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Published on 2010-06-01T12:19:19Z
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2010/06/01
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Hello !
When I try to execute following querry:
SELECT id_subscriber
INTO newsletter_to_send
FROM subscribers
I get an error:
#1327 - Undeclared variable: newsletter_to_send
What is wrong with that query ?
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I tried everything till now:
sudo apt-get remove mysql-server mysql-client mysql-common
sudo apt-get purge mysql-server mysql-client mysql-common
sudo apt-get autoremove
and even more commands...
But whenever I am trying to locate mysql. I get a no. of files related to mysql
command:
shell>>…
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Mysql was started:
/usr/bin/mysqld_safe --datadir=/srv/mysql/myDB --log-error=/srv/mysql/logs/mysqld-myDB.log --pid-file=/srv/mysql/pids/mysqld-myDB.pid --user=mysql --socket=/srv/mysql/sockets/mysql-myDB.sock --port=3700
but when I'm trying to do something:
ERROR 1548 (HY000) at line 1: Cannot…
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A client of my IT-consulting service owns a web-development shop. He's been having problems with a Slackware 12.0 server running MySQL 5.0.67. The machine was set up by the client's sysadmin, who left on bad terms. My client no longer employs a sysadmin.
As far as I can tell, the only copy of MySQL…
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Can't start mysql with:
sudo /usr/bin/mysqld_safe --datadir=/srv/mysql/myDB --log-error=/srv/mysql/logs/mysqld-myDB.log --pid-file=/srv/mysql/pids/mysqld-myDB.pid --user=mysql --socket=/srv/mysql/sockets/mysql-myDB.sock --port=3700
120222 13:40:48 mysqld_safe Starting mysqld daemon with databases…
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MySQL is one of the most popular database language and I have been recently working with it a lot. Data have no barrier and every database have their own place. I have been working with MySQL for quite a while and just like SQL Server, I often find lots of people asking me if I have a tutorial which…
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I exported a live MySQL database (running mysql 5.0.45) to a local copy (running mysql 5.1.33) with no errors upon import. There is a view in the database, that when executed locally, returns a different set of data than when executed remotely. It's returning 32 results instead of 63. When I execute…
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This is a query I am doing with mysql using PHP
This is the query line
<?php
$query = "SELECT * FROM node WHERE type = 'student_report' AND uid = '{$uid}' LIMIT 1 ORDER BY created DESC";
?>
I get the following error
You have an error in your SQL syntax; check the manual that corresponds…
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MySQL's query cache is an impressive piece of engineering if sometimes misunderstood. Keeping it optimized and used efficiently can make a big difference in the overall throughput of your application, so it's worth taking a look under the hood, understanding it, and then keeping it tuned optimally.
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Hi all,
I have the following table:
Service_ID feedback
31 1
32 1
33 1 1
I have the sample code to find the sum:
ResultSet res = st.executeQuery("SELECT Service_ID,SUM(consumer_feedback)…
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I have a table with at least a couple million rows and a schema of all integers that looks roughly like this:
start
stop
first_user_id
second_user_id
The rows get pulled using the following queries:
SELECT *
FROM tbl_name
WHERE stop >= M
AND first_user_id=N
AND second_user_id=N…
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