'Displays sixth number generated
    txtSixth.Text = (RandomNumber6)


End Sub

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