Replace whitespaces using PHP preg_replace function ignoring quoted strings
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            by Saiful
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        Published on 2010-05-24T09:00:32Z
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            2010/05/25
            6:31 UTC
        
        
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Look at the following string:
SELECT
    column1 ,
    column2, column3
FROM
    table1
WHERE
    column1 = 'text, "FROM" \'from\\\' x' AND
    column2 = "sample text 'where' \"where\\\" " AND
    ( column3 = 5 )
I need to escape unnecessary white space characters from the string like:
- removing white space from beginning and ending position of , ( ) etc
- removing newline (\r\n) and tabs (\t)
But one thing. The remove process could not remove white spaces from the quoted string like:
- 'text, "FROM" \'from\\' x'
- "sample text 'where' \"where\\" "
etc.
i need to use the PHP function: preg_replace($pattern, $replacement, $string);
So what will be the value of $pattern and $replacement where the value of $string is the given SQL.
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