Use an Array to Cycle Through a MySQL Where Statement

Posted by Ryan on Stack Overflow See other posts from Stack Overflow or by Ryan
Published on 2010-05-23T16:23:12Z Indexed on 2010/05/23 16:31 UTC
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I'm trying to create a loop that will output multiple where statements for a MySQL query. Ultimately, my goal is to end up with these four separate Where statements:

`fruit` = '1' AND `vegetables` = '1'
`fruit` = '1' AND `vegetables` = '2'
`fruit` = '2' AND `vegetables` = '1'
`fruit` = '2' AND `vegetables` = '2'

My theoretical code is pasted below:

<?php

$columnnames = array('fruit','vegetables');
$column1 = array('1','2');
$column2 = array('1','2');

$where = '';
$column1inc =0;
$column2inc =0;

while( $column1inc <= count($column1) ) {
    if( !empty( $where ) )
    $where .= ' AND ';
    $where = "`".$columnnames[0]."` = ";
    $where .= "'".$column1[$column1inc]."'";

    while( $column2inc <= count($column2) ) {
        if( !empty( $where ) )
        $where .= ' AND ';
        $where .= "`".$columnnames[1]."` = ";
        $where .= "'".$column2[$column2inc]."'";

            echo $where."\n";

    $column2inc++;
}

$column1inc++;
}

?>

When I run this code, I get the following output:

`fruit` = '1' AND `vegetables` = '1'
`fruit` = '1' AND `vegetables` = '1' AND `vegetables` = '2'
`fruit` = '1' AND `vegetables` = '1' AND `vegetables` = '2' AND `vegetables` = ''

Does anyone see what I am doing incorrectly? Thanks.

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